I need to calculate the sum of digits in a numeric string. The function should keep on adding the digits of each result, till the final sum is a single digit. Please refer to the following example and result expected:-
Supposed the number entered in Cell A1 is 456789
Result 1 = 4+5+6+7+8+9 = 39
Result 2 = 3+9 = 12
Final Result required = 1+2 = 3
i need to format my numbers in the following format
10,00,000.00
the first three digits will be separated and then subsequently 2 digits
I'm working on a project where I need to prevent the user from entering non-digit string inputs. I've tried the using IsNumeric(MyString). but that doesn't prevent , + - signs to be entered. I also had to conditionally enable the input of a string with leading zeros like "01" so what I've ended up with is a rather messy looking' sub that handles this (don't know if forum rules allows me to show it here?). The problem is that I'm not a 100% sure that my sub fit to handle all eventualities so therefore my question is whether there is an easier, fool proof way to check my strings?
View 6 Replies View RelatedWhen we give formulas say for eg
cell A5/Cel d4*30/365
we format for two digits so i get in my spread sheet cell as
60423.28
but it is actually
60423.28302
so over a period of time my figures posted in accounts dont match to excel spreadsheet.
How can i get the excel spreadsheet to not only show two digits but calculate to two digits as well So say if my calculation result is
60423.276 it should not only show 60423.28 but also be that way and not 60423.276
I have some code where I need to check if the first five char are numbers and not letters.
I have in a column for example
12345-someone is here
23456-someone else is here
someone is here too
I need to get all of the ones that have 5 digits and not pull in the other into a new list.
I have tried Left(CPHierAll. Cells(CPHierAllRow, 1),5) which will get me the fist 5 char. and then i need to check to make sure that they are all numbers and not char.
if Left(CPHierAll.Cells(CPHierAllRow, 1),5) = "#####" then
But this does not bring anything in.
I also tried if CPHierAll.Cells(CPHierAllRow, 1),5) = "#####" then
I have 3 column that i am checking for different thinks the first two work just find and seperate out on the check but the last one with the numbers is being a pain.
I have a long string that has a list of digits in the middle that I want to extract. The string is variable length and the number of digits I want to extract is 5-7. I also have slashes in between the numbers I want to extract. I need a UDF that allows me to extract the 5-7 digit number from the string and restrict around the slashes (i.e. if two sets of digits in the string match the condition for extraction, extract the one around the slashes.) For example my original data is like
1. aaa/12345/aaa/123
2. aaaaa/123456/aaaaaa/3423
3. 323/aa/1234567/aa
and I want for results
1. 12345
2. 123456
3. 1234567
Is there a UDF that allows me to do this?
I wrote an excel program in Excel'03 for a dental office to manage state assistance patients and one of the table columns is the state assistance number. The problem is that the program defaults to a number format when it is entered instead of a text format, which is what I want. The issue is that state assistance numbers are always 8 digits and when it defaults to a number field the program drops the required preceeding zeros.
For example the number 00123456 will sometimes show up as 123456, which is wrong. It's like sometimes it will show up right and other times it gets a butterfly in its brain and deletes those zeros irritating the receptionist here. So, how do I get the table to either stay in text format or set up a number format that keeps the preceeding zeros?
I have a number, eg, 1234567 and rounded to prepare the shrink of the size of the number like
= Round(a1, -3). I have, say now, 1234000.
I need to strip "000" from the number and place 1234 to a cell.
I am using the following to check if a string has a sequence of 6 decimal digits in it. But am getting an error. If(str Like *######*). I have to check if str has values like 123456USA ; ABC725439 ; jh658478hd. I thought # represents a single digit and * represents any no of characters
View 2 Replies View RelatedCan a vba macro be provided for splitting a number into digits? The number will be in Sheet 1 but splitted number will be on sheet 2. Splitting of numbers means a number entered into a cell will be splitted into different column/cells with one digit per cell.
View 14 Replies View RelatedI work in a finance department and we have MANY numbers consisting of 7 digits. Is there a way to enter in the entire number, but only display the first 4 digits?
View 9 Replies View RelatedI want to extract the fifth and sixth digits from an 8 figure number i.e. 20010891 would equal 10.
I have tried every combination of Left & Right combined with Find that I know and nothing works.
In my worksheet there is a column with values of either 3 or 4 numbers. If the value only has 3 numbers I would like to add a space before the first number, to ensure the proper line-up when saving the sheet as a text file. How can I do this (conditional formatting or macro??)
View 5 Replies View RelatedI need a formula to extract the first two numbers and move them to the back of the number remaining. For example, the original number is 235871, the result would be 587123.
My numbers always have six digits but may at times have seven.
Does anybody know of a special format or a rounding function that displays or rounds a number off to a specific number of significant digits.
Lets say I would like 3 significant digits this would be the results:
0.40019 -> 0.400
6.543 -> 6.54
12.543 -> 12.5
32 -> 32.0
564.7894 -> 565
54387 -> 54400 (or 5.44E+4 to be correct, but i can live with 54400)
as you can see in the picture;
it is possible to separate numbers from Column A into each column of B and C?
I have a calculated field which is essentially two concatenated values (DDMMYY and sequential numbers starting from 1). I want it so that any single digits will automatically have a zero in front (e.g. 01, 02, 03 etc). The concatenating takes place in VBA so it has to be coded...
View 3 Replies View RelatedNeed a formula in M2 that will count the number of digits that match in each row. The digits in H:L compared to the master list in A:A119766. The count will be from 0-5 for each row. The digits must be in same column....
