I am trying to write a function that finds and breaks a cell about the first space.
Worksheet is:
=LEFT(name,FIND(" ",name)-1)
Have tried...
Function Firstname(name)
Dim Space As Integer
Set Space = .Find(" ", name)
Firstname = Left(name, Space)
End Function
and also...
Function Firstname(name)
firstname = left(name,find(" ",name)-1))
End Function
I can do this in Excel, but I don't seem to have a single example to hand of how, using VBA, to extract all characters up to but not including, the first space character in a cell.
View 9 Replies View RelatedI am attempting to utilize the Mid, Left, and Right functions to parse out data returned in a single cell. There are twelve months of data returned with the "title" listed after. I would like to be able to FIND the title and return a specific number of characters of data to the LEFT not the right (as Mid seems to do).
EX.
Cell A1{ 1 2 4 5 3 5 TITLE1 1 2 3 6 7 4 5 TITLE2 3 4 5 2 4 5 TITLE 4 }
Cell A2{ 1 2 4 5 3 5 TITLE2 1 2 3 6 7 4 5 TITLE3 3 4 5 2 4 5 TITLE 4 }
I would like to be able to search each cell for the "TitleX" then parse data out to the left of that title (and if not found, return "").
There are too many different Titles to use IF statements and I cannot change that the data comes to the left of the title.
I have two words of differing character lengths separated by a space.
How can I remove the first word... essentially, all the charcters to the left of the space AND the space itself?
I am blanking out. I want to pull the data out until a space (one formula from the left and one from the right). Ithink it's a mid function but not sure.
Example
John, Doe
I would like to get:
John,
and
Doe
Sub GetThatstring()
Dim strMonth As String
Dim iYear As Integer
Dim StrMnthYear As String
strMonth = Trim(Left( Range("A1"), _
InStr(1, Range("A1"), " ", vbTextCompare)))
MsgBox strMonth
iYear = Mid(Range("A1"), _
InStr(1, Range("A1"), " ", vbTextCompare) + 1, 4)
MsgBox iYear
StrMnthYear = Trim(Left(Range("A1"), _
InStr(1, Range("A1"), " ", vbTextCompare) + 4))
MsgBox StrMnthYear
End Sub
I have a column of cells likes:
5/5058 Jack Daniels
5/29AA Crown Royal
I want to delete everything to the left of the first space.
So it will look like:
Jack Daniels
Crown Royal
It has to be vba though. I have done alot of trim in just formulas but this is first time in VBA. The above code is one I found by searching but not sure what to do to modify it.
This will be for range AM2:AM2000
I'm looking for a formula that pulls the text from a cell unti it hits a space. I'm using the formula below but keep getting #VALUE results. B1: =LEFT(A1,FIND(",",A1,1)). I know it's not that hard but can't figure it out.
View 4 Replies View RelatedI'm looking for a way to split a cell with text into two cells. The first cell can only contain up to 40 characters, the rest needs to go in the second cell. However, I don't want the text to be split in the middle of a word. So basically, if the text is in cell A1, I need to find the closest space to the left of position 40 in A1, and move anything to the right of this position to B1. Example:
Original text:
A1: One green apple and a bucket of small onions that smell nice
I want to avoid this:
A1: One green apple and a bucket of small on
B1: ions that smell nice
I want to achieve this:
A1: One green apple and a bucket of small
B1: onions that smell nice
Automatically format a textbox on a userform so that it puts a space immediately before the last 3 characters, regardless of how many characters are put in?
View 9 Replies View RelatedI have following kinds of texts in a column.
MISCELLANEOUS
EQUIPMENT
JBKU348597-3
T-225
75984
I want to convert above texts with space between every character as follows:
M I S C E L L A N E O U S
E Q U I P M E N T
J B K U 3 4 8 5 9 7 - 3
T - 2 2 5
7 5 9 8 4
I am trying to find numbers before a space character.
For example...
In column 1..................to return in column 2
23 cars................................................. 23
5 trucks................................................. 5
150 vans.............................................. 150
I can't use MID Function as it can be 4 numers long...
I am looking a macro which should perform below activities
I have a lists of suppliers which needs to cleansed....
1.replace all the special characters with a space
2.replace Corporation with Corp
Incorporation with Inc
Limited with Ltd
Limited partnership/ltd partnership with LP
Company with Co
ASSC/ASSOC with ASSOCIATION/ASSOCIATES (SEARCH SUPPLIER IN GOOGLE FOR THE CORRECT ONE)
MGNT with MANAGEMENT
SVCS with SERVICES
DEPT with DEPARTMENT
Unltd with UNLIMITED
Ctr with CENTER
UNIV with UNIVERSITY
3. Remove any text, Special characters and numbers after INC,CO, LTD, CORP,LLP, LLC
The macro should when I select any particular column... not restricted to column A
I've a column of data as below:
ROACH (#21)
SHARK (#11)
SHARK (#13)
UNICORN (#26)
ROACH (#20)
TRIGGER (#09)
UNICORN (#06)
UNICORN (#09)
UNICORN (#11)
VIMBA (#03)
VIMBA (#04)
TRIGGER (#06)
ROACH (#07)
ROACH (#08)
ROACH (#10), UNICORN (#24)
What I need to do it to strip off all the characters after the first space.
