Getting Error For For Each Loop With If Statement
Nov 9, 2013
I am getting the Run-time error '380'. Could not set the value propery. Invalid property value.
I have a user form for data entry purpose which is working fine. Now, I am making a code for data editing purpose which pulls out data from the worksheet into the user form.
I am able to do this for text boxes and combo boxes that are not linked with each other. However I am getting a problem in the following case; I have a combo box and a text box that are linked to each other by combo box _change code which is below which may be the reason for the error I am getting for the next code...
Code:
Private Sub cmbColor_Change()
If cmbColor.Value = "Other" Then
lblColor.Visible = True
[Code]....
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May 18, 2009
I have the following loop that should look through my rows of data for the Value "Y" in column T, for those rows that contain "Y" it should update column K with the variable xdate. For some reason it doesn't seem to work, it changes the first entry it finds and then seems to crash, I have to use CTRL+BREAK to stop it.
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Aug 8, 2013
I am trying to loop through a range, checking for a cell to contain one of two characters and then put a value in a cell to the side (well 3 away) of it. Im getting an error for Type mismatch on line:
VB:
If CellContent = "h" Or "v" Then
the data in the cell is an along the lines of '12.34.56.43 som-thi-vh-ng1'
VB:
Dim MyRange, MyCell As Range
Dim CellContent As String
Sheets("Sheet1").Activate
[Code]....
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Sep 2, 2008
how to get my LINEST function to work properly. Now, what I'd like to do is have it reduce or increase the order of the polynomial until R^2 equals 1.0, or the polynomial reaches 6th order, whichever comes first.
Can I do this with a bunch of nested IF ELSEIF statements, or is there a cleaner way to do this?
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Jul 31, 2013
I have a code like this below
Sub Copydata()
Dim emre As Integer
For emre = 100 To 121
Sheets("CP TB").Select
ActiveSheet.Range("$B$8:$G$10000").AutoFilter Field:=3, Criteria1:=emre
Range("E8:F8").Select
[Code] .....
I want to skip values when the selection is a value I choose. I tried to put a "If" statement but I couldn't make it work.
The IF statement will check the selection after red colored code. if cell value is "a" then it will go for Next emre.
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Aug 5, 2008
I have the following code which previously was showing an error on the Do While line. It was suggested that I change the line too Range("B2").Text. However, the loop is not deleting the rows based on "#N/A". Can anyone offer any suggestions?
Selection.Sort Key1:=Range("B2"), Order1:=xlAscending, Header:=xlGuess .....
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Jun 15, 2007
So here is my problem:
how do you repeat a write statement four time
form 1234 to 1234123412341234
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Oct 16, 2007
If ComboBox1.Text = " Market 1" Then
StoreNumList = Array ("66", "67", "107", "222") 'obviously array string is much longer than this
For x = LBound(StoreNumList) To UBound (StoreNumList)
StoreNum = StoreNumList(x)
ComboBox1.value = StoreNum
Call btnOK_Click_Process
Next x
Program runs fine first step through. It calls the btnOK_Click_Process sub routine just fine. However on second and subsequent For/Next cycles it does not call btnOK_Click_Process.
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Nov 12, 2013
I am having an issue getting an IF statement to work inside a DO loop. I have Microsoft Excel 2007 and Windows 7 Entreprise.
In my Excel spreadsheet, I have in column B a list of keywords and in column C the category to which each keyword belongs. For instance, the keyword "boot" goes withe the category "Shoes", "scarf" goes in "Accessories", etc.
In another column, I have a list of product descriptions (like "Black Boots" or "Silk Scarf") and I would like to assign the relevant category to each product. I thought to do this by creating a new function in VBA. This function would go through the whole list of keywords in column B, checking if the keyword is included in the product description. If it is, the function's result would be the relevant category, and if it is not, the function would search the next line in column B, until a relevant keyword is found, or until the end of the list.
Here is the code I have written so far:
Code:
Function SegmentSearch(Item)
Dim i As Integer
i = 1
Do
i = i + 1
If Application.WorksheetFunction.IsNumber(Application.WorksheetFunction.Search(Sheet5.Cells(i, 2), Item)) = "TRUE" Then SegmentSearch = Cells(i, 3)
Loop Until Application.WorksheetFunction.IsNumber(Application.WorksheetFunction.Search(Sheet5.Cells(i, 2), Item)) = "TRUE"
End Function
Without the loop, the function works fine (if "Item" happens to include the first keyword in the list) but as soon as I try putting the loop I get a #VALUE! error.
