How would I find the first cell in column A containing a number, like HY42128PP, and then offset 1 row up from there to start my autofilter?
Also, to copy the worksheet headings, what code would copy all rows from row 1, down to 2 rows above the first cell in column A containing numbers, and insert those rows in another sheet?
I have a column contains Postal Adress in more than 5000 rows. Column contains Door Number, Area, City and Zip code. I need to separate "Zip code" alone in next coulmn. Zip code (of India) will be in six digits like "600083" also some cases contain space in middle of zip code like "600 083" (after 3 digits). Is there any way to do this without doing cut & paste?
I have a column contains Telephone numbers with or without area code and country code for across the country (India). I need to extract the telephone numbers alone (neither area code nor country code). Telephone numbers will be 6 or 7 or 8 digits (not more than that). Is it possible to extract any set of numbers contain 6 or 7 or 8 digits continously? Some of the cases contains 2 contact numbers (2 set of 6 or 7 or 8 digit characters, between special characters will be there like slash, comma, space, hypen, etc.,
Column A in Excel has loads of numbers all in this format 971-417. I need to have each of those two numbers in a separate cell from each other(and without the hyphen of course).
Column A Needs to be: Column A Column B 971-417 971 417
In short, I'm looking for a quick way to put each number in its own cell for hundreds of rows. Are there formulas I can use to do this or does it have to be done slowly, one at a time, stripping the information from one cell to another?
i have a list of information, and from that i want to extract a certain piece from that information and out it in a new cell... eg. 'KLM00506', 'KLM00409-10', 'KLM00821-9' etc
as you can see, the info is not in the same length what i need is to take out the FIRST 6 characters and have the remaining to be in a new cell
anyone has an excel formula that i can use ? not really interested in code, cause in this particular worksheet, everything is at its' place, no code required
This is very similar to my previous post, which was solved. Now that I've extract the numbers, I need to extract the text for the specific work activities, for example 13Z or 9GGG. I'm assuming some variation on this formula:
I have a problem that I just dont seem to have the brain power to solve right now. I have a list of websites and I need to extract all characters after the last / in the URL. URL example:.....
I have been using the find function in conjunction with LEN and RIGHT etc but the multiple instances of / is causing headaches for me. Also, the trailing string of characters that I want to extract can be both text or numeric and are of differing lenths.
I am attempting to utilize the Mid, Left, and Right functions to parse out data returned in a single cell. There are twelve months of data returned with the "title" listed after. I would like to be able to FIND the title and return a specific number of characters of data to the LEFT not the right (as Mid seems to do).
I have a list of numbers in which I need to return the last 5 digits; the length of the string may vary.
However, if the last two digits of the number ends in a specific value then it should skip over the last two numbers and return the preceding 5 digits.
I have tried and have used the very basic Left, Right and Mid functions. My problem is I dont know how to code the formula to identify the last two digits and skip over them, if necessary.
I have provided an attached example.
Extract numeric value based upon ending characters.xlsm
I'm working with a large list of items of varying length. A sample worksheet is attached. I need to do the following:
1) If the characters after the final forward slash from the right are of the pattern "tttxxx" (where "t" is text and "x" is a number/digit), then return all characters to the right of the final slash, including the slash itself:
Y:/Series/hun/hun109 ----> /hun109
2) if the characters after the final slash from the right are not of the pattern "tttxxx", then return all characters after the second slash from the right, including the slash:
Having trouble with this one. Searches seem to bring up every other variation of extracting info from strings except this.
I have cells which contain alphanumeric strings as below and, using a formula, I want to extract everything from and including the last letter to give A 2-3, B 3 and C 3-4 in the examples below.
I can do this in Excel, but I don't seem to have a single example to hand of how, using VBA, to extract all characters up to but not including, the first space character in a cell.
Cell R2 contains this value: " Forecast Time: 240 Index A forecast = 9078.314". I want to extract the characters "9078.314" and put them in a different cell. The cell that it should be affected to depends on the characters "240". I believe I should use the MID() and VLOOKUP() functions but I get stuck at the very first step of extracting my data.
I can't use the "" sign as delimiter to separate them into different columns because the age,city,name and height fields are in random positions on different cells.The good thing is person's name will always come after "name" string, age is alwals followed by "age" string, so it cannot be like nameheight40Michigan180
I think the following would be the easiest method(not for me tho).If on B1 I had a formula that said "find the string "name" and write anything after it until you reach the next "" character".On C1 field I could have a formula "find the string "age" and write anything after it until you reach the next "" character.On D1 I would have the same for "height" string,then on E1 for city string.
My question is somewhat similar to this one Extract A String Between Two Characters
Formula which outputs the data between 3rd and 4th instances of the "_" character.Can we substitute "3rd and 4th" with a specific strings like "age" or "height" ?
Is there an Excel formula to remove the spacebar + characters in red, as shown below? I need to be left with only the last name, first name and the semicolon.
Mouse, Mickey ;
Microsoft Outlook has changed the way that email addresses from the global addressbook copy and paste (from version 2003 to version 2010).
So we have people's names in a table. First name in one column and last name in another column. We have a 3rd column where we can use 8 characters to do a combination of First 5 of Last Name + first 3 of first name. However, if someone's last name is only 3 or 4 characters, we'd then want to take more from the first name to fill out the 8 characters.
So: Charles Johnson -> Johnscha John Smith -> Smithjoh Willian Wu -> Wuwillia
What's the best way to do that without creating some crazy formula with tons of if/thens?
How can I make combobox have only first 18 characters from a cell to appear, Have tried max lengh to 18 but still on the output it shows the full string... or an alternative how can i fix sheet column to 18 characters input ????
Ok so my formula simply wants to substitute a really long string of text with a blank cell. Problem is that the really long string of text goes over the 255 char limit for a formula.
How can I go about solving this problem. I think you could name the string of text as a variable such as "long text" and then use the substitute formula as such:
=SUBSTITUTE(A1,"long text", "")
Something like that? I don't know if it would work or the steps to name the variable.
I'm trying to make a chart viewer on the first sheet of my spreadsheet and am using this website as a guideline, [URL] However instead of the 3 charts in the example, I have 12 which makes my formula for defining a name substantially longer.
By moving my charts to the same sheet and getting rid of the INDIRECT formulas, I shortened my formula to 291 characters which is too long as the limit is 255.