InputBox Error :: Simple Statement

Jul 30, 2009

experienced coder (not VBA) and I'm having trouble with a simple statement. No idea why it was working before and moving it to it's own Sub screwed it all up.

Sub InitialMessage()
On Error GoTo BadEntry
SiteTotal = InputBox("Enter the number of approved sites *Must be an Integer > 0*")

BadEntry:
Entry = "Bad"
Msg = "An error occurred!" & vbNewLine
Msg = Msg & "Make sure you enter a valid value in all the prompted Message Boxes"
MsgBox Msg

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Jun 3, 2008

I have a VBA userform with various textbox fields like 'Name' and 'Address' and 'Amount'
I would like an input box to pop up that asks the user to 're-enter for verification'
So that they have to type the same thing twice, to protect against typos

How do I code it so the program compares the inputbox to the textbox and passes only if they are identical?

(or even, using two inputboxes instead if that would be easier)

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I have found a base macro that has most of what I want the only problem is I need it to search column A by the data entered by the user in the inputbox and send out an email if it meets all the requirements. I also need it to be able to be able to do that search by only the first letter of the company name (example, only needing to put in A in the inputbox for Amber Inc.). If I remove the red text the macro works perfectly but just runs down the list on the spreadsheet.

Column A has company names, Column B has email address' and Column C has the company contacts first name.

[Code] .....

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I am trying to do a nested IF statement in which if Cell A has a number, display it. If Cell A = "", look in Cell B. If Cell B has a number, display it but if its "", then display Cell C.

I have the IF statement working for the first two pieces but don't know how to incorporate a third statement: =IF(A="",B,A)

This works - how do I get it to check Cell B and show Cell C if B is empty?

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Mar 30, 2008

I'm a new user here and am relatively raw in excel, and today I decided to make a type of Point-Of-Sale Workbook. I'm sure it has been done, and there are probably simple templates other places, but I want to say that I've done it :P. Basically, ive created page 1 as a recipt-type page that I can print off for customers that is set to total and add-in taxes and fees and all that jazz. The page 2 is a complete inventory of my parts.

Now what I want to do is save myself a little time. I want to be able to enter an Item Number in one of the cells in page 1, and have it automatically fill in the cells for the Item and Item Cost.

So I'll probably need something like.. IF Cell b2 on Sheet1 (Item Number) = Any number from Sheet 2, C column (Item Numbers), then Cell b3 (Item) on sheet 1 = corresponding row and cell (Item) on sheet 2, and Cell b4 (Item Cost) on sheet1 = Corresponding row and cell (Item Cost). If not, then do nothing.

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Nov 3, 2012

Background: The user makes a selection from a drop down box on the main sheet (sheet5, G12). The drop-down box is linked to *Sheet31.Pax_Nav*. If the drop-down box's linked cell value is less than 5, then do nothing (manual input required). If it is greater than 5, then the vlookup matches that number to a person in the database and returns their weight. The code will pull the required person's weight but then Excel will hang and freeze.

Private Sub Worksheet_Calculate()
On Error Resume Next
If Sheet31.Range("Pax_Nav") > 5 Then
Sheet5.Range("G12").Value = Application.WorksheetFunction.VLookup(Sheet31.Range("Pax_Nav").Value, Sheet31.Range("H17:L48"), 5, False)
Else
End If
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Oct 16, 2009

I am trying to only have the option 1, 2, or 3 be entered. I have that part down, but if someone clicks cancel or just closes the input box i get the type mismatch I believe because no integer was found....is there a way around this?

Dim intResponse As Integer
intResponse = InputBox("Choose One" & Chr(10) & Chr(10) & "1 - Lease Lock" & Chr(10) & "2 - Upgrade" & Chr(10) & "3 - Lease Lock & Upgrade", "Contract(s) sent out")
If inResponse <> 1 Or strResponse <> 2 Or strResponse <> 3 Then
MsgBox "Must choose (1,2,3)"
Exit Sub
End If

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Aug 1, 2008

I am using an inputbox to get a range a data from the user.

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Apr 25, 2014

Using this formula for a bank account,

=IF(SUM(C2-A1+B1)=C1, "match", "NO match")

down a column of about 3000 rows, yields only one cell with an unexpected and probably incorrect response in G2 with a "NO Match" - where the math is correct ?

A B C D
63.58 0.00 -54.97 match
64.57 0.00 8.61 NO match
128.21 0.0073.18 match
201.39

Details:

Attachment is included;
temp2.xlsx

in a bank account file, where "C2" is the previous balance, "C1" is the current balance, "A1" is any check written, "B1" is any deposit applied.

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Jan 19, 2012

I'm getting a mismatch error on my If activecell.value > 5 Then portion of this code. I'm trying to say if the value in column AG is greater than 5 then create an email address from the first and last name. I've even made sure to copy and paste the formula results as values.

Code:
Sub CheckPFPDates()
Dim OutApp As Object
Dim OutMail As Object
Dim cell As Range
Dim emails As String
Dim salution As String
Dim currenttime As Integer

[Code] ........

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Jun 30, 2013

I am trying to use FIND and an array formula to find the position of text in a range of cells (A2 and A3 in the example) which could be one of a number of options (C1:D1 here). But the array formula throws up the following error: "A value used in the formula is of the wrong data type". The simplest illustration of the problem is as follows. The formula in B2 is

Code:
{=FIND(($C$1:$D$1),A2)}
and $C$1:$D$1 contain REF and ATM respectively. [/CODE]
REF
ATM
203047 05AUG 08.55 OKEHAMPTON ATM
#VALUE!
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22

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Jun 30, 2009

I have the inputbox so i can set a string value,
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If the inputbox has a value do >>>>>>That>>>>>

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Sep 26, 2007

I have a formula, that is return a #Value! error for the blank cell that are referred to in the formula. How do I get rid of the #Value! error when I fill down? The formula works great.

=IF(G21>0,IF(A21+182

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Mar 4, 2014

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I have a user form for data entry purpose which is working fine. Now, I am making a code for data editing purpose which pulls out data from the worksheet into the user form.

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Code:
Private Sub cmbColor_Change()
If cmbColor.Value = "Other" Then
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[Code]....

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Jan 19, 2010

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Jan 7, 2010

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if Statement B: =IF(M4>$B$17,0,LOOKUP(M4,$AA$36:$AB$44)*$B$15/12) works well too

now I am trying to say

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Code:
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May 6, 2014

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My problem is that, unless I use something like xlCellTypeVisible, when there is no data shown it still copies and pastes all the hidden records. And if I do use it when no filtered data, I currently get an error "No cells were found".

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My current if statement reads as follows:

[Code] .....

I think I might need to use some sort of On Error Resume Next statement, but I have never used these before. When I tried adding that before the If statement, it just ignored the criteria and tried copying hidden rows - the exact opposite of what I want.

I'd like something that said, if this condition = error, skip over entire if statement and carry on with rest of the sub.

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Aug 27, 2008

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code died at RS.Open SQL, CN
/////////////////////////////////////////////////////////
Sub GET_OSI
Dim sn as String, osi as string, saposi As String

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LastColumn = Sheets("Timelines").Range("A1").End(xlToRight).Column
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'Screen update test
'-------------------------
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'display message
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Seems simple enough,eh?

When I step through this code the first statement works(sheet1 is selected)
The next statement is executed without an error, so I assume it works
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Sub SheetFinder()

Application.MacroOptions Macro:="SheetFinder", _
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msg1 = "What sheet would you like to go to?"
msg2 = "I'm sorry, but that sheet could not be found."
On Error Goto NotFound

TryAgain:
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