I have 2 cells with dd/mm/yy h:mm format. I have been using =TEXT(BQ3-BP3,"[h]:mm") to work out the hours and minutes difference between the 2 cells. However I would like the formula to work so that the hours and minutes difference will only come into effect after midnight on the first day. For example
01/01/06 23:30 - 01/01/06 23:45 would read 00:00
but
01/01/06 23:30 - 01/02/06 00:45 would read 00:45
I am currently usins Excel 2007 and would like to calculate the diferrence in hours and minutes (ideally in decimal e.g 4:30 should be reflected as 4.5) between two date and time groups, excluding the non-working time between 17:00 and 09:00, weekends and holidays. An 8 hour working day is to be used. I have attached a spreadsheet were I tried to achieved the above with little success.
View 2 Replies View RelatedI have tried several ways to calculate the difference between 2 dates/Time fields. Here is what i have tried and the issues i am encountering.
Cell F3 Has the Create date and Cell G3 has the resolution date and i need to calculate the difference between the 2 in months, Days, Hours, Mins and seconds:
1st option - =G3-F3 and set the format of the cell to mm "m "dd"d" hh"h "mm"m "ss"s "
The problem is, for some reason the months isn't calculating correctly and appears to add 1 month
2nd option - =DATEDIF(F156,G156,"y")&"y "&DATEDIF(F156,G156,"ym")&"m
"&DATEDIF(F156,G156,"md")&"d "&TEXT(MOD(G156-F156,1),"hh""h ""mm""m ""ss""s""")
This appeared to work however because it looks at the date and time separately, when there are 22 hours difference which spans over 2 dates ( Created 13/06/2013 10:30:00 Resolved 14/06/2013 08:34:00) its shows as 1 day and 22 hours which isn't correct.
How to find the difference between 18/04/2013, 13.40 hrs and 20/04/2013, 11.40 hrs to get the result as 1 day and 22 hrs
View 9 Replies View Related1.The attached file shows an example extract of a data extract that has thousands of lines. See the Data Tab.
2.What I need is some time that has passed between two dates in a DDHHMM format
3.What I then need is the top 50 of each of the times (or the longest time past)
4.The column headers will be: WO Number | Contractor Name | Time Calculation – see the various Report tabs
5.The calculations in the Data tab are between the following columns.
a.Difference between Column Z and Column AC
b.Difference between Column AC and Column AD
c.Difference between Column AD and Column AE
d.Difference between Column AE and Column AF
6.Is it possible to show the top 50 only in time?
This report is forming a part of a larger report and all other formulas are already present so I am hoping to keep the file size quite small. The aim is to then hand this over to someone else to just print on a monthly basis depending on the data that gets added with minimum input.
I need to enter a formula that calculates the time a report is received from the time it was recorded in our database. therefore, it needs to exclude non working hours. here are the fields:
A1 2008/10/10 16:30
B1 2008/10/11 09:30
C1 8:00
D1 17:00
A1 = report received
B1 = reported recorded in db
C1 = work day start time
D1 work day end time
Where the answer should = 2 hours.
I am not an experienced excel user and so far the only formula I have now is: =TEXT(B1-A1, "d:hh:mm")
And how do I account for weekends?
Instead of calculating a time difference manually I want to have a formula do it for me. What I want to achieve goes as followed:
08/06/2006 04:33
12/06/2006 01:05
Time difference is 92:32 [hh:mm]
another example:
09/06/2006 12:42
12/06/2006 11:35
Time difference is 70:53 [hh:mm]
So instead of getting 92:32 and 70:53 by calculating it myself I would like to have a formula do it for me. Otherwise I'll have to invest a lot of time to get the information I need.
i am trying to find the time difference between two cells and present the date in a third cell. The data in the cells are in a non standard date/time and i need to create a special format i think. The cells look like this.
fldcollected fldaccepted Type Time between being received by database and eccepted
2013-11-06 15:59:29.1002013-11-07 08:41:12.000PSTN
I have
Code:
Start date 21/08/2012 23:21:30
End Date 24/08/2012 22:21:45
is there a formula to get the time difference in Hours for example in this case its 72:01:15 72 Hours, 1 minute & 15 seconds
Formula to calculate time allotted minus time used and show the difference in hour and minute.
View 1 Replies View RelatedThis may be a bit vague but here goes.
I have to calculate the difference between the start time and end time of a job. The only catch is, how can I avoid calculating "out of hours" time. So, if a job goes from 9am to 9am the next day, I want it to avoid calculating between the hours of 23:30 and 03:30.
