I need a code to open a file automatically based on file name, for example if the active file name is "trial", then it need to open another file named "trial1" based on which the macro will run, because I have two set of files and I want to compere daily with two users. for example the file names in Set a- iron, cement, stone, sand where as the set b-iron1, cement1, stone1, sand1
View 1 RepliesI need to open an excel file based on a date mentioned in the file name, but minus 1 day. The file name is composed with Statistics_date_time.xls
Example: statistics_20140423_142754.xls
Once I need to open the file (only in the mornings), it has to be the one from the previous day to see the yesterdays performance. How can I create a macro that will look at the date in the file and take the one from yesterday?
This will be a part of a macro I'm making. The rest of the macro will just format the file and combine a few ones from different departments.
I have a tool file which contains Excel VBA codes. When I click button it asks to select a file. I want that anytime I click the button the dialogue box should open in the folder containg the tool.,
View 1 Replies View RelatedI am trying to open a website, then for excel to download the csv file, then for it to save it in a specific folder under a specific name and file format (excel).
I am successful at opening the website with the following code, but how to do the rest.
Sub Searchez()
Dim IE As Object
Set IE = CreateObject("InternetExplorer.Application")
IE.Navigate "http://quote.morningstar.ca/Quicktakes/stock/keyratios.aspx?t=clwr®ion=USA&culture=en-CA&ops=clear" 'load web page google.com
IE.Visible = True
While IE.Busy
DoEvents
Wend
'IE.Navigate2 "javascript:SRT_keystuts.exportcsv()"
'this is the name of the download link as from when i hover my pointer over download link.
End Sub
I'm working on the following
Workbooks.Open Filename:= _
"D:CommondataIBMmainBRANCHBURG-PRODUCTS-BOM-ALUMINUM-UPDATE-" & Ucase(Format(DateAdd("y", 0, Date)), "YYYY-MM-DD")&".XLS"
ChDir "D:CommondataIBMmain"
ActiveWorkbook.SaveAs Filename:= _
"D:CommondataIBMmainBRANCHBURG-PRODUCTS-BOM-ALUMINUM-UPDATE-NAFTA.XLS", _
FileFormat:=xlNormal, Password:="", WriteResPassword:="", _
ReadOnlyRecommended:=False, CreateBackup:=False
ActiveWindow.Close
Date: 2009-06-03
What I'm trying too do is open a file, make an exact copy and save it under a new file name.
My problem is in the date formula the day is not always the same. In the sample case it's 03 at other times the day will change.
is there a way too get this too work irregardles of what the day might be?
I want to open a specific sheet and refresh only said sheet when i open another sheet for example x.xls
So opening x.xls will automatically open y.xls
I've tried this in the workbook code area but it doesn't do anything.
[Code] .....
Actually i've downloaded Tracking report of my SPO and this report is on 4-5 csv files (1 file per week). I have to gather data from these 4 files into one Worksheet. I have to do this with command button on my worksheet; with Open file dialogue box (i want to locate the csv files).
CSV files are something like that (I need only first 4 columns):
ABCDE1Name MSISDN Date Location MapLink 2M. Younus Safi "923***550577" "2011-10-07 20:36:18" "ACB Tower Badragah Chakwal. Badraga" "http://asdf.com" 3M. Younus Safi "923***550577" "2011-10-07 19:36:26" "ACB Tower Badragah Chakwal. Badraga" "http://asdf.com" 4M. Younus Safi "923***550577" "2011-10-07 16:39:58" "ACB Tower Badragah Chakwal. Badraga" "http://asdf.com" 5M. Younus Safi "923***550577" "2011-10-07 15:37:23" "ACB Tower Badragah Chakwal. Badraga" "http://asdf.com" 6M. Younus Safi "923***550577" "2011-10-07 14:37:05" "ACB Tower Badragah Chakwal. Badraga" "http://asdf.com"
and my Worksheet is like that (With a command Button):
I want to import first 3 columns of csv file on first 3 columns on my worksheet; leave 2 columns blank and then import the 4th column... now for example i have done importing data from 1st csv file and the data is on 50 rows.. i click the command button again, locate the 2nd csv file.. do the same thing (import 1st 3 columns, 2 blank, then 4th) --from 51st Row-- and so on...
ABCDEF1NameMSISDN DatedBlankBlank Location2
3
4
5
6
7
I need a VB code to open excel files located in a path (fixed path) by providing a part of file name through a input box
for ex: I have some files located in my local drive as below
1. colurgreen.xls
2. colurred.xls
3. colurblue.xls
I need a input box asking for file name and I input "green" or "red" or"blue" and it should open the resp file.
I have the need to be able to open a closed file to archive some data from a
current file.
what coding i need to be able to kick the "open file" bit off?
