I want to create a Macro to open a file based on the data of a particular cell to update the data for macro file from that file.
For example I have 3files named Dept1, Dept2, Dept3 and I have one more file named Cost Sheet which contained macro and based on the cell D2 of my macro file I need to open the particular file i.e Dept1, Dept2 or Dept3 and the updated procedure and cell ranges are same for all file
I am using the following code to open an existing file whose name is in cell A1. I want to modify the code so that if the spreadsheet does not exist, a template (Costing.xlt), in the same director, is opened and then saved with the name in cell A1.
Workbooks.Open Filename:="C:Spreadsheets" & Range("A1") & ".xls"
is there a way using VBA code that you can have a file path entered into cell 'A1'
and then when you run the macro, the file referenced in the file path in cell 'A1' will open,
I would like to run a macro that is going to open a file (Test.xls) Simple so far....
However, this file is 1. stored every month in a different folder (eg: 200709,200710, etc..) and the file is named according to the month (eg: Test09.xls, Test10.xls, etc...)
In my excel book, I did created two cells which I already use to save a document according to those cells. One cell with Acct Period (200710) and another one with the month (10).
I have tried the following formula with no success:
OpenWorkbook "\pathpathpath" & Range("Accout Period") & "Test" & Range("Month") & ".xls"
I have an existing spreadsheet with a column of strings (actually VIN numbers). These numbers correllate to a bunch of text files, that can exist in one of three folders (UsernameDesktop1, 2, or 3) on my desktop. What I need the macro to do is:
1) get the filename from A2 (A1 is a heading row)
2) Find the appropriate text file in one of the three folders
3) Put the folder name into I2
4) Scan the text file for some strings, and copy some data that follows those strings into J2:O2 (I can handle programming this)
5) Close the text file
6) repeat above for the remainder of filenames (about 1800 files)
I've encountered a bit of an odd one. I am opening a tab delimited file, which has been sved as an xls. When I open from file manager, it opens correctly. When I open from Excel, I have to go through 3 screen dictating how the data is set up, and the end result is that a couple of the numbers come through as text, rather than numbers.
Failing an explanation - how do you open workbooks as file system objects - currently I am opening them using
Workbooks.Open Filename:=wb.Path & "/" & ws. Range("B1").Value
If I open them by mimicking the FM, perhaps it will work OK.
I need to open an excel file based on a date mentioned in the file name, but minus 1 day. The file name is composed with Statistics_date_time.xls
Example: statistics_20140423_142754.xls
Once I need to open the file (only in the mornings), it has to be the one from the previous day to see the yesterdays performance. How can I create a macro that will look at the date in the file and take the one from yesterday?
This will be a part of a macro I'm making. The rest of the macro will just format the file and combine a few ones from different departments.
I'm using excel to parse txt a file with account numbers in it. If it finds a dodgy number I want it to delete the entire line in the text file. I have manage to write the code that opens the file and locates the dodgy numbers, however I'm not sure whether it is posible to select the line and delete it.
View 6 Replies View RelatedI am trying to open a txt file, but I get an error message that says "Run-time error '52': Bad file name or number. The file name is correct. I tried two ways to pass the name -- as a variable and from Application.GetOpenFilename("Text Files (*.txt), *.txt"). The line where VBA complains is "Open fileToOpen For Input As #InFile"
View 3 Replies View RelatedI have an userform where the user browse to input an text file, how do i open the text file from the given path in and excel format in VBA?
View 8 Replies View RelatedI am writing a macro that creates a text file and inputs data into it with a for loop. Is it possible to actually open the text file window after entering the data so that the user sees whats inside the text file?
View 8 Replies View RelatedI need a code to open a file automatically based on file name, for example if the active file name is "trial", then it need to open another file named "trial1" based on which the macro will run, because I have two set of files and I want to compere daily with two users. for example the file names in Set a- iron, cement, stone, sand where as the set b-iron1, cement1, stone1, sand1
View 1 Replies View RelatedI'm trying to use Excel to build a text file based on values from certain cells in Excel 2010. This is based partially off of static text that never changes and variables that will need to change. For example, I want Excel to output a text file that has the following text: The red fox jumped over the $X twice. I would want $X to be replaced by the value of A1 of the active worksheet. I will also have several lines like that, so it won't just be a single line, but anywhere from 20 - 120.
View 1 Replies View RelatedI have created a macro that auto generates SQL code based on user input from a worksheet. The SQL script is written to a text file. I would just like to visually open the text file with notepad when the macro is finished executing.
