I am having problems in Excel 2007 using hyperlink formula to jump to a different worksheet in the same workbook.
Filename: Model Variables.xlsx
Worksheet to seek: Org Structure
Cell to seek: A1
Formula tried: =HYPERLINK("[Model Variables.xlsx]Org Structure!B4", "My Cell on different sheet")
Error: Reference is not valid
I used the vba recorder to get the code and didn't change one thing, and now I am getting an error when i click on the command button to execute the code.
error
Run time error 1004
The sort reference is not valid. Make sure that it's within the data you want to sort, and the first Sort By Box isn't the same or blank.
Row 1 = column headings
row 2 is the first set of data, *****, however, most of the data in the column is blank. There are only 2 options, (Yes) or blank, and I am trying to sort the sheet so all the (Yes) appear at the top
when i did the macro recorder, it seemed to work.
I am trying to create a pivot table on a new sheet names as 4x4
I am getting following error:
Error : 1004
Reference Not Valid
I am not sure where is the problem. I have generated this code by using macro recorder and just changed the source and destination of the pivot generation code.
I have the following macro, which is assigned to ctrl+shift+h to allow users to make a list and to insert hyperlinks to other sheets that have more details than the list can show:
Code:
Sub linker()
Dim strDocument As String
Dim strSheet As String
Dim strAddress As String
Dim strLink As String
[Code] .......
I was surprised to see that even if the contents of the active cell is not a valid sheet name in the target document, the link is still inserted without error. If the link is subsequently clicked, the target document will open and an "invalid reference" error box will appear.
Is there any way to check whether the contents of the cell constitutes a valid sheet name in the target workbook at the point at which the hyperlink is created, without opening up the target document?
I have a list of University courses listed in Sheet1. Column A contains a unique course code. If there is a problem with a course, a second worksheet (called Anomalies) contains the same unique course code with description of the problem(s).
What I'm trying to do is: in Sheet 1, create a hyperlink to the relative cell in Sheet 2 that shows the course code and description. I've gotten close, but am not sure how I can do this without having to update two formulas. In short, I can't find a way to combine the two formulas.
What I've done is the following: in Sheet 1, column B, created a HYPERLINK formula, thus: =HYPERLINK("#"&CELL("address",INDIRECT(C54)),A54)
Column C contains a formula to lookup the relative position in the Anomalies worksheet, which can be referenced back to the HYPERLINK formula, thus:
=("Anomalies!A"&MATCH(A54,Anomalies!A:A,0))
Sheet1 is fairly static, but Sheet2 (Anomalies) is being updated all the time. I could just hide column C and then column B will update based on that, but I'd prefer a cleaner solution.
I've tried joining the two formulas, by replacing the INDIRECT part with the second formula, as per the following: HYPERLINK("#"&CELL("address","Anomalies!A"&MATCH(A54,Anomalies!A:A,0)),A54)
but I get an error.
I am using EXCEL 2007. When I refresh the individual pivot tables, I don't get any error. But when I click on Refresh all Pivot, I get a Reference if not valid error. The source for my pivot is referencing to another workbook. Why is there this error and how can I resolve it?
View 4 Replies View RelatedI created an add-in for Excel 2003 by following your site's instructions, substituting my own subroutine's name for "MyGreatMacro" (for the purposes on testing all it does is spit out a MsgBox). I then put the resulting xla file on a network drive and went through the standard process for installing an Addin :
Tools -> Addins -> Browse for the file and hit ok, check it off, etc
This works perfectly fine when i try to install on my own machine, but when I try on other user's machines I get an error message stating that the xla file is not a valid Addin. Excel's error message in this case is about as unhelpful as they come.
I've been trying to create pivot table in excel 2010. Unfortunately I've been getting this message "Data source reference is not valid"?