I do routine tasks every day which involves opening 3 different files and pasting data into my main file. The data is always in the same format, and the 3 files are saved in the same location (3 different folders through). The 3 files are saved each day and the naming convention is constant, with only the date changing. For example, the files are always saved in C:My Documents and the files are called test_05.02.2013.xls. Tomorrow the file will be called test_06.02.2013.xls and so on.
So each day I will be rolling a file forward and I want to bring in the info from each of these files based on the new day.
How to do 1, and I will do the others (because the concept will be the same).
I am using the following code to open an existing file whose name is in cell A1. I want to modify the code so that if the spreadsheet does not exist, a template (Costing.xlt), in the same director, is opened and then saved with the name in cell A1.
Workbooks.Open Filename:="C:Spreadsheets" & Range("A1") & ".xls"
I've got a couple of formulas in a workbook which lookup values in another workbook. When I reopen the initial workbook the formulas results come back as errors (i.e. #VALUE!) unless the workbook it is looking at is also open. This is not desirable, does anyway know how I can lookup values in another workbook which are not open? The formula which is causing me problems is as follows:
= SUMIF( 'H:Infozoom[2006-01_assy.xls]New Table1'!$F:$F,$A8,'H:Infozoom[2006-01_assy.xls]New Table1'!$AH:$AH)/60
I've encountered a bit of an odd one. I am opening a tab delimited file, which has been sved as an xls. When I open from file manager, it opens correctly. When I open from Excel, I have to go through 3 screen dictating how the data is set up, and the end result is that a couple of the numbers come through as text, rather than numbers.
Failing an explanation - how do you open workbooks as file system objects - currently I am opening them using
Workbooks.Open Filename:=wb.Path & "/" & ws. Range("B1").Value
If I open them by mimicking the FM, perhaps it will work OK.
When it opens the desired file, it increments the file name by 1 each time it is opened (via the macro).
Example;
The first time it is opened you see the file name in the header read "P'Binder L&T Pages" for a moment, then it changes to "P'Binder L&T Pages1"...
I close the file and open it again (via the macro), and see the file name in the header read "P'Binder L&T Pages" for a moment, then it changes to "P'Binder L&T Pages2"...
The file name continues to increment on every opening until the PC is rebooted, then it starts at 1 again.
Sub OpnLTpages()
Dim wb As Workbook
Dim AlreadyOpen As Boolean
AlreadyOpen = False
For Each wb In Workbooks 'Scan open workbooks
If wb.Name = "P'Binder L&T Pages.xls" Then ........................
How to open files based criteria in cells value?
[Code] .....
is there a way using VBA code that you can have a file path entered into cell 'A1'
and then when you run the macro, the file referenced in the file path in cell 'A1' will open,
The code below opens a window which allows the user to select a file to open. Apparently, it starts in the directory of the file containing the macro. How would I modify this to open in "M:Archived PO ResponsesProcessed"?
View 3 Replies View RelatedI want to create a Macro to open a file based on the data of a particular cell to update the data for macro file from that file.
For example I have 3files named Dept1, Dept2, Dept3 and I have one more file named Cost Sheet which contained macro and based on the cell D2 of my macro file I need to open the particular file i.e Dept1, Dept2 or Dept3 and the updated procedure and cell ranges are same for all file
I have the current code that opens our raw data file and copys it into my workbook. However it now turns out the file is saved everyday as a new file with todays date on the end. Here is my current code:
Sub CopyRaw()
Application.DisplayAlerts = False
Sheets("PROD_SELECTION").Visible = True
Sheets("PROD_SELECTION").Select
ActiveWindow.SelectedSheets.Delete
Application.DisplayAlerts = True
[Code] .....
Todays file is now in the name "I:SalesSales and MarketingMarketing List Product Selection Details (20140416)"
I know i can do this somehow using the Date function but the closest I have got is using
"YEAR(NOW())&RIGHT(MONTH(NOW())+100,2)&DAY(NOW())"
To generate todays date like so: "20140416" but I dont know how to get that into my code correctly so i open the file with that on the end.
I have files saved as a code, then a customer name. I'm trying to write some more code to open the file only based on the initial code.
For example the file name is X090000 TEST
This doesn't work;
Open("V:\\\" & oldFileName & "*" _
& ".doc")
I would like to run a macro that is going to open a file (Test.xls) Simple so far....
However, this file is 1. stored every month in a different folder (eg: 200709,200710, etc..) and the file is named according to the month (eg: Test09.xls, Test10.xls, etc...)
In my excel book, I did created two cells which I already use to save a document according to those cells. One cell with Acct Period (200710) and another one with the month (10).
