If Statement To Long - Keep Getting Error?

Mar 4, 2014

I'm working on a spreadsheet that i have a long if statement and it keeps till me i have a error. I stated reading and come to find out you can only have 7 statement.

=IF($R$6="X",VLOOKUP($A25,VISION,2,FALSE),IF($R$7="X",VLOOKUP($A25,VISION,3,FALSE),IF($R$9="X",[code]....

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Switch Statement Is Too Long For VBA. To Make The Switch Statement Work Over Two Lines

Jan 6, 2009

I have created a very long switch statement, which is too long to be placed in one row in VBA. I have attempted to put a space and underscore at the end of one line and continue the statement on the row below by placing a comma at the start of the second line. VBA will accept my efforts, but when I run the statement in the immediate window, the following error appears.

"Invalid procedure call or argument"

I understand that there are certain rules where I can split a switch statement onto two lines, yet I do not know what they may be.

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Jan 5, 2010

I've attached an example of what I am trying to achieve and an explanation as well. I'm trying to avoid the use of a macro as I don't understand them and I will need to modify the sheet later on which could cause problems. However, if a macro is the only solution, then I will have to make due with one.

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Dec 21, 2009

I have a formula which is currently too long and which I'm sure could be done more efficiently. That plus Excel is saying the formula is too long. I have pasted the formula below and broken it up for clarity:

---------------------------------------------------------------------------------
=IF(AND(E3="Three",I3<=100),
(I3*VLOOKUP(C3,costsnetwork,10,FALSE)/100),

IF(AND(E3="Three",I3<=250),
(100*VLOOKUP(C3,costsnetwork,10,FALSE)/100)+((I3-100)*VLOOKUP(C3,costsnetwork,11,FALSE)/100),

IF(AND(E3="Three",I3<=850),
(100*VLOOKUP(C3,costsnetwork,10,FALSE)/100)+(250*VLOOKUP(C3,costsnetwork,11,FALSE)/100)+((I3-350)*VLOOKUP(C3,costsnetwork,12,FALSE)/100),

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Alternative For Extra Long Nested If Statement

Sep 20, 2012

I was trying to search for a set of keywords in column1 and if the logic is true then print predefined word in column 2. The problem is I have 14 sets of keywords for which I tried creating the longest if statement only to find out that the limit is 7. Below are few of the sets.

=IF(COUNT(SEARCH({"SAN","lpfc","scsi","adap","path"},S2)),"STO")
=IF(COUNT(SEARCH({"process","nim","root/bin","agent","genhkdly","script","dbsync_dly","vcs","listener","horcm","msoffline","cpu mdmprd"},S2)),"APP")
=IF(COUNT(SEARCH({"percent","inode","space","check-kerberos","nfs","file system","jfs"},S2)),"FLS")

[Code] ....

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Jul 7, 2006

I am trying to write the following statement in a cell in excel lets say O3 so I can drag it down to the rest of the column, I was trying to see if there was a previous posting about this but I didn't find it. the if statement goes like this:

=IF(M3=Sheet3!$B$2,Sheet3!$C$2,IF(Sheet1!M3=Sheet3!$B$3,Sheet3!$C$3,IF(M3=Sheet3!$B$3,Sheet3!$C$3,....until it reaches to if(Sheet3!$B$20,Sheet3!$C$20,"PENDING"))

Is there a way I can do this I know probably through a VBA but I have no idea how to set it up.

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May 28, 2014

formula to find specific text from statement.

I manage to use formula find for 1 text in 1 statement, but in confuse how to get another text found if i have "8 text" to find. Generally, there will only be "1 text" for each statement.

Maybe in 1 statement there have only "IC" or "Staff Tagging" or Name" or "Product" or etc till 8.

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Aug 18, 2009

I need to write a formula but excel shows an error message "Formula Too Long." There are two long strings of the formula that I repeat several times. Is there any way to put these strings in other cells and reference them within the formula? Each of the strings looks very similar to this:

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Oct 4, 2007

I have the following code written:

If InStr( Cells(i, 3).Value, "Other") > 0 Then _
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This seems to work fine for the most part. However, if the value in Cells(i, 4) is too long, I seem to get a Run-time error '13': Type mismatch. Is there any way to rework this code so it can replace even if the string in Cells(i, 4).Value is too long?

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Nov 25, 2008

I am working on using an excel workbook as part of a roll playing game and I am trying to record a macro and then put that in a command button which uses the randbetween, multiple if statements and multiple vlookup functions. I have successfully done similar things by just recording a macro and then pasting that into the VB editor. However this time I get a unable to record macro after putting the formula in the selected cell. I have tried copy and paste and just typing the formula with the same results.

