Count The Number Of Digits That Match In Each Row

Dec 24, 2009

Need a formula in M2 that will count the number of digits that match in each row. The digits in H:L compared to the master list in A:A119766. The count will be from 0-5 for each row. The digits must be in same column....

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Excel 2007 :: Count Number Of Digits Without Counting Digit Twice

Sep 10, 2013

The values in columns b:d range from 000-999. I need a formula that will count the number of digits in B:D that match the 3 values in H1 without counting a digit twice. The existing formula counts a digit twice, like the value in H4.

DIGIT HITSABCDEFGH10,1,2209/09/132192191222309/09/134824821441409/08/131191191112509/08/139799792550609/07/137177171551709/07/138668662000
Excel 2007Worksheet FormulasCellFormulaE2=B2&C2&D2F2=SUM(B2:D2)G2=MOD(F2,10)H2=SUMPRODUCT(--ISNUMBER(FIND(","&$B2:$D2&",",","&H$1&",")))E3=B3&C3&D3F3=SUM(B3:D3)G3=MOD(F3,10)H3=SUMPRODUCT(--ISNUMBER(FIND(","&$B3:$D3&",",","&H$1&",")))E4=B4&

[Code] ......

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I'm trying to Count the number of Entries on a Sheet that match an Hour. Looking through the availiable functions i found COUNTIFS, which is exactly what I want. However, when I try to compare the Hour values within the COUNTIFS arguments, there is an error.

This is the function that I figured would work here:
=COUNTIFS(HOUR(Sheet1!G:G), HOUR(E6))

which should count all entries in column G where its HOUR matches the HOUR in E6 (all are time format). I do realize that in the example above there is only one comparison made and i'm using COUNTIFS instead of COUNTIF, but i'll be adding other comparisons to it once i get this first comparison working.

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match 457 = 1

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Feb 12, 2009

I wrote an excel program in Excel'03 for a dental office to manage state assistance patients and one of the table columns is the state assistance number. The problem is that the program defaults to a number format when it is entered instead of a text format, which is what I want. The issue is that state assistance numbers are always 8 digits and when it defaults to a number field the program drops the required preceeding zeros.

For example the number 00123456 will sometimes show up as 123456, which is wrong. It's like sometimes it will show up right and other times it gets a butterfly in its brain and deletes those zeros irritating the receptionist here. So, how do I get the table to either stay in text format or set up a number format that keeps the preceeding zeros?

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I need to strip "000" from the number and place 1234 to a cell.

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Jun 24, 2013

I would like a formula to count the number of unique digits from a range of cells.

For example...

Range A1:F1...
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Range A2:F2...
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May 13, 2013

I'm trying to develop a new daily timesheet for my production workers, where non-production items are recorded in 15 minute intervals. The user would put in "Clock in" by the corresponding time, and the same for "Clock out" at the end of the day. Any non-production items will be type in next to their appropriate time. Since clock in and clock out times will vary, I need to set up a formula that searches the array of cells for the day, finds the "Clock in" and "Clock out" values, and counts any blank cells in between them. Basically the blank cells will equal production time, and the result of the Count function will be multiplied by 0.25 to get the hours.

I am having a very difficult time finding a way to set the "Clock in" and "Clock out" cells as the range for the Count function, because it won't always be the same cells. What would be the best way to automatically have excel find the cells containing these values and set them as the range criteria for a Count function?

The formula at the bottom was one of my initial attempts, but it didn't work. I took out the '=' for the screenshot, so that wasn't the problem.

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I would like a function that checks an input number to see if it contains unique digits. If the digits are unique the output is 1 else the output is -1. Thus, supposing we call the function UNIQ(), we find UNIQ(15423) = 1 but UNIQ(154532) = -1. The input is always a positive integer.

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Jun 13, 2008

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Jun 1, 2009

I need Excel to create Date's of Birth from following data in column A. If the data are 7 numbers long, I need to add a '0' to the start and have used the custom format of 0#######. This works fine but I need the data in column B to just display the first 4 digits. I have used =LEFT(A1,4) to do this, but it's not picking up the 0's which I've added.

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I am wanting to create a VB script that will take a number (in general format) of two or three digits, convert it to text, then make sure that there are enough zeros preceeding the number to make exactly 6 digits. Examples of the initial number (before the macro is run) and the final number (after it is run): ..

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Oct 17, 2011

I have in my cell a number, namely, 5260007005020024100055040300004110000000

What I would like to do is extract a set of digits from it,

Starting from the second 2, and shown here in the dots. I need all of the numbers in a separate cell, "52600070050200 .24100055.. 040300004110000000"

Hope this is clear. bearing in mind the number will remain as one so I would need to start at 14 then using LEN or something I'm not sure, extract the following 8 into another cell.

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Nov 20, 2012

I have a large file with cells filled with text (converted from a database, imported into Excel). The text is in rows of column A and always contains a 16 digit number, which is what I need. I am able to clean up this text and show only this number, but then Excel shows the last digit as a '0'.

An example of the text I need to filter the 16-digit number from: GIRO 6838657 K MAHMODBETALINGSKENM. 7062542158461684 STORNOADMINISTRATIEVE REDEN 1 ZIE DE TOEGEZONDEN KENNISGEVINGVAN VERHAAL OF CJIC.NL/VZD

I've altered some of the information in here so this is fake. The text is messy but all I need is the number.

This is the macro I use to clean up the text and leave only the 16 digit number:

Sub CleanUp
Dim e As Variant
With CreateObject("VBScript.RegExp")

[Code].....

It sort of works, but when I run it, I get this number as a result: 7062542158461680 (last digit is changed into a zero).

I've been trying to insert this line into the macro but it doesn't work: Columns("A:A").NumberFormat = "@"

How do I change the outcome of this macro into the actual number?

If this is impossible to do, I can also manage if there is a way to filter only the last 9 digits from the 16 digit number. I can work with that, too.

I use Excel XP (2002) at work.

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Sep 20, 2013

counting some room numbers that meet a specific criteria. For example:

Let's say i have room numbers

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2148
3422

I need to count the room numbers which the last two digits are greater than 40.

So far I have tried to separate the last two by using the Right formula but then when I try to use countif, it doesn't work as I guess that the result of the extraction comes back a a text value

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Apr 13, 2014

I am working on my project for VBA and I need to make a program for Large Factorials sch as 25!, which is too big to fit as a Long-integer. I basically have to find a way around this by storing the numbers as arrays F() and C(). Array F is for the multiplication of each cell of memory, and C is for the carries, which will later be added. I need to separate the hundreds, tens and units of each multiplication.

To Further explain, lets say I have 12!; to find this I would take the previously calculated 11! (by using a loop) and multiply 12 by each memory cell of the array F(). So it's kind of like multiplying by hand, you bring down the units and put the carries on top to be added later. I would store the carries as one or two memory locations over of the current I, or the current loop number. So the units of the mult. would be stored as F(I), the tens would be carried and stored as C(I+1), and the hundreds would also be carried, but this time two cells over, so C(I+2)

The main problem I have is finding the proper code to split the number into units, tens, and hundreds, and then assigning them to their appropriate memory cells within their respective arrays.

Here's what I have so far:

Code:
Dim F(1 To 30), C(1 To 30), N As Integer, Fact As Long, Length As Integer, space As Integer
Sub LargeFactorialCalc()
Open "F:project.txt" For Output As #1

F(1) = 1
N = InputBox("Enter the number you would like to take the factorial of: ")

[Code] .......

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