# Display First 4 Digits Of A Number

Dec 5, 2006I work in a finance department and we have MANY numbers consisting of 7 digits. Is there a way to enter in the entire number, but only display the first 4 digits?

I work in a finance department and we have MANY numbers consisting of 7 digits. Is there a way to enter in the entire number, but only display the first 4 digits?

i need to format my numbers in the following format

10,00,000.00

the first three digits will be separated and then subsequently 2 digits

i have 2 coulmns in a listbox. The columns cant display more than 11 digits. So basically it would look like this 1.23456789E+12. I even tried playing with the Columnwidth but that didnt work.

View 2 Replies View RelatedI need a way to display all 8 digit numbers that have the digits 1-8 in them. (ie. 12345678 but NOT 12345679 OR 12345677) Also If I could somehow divide by 13 then check for whole numbers

View 14 Replies View RelatedI am trying to display the results that i get in excel sheet in a userform using textboxes; I need to round off the digits in these textboxes so as to display 2 digits after decimal point! I would like to have the code to solve this problem!

View 4 Replies View RelatedNeed to display time in total minutes but with a space after every 3 digits.

For instance, I can display 0.833333 as total minutes by using the custom number format [m] which displays 1200. But I need it to display as 1 200. I know with a standard number, I could use # ##0 but I don't know how to get both of these custom attributes to work simultaneously.

I wrote an excel program in Excel'03 for a dental office to manage state assistance patients and one of the table columns is the state assistance number. The problem is that the program defaults to a number format when it is entered instead of a text format, which is what I want. The issue is that state assistance numbers are always 8 digits and when it defaults to a number field the program drops the required preceeding zeros.

For example the number 00123456 will sometimes show up as 123456, which is wrong. It's like sometimes it will show up right and other times it gets a butterfly in its brain and deletes those zeros irritating the receptionist here. So, how do I get the table to either stay in text format or set up a number format that keeps the preceeding zeros?

I have a number, eg, 1234567 and rounded to prepare the shrink of the size of the number like

= Round(a1, -3). I have, say now, 1234000.

I need to strip "000" from the number and place 1234 to a cell.

I'm trying to create a completion statement on where I will add up the money my client has sent to me and also add up the money I need to pay out in order for them to complete their transaction. The end result I want is I would like to display whether my client has given me to much money and I need to repay them. Or if they haven't given me enough then I need to invoice them. I need excel to display for me after all the figures have been added and subtracted if the end figure is negative then display in D19 (balanced owed to you). If the end figure is positive (Balance required from you) display in D20.

View 12 Replies View RelatedCan a vba macro be provided for splitting a number into digits? The number will be in Sheet 1 but splitted number will be on sheet 2. Splitting of numbers means a number entered into a cell will be splitted into different column/cells with one digit per cell.

View 14 Replies View RelatedI want to extract the fifth and sixth digits from an 8 figure number i.e. 20010891 would equal 10.

I have tried every combination of Left & Right combined with Find that I know and nothing works.

In my worksheet there is a column with values of either 3 or 4 numbers. If the value only has 3 numbers I would like to add a space before the first number, to ensure the proper line-up when saving the sheet as a text file. How can I do this (conditional formatting or macro??)

View 5 Replies View RelatedI need a formula to extract the first two numbers and move them to the back of the number remaining. For example, the original number is 235871, the result would be 587123.

My numbers always have six digits but may at times have seven.

Does anybody know of a special format or a rounding function that displays or rounds a number off to a specific number of significant digits.

Lets say I would like 3 significant digits this would be the results:

0.40019 -> 0.400

6.543 -> 6.54

12.543 -> 12.5

32 -> 32.0

564.7894 -> 565

54387 -> 54400 (or 5.44E+4 to be correct, but i can live with 54400)

I need to calculate the sum of digits in a numeric string. The function should keep on adding the digits of each result, till the final sum is a single digit. Please refer to the following example and result expected:-

Supposed the number entered in Cell A1 is 456789

Result 1 = 4+5+6+7+8+9 = 39

Result 2 = 3+9 = 12

Final Result required = 1+2 = 3

as you can see in the picture;

it is possible to separate numbers from Column A into each column of B and C?

I have a calculated field which is essentially two concatenated values (DDMMYY and sequential numbers starting from 1). I want it so that any single digits will automatically have a zero in front (e.g. 01, 02, 03 etc). The concatenating takes place in VBA so it has to be coded...

View 3 Replies View RelatedNeed a formula in M2 that will count the number of digits that match in each row. The digits in H:L compared to the master list in A:A119766. The count will be from 0-5 for each row. The digits must be in same column....

View 9 Replies View RelatedI would like a function that checks an input number to see if it contains unique digits. If the digits are unique the output is 1 else the output is -1. Thus, supposing we call the function UNIQ(), we find UNIQ(15423) = 1 but UNIQ(154532) = -1. The input is always a positive integer.

View 7 Replies View RelatedI have problems in PASTING my 19 digit number from the source report into excel.

