Delete If Cell < 16 Characters []
Nov 17, 2006I have a formula which I have been using for testing up till now. =IF(LEN(Q3)
View 4 RepliesI have a formula which I have been using for testing up till now. =IF(LEN(Q3)
View 4 RepliesI can't get this code to work which I want to delete the entire row if the cell in the specified range contains only 3 characters;
Code:
Sub CharCount()
Dim cell As Range
Dim bottomK As Integer
bottomK = Range("D" & Rows.Count).End(xlUp).Row
Dim rng As Range
Set rng = Range("D2:D" & bottomK)
For Each cell In rng
If Len(cell) = 3 Then
EntireRow(bottomK).Delete
End If
Next cell
End Sub
I need a way to check to see if the first four characters of cell A1 is = 2006. If it is, do not delete the row, else, delete the row. Have tried everything I can think of.
View 5 Replies View RelatedHow can I delete characters unallowed in file names in cell text all in one go instead of below long macro. (i.e. can you minimize the below vba)
These characters that I wanna delete
"/", "", ":", "*", "?", "< ", ">", "|"
Code:
Range("A1").Select
Selection.Replace What:="""", Replacement:="", LookAt:=xlPart, _
SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _
[Code].....
I have a keyword list in ColA. about 25,000 phrases.
What I want to do is create a macro button.
when i click on it a pop up box would appear called "Deleting Characters"
It will have to 2 rows, 1 saying "More Than",, the other saying "Less Than"
So, beside these words are input boxes.
So I can type the numbers "2" and say "50"
So it will look at all the rows of data in my ColA (Always from A3 downwards)
and deletes all rows with less than 2 characters and more than 50 characters.
When it is finished a floating box appears saying
"123 Characters Less Than 2 Deleted"
"101 Characters More Than 50 Deleted"
Sub NoOfCharacters()
Dim lastrow As Long, TotP, TotC, AvC
lastrow = Cells(Rows.Count, 1).End(xlUp).Row
If lastrow < 4 Then
MsgBox "Nothing to sort!"
Exit Sub
End If
Range("B1").EntireColumn.ClearContents
Range("B3").Formula = "=LEN(A3)"
Range("B3").AutoFill Destination:=Range("B3:B" & lastrow)
Range("A3:B" & lastrow).Sort key1:=Range("B3"), order1:=xlAscending, Header:=xlGuess
TotP = lastrow - 2
TotC = Application.Sum(Range("B3:B" & lastrow))
AvC = TotC / TotP
MsgBox "Total No Phrases: " & Chr(9) & Chr(9) & Chr(9) & TotP & Chr(13) & "Total No Characters: " & Chr(9) & Chr(9) & TotC & Chr(13) & "Avg No Characters Per Phrase: " & Chr(9) & AvC
End Sub
"Is there some VBA code which could delete all first, second or third
characters of a text? Could it be done to the three last characters
from this same text and these be displayed on reverse order?"
Example:
AAAASAHDASK
AAASAHDASK
AASAHDASK
ASAHDASK
SADHASAAAA
ADHASAAAA
DHASAAAA
From the names listed in column A, in the table listed below, I wish to delete everything
to the right of the first two characters.
So the new column A would look this.
A
1
E HAZARD
2
F LAMPARD
3
F MALOUDA
[code].....
I am trying to write a macro that will go through each cell in a column with the following format "| 12- 4" or "| 60-11" and will remove the first to character "| ".
There numbers are lengths, the first being feet the second inches. I would like to achieve in a separate column the numerical length (with decimals) multiplied by 1%. My code is as follows I just need help on the conversion.
Sub newLength()
Dim LR, lrow As Integer
Dim feet, inches, Line As Double
LR = Range("B65536").End(xlUp).Offset(1, 0).Row
For lrow = LR To 2 Step -1
If Cells(lrow, "D") <> Cells(lrow - 1, "D") Then
Rows(lrow).Insert Shift:=xlDown
End If
feet = Left(Cells(lrow, "E").Value, 4)
inches = Right(Cells(lrow, "E").Value, 2) / 12 'I need to debug this line, but I suspect there is more I need to do.