View 2 Replies View RelatedI successfully created two PivotTables two days ago, but when I added more rows of data to the source worksheet I could not refresh either PivotTable view. So after much frustration, I deleted both worksheets and again tried to create a new PivotTable using the wizard. I keep getting this error, and have no idea what it is telling me so that I can go about fixing it:
"The PivotTable field name is not valid. To create a PivotTable report, you must use data that is organized as a list with labeled columns. If you are changing the name of a PivotTable field, you must type a new name for the field."
When I open my Excel workbook, I get the following error:
Removed Feature: External formula reference from /xl/externalLinks/externalLink1.xml part (Cached values from external formula reference)
I am asked if I want to recover the contents of the file.
I was able to get VBA to post this relative reference, which sticks the formula
=DATE(YEAR($D2),MONTH($D2)+6, DAY($D2)+1) into a cell in Col J.
All fine and dandy, works as it should with this formula.
Code:
.Cells(Row, "J").FormulaR1C1 = "=DATE(YEAR(RC4),MONTH(RC4)+6, DAY(RC4)+1)"
However, when I try this with a different formula =IF(ISNUMBER(SEARCH(C2,H2)),"REPEAT","SAFE"), I'm getting a compile error: Expected end of statement with this code:
Code:
.Cells(Row, "I").FormulaR1C1 = "=IF(ISNUMBER(SEARCH(RC3,RC8)),"REPEAT","SAFE")"
The error message highlights the word REPEAT. I suppose it's something with all the quotes throwing off where compiler thinks the end of the formula should be.
I am trying to do Vlook up but the reference cell indicates formula error even if this has values.
I have to do F2 in every cell to make the Vlookup work. Is there any way to remove this?
Excel 2007
No empty rows
No empty cells
No calculations in cells
Field names look fine - no punctuation no merged cells
If I select one column - any single column I can generate a pivot table but not with multiple columns
A1 refers to B1 which contains a number or #VALUE!
What could I use in A1 to return a number and if B1 = #VALUE!, a zero.
I am having a slight problem copying hyperlinks. I have written some code that sorts data by date and then creates a simple diary. It originally placed the name of the event in the new diary sheet. What I would like to do is instead of copying the name into this new sheet copy a hyperlink that I have created to the company's website for that event.
I can create the hyperlink using hyperlink(B1,A1) where A1 is the company name and B1 is the web address but since the new sheet will not have the underlying data I need to actually copy the values and format of the hyperlink rather than the formula.
I have a small issue with hyperlink :
https://.../Search/QuickLink.aspx?n=A123-BCD-E-FGH-I456_JK789_0-12345&t=3&d=Main%5ceBProd&sc=Global&r=A12&cno=E_SOURCE&m=l
A123-BCD-E-FGH-I456_JK789_0-12345 - needs to be B2 cell value
A12 - needs to be C2 cell value
when I drag the function down, it has to pick B and C valued according to row. I am missing a mistake somewhere.
I last tried this function and it didn't work.
=IF($B2<>"",HYPERLINK("https://.../Search/QuickLink.aspx?n="$B2"&t=3&d=Main%5ceBProd&sc=Global&r="$C2"&cno=E_SOURCE&m=l","Open"),"")
I'm working on a formula to get the the path of a picture on a different sheet in a workbook. I am trying to get use the hyperlink function to reference that cell on the the other sheet. It looks right but I get an error saying that it cannot open the specified file.
This is what my formula looks like:
=HYPERLINK(ADDRESS(4,12,2,,"Sheet 1"),2)
I need it to actually get the actual text value of the cell I am trying to reference. How would I do that?
I have around 30k data. which is in invalid format.
Ex: 12987654321vinay kk 876543219
32567456789 kkccjhg fo 345678921
I want to convert this into correct format as below with start letter from MOD, 987654321,, vinay, kk,87654219
MOD,567456789, , kkccjhg, fo,345678921
I want to know which are formulas I have to use to get this info in correct format.
I have two columns with values, and want to display "Valid" or "Invalid" in a third column, dependant on the two preceeding values.
If both column 1 and column 2 contain #N/A, then I want the third column to display "Invalid".
If the above is not true, then I want the third column to display "Valid".
I've been trying different syntax with IF/AND but cannot achieve the result.