I have tried the following formula with no success:
OpenWorkbook "\pathpathpath" & Range("Accout Period") & "Test" & Range("Month") & ".xls"
I managed to create some code that will connect to a workbook and take the data from there.
It is kind of SQL mixed with VBA. I just got this by finding it in google (I don't have the link handy now).
What the file does, is it will take 2 columns from a workbook called "Test.xls" and then take out 2 columns "Name" and "ID".
The only thing is, this is only a test and not the actual files I need to open. the files are always saved on the same folder, but the name is the day of the export of it. So when I export a file today, it will get 2014.09.10.xls. The sheet (only 1) will also get that name.
How could I change the below code that it will take that file based on today's date and read from the sheet with today's data?
VB:
Sub sbADO()
Dim sSQLQry As String
Dim ReturnArray
Dim Conn As New ADODB.Connection
Dim mrs As New ADODB.Recordset
Dim DBPath As String, sconnect As String
'DBPath = ThisWorkbook.FullName
[Code] ....
I have a workbook were a user will write down some info. Then I need to copy that data to a second workbook located anywere in the Hard drive. i used the function "GetOpenFilename" or the "Application.dialogs(xlopenfile) to ask the user where is the file (and open it). Now I need to get the name of that file. How can I get it?(the name of the file the user selected to open). P.S. I saw there is somewhere a "Print" function to copy data from a workbook to another closed workbook. I was planning to have both workbooks open and then just use several lines like:
View 4 Replies View RelatedWhat I would like to do is to open an excel workbook from a bat file in dos with one arguement.
so something like
start c:lacklist.xls 2315t
Once the blacklist.xls is opened I would like to have the macro to save the excel file as a csv file ignoring all the prompts and use the argurement 2315t as the directory to save it to on the j drive ie save to j:2315tlacklist.csv. Then close the workbook and continue with the rest of the commands in the bat file.
I'm guessing I have to use GetCommandLineA to read in the arguement but I can't find anything on the net that gives a clear explanation of how to use it.
I'm on excel 2010 and I have a small group excel files I open everyday. Most of the files are static in name and location. I've got a macro created to open those files, which works fine with workbooks.open and the file path.
There are two report files I want to incorporate into my macro of workbooks to open. The files are created weekly and the files names have the following format: "Report Name (YYYY-MM-DD).xlsm". I don't want to use the file's last modified date because older files may get edited after the more recent ones are created. The files are also not always created on the same day, so the solution needs to be flexible enough to not refer to a specific day of the week or anything.
Macro open an excel file based on the latest date found in filename.
I have a requirement to download a lot of historical data files from the archieve of an website. The url goes something like this: [URL]....
This downloads file for 21022014 ie. 21-Feb-2014. I need to be able to have a facility to have a selection criteria on my user form (in excel) where I specify a date range and the macro automatically downloads all the valid excel files available within that date range (files for Saturday, Sunday and some holiday dates will not be available in the website archive database) one after the other (like at single clcik of button) into a specific location (predefined viz.. c:/Users/EOD files/) on my laptop. Best would be if I am able to select the save location run time by using a 'Browse' like feature where I go and choose my local laptop folder...same type when we try uploading a file from our laptop to the web..
I have attached the file I am working on. I am attempting to create a link to an external file based on the value of cells in column A. Then I would like to simply copy the formula down, lets say in Column B, the rows and as I do the external file reference will change depending on the value within the cell in Column A. I hope that I am making sense.
I am using Windows Vista with Excel 2007. The files will all be within the same file folder, however, there are hundereds of files so I won't be able to open them all for the indirect to work.
I have a Workbook that already has a macro in it that will generate multiple sheets based on certain criteria.
For each of these newly generated sheets (numbered 1-6 in the attached example), I need to be able save each of them to a PDF file based on a unique name contained in a certain cell (in this case, each named is referenced in cell Q1 of each sheet). As such, I should end up with 6 pdfs based on the attached sample files.
The PDFs would ideally need to be landscaped and should be just 1 page per sheet.
In my attached sample workbook, you'll notice that I have a "PracticePrint" macro that doesn't quite get the job done. One other criteria involves not printing any sheet with the characters "1010" in it (my PracticePrint macro is setup to do that, but it fails to do much else).
I want to create a macro that will “open the look in list” and stop so I can pick a file to open. I’ve tried to use “record a macro” and “ctrl-o”, but the record a macro won’t stop until I pick a file or cancel the file list. I also tried to use “o” in the short cut key box
View 5 Replies View RelatedVBA coding for automatically saving an excel file as another file using the current date as part of the file name together with "32ga" as a constant add-in. I also what this macro to run at a particular time of the day let say 00:20hrs. The excel file i want to save as is always open . It has data that changes every 24-hrs.
View 1 Replies View Related