I have following snippet of code. it is very simple.
Code:
Sub GetDatafromXmlToTemp()
Dim str As String
Sheets("sheet1").Select
desc = WorksheetFunction.Match("FAMILY_ID", Rows("1:1"), 0) ' gives column number for ex 4 for "D"
[Code] .....
I am getting error "Argument not optional" in line.
Code:
str = ColLetter
I have this code snippet..
Code:
Function appointment(ByVal day As String, ByVal hour As Integer) As String
' Insert code to return any appointment for the given day and time.
Return "appointment"
End Function
But I get this error. Compile error: Expected: end of statement
I am trying to search for a phrase in a particular column but the excel search function is returning !Value as an error...
Both fields are text so nit sure what is wrong here.
I have a list of cities that i want to cross reference across a cloumn of notes on another sheet. So, I really want to search for the city (Sheet1 Cell A1) in Notes Sheet2 Cell A1) and I want to return it in Sheet1 Cell B1 Whether it exisits in the notes. I then want to copy this down my list of cities in Sheet1 Column a.
I get syntax error on return statement. I am using Excel 2010.
View 2 Replies View Relatedwhether I can handle errors in a way that tells me which object caused the error?
For example if a userform has two combobox's and one causes an error, can I return to a message box containing the name of the object (combobox1 or combobox2)?
I have tried returning err.source but I am either not using it correctly or it isn't intended to be used this way.
I am trying to run create a simple macro that copies and paste special values - something I have done 100's of times but for some reason I keep getting an error message - even though I recorded the macro and didnt write it by hand - see below:
Sub Macro6()
Cells.Select
selection.Copy
selection.PasteSpecial Paste:=xlPasteValues, Operation:=xlNone, SkipBlanks _
:=False, Transpose:=False
End Sub
For which I get 'Compile Error - Expected Function or Variable'
my lookup isnt returning the correct data- already tried sorting it doesnt work im pretty sure ive put in the correct formula
View 6 Replies View RelatedFunction Haversine has correct value in debugger but in cell it has the same value as Haversine2. Is this a known bug?
Public Function Haversine(lat1 As Double, long1 As Double, lat2 As Double, long2 As Double) As Double
Dim temp As Double
[Code]....
I keep getting the "You've entered too many arguments for this function" error.
Here is the formula:
=IF(B15=D40,E40,"",IF(B15=D41,E41,"",IF(B15=D42,E42,"","Invalid Shipping option")))
I want a UDF; = OK (f1,f2) each argument being an alternative function. If f1 returns an error message then use f2. Should be easy but I cannot get it to work.
View 5 Replies View RelatedI am trying to return a TRUE or FALSE based on a date in a cell.
for example:
if cell A1 = 07/11/2009
I want A2 to show TRUE or FALSE if A1 is 14 days or more behind todays date.
I have tried stuff like:
=IF(A1=TODAY()-14,"True","False")
but it just always says false. EDIT: I have just noticed that if I change the date in A1 to exactly 14 days behind todays, it returns TRUE. So, it does work. Do I need to add a GREATER THAN in there?
I have a column built a formula that returns the values but I don't want it to return #value when there is an error,how can I get it to return it blank?
View 11 Replies View RelatedIs there any more efficient way to get a formula that tries to get pivot data to return data to show zero, rather than ERROR, than this?
=if(iserror("the get pivot data formula"),0,"the get pivot data formula")
I am trying to squeeze some more effenciency into a ridiculous spreadsheet, and I hate that this formula has to do 2 lookups and an if statement. If this really is 2x the work, I was wondering if there is a more efficient way?
The formula below is returing a 0 when vlookup does not find a match. Is there a way to return a space rather than a error or zero when the lookup is not met....
View 9 Replies View RelatedIf lookup doesn't find a match in the first column, can I get it to return an
"ERR" or "0", something that would let me know there was no match? Right now
it returns the value in the second column of the closest value.
I'm trying to get a "simple" function to return a number and not the #NAME?error!
I'm writing the following vba code. It's located in the sheet1 vba code area.
On the spreadsheet itself, on sheet1, column C, there is data from row 1 down to row 55. I have tried formatting the Column as General, text,etc.
Function Asset() As String
Asset = Range("C1").End(xlDown).Row
End Function
When I type into the spreadsheet =Asset() , I get the #NAME? instead of the number 55.
When I step through in debug mode, Asset shows Asset="55" , but my function doesn't return it!
I am trying to use a function to look at the value in one cell and return a value to the cell with the functional equation. I think I use the "IF" Function. But it is a little more complicated than I can do. In my sheet, there is a number in D3. I want to create an equation in D4 that evaluates the value in D3. If D3 is between 0 and 100, I want the equation in D4 to return the value 1; If D3 is greater than 100 but less than or equal to 200, I want D4 value to be 2; if D3 greater than 200 but less than or equal to 300, D4 return 4. I would like this to continue in increments of 100 until D4 equals 10.