View 9 Replies View RelatedI would like a function that checks an input number to see if it contains unique digits. If the digits are unique the output is 1 else the output is -1. Thus, supposing we call the function UNIQ(), we find UNIQ(15423) = 1 but UNIQ(154532) = -1. The input is always a positive integer.
View 7 Replies View RelatedI have problems in PASTING my 19 digit number from the source report into excel.
E.g, the original value is 8321515222222123122 but it always transfer to 8321515222222120000
I have tried the simple cell format setting, that is after pasting, I set the cells to text, but it doesn't help and also try the custom fomat "###################", but it is still the same result with the last 4 digit lost.
What I want the format to be is not in scientfic and have to be full display.
a2 needs to contain a number (multiple of 10 10-90) and then d2 must contain a formula that gives that number in word form.
I need to do the same thing in b2 and e2, only with a number 20-99 not neccesarily ending in 0.
I need Excel to create Date's of Birth from following data in column A. If the data are 7 numbers long, I need to add a '0' to the start and have used the custom format of 0#######. This works fine but I need the data in column B to just display the first 4 digits. I have used =LEFT(A1,4) to do this, but it's not picking up the 0's which I've added.
View 11 Replies View RelatedHow do I limit the number of digits to the right of the decimal in a calculation?
View 3 Replies View RelatedI am wanting to create a VB script that will take a number (in general format) of two or three digits, convert it to text, then make sure that there are enough zeros preceeding the number to make exactly 6 digits. Examples of the initial number (before the macro is run) and the final number (after it is run): ..
View 8 Replies View RelatedI have in my cell a number, namely, 5260007005020024100055040300004110000000
What I would like to do is extract a set of digits from it,
Starting from the second 2, and shown here in the dots. I need all of the numbers in a separate cell, "52600070050200 .24100055.. 040300004110000000"
Hope this is clear. bearing in mind the number will remain as one so I would need to start at 14 then using LEN or something I'm not sure, extract the following 8 into another cell.
I have a large file with cells filled with text (converted from a database, imported into Excel). The text is in rows of column A and always contains a 16 digit number, which is what I need. I am able to clean up this text and show only this number, but then Excel shows the last digit as a '0'.
An example of the text I need to filter the 16-digit number from: GIRO 6838657 K MAHMODBETALINGSKENM. 7062542158461684 STORNOADMINISTRATIEVE REDEN 1 ZIE DE TOEGEZONDEN KENNISGEVINGVAN VERHAAL OF CJIC.NL/VZD
I've altered some of the information in here so this is fake. The text is messy but all I need is the number.
This is the macro I use to clean up the text and leave only the 16 digit number:
Sub CleanUp
Dim e As Variant
With CreateObject("VBScript.RegExp")
[Code].....
It sort of works, but when I run it, I get this number as a result: 7062542158461680 (last digit is changed into a zero).
I've been trying to insert this line into the macro but it doesn't work: Columns("A:A").NumberFormat = "@"
How do I change the outcome of this macro into the actual number?
If this is impossible to do, I can also manage if there is a way to filter only the last 9 digits from the 16 digit number. I can work with that, too.
I use Excel XP (2002) at work.
counting some room numbers that meet a specific criteria. For example:
Let's say i have room numbers
1233
1234
569
2148
3422
I need to count the room numbers which the last two digits are greater than 40.
So far I have tried to separate the last two by using the Right formula but then when I try to use countif, it doesn't work as I guess that the result of the extraction comes back a a text value
I am working on my project for VBA and I need to make a program for Large Factorials sch as 25!, which is too big to fit as a Long-integer. I basically have to find a way around this by storing the numbers as arrays F() and C(). Array F is for the multiplication of each cell of memory, and C is for the carries, which will later be added. I need to separate the hundreds, tens and units of each multiplication.
To Further explain, lets say I have 12!; to find this I would take the previously calculated 11! (by using a loop) and multiply 12 by each memory cell of the array F(). So it's kind of like multiplying by hand, you bring down the units and put the carries on top to be added later. I would store the carries as one or two memory locations over of the current I, or the current loop number. So the units of the mult. would be stored as F(I), the tens would be carried and stored as C(I+1), and the hundreds would also be carried, but this time two cells over, so C(I+2)
The main problem I have is finding the proper code to split the number into units, tens, and hundreds, and then assigning them to their appropriate memory cells within their respective arrays.
Here's what I have so far:
Code:
Dim F(1 To 30), C(1 To 30), N As Integer, Fact As Long, Length As Integer, space As Integer
Sub LargeFactorialCalc()
Open "F:project.txt" For Output As #1
F(1) = 1
N = InputBox("Enter the number you would like to take the factorial of: ")
[Code] .......
I have 4 and 5 digit numbers. For the 4 digit numbers, I want to be able to distinguish between the numbers by the last digit. For the 5 digit numbers, I want to be able to distinguish between the numbers by the last two digits.
Example: For 4 digit numbers, I would like to do something with all numbers ending in 1, 2, 3, 4, 5, 6, 7, and 8. For 5 digit numbers, I would like to do something with numbers ending in 10, 11, 12, 20, 21, etc.
The first step in being able to do this, I guess is distiguishing between 4 and 5 digit numbers, which I know can be done by the number lenght. However, the second part of looking at the last digit or the two last digits I don't know how to do.
I have a list of numbers with 2, 3, and 4 digits. Is there a formula that can recognize if there are only 2 digits, it will add 2 zeros in front of the number.
For example,
47 will become 0047
234 will become 0234
1234 will become 1234
