"Is there some VBA code which could delete all first, second or third
characters of a text? Could it be done to the three last characters
from this same text and these be displayed on reverse order?"
Example:
AAAASAHDASK
AAASAHDASK
AASAHDASK
ASAHDASK
SADHASAAAA
ADHASAAAA
DHASAAAA
From the names listed in column A, in the table listed below, I wish to delete everything
to the right of the first two characters.
So the new column A would look this.
A
1
E HAZARD
2
F LAMPARD
3
F MALOUDA
[code].....
How can I delete characters unallowed in file names in cell text all in one go instead of below long macro. (i.e. can you minimize the below vba)
These characters that I wanna delete
"/", "", ":", "*", "?", "< ", ">", "|"
Code:
Range("A1").Select
Selection.Replace What:="""", Replacement:="", LookAt:=xlPart, _
SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _
[Code].....
I have a keyword list in ColA. about 25,000 phrases.
What I want to do is create a macro button.
when i click on it a pop up box would appear called "Deleting Characters"
It will have to 2 rows, 1 saying "More Than",, the other saying "Less Than"
So, beside these words are input boxes.
So I can type the numbers "2" and say "50"
So it will look at all the rows of data in my ColA (Always from A3 downwards)
and deletes all rows with less than 2 characters and more than 50 characters.
When it is finished a floating box appears saying
"123 Characters Less Than 2 Deleted"
"101 Characters More Than 50 Deleted"
Sub NoOfCharacters()
Dim lastrow As Long, TotP, TotC, AvC
lastrow = Cells(Rows.Count, 1).End(xlUp).Row
If lastrow < 4 Then
MsgBox "Nothing to sort!"
Exit Sub
End If
Range("B1").EntireColumn.ClearContents
Range("B3").Formula = "=LEN(A3)"
Range("B3").AutoFill Destination:=Range("B3:B" & lastrow)
Range("A3:B" & lastrow).Sort key1:=Range("B3"), order1:=xlAscending, Header:=xlGuess
TotP = lastrow - 2
TotC = Application.Sum(Range("B3:B" & lastrow))
AvC = TotC / TotP
MsgBox "Total No Phrases: " & Chr(9) & Chr(9) & Chr(9) & TotP & Chr(13) & "Total No Characters: " & Chr(9) & Chr(9) & TotC & Chr(13) & "Avg No Characters Per Phrase: " & Chr(9) & AvC
End Sub
I have a formula which I have been using for testing up till now. =IF(LEN(Q3)
View 4 Replies View RelatedI am trying to write a macro that will go through each cell in a column with the following format "| 12- 4" or "| 60-11" and will remove the first to character "| ".
There numbers are lengths, the first being feet the second inches. I would like to achieve in a separate column the numerical length (with decimals) multiplied by 1%. My code is as follows I just need help on the conversion.
Sub newLength()
Dim LR, lrow As Integer
Dim feet, inches, Line As Double
LR = Range("B65536").End(xlUp).Offset(1, 0).Row
For lrow = LR To 2 Step -1
If Cells(lrow, "D") <> Cells(lrow - 1, "D") Then
Rows(lrow).Insert Shift:=xlDown
End If
feet = Left(Cells(lrow, "E").Value, 4)
inches = Right(Cells(lrow, "E").Value, 2) / 12 'I need to debug this line, but I suspect there is more I need to do.
Cells(lrow, "F") = feet + inches
Next lrow
End Sub
Sub rightval()
Dim myrange, mycell As Range
Set myrange = Sheets("Sheet1").Range("A1", Range("A65536").End(xlUp))
For Each mycell In myrange
If Right(mycell.Value, 1) = "." Then
mycell.Value = Left(mycell.Value, Len(mycell.Value) - 3)
End If
Next mycell
End Sub
I'd like to delete the last three values of one cell only if it contains a period.
