Color Cell - Code Not Working

Apr 25, 2007

I am trying to a macro that allows me to change the backgroud color and font color depending of the value of the cell.

For example is cell A1 is having the value between 1 to 3 the background color of the cell will the light turqoise, if the value is between 4 to 20 the cell background color will be green and so on.

I have based on certain posted example and adapt to my code but somehow it is not working.

Private Sub Worksheet_Change(ByVal Target As Range)
If Target.Count > 1 Then Exit Sub
Select Case Target.Value
Case Is = 1, 2, 3
Target.Interior.ColorIndex = 34
Case Is = 4, 5, 10, 20
Target.Interior.ColorIndex = 43
Case Is = 30, 40, 50

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Jul 22, 2013

This very simple color code below worked before but now it gives "Application-defined or object-defined error". When I try it on a new workbook, it works fine.

Code:
Sub sdsdfsd()
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Jul 10, 2012

I have the following code to check the date of birth entered into cell C18 and to alert the inputter if the age is either under 16 or over 25.

VB:
Sub AgeValidation()
Dim age As Integer
Dim dob As Range
Dim AgeMsgAnswer16 As String
Dim AgeMsgAnswer25 As String

[Code] .....

It works to some extent in that the correct message box pops up if the age is under 16 and similarly if over 25. If answering Yes on either message box then the correct thing happens. Its what happens if the inputter selects No thats not right. If the age is under 16 and the user selects No in answer to "Is this correct?" then the code is clearing the cell contents and showing the calendar again but is also popping up the 'Over 25' validation message box which then won't go away until Yes is selected. Also there are then multiple copies of the calendar open.

What I need the code to do is look at the date selected from a popup calendar in c18 and decide if that age is within the 16-25 year old range. If it is outside that then the inputter needs to be alerted to it. I can't use the inbuilt data validation because there are some scenarios where it would be acceptable to have an age outside of that range but we want to cover inputting errors as well as double checking the age.

When a msgbox pops up to alert the inputter and they choose "Yes" to say the date of birth is correct then I want the focus to go to cell C20 ready to input the next piece of information.

When the inputter selects "No" on the message box, then I want the original date to be deleted and the calendar to reappear so they can select another date. So effectively resetting the field so they can start again choosing a date like when they first entered the cell.

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[Code] ......

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Jan 15, 2014

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also, were do I add this macro? under sheet1? this workbook? or as a module?

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Dec 26, 2007

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If a cell in row 1 contains an x, then all cells in that column with an x has an Interior.ColorIndex of 45

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Feb 18, 2007

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G
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G2
S
Y
H
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Apr 20, 2009

I am trying to display a message box for the user if there is "agency" in cell o8 but nothing in p8... I tried the following code but it doesnt work..


If Range("o8").Value = "Agency" And Range("p8").Value = "" Then

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I have previously used the following code to successfully pull out IE webpage source code for string manipulation.

Its a crude example to demonstrate the principle:

Public Declare Sub Sleep Lib "kernel32" (ByVal dwMilliseconds As Long)
Public IE As Object
Sub Sample()
Set IE = CreateObject("InternetExplorer.Application")
IE.Visible = True

[Code] ......

However when I substitute in a Google websites address into the IE.Navigate command, the code runs to the "Source_Code = IE.document ...." line then flags up a Microsoft Visual Basic error. "Run-time error '438': Object doesn't support this property or method"

The webpage that I am trying to access is a confidential company site, so you won't be able to access it yourself, but starts with [URL] ......

The one thing that I have noticed about this website is the Privacy Report icon in the lower right status window (Picture of an eye with a restricted symbol in front). I don't know whether this is the cause of my problem, or purely an incidental observation.

Is there something peculiar with Google sites that means that the source code cannot be extracted in general, or is this an issue specific to my site ? Does the Privacy Report icon have any relevance, and if so how do I switch that off ?

Using :
MS Excel 2010
IE Explorer 8.0

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Dec 2, 2013

I am using Windows 7 and Excel 2010.

Is there a way to create a macro to color code a cell based on the value in a cell, and then look up a value in a table, then color code it based on where it fits into the table?

I have a table of values for about 30 projects. In column g - there is a CPI value (see bold column)

Example: Project ID
Name
Program
PMT
SI ID
AC
Milestone
TCP Level
[Code] ......

Here is the table:

I have to color code a cell, base on the CPI and how it fits into the table below. So if the current Milestone is M2 or M3 and the CPI calculated is .14 the cell would be colored RED, if the CPI number is 2.01 for M2-M3 I would want cell to be colored Turquiose. If we were at Milestone M6 and the CPI was 2.01, it would be colored blue. If the CPI was .75 at Milestone M5, it would be colored Green

LEGEND
Earned Value Limits

Milestone
RED
Yellow
Green
Turquoise
Blue

M2-M3
2.15

M4-M6
1.66

M7-M11
1.26

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Looking forward VBA coding for:

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An error msg pops up upon attempting to save, stops the save and colors each cell yellow that needs info entered into.

Using Excel 2010.

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Aug 9, 2013

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Color Code
Result

CH4OH
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1.0

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I need the final result automated as follows,

If 2 green of the 4 products, then final result Gree
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Apr 24, 2007

Function AH02(FIF, xi, di, zi, nt, TAI, ZMT, xi2, nr)

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ermess = 0
t = TAI
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I have the next VBA-

Private Sub Worksheet_Change(ByVal Target As Range)
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Range("G8").Value = Range("G8").Value + 1
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Application.EnableEvents = True
End If
End If
End If
End Sub

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