I get the error message "The PivotTable field name is not valid. To create a PivotTable report, you must use data that is organized as a list with labeled columns. If you are changing the name of a pivot Table field, you must type a new name for the field." when I try to make a pivot-table.
View 3 Replies View RelatedIs there a way to generically reference a directory when creating a hyperlink? By this I mean, I have an XLS that documents the flow of a process. As an outcome of this process, text files are generated.
This process may be run multiple times. I would like to be able to create multiple directories: Run1, Run2, Run3, ...
I would like to put a copy of the XLS in each directory. I would like to put the output files from each run into their respective directory.
I would like to put hyperlinks in the XLS that point to the flat files. However, when I add a hyperlink it contains the full directory path. Something like C:MyDocumentsRun1output1.txt.
So, if I copy the XLS into directory Run2, the hyperlink is still going to point to a data file in directory Run1.
How can I generically default to look in the 'current' directory for a file? Or is there a different/better way around this? ............
I want to be able to create a hyperlink in a cell that is the result of a simple reference formula. i.e. if cell A1 on worksheet A is a formula "='SheetB"!A1", can I create a hyperlink automatically from SheetA Cell A1 to 'SheetB'!A1?
I would like for the hyperlink to be is cell A1, so I beleive that would be a macro / VBA solution.
Also, is there a formula solution that could go in B1 "=hyperlink(A1)", where the formula will then recognize the referenced cell (rather that the formula result) and hyperlink to SheetB:A1?
VB:
Sub RenameTabs()
For i = 1 To Sheets.Count
If Worksheets(i).Range("C1").Value <> "" Then
Sheets(i).Name = Worksheets(i).Range("C1").Value
End If
Next
End Sub
I change my tab names with the above but than my hyperlinks breaks.
I have a workbook with many tabs and within those tabs there are many hyperlinks to other areas within the same workbook. When I add or delete lines or rows, the corresponding hyperlinks do not stay with the changed cell. Is there any way to make the cell reference in a hyperlink an absolute similar to how you do with a formula?
View 2 Replies View RelatedI need to create a Hyperlink to a static URL but then add a cell reference
The static url is known - [URL]
A column in my spreadsheet contains the data needed to add to the end of the static URL - so it would look like [URL]
I tried this
=HPYERLINK("www.helloworld.com)+B2,Link - but it is not working :-(
On a worksheet, I created:
- a list of data
- a pivottable based on these data
When moving this worksheet this worksheet to another workbook, the pivot table can't refresh anymore. This throws an error message "Reference is not valid". To work around this problem I need to adapt the datasource. The same occurs if the list and the pivot table are on separate sheet, with the added strange behaviour that, when data an PT are split, it is not possible to move both sheet together.
This would not be a big issue if my problem had to be solved manually. The real problem is that I need to move the sheets from a C# program.
I'm looking to put a formula in the last column (Card Valid/Invalid (N3:N8)).
I want this formula to say IF Project Name OR Start date OR Due Date or Type OR Author OR VS are empty then I want the last column to say Invalid else if all of these columns are filled in then give valid. Also if a completed date or no. of review loops are filled in but not both then give Invalid but if both are filled in then as well as all the rest of the info give Valid.
Project Name - Valid/Invalid is B2-N2
i am getting an error when trying to hyperlink from one page in a workbook to
another page in the same workbook. the error simply states that "cannot open
the specified file"
is there a way to fix this???
I have a VB function in a worksheet that requires data from a workbook that is not under my control. The problem is that the workbook does not always have complete data. Often cells are filled with #VALUE, when this occurs I need a way to tell my VBA to assume a value of 0. I have tried using if(cell="#VALUE", 0,cell) but to no avail. any suggestions?
View 7 Replies View RelatedI am using the code below to send emails from my Outlook Express. The code is working fine. Recently, I added additional email addresses into this code. When I did, I got an error message. The error message is below. Please help me modify this code or propose an alternative because I need to send out many emails. I prefer not to use Outlook unless I have got no choice....
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