View 2 Replies View RelatedI have a large text file (greater than 64k lines) which I need to import into excel. I only need anything imported from the text file that is for dates I specify. So I would like to run a line by line query and only import the lines I need.
The dates are always in position 43-50 (dd-mm-yy) in the text file itself, so the code would have to look at that section, see if the date is within the range specified and only import if it is (and then move onto the next line).
I work for a company that has about 650 locations. Each location has a location manager that is responsible for submitting a Performance Review spreadsheet for all the employees at their location.
Currently I have an Excel file that has all employees/locations. One of the columns on my spreadsheet is "Location ID"...which is literately a number we've assigned to our Locations. I have an Excel template saved that I'd like each Location to open into.
Can someone help me? I need each location to be it's own spreadesheet...which I have a template created already. I'd prefer to find an automated way to do this...rather than manually creating 650 spreadsheets.
I'd prefer to do this in anoter application, such as MS Access, but senior management already made the decision this will be done in Excel...so I'm stuck with what I got.
I am writing some code to open up a file and use the text import as the files are data files. i currently have
View 4 Replies View Relatediam trying to open a workbook from a forms textbox.text value. i have got this so far
Private Sub cmdOpenProject_Click()
Workbooks.Open Filename:="C:Documents and SettingsOwnerDesktopExcelStuffTextBox1"
End Sub
have also tried
Private Sub cmdOpenProject_Click()
Workbooks.Open Filename:="C:Documents and SettingsOwnerDesktopExcelStuffTextBox1.text"
End Sub
1. Open a text file from a directory on my computer
2. Feed the data into a Excel spreadsheet
3. Parse the text from the text file into columns
an example of some of the stuff in the text file (its all fake btw )
192.168.1.216,,,
J2MARTIN,20/08/1999,8:57:27 a.m.,
372,http://www.microsoft.com/isapi/redir.dll?,,
192.168.1.216,,,
J2MARTIN,20/08/1999,8:57:27 a.m.,
326,http://home.microsoft.com/,,
192.168.1.216,,,
J2MARTIN,20/08/1999,8:57:29 a.m.,
37014,http://www.msn.com/default.asp?,,
Is it possible to feed all this data into excel into seperate rows and then start parsing it into columns of
IP Username Date Time KbUsage URL
I have a folder that has a bunch of text files in it with numeric names (they are store numbers 2, 3, 165, 188, etc...). I need to open those files (in excel), run a macro on them (this portion of the macro has already been created), and then save them with the same name as the txt file but in an xls format and close. It would be great to have the whole folder process automatically but I am willing to start small. Further, I'd like it to not ask for a filename, and I don't want to see the SaveAs dialog box. So far I have been able to get the macro to run through the my processing of the text file all the way to the SaveAs portion, but the code in my macro opens the SaveAs box and puts the filename of the txt file in the file name box in quotes with the txt extension. Below is the code.
Sub Macro3()
sFile = Application. GetOpenFilename( _
fileFilter:="Text Files (*.txt), *.txt", FilterIndex:=1, _
Title:="Open Workbook")
Workbooks.OpenText Filename:= _
sFile, Origin:= _
xlWindows, StartRow:=1, DataType:=xlFixedWidth, FieldInfo:= Array(Array(0, _
1), Array(5, 1), Array(26, 1), Array(35, 1), Array(39, 1), Array(46, 1), Array(51, 1), Array _
(58, 1), Array(75, 1), Array(87, 1), Array(91, 1), Array(97, 1), Array(99, 1), Array(111, 1) _.....................
How to open files based criteria in cells value?
[Code] .....
The code below opens a window which allows the user to select a file to open. Apparently, it starts in the directory of the file containing the macro. How would I modify this to open in "M:Archived PO ResponsesProcessed"?
View 3 Replies View RelatedI have the current code that opens our raw data file and copys it into my workbook. However it now turns out the file is saved everyday as a new file with todays date on the end. Here is my current code:
Sub CopyRaw()
Application.DisplayAlerts = False
Sheets("PROD_SELECTION").Visible = True
Sheets("PROD_SELECTION").Select
ActiveWindow.SelectedSheets.Delete
Application.DisplayAlerts = True
[Code] .....
Todays file is now in the name "I:SalesSales and MarketingMarketing List Product Selection Details (20140416)"
I know i can do this somehow using the Date function but the closest I have got is using
"YEAR(NOW())&RIGHT(MONTH(NOW())+100,2)&DAY(NOW())"
To generate todays date like so: "20140416" but I dont know how to get that into my code correctly so i open the file with that on the end.
