I am trying to find numbers before a space character.
For example...
In column 1..................to return in column 2
23 cars................................................. 23
5 trucks................................................. 5
150 vans.............................................. 150
I can't use MID Function as it can be 4 numers long...
Automatically format a textbox on a userform so that it puts a space immediately before the last 3 characters, regardless of how many characters are put in?
View 9 Replies View RelatedI have following kinds of texts in a column.
MISCELLANEOUS
EQUIPMENT
JBKU348597-3
T-225
75984
I want to convert above texts with space between every character as follows:
M I S C E L L A N E O U S
E Q U I P M E N T
J B K U 3 4 8 5 9 7 - 3
T - 2 2 5
7 5 9 8 4
I am looking a macro which should perform below activities
I have a lists of suppliers which needs to cleansed....
1.replace all the special characters with a space
2.replace Corporation with Corp
Incorporation with Inc
Limited with Ltd
Limited partnership/ltd partnership with LP
Company with Co
ASSC/ASSOC with ASSOCIATION/ASSOCIATES (SEARCH SUPPLIER IN GOOGLE FOR THE CORRECT ONE)
MGNT with MANAGEMENT
SVCS with SERVICES
DEPT with DEPARTMENT
Unltd with UNLIMITED
Ctr with CENTER
UNIV with UNIVERSITY
3. Remove any text, Special characters and numbers after INC,CO, LTD, CORP,LLP, LLC
The macro should when I select any particular column... not restricted to column A
I've a column of data as below:
ROACH (#21)
SHARK (#11)
SHARK (#13)
UNICORN (#26)
ROACH (#20)
TRIGGER (#09)
UNICORN (#06)
UNICORN (#09)
UNICORN (#11)
VIMBA (#03)
VIMBA (#04)
TRIGGER (#06)
ROACH (#07)
ROACH (#08)
ROACH (#10), UNICORN (#24)
What I need to do it to strip off all the characters after the first space.
I assume I can use FIND and then LEFT, but how to I put this into a Macro?
I need to add spaces to a string of characters so that it is readable, the database is huge so I cannot do it manually:
For example,
123456John Doe 3456Adam Sharp I need it to apperar as:
123456 John Doe 3456 Adam Sharp
but still remains at the same column. Is there a quick way to do this ?
I am trying to write a function that finds and breaks a cell about the first space.
Worksheet is:
=LEFT(name,FIND(" ",name)-1)
Have tried...
Function Firstname(name)
Dim Space As Integer
Set Space = .Find(" ", name)
Firstname = Left(name, Space)
End Function
and also...
Function Firstname(name)
firstname = left(name,find(" ",name)-1))
End Function
I want to write a macro that will check every selected cell. It should detect if there is a space after the fourth character. If there is a space, go to the next selected cell. If there is no space, add a space and go to the next selected cell.
View 5 Replies View RelatedI have text string and would like two formulas to find,
1) the characters after the last space and
2)to find the number of characters after the last space.
I have text string and would like two formulas to find, 1) the characters after the last space and 2)to find the number of characters after the last space.
View 9 Replies View RelatedI want to remove the front zero(s) from the front and put a space before the last two letters for the following column of data in Excel:
0001MG
0020MG
0100MG
1000MG
Final result will have this format and the data are right aligned.
1 MG
20 MG
100 MG
1000 MG
The numbers can vary (e.g. 0150MG, 0025MG,etc.) but the arrangement is always the same: four figures for the first 4 characters and two letters for the last two characters.
The format of the cells containing the data is: “General”
My table has 7 columns and these data are in the 5th column in a worksheet called “ProductSummary”. The number of rows for the records can vary from 10 to over a couple of hundred.
How can I use VBA to: 1) automatically select the table range in that worksheet and reformat all the data in the 5th column.
Using VBA, how can I determine if a cell contains only white spaces and NO valid characters?
View 2 Replies View Relatedthere is AT() which finds the first occurrence of a string searching from the left like FIND() and SEARCH(), and RAT() which finds the first occurrence searching from the right-to-left.
A single column with names:
John Doe
Jane Marie Smith
Dr. Alex R. Jones
Bill
I need two columns that would look like:
John.................Doe
Jane Marie........Smith
Dr. Alex R.........Jones
Bill
I can do this in Excel, but I don't seem to have a single example to hand of how, using VBA, to extract all characters up to but not including, the first space character in a cell.
View 9 Replies View Relatedusing this format *.#,##0_);*.(#,##0);*.0_);@*. I get this:
Bonds..................................
would like custom format to do this,
Bonds . . . . . . . .
note:@ sign activates text formatting, *=repeats .=character being repeated
I've tried putting space characters before and after the period - no luck
Below is the "real formula"
=IF(SUM($F$4-$E$4)= 0," ",SUM($F$4-$E$4)) 'If the value is 0 then enter a space in the cell.
