Loop And Parse All Occurrences Of Text After Text In A String

Nov 29, 2011

I am working on modifying this code (below) that I found here: VB Macro to search webpage for text string

Code:

Option Explicit
Public stResultstr As String
Sub SearchForString()
Dim rngURL As Range
Dim cll As Range
Dim stCheck As String
Dim xmlHttp As Object

[Code]...

So right now I have the script prompt you for a URL range, then it asks you for what you want to search for, and I have it set to return the next 10 characters from that found point.

You can see here:

Code:

If InStr(1, stResult, stCheck, vbBinaryCompare) > intt Then
intt = InStr(1, stResult, stCheck, vbBinaryCompare) + Len(stCheck)

I began to create something to identify the last position of the found item because next I want to loop it to find the next occurance of the same thing and return the next 10 characters after it in the next cell to the right in that same row:

Code:

cll.Offset(, 1).Value = stResultstr

Again, what I want to do here is find and parse out every occurence of a string (inputbox) found on a web page url in column A. The parse occurrences will go to the right in cells C though ? for row N.

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Parse Text String

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I need to parse text strings and format them.

The string looks like this and runs down an unknown number of rows in one column, Col A.

+000800-000900+00123456-000800+0012345650+000700

I want to parse this so that the results will be text to columns

80.0 90.0 1234.56 80.0 1234.56 50 70.0

I want to thank BrettH for creating this VB. I want to manipulate it to read every row in Col A that has data, and then I want to parse the data as shown above. BrettH's VB works but I couldn't modify it to read all the rows that had data. I tried looping the rows using a counter loop and also a For Each loop, but could'nt get it to work.

Sub ParseInCellMath()
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Comments
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