See the excel sheet [URL]
I need to delete all the digits before / and also the / - in the valuta columns. But this =RIGHT(B2,LEN(B2)-6) doesnt work It says > the formula you typed contains an error
I have about 2000 rows, all with an amount of words between 2 and 6. I want to limit each row to keep only the first TWO words. Is there a way to do this?
If not, is there a way to limit each row to only keep the first 11 characters?
I ve got a list multuple values. All of them contain 00 before the actual value. How can I delete those two 00.
Here's an example
Currently Desired Outcome
0030148099 30148099
0030148099 30148099
0030148100 30148100
0030148100 30148100
0030148101 30148101
I can't get this code to work which I want to delete the entire row if the cell in the specified range contains only 3 characters;
Code:
Sub CharCount()
Dim cell As Range
Dim bottomK As Integer
bottomK = Range("D" & Rows.Count).End(xlUp).Row
Dim rng As Range
Set rng = Range("D2:D" & bottomK)
For Each cell In rng
If Len(cell) = 3 Then
EntireRow(bottomK).Delete
End If
Next cell
End Sub
I need a formula which can clean up a huge data set. Essentially i need to delete the entire word which contains the characters "aceae". note that "aceae" is a suffix, but i need to delete the entire word not just the suffix, plus keep the rest of the string. i have tried the "find and replace" function of excel with wildcard, but that deletes everything before/after without deleting the entire word. i have tried a combination of formulas to isolate the unwanted words, but that method is inefficient and inaccurate. below is a schematic of what im looking to do:
Column A ------------------------------ Column B
l. planeri asteraceae africa laselva-----> l. planeri africa laselva
l. planeri moraceae europe singer------> l. planeri europe singer
origin l. fluviatilis bignoniaceae asia----> origin l. fluviatilis asia
alternate l. fluviatilis piperaceae asia---> alternate l. fluviatilis asia
I need a way to check to see if the first four characters of cell A1 is = 2006. If it is, do not delete the row, else, delete the row. Have tried everything I can think of.
View 5 Replies View RelatedI have a spreadsheet that i manually edit each and everyday e.g.
A B C
EABGL/UD NDT254892
MRMR/RUS/ELQNS259762
LSL/UW/B LQNS267259
WWEX/UQ bbr263666
LWL/KL/B 270407
MYTCJ/UB NDT271774
LNL/SB/UB HLC - 271955
SMMQD/WT HLC - 269516
EACO/TN/UGBBR257827
NILVA/UC EUi273645
For everything that doesnt equal EM, LN, LW and TH in column A, everything should be deleted in column B.
For the remaining EM, LN, LW and TH, i would then like it to delete / (forward slash and all characters after this) so that this would make my life easier.
I am working on sales information which includes postcodes. What i need to do is seperate the first or first two text characters from the rest of the postcode. I have attached a small snipet of what i am working on. Currently i am using the =Left(A4,2) but this will give me in some case a numerical value aswell. For example E1 or G1 in the case of the sample attached. Is there a formula that exists where it will just return the text values in a cell and not numerical values.
View 6 Replies View Relatedin VBA how would I script to search down column and if the cells starts with "20" delete the first 13 characters?
also if it finds more than 10 empty rows it cuts the loop otherwise I may be waiting a while
I have one column with many numbers. Some have one dash and some have two.
Example:
123-123456-65
012-789546-1
98B12354-889
Is there a way that I can remove all characters after the last – (dash) in the number?
Example:
If number is 123-123456-65
Then 123-123456
If number is 98B12354-889
Then 98B12354
If someone could just lead me in a direction, I might be able to figure it out. However, my code is elementary and most of the time, I record macros and the play with the code until it does what I want.
I have a cell (B2) I would like to apply multiple data validations to.
I know I need to use the custom formula option but don't know how to write the formula.
I don't even know if it is possible, but here is what I'm after
I need to make sure the cell is 4 digits long
I need to make sure the cell starts with a zero (Because the cell starts with a zero I have it as a text cell)
I need to make sure the 2nd number is not 0 if A2 begins with 5 (A2 is also a text cell).
