How To Remove First 2 Digits If They Are Certain Numbers
Jan 29, 2014
I have a excel file, I need to remove the first two digits if they are certain numbers, such as 12. For example, if the number is 12987654, then I need remove 12, and it will be "987654" , but if it is not 12 in the first two digits, then keep it no change, for example if it is 345678, then keep it.
I barely work with Excel formulas, now I need connect the excel file with my Database table. I need to make the file matches the DB.
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...). Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below: De Wetshof Finesse/Lesca Cahrdonnay ‘07 De Wetshof Sauvignon Blanc ‘07 Lord Neethling Cabernet Franc 2002 Lord Neethling Pinotage ‘01 Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07 Jacobsdal Pinotage 1994 Zondernaam Sauvignon Blanc 2007 Tokara Red 1976 St Emilion 03 Tokara rose Plasir de Merle Cabernet Sauvignon ‘05 DuToitskloof Pinotage/Merlot/Ruby Cabernet 1999 Tradition Juracon 375ml
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in: =IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.
Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below: De Wetshof Finesse/Lesca Cahrdonnay ‘07 De Wetshof Sauvignon Blanc ‘07 Lord Neethling Cabernet Franc 2002 Lord Neethling Pinotage ‘01 Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07 Jacobsdal Pinotage 1994 Zondernaam Sauvignon Blanc 2007 2003 Tokara Red 1976 St Emilion 03 Tokara rose Plasir de Merle Cabernet Sauvignon ‘05
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in: =IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2))) As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
Does anyone have an idea on how to help with this?
Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.
However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.
I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.
=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)
1. Remove the first 4 digits from each "Appeal ID"
2. Insert a new column (first column) called "Chapter"
3. Run a v-lookup down the new column against a file that is stored on my desktop. The v-lookup will cross check the Appeal ID against the file to identify the Chapter
4. Sort the data alphabetically by Chapter
5. Create seperate Excel files for each Chapter ...
I know how to remove the first part of a text, but not the end. I have a very large amount of data in which the first column contains a product description and then the UPC code. I need to isolate the product name from the UPC code into 2 columns. I used =RIGHT(B2,14) to isolate the UPC, but since the length of the product name varies, I'm not sure how to isolate the product name. I have looked at using the TRIM and TRUNC functions without any luck. 'Text to columns' doesn't work because I have multiple spaces, 'Text to columns' would work if I could used 2 digits as the delimiter, but the function doesn't allow that.
Can someone please suggest a function or formula for this?
Here is an examples of how the text appears in the field. (Note: I only need to cut off the UPC code, I need the measure information to stay).
some really long product name 12 oz 5 bag 09-99999-99999 another shorter name 2 oz 09-99999-99998
I have found a very useful UDF for removing non-alpha characters from strings. (See below, Credit for posting to Stanley D Grom - Ozgrid post ´Removing Non-alpha Characters From Text´).
Option Explicit
Private Function RemoveCharacters(InString As String) As String Dim intLoopCounter As Integer Dim intStringLength As Integer Dim intASCIIVal As Integer intStringLength = Len(InString) InString = LCase(InString) For intLoopCounter = 1 To intStringLength intASCIIVal = Asc(Mid(InString, intLoopCounter, 1)) If intASCIIVal >= 97 And intASCIIVal <= 122 Then RemoveCharacters = RemoveCharacters + Mid(InString, intLoopCounter, 1) End If Next intLoopCounter End Function
Two requests:
1. Could the UDF be modified such that any part of a string contained within brackets is also removed (e.g. "NLGA High Street (West-Enfield), EN6" becomes "nlgahighstreeten")?
2. Can an argument be added to the format of the UDF, such that numbers (0 to 9) are either included or excluded (e.g. RemoveCharacters(A1,1) where the argument ´1´ would include any numbers (0 to 9), so "NLGA2003 High Street (West-Enfield), EN6" becomes "nlga2003highstreeten6")? ´blank´or ´0´would exclude these numbers, i.e. would return "nlgahighstreeten"
I have a unique 6 digit number in a column. I have 2500 rows. I need to cut the first three numbers only leaving the last 3 numbers in the column for each row.
Example: 112345 234325
I would need 112, and 234 deleted. Checked the forum and cannot get quite what I want.
I have a column with numbers in about 500 rows. The entries are 5 numbers long and others 8. So I thought i could use one of the following: A macro code to tell a cell to delete the first 3 numbers if the entry is 8 numbers long?
OR
A macro code to tell a cell to reduce itself to 5 digits long starting from the right? Attached is a small example
I need to list 4 digit numbers in each section followed by commas, but whatever I do it goes to 3digits (e.g. I need "1234,5678,9123" and as soon as I hit Enter it goes to "123,456,789,123"). It wont work to format as text because I have a whole bunch of 12 digit numbers to break up into 4.