And below is the VBA formula
"=if(sum(" & LastRowCell & "-" & FirstRowCell & ")= 0," & " " & ",sum(" & LastRowCell & "-" & FirstRowCell & "))"
The real formula works, but I am having having difficulties with the syntax of the VBA formula. The above VBA formula works to, but enters a 0 in the cell instead of a space.
I was hoping someone could help me out. I've been trying to put together a formula to find special characters with no luck.
Characters I’m looking for are:
I'm having the following little problem, and i'm hoping that
someone here can help me solve it.
I have a number of rows containing data starting at row 1.
I already made VBA code which finds the last row containing data.
That row number is stored in the variable "LastRowWithData".
What i want to do now is the following.
In column B (in row 1 to the row number stored in "LastRowWithData"),
there are long code's which all have to be checked for unwanted characters.
Some of these unwanted characters are the "I" and "O" characters both in
upper case and lower case.
If these characters are found a messagebox has to appear, saying something
like "Illegal character found in cell ____".
If more than one cell containing unwanted characters are found, either more
messageboxes with the cell coordinates have to be displayed or one messagebox
displaying all the cell coordinates in which the unwanted characters are found.
Im planning to use a while - wend statement to check all cells for unwanted
characters. (While ActiveCell.Row LastRowWithData)
Is there a simple way to do this in (Excel 2003) VBA ?
i bought a tattslotto scratch card (for those of ya outside of australia, not sure what youd call em, basically lottery ticket/game), this game is essentially a crossword puzzle, you scratch your letters out in a box then you have a list of words, you need to find words that are made up entirely of your letters, the more words you find, the more you win ive kind of screwed up the card and scratched out words i dont have, however i do have atleast 2 words and i think ive got more, potentially could win big but wanna know how much before i go claim it
ive opened up a new workbook, in the A column ive got a list of all my words, then in C1 ive got a field where ive entered all my letters, wondering if theres a way to get excel to work it out for me (like an IF statement on the fields in column A to compare them to C1, or some kind of conditional formatting rule)
Is there a way to extend the space of my userform beyond its maximum space? I have tried using vertical scroll bars but they were of no use.
View 1 Replies View RelatedI have been working on different formulas to return the text string between the first and last space and have been unsuccessful. Is this possible?
I have tried several combos or Left and Right, I have been able to get the values after the first space, and the values before the last space, but not between the spaces.
String: Y60
~C CULT NUCLEUS 3X2 SPRING WST BK XL
Desired results: D60
CULT NUCLEUS 3X2 SPRING WST BK
I have two words of differing character lengths separated by a space.
How can I remove the first word... essentially, all the charcters to the left of the space AND the space itself?
I'd like to be able to search a spreadsheet for a specific word or series of characters. Once all of the ROWS that contain the characters are found, I'd like to be able to have another spreadsheet with ONLY those rows (all columns).
View 8 Replies View RelatedI have the following formula that works fine until someone uses the space bar to clear a cells contents
=COUNTA($D11:$AI11)
When the space bar is used to clear a cells contents the COUNTA statements includes the space in the count. How do I count the number of cells with content and exclude the space bar space in a cell?
If find dot. with out space in ( A1 ) cell remove space after dot in cell ( B1 ) Cell, vb or macro
A
B
M V Micunovic
MICUNOVIC,M V
L.T.Kudrjavceva
KUDRJAVCEVA,L. T.
D Sumarac m.l.
M. L,D SUMARAC
I only want to remove one space at the end of my text within a cell, if there is a space.
Code:
Sub hth()
Dim c As Range
For Each c In Range("H1", Range("H" & Rows.Count).End(xlUp))
c.Value = Trim(c.Value)
Next c
End Sub
Is there an Excel formula to remove the spacebar + characters in red, as shown below? I need to be left with only the last name, first name and the semicolon.
Mouse, Mickey ;
Microsoft Outlook has changed the way that email addresses from the global addressbook copy and paste (from version 2003 to version 2010).
I'm trying to use conditional formatting to highlight cells in a column that have less than 8 characters.
I know the LAN function, but I don't know how to make it work for the conditional formatting.
I have been trying to write two formulas in one cell. I have been able to write them both separately but have been unable to join them both together. What I am trying to do if first search name them how many reoccurring numbers appear. I have provided an example below
a b c d
1 Tom 333
2 Sam 22
3 Sam 22
4 John 5
5 Sam 22
6 Sam 1
7 Tom 3
8 Tom 333
So the answer would be
Tom = 2
Sam = 2
John = 1
So we have people's names in a table. First name in one column and last name in another column. We have a 3rd column where we can use 8 characters to do a combination of First 5 of Last Name + first 3 of first name. However, if someone's last name is only 3 or 4 characters, we'd then want to take more from the first name to fill out the 8 characters.
So:
Charles Johnson -> Johnscha
John Smith -> Smithjoh
Willian Wu -> Wuwillia
What's the best way to do that without creating some crazy formula with tons of if/thens?