Extract Numeral/s Between Characters?
Dec 29, 2013
I would like to extract any numerals between the comma and colon. (Format is text)
Example: 8 Dec, 1:52PM (1 to show in another cell)
Format is always the same but date/day & hour may change. (Hence changing number of characters depending on day and time.)
Example: 11 Dec, 10:49AM (10 to show in another cell.)
View 2 Replies
ADVERTISEMENT
Apr 21, 2008
How would I find the first cell in column A containing a number, like HY42128PP, and then offset 1 row up from there to start my autofilter?
Also, to copy the worksheet headings, what code would copy all rows from row 1, down to 2 rows above the first cell in column A containing numbers, and insert those rows in another sheet?
View 13 Replies
View Related
Feb 3, 2012
In column M I have data that lists a number, then number of metres between brackets. For instance
Column M
11 (79m)
1 (5m)
22 (123m)
Basically what I want to do is to always return the number of metres without m, so the data between "(" and "m".
I tried to do this using the find and mid formulas, but I either haven't got it quite right. I'm only after a spreadsheet solution (not VBA).
View 6 Replies
View Related
Oct 8, 2013
Data in field A1 currently appears as below.
8/10
I want to extract everything to the right of the "/" in a new field.
The formula that I am using is =RIGHT(A1,FIND("/",A1)-1)
For some reason, I am only receiving a 0 in the new field and not the 10 that I expect.
What's odd is that the formula is working as intended on every other field except this one.
View 6 Replies
View Related
Jul 1, 2009
I have a column contains Postal Adress in more than 5000 rows. Column contains Door Number, Area, City and Zip code. I need to separate "Zip code" alone in next coulmn. Zip code (of India) will be in six digits like "600083" also some cases contain space in middle of zip code like "600 083" (after 3 digits). Is there any way to do this without doing cut & paste?
View 9 Replies
View Related
Jul 3, 2009
I have a column contains Telephone numbers with or without area code and country code for across the country (India). I need to extract the telephone numbers alone (neither area code nor country code). Telephone numbers will be 6 or 7 or 8 digits (not more than that). Is it possible to extract any set of numbers contain 6 or 7 or 8 digits continously? Some of the cases contains 2 contact numbers (2 set of 6 or 7 or 8 digit characters, between special characters will be there like slash, comma, space, hypen, etc.,
Here are some examples: ....
View 9 Replies
View Related
Sep 28, 2006
Column A in Excel has loads of numbers all in this format 971-417. I need to have each of those two numbers in a separate cell from each other(and without the hyphen of course).
Column A Needs to be: Column A Column B
971-417 971 417
In short, I'm looking for a quick way to put each number in its own cell for hundreds of rows. Are there formulas I can use to do this or does it have to be done slowly, one at a time, stripping the information from one cell to another?
View 6 Replies
View Related
Nov 15, 2006
i have a list of information, and from that i want to extract a certain piece from that information and out it in a new cell...
eg. 'KLM00506', 'KLM00409-10', 'KLM00821-9' etc
as you can see, the info is not in the same length
what i need is to take out the FIRST 6 characters and have the remaining to be in a new cell
anyone has an excel formula that i can use ? not really interested in code, cause in this particular worksheet, everything is at its' place, no code required
View 4 Replies
View Related
May 6, 2009
This is very similar to my previous post, which was solved. Now that I've extract the numbers, I need to extract the text for the specific work activities, for example 13Z or 9GGG. I'm assuming some variation on this formula:
=LOOKUP(9.99E+307,--MID(C4,MIN(FIND({1,2,3,4,5,6,7,8,9,0},C4&1234567890)),ROW(INDIRECT("1:"&LEN(C4)))))
is the solution, but I'm struggling with making the correct alterations.
View 2 Replies
View Related
Apr 24, 2009
I need a Excel 2007 formula that will extract a string of text that is seperated by characters.
Example:
in Cell (A1) I have the following
ALA 11 : [ MOBILE ] 36619 1/2 ... HOME ... JUNE 2009 / TODAY: $ 50000
End Result wanted:
Cell (A2) 11
Cell (A3) MOBILE
Cell (A4) 36619 1/2
Cell (A5) HOME
Cell (A6) JUNE 2009
Cell (A7) 50000
View 8 Replies
View Related
Dec 23, 2009
I have a problem that I just dont seem to have the brain power to solve right now. I have a list of websites and I need to extract all characters after the last / in the URL. URL example:.....