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Dec 28, 2006
My nested loop works as intended without If statements, ie it counts non blank cells in a series of 17 ranges (this loop is called the CountRangesOnEachRow loop) AND then drops down a row and repeats (this loop is called the RowNo loop). The problem is that once my first If statement occurs the RowNo loop fails and it stops at the first row.
The first If statement is designed to do the following:
1. Tests to see if A4 has data. If yes, copy cell contents (pupil's name) to Sheet(2).Range("StudentName")
2. If empty skip the countranges loop and move down a row to A5.
3. Cells A4:A35 need to be tested for data in this manner.
I've included a sample workbook & code with the IF statement comment blocked so you can see what it should do AFTER it tests the A column for data. The macro should end after row 6 as A6:A35 are all blank.
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Sep 17, 2009
Setting value in For Each statement stars infinite loop. I am trying to get the following script to work
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Aug 22, 2008
I think the problem is the order in which I have the "next" loops. I would like to evaluate the if statement below over a range of cells
Sub Analysis()
Dim i As Integer
Dim x As Integer
Dim y As Integer
Dim k As Integer
Dim TheLast As Integer
TheLast = Sheets("Name").Range("c" & Rows.Count).End(xlUp).Row
For i = -7 To -26 Step -1
For x = 24 To 43
For y = 14 To 43
For k = 16 To TheLast.................
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Sep 26, 2007
I have a formula, that is return a #Value! error for the blank cell that are referred to in the formula. How do I get rid of the #Value! error when I fill down? The formula works great.
=IF(G21>0,IF(A21+182
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Dec 17, 2008
Can't seem to figure out why my Do Loop keeps giving me an Error of "Loop without Do".
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Mar 4, 2014
I'm working on a spreadsheet that i have a long if statement and it keeps till me i have a error. I stated reading and come to find out you can only have 7 statement.
=IF($R$6="X",VLOOKUP($A25,VISION,2,FALSE),IF($R$7="X",VLOOKUP($A25,VISION,3,FALSE),IF($R$9="X",[code]....
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Jan 19, 2010
worksheets("Demorecords").Range("k2").formula = _
"=IF(AND(DAYS360(N2,Current_Date)>" & _
Combobox1.Text "!$B$6,DAYS360(N2,Current_Date)" & Combobox1.Text "!$B$7,"Pending Delete","Persistent"))"
A error box says compile error: expected end statement and then highlights this part (red)
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Jun 10, 2014
I attempted to initialize values on a few Dim statements, but got compile errors: "expected end of sentence".
VB:
Dim sumTtl As Currency = 0
Dim searchTxt = "West"
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Apr 16, 2009
when i write the following line to open the recordset then it gives me syntex error.
rs.Open "select batchno from tblmain", cn, adOpenKeyset, adLockOptimistic, adCmdTable
and if i write the following line then it works fine.
rs.Open "tblmain", cn, adOpenKeyset, adLockOptimistic, adCmdTable
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Jan 7, 2010
if Statement A: =IF(M4>$B$17,0,LOOKUP(M4,$AA$20:$AB$29)*$B$15/12) works very well
if Statement B: =IF(M4>$B$17,0,LOOKUP(M4,$AA$36:$AB$44)*$B$15/12) works well too
now I am trying to say
=IF('Input Page'!B36="yes",(IF(M4>$B$17,0,LOOKUP(M4,$AA$36:$AB$44)*$B$15/12),(IF(M4>$B$17,0,LOOKUP(M4,$AA$20:$AB$29)*$B$15/12))))
Basically, if B36 is yes, use If Statement B, otherwise IF Statement A. If I write Yes, I get a "Value" error, if I change the yes to 1, I get a FALSE error.
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Oct 16, 2013
I have this line of code:
Code:
If Left(value.use_type, 1) = "D" Then
Where use_type is a field in a user form.
I am getting an "object required error"
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Jul 30, 2009
experienced coder (not VBA) and I'm having trouble with a simple statement. No idea why it was working before and moving it to it's own Sub screwed it all up.
Sub InitialMessage()
On Error GoTo BadEntry
SiteTotal = InputBox("Enter the number of approved sites *Must be an Integer > 0*")
BadEntry:
Entry = "Bad"
Msg = "An error occurred!" & vbNewLine
Msg = Msg & "Make sure you enter a valid value in all the prompted Message Boxes"
MsgBox Msg
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Jul 24, 2009
I have cobbled together some code that I hoped would do the following:
Sort data
Copy all data from one person and put it on a sheet
Create a pivot on that data
populate another sheet based on that persons data
Save as a PDF
Clear the data and start again for the next employee
I have copied this from other macros I have used in the past. Up until now the parts I have been working on have been ok. however when I try and run it now I get a "Loop Without Do" error. I really can't figure out why.