Another example is if a job goes from 02:00 to 04:00, I want it to avoid the tim between 02:00 and 03:00.
If there is a difference in days, so the job goes overnight, how do I take that into consideration also.
I've got a time difference from 8:00AM - 12:30PM as 4.30 I'm trying to get the minutes, .30, converted into a 6 minute increment, .5. Is it possible to do this and if so how would it be done? Below is a chart of how the time is converted from 6 minutes increments into decimal form.
6 = 0.1 36 = 0.6
12 = 0.2 42 = 0.7
18 = 0.3 48 = 0.8
24 = 0.4 54 = 0.9
30 = 0.5 60 = 1.0
i want to ask for a reason if a item is late where M & line is the time it should have left and N & line is the actual time it left.
TL is the difrence between the two times
i want the input box to read " DRIVER DISPATCHED 30 MINUTES LATE PLEASE ENTER REASON"
but it returns "DRIVER DISPATCHED -.11233543 E2 MINUTES LATE"
how do i format this to show the difrence in minutes
TL = Range("N" & Line) - Range("M" & Line)
late = InputBox("DRIVER DISPATCHED " & TL & " MINUTES LATE PLEASE ENTER REASON")
I'm trying to calcuate the time difference using military time.
For example:
A1 has 0400 A2 has 0430 A3 SHOULD be :30
B1 has 1500 B2 has 1715 B3 SHOULD be 2:15
Unfortunately I either keep getting all zero's, or the correct answer but without the ":" in the answer (b3 would look like 215)
i am trying to create a forumla in a column (D in my expamle below) to count the number of days between two dates. Knowing that col D will change everytime the @now date changes - but thats ok..
COL A COL B COL D
ROW 1 Open Date Closed Date Count of days open
ROW 2 4/1/07 BLANK CELL Formula result here
ROW 3 4/1/07 9/5/07 Formula result here
if col b has a date then subrtract col a from b and display the # result, if col b is blank then subtract col a from location I store the @ now date - say Col ZZ Row 99? so no matter there is a count of number of days in every row in column D
I have column B with a heading "Days Remaining" and column L with a heading "Deadline". starting with row 5, I need to be able to enter a date in L5 and see the days I have left, from that day untill today, on B5. I need to then be able to enter a date into L6 and see a result in B6 and on and on. Then I need to be able to insert or delete a column and have the formulas still work in the columns with the heading "Days Remaining" and "Deadline"
View 7 Replies View RelatedFormula query
Column “A” list of dates correspondence in
Column “B” list of dates correspondence reply out
Need to calculate how many times the difference between date in and reply date is <= 5 in a specific time period.
The start date is entered in say, “K1”
The end date is entered in say, “L1”
Also calculate difference in dates between 14 days and 21 days for time period
Also with reply in column “B” not sent until over 28 days. I have tried SUMPRODUCT with (date_in=K1)*(date_out<=L1) for the dates but unsure how to define <=5
I work at a call center and I get the data as Date, Time of calling and Duration of the call. Now since this is an overseas call center, even though the calls spills over 12midnight, the corresponding date shows as the date when the agent logged in.
So I get the data in this format, Date: 06/11/2012, Time: 19:00:00 - 04:00:00.
How do I calculate the time difference at one go without first getting the time difference from the time of login till midnight and then add that to the time difference of midnight till time of logout. I have attached a file for your review.
I'm calculating the difference in time:
9:54-9:45 = 0:09
Now to convert this in minutes (in number format), I multiply this number with 1440:
0:09*1440 = 9
When I click the cell this number is actually 9.0000005, rather than exact 9. I need it to be exact 9 since I have to match this number from other excel sheet.
To sum up:
This is what I expect:
31.99999 should be changed to 32
10.000001 should be changed to 10.
does anybody knows an idea how to get the time difference without getting the #NUM! error message?
Column A contains Start Time while Column B contains end time, if the time in column A is 11:45 PM and the time in column b is 12:15 AM, then I would get this error message...any idea how can i get the time difference without having to use the [hh]:mm format? i would like to use the hh:mm AM/PM format instead.
Given any two timestamps with the format
dd-mmm-yyyy hh:mm:ss AM/PM
How to calculate the total time difference in seconds.
For e.g. calculate the time difference in seconds for following
07-Nov-2009 00:00:01 AM
06-Nov-2009 11:59:59 PM
Answer should be 2.
I have a userform with a number of textboxes where the time is entered in the format like 00:00, (24 hour clock).