View 1 Replies View RelatedIs it possible to add some code that will make the function return 0 if it would otherwise return #VALUE!.
Without getting to involved here is the main piece of code.
Public Function FixedCosts(RscNum As Integer, InstYear As Long, CalcYear As Long, MW As Double)
FixedCosts = numMonths * MW * Adjust * (CapCarryCostMonthly + OtherFixedMonthly + TransCap) / 1000
i created a function called ColorFunction
but when i try to access the function it says
Book1.xls!Module1.ColorFunction
when i select this it says
Function Arguments
No help available
The function takes no arguments
Formula result =
but when i run it for the first time
it worked, but when i try to use again after saving the book .
my formula called ' conversion' used to convert foreign money in EUR does not
seem to work. My formula gives a value error. I wonder why...
Function Conversion(Position As Integer, Currency As Integer) As Integer
Dim USD As Integer
Dim GBP As Integer
Dim CHF As Integer
Dim JPY As Integer
Dim NOK As Integer
Dim NZD As Integer
Dim SEK As Integer
Dim ZAR As Integer
Dim ISK As Integer
Dim TRY As Integer
Dim AUD As Integer
' here i give a destination to my forex quotes who are in a excel sheet
USD = Range("N9").Value
GBP = Range("N10").Value
CHF = Range("N11").Value
JPY = Range("N12").Value
NOK = Range("N13").Value
NZD = Range("N14").Value
SEK = Range("N15").Value
ZAR = Range("N16").Value
ISK = Range("N17").Value
TRY = Range("N18").Value
AUD = Range("N19").Value
When I try a MATCH function, I substituted the range through the ADDRESS function. But, it returns #VALUE error. When I manually typed the same range address, it produces the results. I've been behind this more than 8 hours still I can resist the heat on my cool head! But, I thought you coolest head guys need some heat to warm up for to-day's challenge.
View 9 Replies View RelatedI am using an array formula like this in cells A2:H100 of a worksheet:
=INDEX('Source Data'!$A$2:$Q$5000,SMALL(IF(('Source Data'!$I$2:$I$5000>=$O$1)*('Source Data'!$I$2:$I$5000<=$P$1)*('Source Data'!$M$2:$M$5000>0),ROW('Source Data'!$A$2:$Q$5000)-ROW('Source Data'!$A$2)+1,ROW($Q$5000)+1),ROW()-1),1)
The function must be present in all 99 rows to accommodate potential data, but there is rarely enough data to populate the entire sheet, leaving #REF! errors in some cells. Putting aside that using this many array formulae is sloppy programming, how do I craft the function above to return no value if the function evaluates to an #REF! error?
I am trying to use the IF function to return a false value if the combined sum of a row is not the same as either of the 1st 2 cells. If that makes any sense!
This is the formula I would like to use. =IF(SUM(g3:g9)=g1 or g2 then y if true and x if false. I thought it would be easy but I can't figure out how to do it
The function "VAL" will return the value of a numerical string as a double. Is it possible to get a similar function that will return the value as a long.
View 5 Replies View RelatedNew to creating macro's but looking for a macro or a function to get the below results. The first 2 columns are givens and looking to return the 3rd column. Is there any code that can do this?
Hierarchy
Path
Expected results
000000010HIER_NODE
[Code]....
I have a cell with a text string >3, and would like it to return the number (not text) 3. I could use Right but since the number will not only be single digit I don't think this will work.
View 9 Replies View RelatedI've searched for an example of function that returns a variable, however, I'm unable to find one other than the one just has return variable on the end. I was wondering what I have wrong in the following code. This is placed in a module to make it available to all my worksheets.
Public Function findLR(Worksheet, Column) As Integer
LR = Worksheet.Cells(Rows.count, Column).End(xlUp).Row
return LR
End Function
I am looking for a formula that will yield the following: IFAH9>AI9 return the word Green, IFAH9=AI9 return the word Blue, IFAH9<AI9 return the word Yellow. If AI9 is blank stay blank.
View 3 Replies View Relatedit returns an error when I try to enter it. Is there a brave soul which a good eye for errors that might be able to shine some light on the error. Currently it appears the error centers around the MONTH( ) portions of the function. But each embedded function is able to stand alone and I can't imagine why they won't work together.
View 4 Replies View RelatedI am struck in using IF /AND in nested function as follows,
A1B1C1D1E1F1G1
1 3 5 7 9 32
=IF(AND(F2>G2,AND(IF(A2>1,A2,AND(IF(C2>5,C2,AND(IF(E2>9,E2),""))
(Above, A1 to >G1 are cell address , in exact rows are actual values)