I have been using the find function in conjunction with LEN and RIGHT etc but the multiple instances of / is causing headaches for me. Also, the trailing string of characters that I want to extract can be both text or numeric and are of differing lenths.
View 3 Replies
View Related
Oct 6, 2006
I am trying to write a function that finds and breaks a cell about the first space.
Worksheet is:
=LEFT(name,FIND(" ",name)-1)
Have tried...
Function Firstname(name)
Dim Space As Integer
Set Space = .Find(" ", name)
Firstname = Left(name, Space)
End Function
and also...
Function Firstname(name)
firstname = left(name,find(" ",name)-1))
End Function
View 6 Replies
View Related
Nov 10, 2006
I am attempting to utilize the Mid, Left, and Right functions to parse out data returned in a single cell. There are twelve months of data returned with the "title" listed after. I would like to be able to FIND the title and return a specific number of characters of data to the LEFT not the right (as Mid seems to do).
EX.
Cell A1{ 1 2 4 5 3 5 TITLE1 1 2 3 6 7 4 5 TITLE2 3 4 5 2 4 5 TITLE 4 }
Cell A2{ 1 2 4 5 3 5 TITLE2 1 2 3 6 7 4 5 TITLE3 3 4 5 2 4 5 TITLE 4 }
I would like to be able to search each cell for the "TitleX" then parse data out to the left of that title (and if not found, return "").
There are too many different Titles to use IF statements and I cannot change that the data comes to the left of the title.
View 9 Replies
View Related
Jan 10, 2014
I have a list of numbers in which I need to return the last 5 digits; the length of the string may vary.
However, if the last two digits of the number ends in a specific value then it should skip over the last two numbers and return the preceding 5 digits.
I have tried and have used the very basic Left, Right and Mid functions. My problem is I dont know how to code the formula to identify the last two digits and skip over them, if necessary.
I have provided an attached example.
Extract numeric value based upon ending characters.xlsm
View 5 Replies
View Related
Nov 7, 2008
Say I have a string "09800EBHR052708"
How would I take the first 5 characters and get a number out of them?
View 14 Replies
View Related
Jun 12, 2008
I have the following in Column A
28VNC
JR2KL
29C9O
PQS11
I'd like have this result
28
2
299
11
How would I achieve this.
View 6 Replies
View Related
May 23, 2008
How can I extract mid section of the string which is always 5 characters long and is always followed by a period "." ?
My account strings are in 3 sections (but the third section isn't always used)
For example,
1.10210
1.22556.001
900101.56201
955261.54444.001
5566625.58886.957756
View 4 Replies
View Related
Apr 9, 2014
I'm working with a large list of items of varying length. A sample worksheet is attached. I need to do the following:
1) If the characters after the final forward slash from the right are of the pattern "tttxxx" (where "t" is text and "x" is a number/digit), then return all characters to the right of the final slash, including the slash itself:
Y:/Series/hun/hun109 ----> /hun109
2) if the characters after the final slash from the right are not of the pattern "tttxxx", then return all characters after the second slash from the right, including the slash:
Z:/Series/crd/crd409/editorial ----> /crd409/editorial
3) if there are less than 3 backslashes in the item, return a blank.
View 3 Replies
View Related
May 14, 2013
Having trouble with this one. Searches seem to bring up every other variation of extracting info from strings except this.
I have cells which contain alphanumeric strings as below and, using a formula, I want to extract everything from and including the last letter to give A 2-3, B 3 and C 3-4 in the examples below.
Sub-base A 2-3
Sub-base B 3
Paving C 3-4
View 7 Replies
View Related
Sep 10, 2013
I can do this in Excel, but I don't seem to have a single example to hand of how, using VBA, to extract all characters up to but not including, the first space character in a cell.
View 9 Replies
View Related
Apr 2, 2009
I need some code to add to my macro. The code needs to cut customer names starting with "A" or a numeral, from sheet 1, column C.
The entire row needs to be pasted into sheet 2, starting at cell A2
View 3 Replies
View Related
Feb 5, 2007
Cell R2 contains this value: " Forecast Time: 240 Index A forecast = 9078.314". I want to extract the characters "9078.314" and put them in a different cell. The cell that it should be affected to depends on the characters "240". I believe I should use the MID() and VLOOKUP() functions but I get stuck at the very first step of extracting my data.
View 3 Replies
View Related
Dec 22, 2013
I have the following type of info in A1,A2,A3...