What I need is code to calculate the time in minutes / hours between 2 of these textboxes and for the result to be displayed automatically in the third textbox with no user input required, (other than to put in the start and end times).
The third textbox must display the result in the same format as above - here is the code I use to get the textbox to force the time in as above;
Code:
Private Sub TextBox3_Change()
Dim t As Date
'If they enter 4 digits and NO colon e.g. 1400
If Len(TextBox3.Value) = 4 Then
[Code] ......
A
B
C
1
Time 1
Time 2
Result
2
8:00
7:30
-0:30
Date OutTime OutDate InTime InTime Difference
01-03-099:0001-03-09NIL
02-03-09NIL02-03-09NIL
03-03-09NIL03-03-0910:002 day(s) 1 hours 00 mins
03-03-0911:1503-03-0918:000 day(s) 6 hours 45 mins
04-03-099:00NILNIL
05-03-09NILNILNIL
06-03-09NILNILNIL
07-03-09NIL07-03-0914:453 day(s) 5 hours 45 mi
In Column E in want the time difference to be calculated as shown above.
I am attempting to pick up a date with time entry on a worksheet and place it into a TextBox on a UserForm. Format on the sheet is mm/dd/yyyy h:mm AM/PM. The UserForm is placing the value as mm/dd/yyyy 12:00 AM. here is the
Private Sub UserForm_Initialize()
If Not Range("dDate").Value = "" Then
TextBox2.Value = Range("dDate").Value
TextBox2.Text = Format(DateValue(TextBox2.Text), "mm/dd/yy h:mm AM/PM")
Else
TextBox2.Value = ""
TextBox2.SetFocus
End If
End Sub
"dDate" is the named range where the date is sitting. The format is also set on the TextBox2 exit event. Can anyone see why only the date portion is being transfered with the default 12:00 AM for no time component of the value?
I've got a spreadsheet of samples taken at certain time intervals for a period of 2.5 hours, they were collected in hh:mm:ss format. Most of them are approximately 5 minutes apart. What I'd like to do is convert the first time to 00:00:00 and then recalculate each sample from there. Is there an easy way to do this?
So, what looks like this right now:
8:45:00
8:45:36
8:50:36
8:55:36
9:00:36
Would look like this:
00:00:00
00:00:36
00:05:36
00:10:36
00:15:36
etc...
I'm trying to calculate the available man hours I have for my shift/team. I have got the basic formula to deduct the time, and lost time for breaks ok, but when the shift end time crosses midnight the formula returns a "value" error message. i.e. start time = 18:00. End time = 24:00 breaks = 15 mins gives me a formula like this =TEXT(O17-N17-P17,"h:mm") and a result of 5:45
How I can make this formula work so it can calculate the variance even though the shift ends at 02:00am the following morning?
I'm looking for a formula in relation to the calculation of time.What I'm looking for is a way of finding the difference between the time two cells and it displaying it in the number of hours e.g.:
Cell 1__Cell 2__Cell 3
12:00 + 18:30 = 6.5 (it is 6 hours 30 mins but I want it displayed as a number.
I am looking to calculate the time difference between 2 date time fields using a specific calendar.
I work in an engineering company and am having problems calculating machine utilization efficiencies.
Example:
Job 1: Start date 06/01/2009 10:00:00
Job 1: End date 06/02/2009 12:00:00
Calendar:
Dayshift: Monday - Thursday 07:15:00 - 16:15:00, Friday 07:15:00 - 12:15:00
Nightshift: Monday - Wednesday 21:00:00 - 07:45:00, Thursday 21:00:00 - 05:45:00
Using the specified calendar I am trying to calculate the time difference between the start and end date of job 1.
I have a userform for a time sheet i am working on. I used the following code to enter the time difference between time in and out.
Code:
'FIRST SET
v = (Me.TimeIn.Value)
w = (Me.TimeOut.Value)
x = Int(v / 100) + (((v / 100) - Int(v / 100)) / 0.6)
y = Int(w / 100) + (((w / 100) - Int(w / 100)) / 0.6)
[Code] ........
The code works fine, however, I have I need to place another time difference in based on from the sameuserform but different comboboxes. I thought it wouldbe easy just to add a second code.
Code:
v = (Me.TimeIn.Value)
w = (Me.TimeOut.Value)
x = Int(v / 100) + (((v / 100) - Int(v / 100)) / 0.6)
y = Int(w / 100) + (((w / 100) - Int(w / 100)) / 0.6)
[Code] ....
When i add the second code i get the runtime error 13. The worse part is that i was going to do this like five times.