I have files saved as a code, then a customer name. I'm trying to write some more code to open the file only based on the initial code.
For example the file name is X090000 TEST
This doesn't work;
Open("V:\\\" & oldFileName & "*" _
& ".doc")
When I export data from .csv or .tsv file to .excel file then all the preceding zero's disappear and the code 0010 display's like 10.
I know I can manually import data from csv to text(option "fromtext" in excel) but i want to do it automatically.
I have below code apearing couple times in my macro and I'd like to make a variable.
Plese see belowe
Workbooks.OpenText Filename:= _
"S:ReportsMy ReportsGuidefilename20080430", Origin:=xlMSDOS, _ ' filename should be another variable as it referes to different files
StartRow:=1, DataType:=xlDelimited, TextQualifier:=xlDoubleQuote, _
ConsecutiveDelimiter:=False, Tab:=True, Semicolon:=False, Comma:=True, _
Space:=False, Other:=False, FieldInfo:= Array(Array(1, 1), Array(2, 1), Array( _
3, 1), Array(4, 1), Array(5, 1), Array(6, 1), Array(7, 1), Array(8, 1), Array(9, 1), Array(10 _
, 1), Array(11, 1), Array(12, 1), Array(13, 1), Array(14, 1), Array(15, 1), Array(16, 1), _
Array(17, 1), Array(18, 1), Array(19, 1), Array(20, 1), Array(21, 1), Array(22, 1), Array( _
23, 1), Array(24, 1), Array(25, 1), Array(26, 1), Array(27, 1), Array(28, 1)), _
TrailingMinusNumbers:=True
I managed to create some code that will connect to a workbook and take the data from there.
It is kind of SQL mixed with VBA. I just got this by finding it in google (I don't have the link handy now).
What the file does, is it will take 2 columns from a workbook called "Test.xls" and then take out 2 columns "Name" and "ID".
The only thing is, this is only a test and not the actual files I need to open. the files are always saved on the same folder, but the name is the day of the export of it. So when I export a file today, it will get 2014.09.10.xls. The sheet (only 1) will also get that name.
How could I change the below code that it will take that file based on today's date and read from the sheet with today's data?
VB:
Sub sbADO()
Dim sSQLQry As String
Dim ReturnArray
Dim Conn As New ADODB.Connection
Dim mrs As New ADODB.Recordset
Dim DBPath As String, sconnect As String
'DBPath = ThisWorkbook.FullName
[Code] ....
Is there a way to open a text file from Excel 2010 and specify that I want it in .xls format?
I am working in compatibility mode, and expected that when I opened a text file from code within an xls file, the text file would have 65,536 rows, but it has 1,048,576. This causes a problem when we try to copy the sheet with the data from the text file, and insert the sheet into our xls workbook. See code below. The error is: Run-time error '1004': Excel cannot insert the sheets into the destination workbook, because it contains fewer rows and columns than the source workbook..
I know I can get the data other ways (such as copying and pasting only the cells containing data) but I was hoping to make minimal changes to the code below as I will have to make it across several templates. Specifically, I was hoping that there was a qualifier I could add to the Workbooks.OpenText statement after "Tab:=True" - Perhaps something about opening the text file in File Format 56. However I have not been able to find out how to do that.
Code:
.....FileToOpen = Application.GetOpenFilename("All Files (*.*),*.*,GeoTAC Files (*.ctf),*.ctf, _
Text Files (*.txt),*.txt,Excel Files (*.xls),*.xls", 1, , , False)
Workbooks.OpenText Filename:=FileToOpen, _
[Code].....
I have a tool file which contains Excel VBA codes. When I click button it asks to select a file. I want that anytime I click the button the dialogue box should open in the folder containg the tool.,
View 1 Replies View RelatedI'm on excel 2010 and I have a small group excel files I open everyday. Most of the files are static in name and location. I've got a macro created to open those files, which works fine with workbooks.open and the file path.
There are two report files I want to incorporate into my macro of workbooks to open. The files are created weekly and the files names have the following format: "Report Name (YYYY-MM-DD).xlsm". I don't want to use the file's last modified date because older files may get edited after the more recent ones are created. The files are also not always created on the same day, so the solution needs to be flexible enough to not refer to a specific day of the week or anything.
Macro open an excel file based on the latest date found in filename.