Cells(lrow, "F") = feet + inches
Next lrow
End Sub
Sub rightval()
Dim myrange, mycell As Range
Set myrange = Sheets("Sheet1").Range("A1", Range("A65536").End(xlUp))
For Each mycell In myrange
If Right(mycell.Value, 1) = "." Then
mycell.Value = Left(mycell.Value, Len(mycell.Value) - 3)
End If
Next mycell
End Sub
I'd like to delete the last three values of one cell only if it contains a period.
See the excel sheet [URL]
I need to delete all the digits before / and also the / - in the valuta columns. But this =RIGHT(B2,LEN(B2)-6) doesnt work It says > the formula you typed contains an error
I have about 2000 rows, all with an amount of words between 2 and 6. I want to limit each row to keep only the first TWO words. Is there a way to do this?
If not, is there a way to limit each row to only keep the first 11 characters?
I ve got a list multuple values. All of them contain 00 before the actual value. How can I delete those two 00.
Here's an example
Currently Desired Outcome
0030148099 30148099
0030148099 30148099
0030148100 30148100
0030148100 30148100
0030148101 30148101
I need a formula which can clean up a huge data set. Essentially i need to delete the entire word which contains the characters "aceae". note that "aceae" is a suffix, but i need to delete the entire word not just the suffix, plus keep the rest of the string. i have tried the "find and replace" function of excel with wildcard, but that deletes everything before/after without deleting the entire word. i have tried a combination of formulas to isolate the unwanted words, but that method is inefficient and inaccurate. below is a schematic of what im looking to do:
Column A ------------------------------ Column B
l. planeri asteraceae africa laselva-----> l. planeri africa laselva
l. planeri moraceae europe singer------> l. planeri europe singer
origin l. fluviatilis bignoniaceae asia----> origin l. fluviatilis asia
alternate l. fluviatilis piperaceae asia---> alternate l. fluviatilis asia
I have a spreadsheet that i manually edit each and everyday e.g.
A B C
EABGL/UD NDT254892
MRMR/RUS/ELQNS259762
LSL/UW/B LQNS267259
WWEX/UQ bbr263666
LWL/KL/B 270407
MYTCJ/UB NDT271774
LNL/SB/UB HLC - 271955
SMMQD/WT HLC - 269516
EACO/TN/UGBBR257827
NILVA/UC EUi273645
For everything that doesnt equal EM, LN, LW and TH in column A, everything should be deleted in column B.
For the remaining EM, LN, LW and TH, i would then like it to delete / (forward slash and all characters after this) so that this would make my life easier.
in VBA how would I script to search down column and if the cells starts with "20" delete the first 13 characters?
also if it finds more than 10 empty rows it cuts the loop otherwise I may be waiting a while
I have one column with many numbers. Some have one dash and some have two.
Example:
123-123456-65
012-789546-1
98B12354-889
Is there a way that I can remove all characters after the last – (dash) in the number?
Example:
If number is 123-123456-65
Then 123-123456
If number is 98B12354-889
Then 98B12354
If someone could just lead me in a direction, I might be able to figure it out. However, my code is elementary and most of the time, I record macros and the play with the code until it does what I want.
I am trying to detete rows that have several specific values, upper and lower case, (A-H) in any of several columns (B through H). I can delete upper and lower case "D"s in column B, but I'm having difficulty stringing together several variations and getting at the "D"s that are midstream (such as: ADeC), I tried ("*D*") to no avail.
With . Cells(Lrow, "B")
If Not IsError(.Value) Then
'****
If LCase(.Value) = LCase("D") Then .EntireRow.Delete
So we have people's names in a table. First name in one column and last name in another column. We have a 3rd column where we can use 8 characters to do a combination of First 5 of Last Name + first 3 of first name. However, if someone's last name is only 3 or 4 characters, we'd then want to take more from the first name to fill out the 8 characters.
So:
Charles Johnson -> Johnscha
John Smith -> Smithjoh
Willian Wu -> Wuwillia
What's the best way to do that without creating some crazy formula with tons of if/thens?
