How To Plot Comparison Of Only 3 Points Against 9 In Graph

Mar 27, 2014

I'm stuck at a point in a graph that I am creating. Attached is as far as I have gone and now i'm having a gap on how to take the 2006, 2007 which is already in graph and add in how these years compare to guidelines visually in the same graph?

for instance ratings 1-9 are grouped in guidelines 1-4, 5-7 etc. How do i add in the 3 guides against each point? I have thought about adding a secondary axis but not how best to demonstrate the range of 1-4 to appear behind or above those points?

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This may sound like a dumb question, but hang with me. I have two series in an xy plot. One is a line (withOUT markers) and one series is just markers (no line).

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Format and Code for the Date Labels:
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Rainfall (mm)
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[Code].....

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for example if i have

X - Y
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Nov 20, 2013

Given 100 samples, to calculate: numbers of hours spent on study is dependent on numbers of hours spent on social networking site.

x (social networking site)
y (study)
x^2

xy

6
4
36
16
24

[Code] .......

SUMMARY OUTPUT

SUMMARY OUTPUT

Regression Statistics

Regression Statistics

Multiple R
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[Code] ....

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Jun 5, 2008

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Sub AddDataToMyChart( Name As Range, XData As Range, YData As Range)

With ActiveChart
With .SeriesCollection.NewSeries
.XValues = XData
.Values = YData
.Name = Name
End With
End With

End Sub
Sub Test()

Dim lngTopRow As Long
Dim lngBottomrow As Long
Dim lngCol As Long

lngTopRow = 3
lngBottomrow = 8
ActiveSheet.ChartObjects(1).Activate

With ActiveSheet
For lngCol = Range("D2").Column To Range("h2").Column Step 2
AddDataToMyChart .Cells(2, lngCol), .Range(.Cells(lngTopRow, lngCol), .Cells(lngBottomrow, lngCol)), _
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Next
End With

End Sub
...

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the Data:

0
0
0
0
0
1.4343
0
0
0
0
0
0
0
0
1.4332................

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I awas trying to make a couple of plots, but they were not llooking like some examples I have.

In the OreDep-updated file attachment is my data I needed to use. I needed to make 2 plots:

Plot 1: Resource Grade (log scale) against the proportion of deposits (linear scale)

Plot 2:Tonnage (log scale) against proportion of deposits (linear scale)

This was done with my old data that is shown in the Macca.xls attachment.

They are meant to cumulative proportion plots. As a line or scattergram. An example of what they are meant to look like is at: http://www.nbmg.unr.edu/dox/ofr962/c11.pdf on Page 4 and 5.

shg managed to make them look like I wanted with the log normal smooth line too.

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C9 39.65 653.95 5.28 163.56 99.56 14.49 ... ...
E9 7535.92 21500.56 2835.88 3122.98 7225.34 5371.25 ... ...
G9 111568 298021 12940 31645 181797 36996 ... ....
...

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I've been trying to work out a code for a while now to plot some series in rows on a graph. The wonderful Mr Pope helped me with one before but for series in columns but i just don't seem to understand it enough to use it for this problem. the graph already has 2 series plotted (called the envelope) so i have to use seperate series to plot the data.

Basically the name of series is down column A
but the range is from E1 to Y1
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Sub adddatatopsd(Name As Range, XData As Range, YData As Range)
With ActiveSheet.ChartObjects(1).Chart
With .SeriesCollection.NewSeries
.ChartType = xlColumnClustered
.XValues = XData
.Values = YData
.Name = Name
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End With
End With
End Sub...........................

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MINMAX
ANF18.6%19.8%
AEO7.8%21.0%
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Attached File : A1.xlsx‎

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Mar 21, 2014

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Jun 11, 2006

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Feb 19, 2014

I have two rows of data, each row also have similar data. I need to find the number of matches that the two lines For example :

7,7,K,A,8,7
K,6,7,7,A,9

To reach the conclusion I need to build six such functions:
=1*(COUNTIF($A$65:$F$65,A66)>=COUNTIF($A66:A66,A66))
=1*(COUNTIF($A$65:$F$65,B66)>=COUNTIF($A66:B66,B66))
=1*(COUNTIF($A$65:$F$65,C66)>=COUNTIF($A66:C66,C66))
=1*(COUNTIF($A$65:$F$65,D66)>=COUNTIF($A66:D66,D66))
=1*(COUNTIF($A$65:$F$65,E66)>=COUNTIF($A66:E66,E66))
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The result is 4

Is there a single formula that will give the result ?

Another question, is there a formula that I can compare to the principle of one line against the 20 lines ?

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