I need a way to display all 8 digit numbers that have the digits 1-8 in them. (ie. 12345678 but NOT 12345679 OR 12345677) Also If I could somehow divide by 13 then check for whole numbers
I would like to extract numbers based on the first 2 digits (22....) of a column along with its next column (on the right) and put them on another sheet.
I am inserting data into my spreadsheet using VBA code to read a file and insert the data into the relevant cells. My problem arises when I have a string such as 80830410205724044. The actual code that inserts the data is as shown (temp is dimmed as string)....
I have a UPC list. Some are more than 12 digits, and some with less than 12 digits. I need to make sure there are 12 digits in each UPC. I know how to count using LEN, strip leading zeros of those UPCs that are >12 digits using RIGHT.
What I need now is any number with less than 12 digits, such as 000123, add a 4 to the beginning (4000123) and fill in '0's in between the 4 and the short UPC number to make 12 digits, 400000000123. They vary from 1 to 13 digits.
I have some numbers around 200 numbers which are not same digits i.e. if 1st number is 7 digits, 2nd number is of 10 digits.
Like this even if i have a number of 1 or 2 digits then all number should have equal digits i.e. in 200 numbers if one numbers is of 13 digits then all the numbers should be 13 digits.
To do this first i am doing this to the right align & comparison all numbers & taking the highest digit number & pre-fixing the other numbers with zeros’ so that all number are equal in number of digits. This is taking huge time.
I want to make a macro or any easy method so that all should have equal no of digits.
I want that if 200 numbers are pasted in the column E i.e. from E2 to E201 then all should be converted to equal digits number by prefixing zeros & should appear in column G from G2 to G201.
And after converting them it should be prefixed with D/ OR D/ABC:
This will be present in B2 cell i.e. this cell will be blank always. And once I have any thing in that cell that should be prefixed to the converted numbers in the column G & they should appear in Column I.
And again the numbers in column G should be prefixed with the content in B2 & should appear in column K in the Ascending order sorted.
Suppose if , I have 500 numbers then they should be converted automatically to equal digits & appear in Column G & prefixed with the contented in cell B2 should appear in Column I & sorted series in ascending order with prefixed with cell B2 in the column K.
And if I have 15 numbers only then it should do the same job easily. Here the numbers of numbers are not defined.
All this should be get done on click of the command button.
I have a macro that copies long decimals (11 places) from an Excel file to a CSV file. However, the long decimals often get truncated from 11 places down to 3 or 4. I've tried a number of different coding methods to combat this, the most recent and most successful of which is shown below
I am trying to filter my excel sheet based on certain digits in a column of part numbers. The part number has 10 characters. I would like to filter it so that all part numbers where the 4th character is the number 5 or 7 is listed and where the 5th character is a zero. (i.e. R4X5831310 is a part number where 5 is the 4th character; I would like the filter to show this part number)
I need a formula to drag down the attached that will place zeros infront of any numbers that don't have 9 digits. so if a part number consists of 6 digits then i need 3 zeros in front of it, if a part number consists of 9 digits then i dont need any zeros proceeding it.
I have got a list of numeric abbreviations, for instance 10739011/21/31/41. What it should really display are the numbers 10739011, 10739021, 10739031 and 10739041 (the first six figures stay the same). All the numbers in my list are 8 figures long. I want to change the list from the list seperated by the backward slash to the complete numbers. I have uploaded an example of the list with backward slash between the numbers. Is there a way that Excel can automatically change these numbers to the full numbers?
Because all the numbers are 8 figures long, I thought the first 6 figures of the 1st number can be copied and those 6 figures pasted before the other two figures after the backslash. Auto Merged Post Until 24 Hrs Passes;sorry, pressed OK too quickly. The problem is that there are sometimes 4 numbers in the cell, sometimes 6 and once three. I would like Excel to complete all the numbers in the cell and then move on to the cell underneath it and so on. Also, I would like each number to have it's own cell.
I have a list of numbers in Column A that I always copy into another sheet. The problem I have is that some of these numbers end in "+" and I can't use them when it has that. I have to go through and one by one take out the plus. I was wondering if it was possible to copy only the numerical values to a new column?
Example
Original What Im Looking For
4 4 56 56 8+ 8 5 5 90 90 2 2 4+ 4 45 45 1 1 67 67
Auto Merged Post Until 24 Hrs Passes;Actually I just figured it out. I did a text to columns with a + sign as the separator and it worked.
I have about 10000 cells of varying length in text and numbers but they all end with numbers on the ends of them. Using text to columns doesn't work because they're all different lengths and it cuts them off in the wrong place.
Is there a formula I can use that will return only the text from these cells and remove the numbers. It would definitely save me time from individually deleting the numbers at the end.
I'm trying to clean up a very large list of last names. Only one individual cell, but that cell includes numbers, decimal points, and spaces inbetween the numbers. All I want left in the cell is the last name. I have just under 100,000 to do! How would I go about this? Using Excel 2007.....