Upon executing the formula I then want it to copy and paste special- values the result.

I'm assuming I have to put the VB code in manually but when I tried to do the formula I got a syntax error.

The worksheet I am working on is named new and I've included the formula in the a text box. I would like the result to show in J12 and be triggered by pressing the cmnbutton in k12.

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May 15, 2007

I have a large spreadsheet, within which i am trying to remove commas from all cells. I get the error 'formula is too long' when I carry out the search. Some of the cells are >1024 characters in length and contain dates, text etc.

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Jul 9, 2009

I have worked on this really difficult long formula, but the problem is, I have been working from my Mac. And my office, which this formula was made for, is all PC. Now generally this isn't a problem, but apparently PC's have a limit on how long the formula can be. Is there anyway to overcome this? I really need this formula to work..

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Sep 26, 2007

I have a formula, that is return a #Value! error for the blank cell that are referred to in the formula. How do I get rid of the #Value! error when I fill down? The formula works great.

=IF(G21>0,IF(A21+182

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Nov 9, 2013

I am getting the Run-time error '380'. Could not set the value propery. Invalid property value.

I have a user form for data entry purpose which is working fine. Now, I am making a code for data editing purpose which pulls out data from the worksheet into the user form.

I am able to do this for text boxes and combo boxes that are not linked with each other. However I am getting a problem in the following case; I have a combo box and a text box that are linked to each other by combo box _change code which is below which may be the reason for the error I am getting for the next code...

Code:
Private Sub cmbColor_Change()
If cmbColor.Value = "Other" Then
lblColor.Visible = True

[Code]....

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Jan 19, 2010

worksheets("Demorecords").Range("k2").formula = _
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A error box says compile error: expected end statement and then highlights this part (red)

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Jun 10, 2014

I attempted to initialize values on a few Dim statements, but got compile errors: "expected end of sentence".

VB:
Dim sumTtl As Currency = 0
Dim searchTxt = "West"

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Apr 16, 2009

when i write the following line to open the recordset then it gives me syntex error.


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and if i write the following line then it works fine.


rs.Open "tblmain", cn, adOpenKeyset, adLockOptimistic, adCmdTable

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Jan 7, 2010

if Statement A: =IF(M4>$B$17,0,LOOKUP(M4,$AA$20:$AB$29)*$B$15/12) works very well

if Statement B: =IF(M4>$B$17,0,LOOKUP(M4,$AA$36:$AB$44)*$B$15/12) works well too

now I am trying to say

=IF('Input Page'!B36="yes",(IF(M4>$B$17,0,LOOKUP(M4,$AA$36:$AB$44)*$B$15/12),(IF(M4>$B$17,0,LOOKUP(M4,$AA$20:$AB$29)*$B$15/12))))

Basically, if B36 is yes, use If Statement B, otherwise IF Statement A. If I write Yes, I get a "Value" error, if I change the yes to 1, I get a FALSE error.

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Oct 16, 2013

I have this line of code:

Code:
If Left(value.use_type, 1) = "D" Then

Where use_type is a field in a user form.

I am getting an "object required error"

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Jul 30, 2009

experienced coder (not VBA) and I'm having trouble with a simple statement. No idea why it was working before and moving it to it's own Sub screwed it all up.

Sub InitialMessage()
On Error GoTo BadEntry
SiteTotal = InputBox("Enter the number of approved sites *Must be an Integer > 0*")

BadEntry:
Entry = "Bad"
Msg = "An error occurred!" & vbNewLine
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May 6, 2014

I am running a macro which filters a column to show only records with "#N/A" (ie an error), and copies these to another worksheet. As I am aiming for no errors, there will be occasions when there is no filtered data.

My problem is that, unless I use something like xlCellTypeVisible, when there is no data shown it still copies and pastes all the hidden records. And if I do use it when no filtered data, I currently get an error "No cells were found".

I have tried many iterations of code correction and i think i'm currently blinded by staring at it so long!

My current if statement reads as follows:

[Code] .....

I think I might need to use some sort of On Error Resume Next statement, but I have never used these before. When I tried adding that before the If statement, it just ignored the criteria and tried copying hidden rows - the exact opposite of what I want.

I'd like something that said, if this condition = error, skip over entire if statement and carry on with rest of the sub.

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Subscript Out Of Range Error When Using Nested If Statement

Aug 27, 2008

I have a Userform which has 2 textboxes. User enter his employee id on textbox1 then enters a valid break time code which are 1,2 and 3 on textbox2. If User typed 1 then first breaktime start time will be pasted on the worksheet. When User returns after break he then enters his employee id again and then type 1 to end his first breaktime, the end time will be pasted on the worksheet. My program works fine however, I am trying to place a code which will prompt the user to end his first break time before entering another valid break code. Kindly check my code below as I am receiving an error message. 'Run-time error 9' Subscript out of range. This thing is driving me nuts. Any advise or can you tweak my coding vba experts.