I assume I can use FIND and then LEFT, but how to I put this into a Macro?
I need to add spaces to a string of characters so that it is readable, the database is huge so I cannot do it manually:
For example,
123456John Doe 3456Adam Sharp I need it to apperar as:
123456 John Doe 3456 Adam Sharp
but still remains at the same column. Is there a quick way to do this ?
I want to write a macro that will check every selected cell. It should detect if there is a space after the fourth character. If there is a space, go to the next selected cell. If there is no space, add a space and go to the next selected cell.
View 5 Replies View RelatedI have text string and would like two formulas to find,
1) the characters after the last space and
2)to find the number of characters after the last space.
I have text string and would like two formulas to find, 1) the characters after the last space and 2)to find the number of characters after the last space.
View 9 Replies View RelatedI want to remove the front zero(s) from the front and put a space before the last two letters for the following column of data in Excel:
0001MG
0020MG
0100MG
1000MG
Final result will have this format and the data are right aligned.
1 MG
20 MG
100 MG
1000 MG
The numbers can vary (e.g. 0150MG, 0025MG,etc.) but the arrangement is always the same: four figures for the first 4 characters and two letters for the last two characters.
The format of the cells containing the data is: “General”
My table has 7 columns and these data are in the 5th column in a worksheet called “ProductSummary”. The number of rows for the records can vary from 10 to over a couple of hundred.
How can I use VBA to: 1) automatically select the table range in that worksheet and reformat all the data in the 5th column.
Using VBA, how can I determine if a cell contains only white spaces and NO valid characters?
View 2 Replies View RelatedI have a series of alpha numerics items in Cells A1:A999 (i.e AB0001 to AB0999). I need to be able to perform a search the range (A1:A999), and extract items that do not conform to the standard AB prefix. Example, an item of BC0001 could be present in the range. I would need to have that item, either highlighted or displayed in a different column.
View 2 Replies View RelatedI am looking to write a formula in an excell cell to veiw some of the wording in another cell. I know how to say that i want to see the first or last "x" characters in a cell.. But how do i say that i want to see all the info/wording in a cell except the last "x" characters..
View 4 Replies View Relatedusing this format *.#,##0_);*.(#,##0);*.0_);@*. I get this:
Bonds..................................
would like custom format to do this,
Bonds . . . . . . . .
note:@ sign activates text formatting, *=repeats .=character being repeated
I've tried putting space characters before and after the period - no luck
I am trying to extract the last substring in some text that I have. see below for example.
12/30-12/31 Bob Dylan 40.25
I need to extract the 40.25 out. Every line item may be different but the number I am extracting is always after the last space. I tried using mid and find but this doesn't work well when there is more than 1 space in the text.
I'm looking for a way to extract the data after the first space in a string to after the first set of numbers (always 8 digits). The formula I'm using is not accurate since the number of words that appears between the first space to the first set of numbers changes.
Sheet2ABC1Desired results2277 xxx spzrtmhk
companies 12345678 231516990 2475.06 3199.57 23.19 street 1 739.00xxx spzrtmhk
companies12345678 231516990xxx spzrtmhk companies 1234567831528 dts powertrain comp inc
15981808 231516989 43.55 84.40 48.40 5.00dts
[Code] ...........
i have used the RIGHT function to remove the 1L/1S and the 1L from the samples belows
the problem i have is when the 1L is in its cell there are 3 spaces before it
how can i remove those spaces so that all the data is to the left of the cell
BYA001 1L/1S
BYA003 1L
I need a formula, that will, Show the Characters Left of Delimiter (,).
for example:
CABLE, UD SECONDARY #4 DPLX AL
result:
CABLE
I need VBA coding that starts in a cell, moves 5 columns to the left, and then copies the left 8 characters of the string. The Macro should end there, but I'm hoping to be able to then paste those 8 characters elsewhere, say a different programme or web page.
I can move the cell no problem:
ActiveCell.Offset(0, -5).Select
But how to then copy those left 8 characters so it stays in the clipboard at the end of the macro?
The formula needs to be non-cell specific, i.e. I need to use the above selection and NOT a cell name such as A5 etc.
I'm trying to figure out why i'm getting this error: "Object variable or With block variable not set" for this
Sub Macro3()
Dim cel As Range
Dim str1 As String
Dim SearchThing As Range
Set SearchThing = ActiveSheet.Range("I34")
str1 = Left(SearchThing.Value, Len(SearchThing) - 4)
cel.Value = str1
End Sub
The error is specifically with this line
cel.Value = str1....................
I want to take a lot of text fields with alphanumeric characters ie. " '49560-960-A908 "
(always beginning with the character " ' ") and display in another cell position 2 thur 6 ie. "49560"
I have a file that contains 3,500 cells with alphanumeric characters...always beginning with ' but I need the 1st 5 numbers after the ' in a second separate column
I am using (in Column "B") the formula: =IF(A2=A3."",1), copied down as required, to uniquely identify entries in Column "A". In this instance "10", "10A", "10B" and "10C" located in "A5" through "A11" are viewed as the same. Is it possible to have the formula recognize the enties in "A5:A11" as a unique entry and therfore have "1" entered into cell "B11"? The suffix, if used will always be A thorugh Z.
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