Currently I am using the Kickbutt VBA Find Function of Aaron, but I would like to have something that works more efficiently. What I currently do is (assuming all possible values for Column J are A - F):
Find_Range("A", Columns("J"), MatchCase:=True).EntireRow.Delete
Find_Range("B", Columns("J"), MatchCase:=True).EntireRow.Delete
Find_Range("C", Columns("J"), MatchCase:=True).EntireRow.Delete
Find_Range("D", Columns("J"), MatchCase:=True).EntireRow.Delete
Find_Range("E", Columns("J"), MatchCase:=True).EntireRow.Delete
although I just want some code that says: delete all rows except those that have "F" as content in Column J. I already tried something like:
Range("1:65536").Select
For Each cl In Range("J:J")
If cl.Text = "A" Or cl.Text = "B" Or cl.Text = "C" Or cl.Text = "D" Or cl.Text = "E" Then
Rows(cl.Row).Delete
End If
Next
but it also takes much to long. The major problem I think, is that the number of records is variable so I search the entire worksheet...
Is there an Excel formula to remove the spacebar + characters in red, as shown below? I need to be left with only the last name, first name and the semicolon.
Mouse, Mickey ;
Microsoft Outlook has changed the way that email addresses from the global addressbook copy and paste (from version 2003 to version 2010).
I'm trying to use conditional formatting to highlight cells in a column that have less than 8 characters.
I know the LAN function, but I don't know how to make it work for the conditional formatting.
Using Excel 2007. I have a limit of 80 characters and spaces in a particular cell and I need to force those characters/spaces over 80 to the next cell. Is that possible?
View 11 Replies View RelatedI have an index of 80,000 names from an index. Some names appear in multiple volumes and on multiple pages within a volume. While the name is the same, they are different people. The Roman numeral is the volume and the numeric is the page number.
Example of original data: Joe Shmoe V-225, 310 VIII-22, 86, 110
I have separated the data into separate columns. Now I have:
Col 1 Col 2 Col 3 Col 4 Col 5 Col 6
Joe Shmoe V-225 310 VIII-22 86 110
At this point, I want to combine the Roman numeral in Col 2 with Col 3 and 4 and combine the Roman numeral in Col 4 with Col 5 and 6.
There are way too many records for me to manually enter the Roman numeral where missing.
When I try to enter 18 numeric characters in a single cell, the last three characters are converted to zeros. I can find no format that would allow me to see all 18 entered characters. Is there a way of doing this?
View 2 Replies View RelatedI have a spreadsheet which I use to enter notes related to particular invoice numbers. A v-lookup pulls the notes into another tab. What I'm running into is that the notes can be quite lengthy - in excess of 1,000 characters. When the notes get too long, they don't all appear in a single cell (unless it's extremely wide).
I'm wondering if there may be a way to maintain my notes in a word doc instead? Maybe in a table that pulls in using a v-lookup? But I'm not able to figure out how to direct a v-lookup to a word doc.
how many characters a cell can contain?
View 3 Replies View RelatedAs you can see, in D5, I have the charactor chain SRG-DC01-RA-xxxxxxx, and in D6 I have the charactor chain SRG-DC43-RA-xxxxx.
With the formula that I have entered, I would have thought that E5 would have generated "Lawnton". I don't want the formula to pick up the SRG, the RA, or the number, just the DCXX component.
This is what I have now:
=IF(OR(ISNUMBER(SEARCH({"DC43","DC01"},D5))),"Erskine Park","Lawnton")
which has not changed a thing from:
=IF(OR(ISNUMBER(SEARCH({"DC43"},D5))),"Erskine Park")
Surely I am not far off the mark??
Cell E1 having 150 characters (letters), I want to trim first 45 characters in cell E1 and place it in cell B2 and remaining characters in cell E1 (ie. from 46th character till end) and place it in cell A3.
View 1 Replies View RelatedI have SKU numbers in a cell and need to change the location of the sizing digits. Here is the example:
AOP6000SSUMD
AOPSS6000UMD
Is it possible to count the number of characters in a cell?
View 1 Replies View Related