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Jan 30, 2012
I'm trying to do a for each loop in a row, I've tried to drill it down to be as simple as possible, but I keep getting the Run-time error '424': Object Required
I've tried to make it simple, with just inserting a 1 into the cells, still get the error.
Code:
Dim firstRow As Range
Dim rCell As Range
Set firsRow = Worksheets("MAIN").Range("F3", "AG3")
For Each rCell In firstRow 'error shows here
rCell.Value = 1
Next rCell
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Sep 4, 2009
I need my macros to search for the word "Cancel" in columns "T". Once found, I need the macros to make that entire row a certain pattern ( .Pattern = xlGray16)
There will be other wording in these cells that contain "Cancel" or "Cancelled".
A compile error keeps occurring. It says "Ambiguous name detected: FormatCell"..
Sub DoCancelCells()
Dim strSearchString As String
Dim wksSheet As Worksheet
Dim rngSearchRange As Range
Dim intSearchCount As Integer
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May 6, 2014
I am running a macro which filters a column to show only records with "#N/A" (ie an error), and copies these to another worksheet. As I am aiming for no errors, there will be occasions when there is no filtered data.
My problem is that, unless I use something like xlCellTypeVisible, when there is no data shown it still copies and pastes all the hidden records. And if I do use it when no filtered data, I currently get an error "No cells were found".
I have tried many iterations of code correction and i think i'm currently blinded by staring at it so long!
My current if statement reads as follows:
[Code] .....
I think I might need to use some sort of On Error Resume Next statement, but I have never used these before. When I tried adding that before the If statement, it just ignored the criteria and tried copying hidden rows - the exact opposite of what I want.
I'd like something that said, if this condition = error, skip over entire if statement and carry on with rest of the sub.
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Aug 27, 2008
I have a Userform which has 2 textboxes. User enter his employee id on textbox1 then enters a valid break time code which are 1,2 and 3 on textbox2. If User typed 1 then first breaktime start time will be pasted on the worksheet. When User returns after break he then enters his employee id again and then type 1 to end his first breaktime, the end time will be pasted on the worksheet. My program works fine however, I am trying to place a code which will prompt the user to end his first break time before entering another valid break code. Kindly check my code below as I am receiving an error message. 'Run-time error 9' Subscript out of range. This thing is driving me nuts. Any advise or can you tweak my coding vba experts.
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Aug 3, 2012
I keep a formula to many arguments error.
=if(C2="","X","", ), IF(h2="","X","", )
What I am trying to say is if cell c2 is populated enter a "x" and if h2 is populated enter a "x".
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Feb 5, 2014
Excel 2010. Windows 7
Run-time error '-2147467259 (80004005)':
An unexpected token ""20*"" was found following "1' AND
PERIOD = LIKE*. Expected tokens may include: "". SQLSTATE=42601
code died at RS.Open SQL, CN
/////////////////////////////////////////////////////////
Sub GET_OSI
Dim sn as String, osi as string, saposi As String
[code]....
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Apr 13, 2007
I get an application defined or object defined error at the select statement 1004...I know I know I shouldn't be selecting in code so I'll fix that but why can't I set the range?
NumRows = Sheets("Timelines").Rows.Count
LastColumn = Sheets("Timelines").Range("A1").End(xlToRight).Column
LastRow = Sheets("Timelines").Range("A" & NumRows).End(xlUp).Row
Sheets("Timelines").Range(Cells(1, 1), Cells(LastRow, LastColumn)).Select
TIA, Charlie Brown.
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Feb 5, 2009
I ran into a screen update problem in a project I was working on and couldn't find a solution, so I wrote some test code in a new workbook as follows;
Sub Flkr()
'-------------------------
'Screen update test
'-------------------------
'Select sheet1
Sheets("Sheet1").Select
'Disable screen update
Application.ScreenUpdating = False
'Select sheet2
Sheets("Sheet2").Select
'display message
MsgBox "Why is the %&$@ screen updating?", vbCritical, "??????"
End Sub
Seems simple enough,eh?
When I step through this code the first statement works(sheet1 is selected)
The next statement is executed without an error, so I assume it works
The next statement sheet2 is selected, and the screen updates!
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