E.g, the original value is 8321515222222123122 but it always transfer to 8321515222222120000

I have tried the simple cell format setting, that is after pasting, I set the cells to text, but it doesn't help and also try the custom fomat "###################", but it is still the same result with the last 4 digit lost.

What I want the format to be is not in scientfic and have to be full display.

a2 needs to contain a number (multiple of 10 10-90) and then d2 must contain a formula that gives that number in word form.

I need to do the same thing in b2 and e2, only with a number 20-99 not neccesarily ending in 0.

I need Excel to create Date's of Birth from following data in column A. If the data are 7 numbers long, I need to add a '0' to the start and have used the custom format of 0#######. This works fine but I need the data in column B to just display the first 4 digits. I have used =LEFT(A1,4) to do this, but it's not picking up the 0's which I've added.

View 11 Replies View RelatedHow do I limit the number of digits to the right of the decimal in a calculation?

View 3 Replies View RelatedI am wanting to create a VB script that will take a number (in general format) of two or three digits, convert it to text, then make sure that there are enough zeros preceeding the number to make exactly 6 digits. Examples of the initial number (before the macro is run) and the final number (after it is run): ..

View 8 Replies View RelatedI have in my cell a number, namely, 5260007005020024100055040300004110000000

What I would like to do is extract a set of digits from it,

Starting from the second 2, and shown here in the dots. I need all of the numbers in a separate cell, "52600070050200 .24100055.. 040300004110000000"

Hope this is clear. bearing in mind the number will remain as one so I would need to start at 14 then using LEN or something I'm not sure, extract the following 8 into another cell.

I have a large file with cells filled with text (converted from a database, imported into Excel). The text is in rows of column A and always contains a 16 digit number, which is what I need. I am able to clean up this text and show only this number, but then Excel shows the last digit as a '0'.

An example of the text I need to filter the 16-digit number from: GIRO 6838657 K MAHMODBETALINGSKENM. 7062542158461684 STORNOADMINISTRATIEVE REDEN 1 ZIE DE TOEGEZONDEN KENNISGEVINGVAN VERHAAL OF CJIC.NL/VZD

I've altered some of the information in here so this is fake. The text is messy but all I need is the number.

This is the macro I use to clean up the text and leave only the 16 digit number:

Sub CleanUp

Dim e As Variant

With CreateObject("VBScript.RegExp")

[Code].....

It sort of works, but when I run it, I get this number as a result: 7062542158461680 (last digit is changed into a zero).

I've been trying to insert this line into the macro but it doesn't work: Columns("A:A").NumberFormat = "@"

How do I change the outcome of this macro into the actual number?

If this is impossible to do, I can also manage if there is a way to filter only the last 9 digits from the 16 digit number. I can work with that, too.

I use Excel XP (2002) at work.

counting some room numbers that meet a specific criteria. For example:

Let's say i have room numbers

1233

1234

569

2148

3422

I need to count the room numbers which the last two digits are greater than 40.

So far I have tried to separate the last two by using the Right formula but then when I try to use countif, it doesn't work as I guess that the result of the extraction comes back a a text value

I am working on my project for VBA and I need to make a program for Large Factorials sch as 25!, which is too big to fit as a Long-integer. I basically have to find a way around this by storing the numbers as arrays F() and C(). Array F is for the multiplication of each cell of memory, and C is for the carries, which will later be added. I need to separate the hundreds, tens and units of each multiplication.

To Further explain, lets say I have 12!; to find this I would take the previously calculated 11! (by using a loop) and multiply 12 by each memory cell of the array F(). So it's kind of like multiplying by hand, you bring down the units and put the carries on top to be added later. I would store the carries as one or two memory locations over of the current I, or the current loop number. So the units of the mult. would be stored as F(I), the tens would be carried and stored as C(I+1), and the hundreds would also be carried, but this time two cells over, so C(I+2)

The main problem I have is finding the proper code to split the number into units, tens, and hundreds, and then assigning them to their appropriate memory cells within their respective arrays.

Here's what I have so far:

Code:

Dim F(1 To 30), C(1 To 30), N As Integer, Fact As Long, Length As Integer, space As Integer

Sub LargeFactorialCalc()

Open "F:project.txt" For Output As #1

F(1) = 1

N = InputBox("Enter the number you would like to take the factorial of: ")

[Code] .......

I have 4 and 5 digit numbers. For the 4 digit numbers, I want to be able to distinguish between the numbers by the last digit. For the 5 digit numbers, I want to be able to distinguish between the numbers by the last two digits.

Example: For 4 digit numbers, I would like to do something with all numbers ending in 1, 2, 3, 4, 5, 6, 7, and 8. For 5 digit numbers, I would like to do something with numbers ending in 10, 11, 12, 20, 21, etc.

The first step in being able to do this, I guess is distiguishing between 4 and 5 digit numbers, which I know can be done by the number lenght. However, the second part of looking at the last digit or the two last digits I don't know how to do.