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Aug 3, 2012

I keep a formula to many arguments error.

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What I am trying to say is if cell c2 is populated enter a "x" and if h2 is populated enter a "x".

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Feb 5, 2014

Excel 2010. Windows 7

Run-time error '-2147467259 (80004005)':
An unexpected token ""20*"" was found following "1' AND
PERIOD = LIKE*. Expected tokens may include: "". SQLSTATE=42601
code died at RS.Open SQL, CN
/////////////////////////////////////////////////////////
Sub GET_OSI
Dim sn as String, osi as string, saposi As String

[code]....

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Apr 13, 2007

I get an application defined or object defined error at the select statement 1004...I know I know I shouldn't be selecting in code so I'll fix that but why can't I set the range?

NumRows = Sheets("Timelines").Rows.Count
LastColumn = Sheets("Timelines").Range("A1").End(xlToRight).Column
LastRow = Sheets("Timelines").Range("A" & NumRows).End(xlUp).Row

Sheets("Timelines").Range(Cells(1, 1), Cells(LastRow, LastColumn)).Select
TIA, Charlie Brown.

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Feb 5, 2009

I ran into a screen update problem in a project I was working on and couldn't find a solution, so I wrote some test code in a new workbook as follows;

Sub Flkr()
'-------------------------
'Screen update test
'-------------------------
'Select sheet1
Sheets("Sheet1").Select
'Disable screen update
Application.ScreenUpdating = False
'Select sheet2
Sheets("Sheet2").Select
'display message
MsgBox "Why is the %&$@ screen updating?", vbCritical, "??????"
End Sub
Seems simple enough,eh?

When I step through this code the first statement works(sheet1 is selected)
The next statement is executed without an error, so I assume it works
The next statement sheet2 is selected, and the screen updates!

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On Error Statement: Subscript Out Of Range. Go To Sheets

Sep 27, 2006

Sub SheetFinder()

Application.MacroOptions Macro:="SheetFinder", _
HasShortCutKey:=True, ShortcutKey:="G"

msg1 = "What sheet would you like to go to?"
msg2 = "I'm sorry, but that sheet could not be found."
On Error Goto NotFound

TryAgain:
prompt1 = InputBox(msg1, , "Template")

If prompt1 = "" Then
End
Else
Sheets(prompt1).Select
End If

End..........

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Feb 14, 2014

In cell C34 I'm trying to duplicate the content in cell J70, but I don't want to show any content in C34 unless J70 is not blank.

I tried this formula in C34, but I keep receiving an error message:

=if(j70="","",(=j70)

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Apr 18, 2014

I am getting this error and where th If not starts its is in red showing that is where the issue is:

HTML Code: 

Sub RemoveRows()
Dim LR As Long, i As Long
Dim ws As Worksheet
Set ws = Worksheets("100 Airports")
LR = Range("B" & Rows.Count).End(xlUp).Row
For i = LR To 10 Step -1

[Code] .....

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Aug 10, 2012

I have some code below. I have error handling in place for when it tries to open a specific file. If it isn't there then user has option to continue and ignore this file, or browse and select a new one.

The problem is, when the user wants to ignore the file, the "Resume Next" continues to run the VBA assuming the file was ok i.e. the code after the line to open the file. What I would like is for it to skip the succeeding code and go to look for the next file.

Below is the VBA:

Code:
For i = 0 To 2 Step 1

'add in error handling for if the file is missing
On Error GoTo MissingFile
Workbooks.Open Filename:="\hbeu.adroot.hsbcdfsrootgb002hfcfinance01fnce" & qfolder & "Data" & qfile(i), UpdateLinks:=False, ReadOnly:=True

[Code] .........

Missing File:

qMissingPrompt = "There was an error opening data file. Click OK to browse or Cancel to ignore and move to next file"
qAns = MsgBox(qMissingPrompt, vbOKCancel)
'click cancel - ignore error and move onto the next file
If qAns = vbCancel Then

[Code] .......

So, where it says Resume Next, currently it will start running the following (after On Error Goto 0)

Code:
Set datawb = ActiveWorkbook

range("A2").Select
Do Until ActiveCell.Value = ""
etc.

What I would like it to do is go back to is to go to the next i

Code:
For i = 0 To 2 Step 1

Or even to go to the 'Next' statement at the end so that it moves onto the Next i and tries to open the next file.

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