I am trying to detete rows that have several specific values, upper and lower case, (A-H) in any of several columns (B through H). I can delete upper and lower case "D"s in column B, but I'm having difficulty stringing together several variations and getting at the "D"s that are midstream (such as: ADeC), I tried ("*D*") to no avail.
With . Cells(Lrow, "B")
If Not IsError(.Value) Then
'****
If LCase(.Value) = LCase("D") Then .EntireRow.Delete
I frequently need to extract email addresses from huge amounts of text, like 40+ pages long, etc... I was wondering if a macro could be developed somehow to leave me with a stack of email addresses. I suppose the macro would have to test each piece of text for an "@" and a ".com" and then stack only those terms in a column somewhere. Any ideas on how to do this? I am not macro savvy AT ALL...
View 9 Replies View RelatedI've searched Excel's Help but still unsure how to do this. I hope excel experts here can lend me a hand...
I have literally thousands of words in a single columns column which looks like this:
absah
absen
absenan
absensi
abses
absis
absolusi
absolut
absolutisme
...
...
...
etc
My question is what formula if i'd have to enter to add three spaces between characters and five characters at every end of the word so it should look like this?:
a b s a h .
a b s e n .
a b s e n a n .
....
....
etc
Note i have entered a full stop at the end of the example above to make the five spaces visible in this demonstration (I dont need the period character inserted at all).
In my worksheet, column C contains a list of part numbers of various lengths.
How do I copy the part number without the last 3 characters & paste in col D?
I don't mind if this is achieved using VBA code or excel function.
How do I add special characters in-between text? I know how to include a registered sign by using =CHAR(174) but what I do not know is how to include text before and after the sign itself.
ie timeware *registered sign* community
I want to trim text into 10 characters.I am new to excel.
Attached is the sample sheet.
TRIM.xls‎
I am submitting a book CSV file to my website. However, the website will not accept any cell that contains more than 80 characters. The error states the following. "WARNING: Title should be less than or equal to 80 chars; your Title was truncated to 80 chars" repeated 13 times.
View 2 Replies View RelatedI have a textbox in a form and i need to check if the text posted there begins with zero or if it contains spaces. Ex:
05E 9050 01
if this is the text then it shoud warn me becouse there is a zero in the begining and it contain spaces
4P 565001
if this is the text then it shoud warn me becouse there is a space
if there is maximum number of characters in a cell, above which wrapping and the row height auto-fit functions will not work? I typed a paragraph into a cell and have the cell set to wrap and the row height to auto-fit but it does not display on print preview or on actual printing past a certain character in the cell. Even when I manually increase the row height, it still does not display.
View 4 Replies View RelatedI have a spreadsheet that uses sql to gather data from our servers. From this data, I use concatenate function to put the data into one cell ready to copy/paste into our sms program. The program will only take 160 characters at a time..
Result I need:
For the cell to split into two/three cells if over 160 characters (and to break after the last complete word), and if appropriate, it needs to say 1of2 at the beginning of the 1st message for example, and 2of2 at the beginning of the second.
I have a cell which holds text with a maximum number of characters of 6. Let´s say I want this cell to hold a word which is bigger, and trim it till it has 6 characters.
Example: word "Hippopotamus" (longer than 6 characters) should be trimmed so its displayed as "Hippop"(6 characters)
is there a way to specify how i want to trim, either right or left?
Example "Hippop"(6 characters trim right) or "otamus" (6 characters trim left)
I have an formula if statement that returns "deletethisrow" if the test is true.
For every occurence of "deletethisrow" I want to delete the row. The number instances will be variable each time I run the file. So maybe it will find that string, maybe it will find 10 instances. I want to do some kind of loop that won't error out when it cannot find "deletethisrow", but will delete the rows for each instance where it does find this string.
I know it was verbose, but if I just do a loop for a fixed number of loops it will error out if it runs out of rows to delete.