Code:
nameGaryage40cityPittsburgheight190
age30height150
ameLindacityMichigan
citySan Jose
ameHarryheight180age50
My goal is to get as close as possible to this,so it will be easier to sort and manage
Code:
nameGaryage40cityPittsburgheight190
nameLindaage30cityMichiganheight150
nameHarryage50citySan Joseheight180
I can't use the "" sign as delimiter to separate them into different columns because the age,city,name and height fields are in random positions on different cells.The good thing is person's name will always come after "name" string, age is alwals followed by "age" string, so it cannot be like nameheight40Michigan180
I think the following would be the easiest method(not for me tho).If on B1 I had a formula that said "find the string "name" and write anything after it until you reach the next "" character".On C1 field I could have a formula "find the string "age" and write anything after it until you reach the next "" character.On D1 I would have the same for "height" string,then on E1 for city string.
My question is somewhat similar to this one
Extract A String Between Two Characters
Formula which outputs the data between 3rd and 4th instances of the "_" character.Can we substitute "3rd and 4th" with a specific strings like "age" or "height" ?
Code:
=TRIM(LEFT(SUBSTITUTE(MID(A1,FIND("|",SUBSTITUTE(A1,"_","|",3))+1,LEN(A1)),"_",REPT(" ",LEN(A1))),LEN(A1)))
View 3 Replies
View Related
Jan 17, 2012
Is there an Excel formula to remove the spacebar + characters in red, as shown below? I need to be left with only the last name, first name and the semicolon.
Mouse, Mickey ;
Microsoft Outlook has changed the way that email addresses from the global addressbook copy and paste (from version 2003 to version 2010).
View 8 Replies
View Related
May 13, 2009
I'm trying to use conditional formatting to highlight cells in a column that have less than 8 characters.
I know the LAN function, but I don't know how to make it work for the conditional formatting.
View 9 Replies
View Related
Aug 1, 2014
So we have people's names in a table. First name in one column and last name in another column. We have a 3rd column where we can use 8 characters to do a combination of First 5 of Last Name + first 3 of first name. However, if someone's last name is only 3 or 4 characters, we'd then want to take more from the first name to fill out the 8 characters.
So:
Charles Johnson -> Johnscha
John Smith -> Smithjoh
Willian Wu -> Wuwillia
What's the best way to do that without creating some crazy formula with tons of if/thens?
View 4 Replies
View Related
Sep 14, 2009
I have a string of names that run together without spaces or commas between each name.
"Danny TrejoJean Claude van DammeVincent SchiavelliGabrielle FitzpatrickDavid 'Shark' FralickPat Morita" for example.
Is there a way to add a comma and space when an upper case letter is immediately followed by a lower case letter?
View 4 Replies
View Related
Feb 23, 2010
How can I make combobox have only first 18 characters from a cell to appear, Have tried max lengh to 18 but still on the output it shows the full string... or an alternative how can i fix sheet column to 18 characters input ????
View 2 Replies
View Related
Jan 10, 2014
Ok so my formula simply wants to substitute a really long string of text with a blank cell. Problem is that the really long string of text goes over the 255 char limit for a formula.
How can I go about solving this problem. I think you could name the string of text as a variable such as "long text" and then use the substitute formula as such:
=SUBSTITUTE(A1,"long text", "")
Something like that? I don't know if it would work or the steps to name the variable.
View 6 Replies
View Related
Feb 17, 2014
I'm trying to make a chart viewer on the first sheet of my spreadsheet and am using this website as a guideline, [URL] However instead of the 3 charts in the example, I have 12 which makes my formula for defining a name substantially longer.
By moving my charts to the same sheet and getting rid of the INDIRECT formulas, I shortened my formula to 291 characters which is too long as the limit is 255.
=IF($G$9="Sodium",$N$34,IF($G$9="Manganese",$N$35,IF($G$9="Iron",$N$36,IF($G$9="Nitrate Nitrite",$N$37,IF($G$9="Nitrite",$N$38,IF($G$9="Nitrate",$N$39,IF($G$9="PH",$N$40,
IF($G$9="Conductivity",$N$41,IF($G$9="Turbidity",$N$42,IF($G$9="Fluoride",$N$43,IF($G$9="Selenium",$N$44,$N$45)))))))))))
Is there any way to make my formula shorter? Or to reference a cell where I place the formula?
View 5 Replies
View Related