I have a list of numbers with 2, 3, and 4 digits. Is there a formula that can recognize if there are only 2 digits, it will add 2 zeros in front of the number.

For example,

47 will become 0047

234 will become 0234

1234 will become 1234

I am trying to apply conditional formatting to highlight the cells in D column if it starts with 91099 or 91004.

I tried to do the same using wild card, and left function but didn't get the desired output.

I have a very large database where I want to filter out numbers that do

not have certain two digits as their last two. For example, the column

based on which I want to filter out data contains numbers like

197301310153. I want to filter out anything that does not end in 53....

I basically I have a column with numbers. All the numbers are positive integers. What I like to do is have a VBA function that extracts the integers with the largest number of digits. So for example if we have the following column:

12

123

234

12346

2345

[code].....

So basically we search for largest number of digits, and extract the numbers that fit this category, which could be just one number or multiple numbers.

The values in columns b:d range from 000-999. I need a formula that will count the number of digits in B:D that match the 3 values in H1 without counting a digit twice. The existing formula counts a digit twice, like the value in H4.

DIGIT HITSABCDEFGH10,1,2209/09/132192191222309/09/134824821441409/08/131191191112509/08/139799792550609/07/137177171551709/07/138668662000

Excel 2007Worksheet FormulasCellFormulaE2=B2&C2&D2F2=SUM(B2:D2)G2=MOD(F2,10)H2=SUMPRODUCT(--ISNUMBER(FIND(","&$B2:$D2&",",","&H$1&",")))E3=B3&C3&D3F3=SUM(B3:D3)G3=MOD(F3,10)H3=SUMPRODUCT(--ISNUMBER(FIND(","&$B3:$D3&",",","&H$1&",")))E4=B4&

[Code] ......

I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.

=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)

I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).

Is there a way to remove this vintage year form the string?

to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.

examples are like below:

De Wetshof Finesse/Lesca Cahrdonnay ‘07

De Wetshof Sauvignon Blanc ‘07

Lord Neethling Cabernet Franc 2002

Lord Neethling Pinotage ‘01

Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07

Jacobsdal Pinotage 1994

Zondernaam Sauvignon Blanc 2007

Tokara Red

1976 St Emilion

03 Tokara rose

Plasir de Merle Cabernet Sauvignon ‘05

DuToitskloof Pinotage/Merlot/Ruby Cabernet

1999 Tradition Juracon 375ml

I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.

I have had some luck with the left side, as in:

=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))

As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).

I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!

I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.

Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).

Is there a way to remove this vintage year form the string?

to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.

examples are like below:

De Wetshof Finesse/Lesca Cahrdonnay ‘07

De Wetshof Sauvignon Blanc ‘07

Lord Neethling Cabernet Franc 2002

Lord Neethling Pinotage ‘01

Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07

Jacobsdal Pinotage 1994

Zondernaam Sauvignon Blanc 2007

2003 Tokara Red

1976 St Emilion

03 Tokara rose

Plasir de Merle Cabernet Sauvignon ‘05

I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.

I have had some luck with the left side, as in:

=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))

As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).

I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!

Does anyone have an idea on how to help with this?

Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.

However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.

I received a request from a coworker regarding custom formatting some numbers in his spreadsheet. Those numbers are serial numbers of 20 characters long. Sometimes in my files I use this custom number formatting ###0 and its enough for the data I handle. But when I tried to use it in his spreadsheet, the following shows:

8456891070060510000

The cell must look like this: 08456891070060510302

The reason to have it like this is due to a Delivery Program requirement to deliver Set-top Units for repair. The Delivery Program do not recognize other format than the above. My coworker takes the data from a spreadsheet, and the spreadsheet needs a custom number format to display the correct number.

find a custom number format to be able to display as my coworker need it??

Designated Cell = 7

1 10 .034

15 25 .072

35 45 .089

Output Cell = ???

I am trying to find a formula for the output cell. Suppose the designated cell = 7 due to formulas above it. So that number is always given but can change. I then need a formula for the ouput cell that says if the designated cell is greater than or equal to 1, and less than 10, then the output cell should equal .034. So suppose the designated cell = 18.2. Then I would want the output cell to be .072 since it is greater than or equal to 15, and less than 25. The template I am using has 23 rows of numbers like above. I didn't know how to do it for 23 rows though. If/Then doesn't work because it is 23 statements long (well over the seven limit) and the vlookup only works when the cell is equal to a number and not a range.

I have a sheet with column A. This column A contains numbers from 1 number to 6 numbers.

So, one cell can have a '1' or a '999999' or any combination between them. Now this is the problem.

I want a formula that will fill those cells that don't contain a number up to 6 digits. So if a cell contains '254' I will like this formula to fill the cell like this: 000254.

This should happen with any number that don't have a number with six digits.

78 should be 000078, 78652 should be 078652 and so on.

I have a column of numbers ranging from -500 up to 50,000... How do I get it to only display numbers between 0 and 1000?

(I already have a formula attached to this column)

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