I need a VBA code to find the number of characters in each cell and display the result in next column.
For Ex:
ColA:
HI
who
There
output should be
ColA,ColB
HI,2
who,3
there,5
I have shown example for 3 rows only but there are chances like it contains more than 3 rows(Dynamic rows).I tried by creating Range variable but I couldn't succeeded.
in ROW 1 I have columns A thru AD populated with a number in each cell. what I need to do is take that number and fill the below cell with the number times a set character. for instance, A1 has "4" in it, so I want A2 to look like "----"
View 3 Replies View RelatedI am looking too limit a cell too only contain 5 or 7 characters.
I can limit too one length, i.e. just 7, using the data validation function.
I'm creating a spreadsheet (Excel 2003) in which a user enters data in several cells, each of which will permit different numbers of characters (to include spaces). For example, in the first cell, the user will be limited to 50 characters, in the second cell, the limit is 30 characters, and so on.
I found the data validation error alert feature, but want to give the user a cue that the entry is too long so they know to stop typing before moving to the next cell. If they only are alerted when they finish making the entry, they might not take the time to properly reconstruct the entry to meet the size limitation. I'm trying to make this more user-friendly.
Is there a way to set up the worksheet so the user knows that the entry is approaching the character limit? For example, each character filling an individual cell or having a display appear with a count-down for the number of characters remaining in the limit, or something similar.
I have a column that is made up of postcodes, lat, long, eastern, northern data eg: SK10 5BA, 53.291013, -2.096675, 393652, 377121
And I want to end up with a column containing the lat (53.291013) and another containing the long (-2.096675).
I have worked out to use formula's to remove a certain number of characters from the left and right of the cell, but the challenge here is the postcode at the begining of the data, can be varying in length.
know of a formula that will let me copy a certain number of characters within the cell, but counted from the right, as the eastern and northern numbers are always the same length.
I have a cell (A1) with a number in it. The number has 30 digits. I need a formula for (B1) that will enter the same number as A1 but restrict the number to 28 digits. Basically I need it to cut off the last 2 digits.
View 3 Replies View RelatedI need to do a macro to do this:
Count the numbers of the characters in a cell.
The number of characters must be appear in another cell.
This number must be refresh when you type the key, not when you push enter.
I have a description for a couple trucks in my inventory, rather than retyping all the mileage, I would like to select the miles out of the description.
Example:
14.0 Detroit 515 HP, 10 Spd OD, Engine Brake, Air Ride Suspension, 3.42 Ratio, 234" WB, 70" Double Deck Condo, 22.5LP Tires, Aluminum/Steel Wheels, Tandem Axle, 12,000# FA, 40,000# RA, 259,000 Miles
I have tried the find, left and mid formulas but haven't put something together to work just right. I would like to select the 7 characters to the left of "Miles".
Does anyone have any ideas?
i have a problem counting the number of characters in each cell in column "A" in a sheet and checking if number of characters in a cell exceeds 5 characters.
View 10 Replies View Relatedi have a problem counting the number of characters in each cell in column "A" in a sheet and checking if number of characters in a cell exceeds 5 characters.
View 8 Replies View Relatedtrying to limit the number of characters entered in a cell.
I clicked on Custom then =LEN(A10)=6 which works when i enter more or less than 6 characters, however it lets you paste in something which has more than 6 charters.
way to remove a varible number of characters in a cell? My example is in cell range A1:Z1 and each cell could have a different number of characters.
Smith, Sally 5348
Jones, Johnathan 7893
Doe, Mike 2223
What I would like to do is remove the second space and the numbers that follow to get a result of
Smith, Sally
Jones, Johnathan
Doe, Mike
I want to calculate the total number of characters in a cell or group of cells. Also, as a second step, I want to indicate which cells have a total number of characters greater than a certain value.
View 9 Replies View RelatedI wish to limit the number of text characters in a cell and have excel prevent the entry of additional characters after limit is reached. I have tried the Data Validation but it does not preven the entry of additional characters. I want to be able to show the error immediately when the limit is reached and no additional characters are permitted.
View 3 Replies View RelatedDoes 2003 restrict how may characters that you can put in a wrapped cell? Is there anyway to expand?
View 3 Replies View RelatedWhen you want to use Data Validation to limit the entry of the number of characters to a cell does this apply only to the cell that you are entering the characters or can it also apply to a cell that contains a LEN(A1) formula, for instance? Also,does the Data Validation limitation function includes spaces as well? Will the message appear while you are entering the characters (when it has reached the limit) or will it wait until you have hit Enter?
View 1 Replies View RelatedWe have a form that requires descriptive comments to be entered into several rows of merged cells. My goal is to have the form be able to automatically dropped down to the next row of merged cells when the current row of merged cells reaches a maximum number of characters.
And finally, the last row of merged cells would not allow any more characters than the maximum assigned but not advance to another cell automatically.
The rows I am working with specifically are:
Merged Cells F23:R23; A24:R24; A25:R25; A26:R26;...A29:R29
I always seem to have trouble with the Find() and MID() function when used together. I try to following the syntax but it keeping erroring...
I'm trying to remove all the characters before the first non-zero number.
e.g. ABC263080 becomes 263080
PROGO0123 becomes 123
Gotta short question: How can you get the number of characters in a cell? for example I got the word HELLO (5 characters). is there any method which could be applied on the contense of a cell to return the number of characters in the cell?
View 2 Replies View RelatedI am using a vlookup and have a problem. I am assigning a category to an item number based on the first two characters of the item number. For example item number 60123 would equal scrap because of the first two characters of 60. But the item number can begin with either a number or letter. Here is the formula I am using that works for item numbers that begin with numbers:
=VLOOKUP(VALUE(LEFT(E2,2)),Sheet3!A:B,2,FALSE)
It works fine until I reach a item number that begins with a letter, then I get the dreaded #Value error. If I take the value out of the formula then it works for the letter based number items but not for the number based item numbers.
I work for a localizer of text heavy software. Our developers normally use a converter to pull text out of a file and insert it into the program. This text is normally input into an Excel file since it has to correspond with files/locations in the program.
Since the space on the screen of the program is limited, we often face character limits when inputting text into Excel. Now, one cell might hold up to 255 characters, and I could restrict that with data validation, but within one cell I need to restrict each line (with a hard return) to 30 characters to fit on the screen.
So for example I have a row of cells that look like: ....
In a column I have a list with different characters in an order I don't know.
How can I find out how many different characters I have?
In the attached example the result should be 3 (There are A's, B's and C's. But no D's, no E's and so on).
I am using the macro below to count the number of specific character in a cell. The only problem it only counts one cell. How do I modify to display multiple cell counts if more than one cell is selected?
[Code].....
I am using a diamond shape that is copied into the active sheet when the user runs a macro. The user then selects the shape and enters some text. I want to limit the characters to a certain number or at least be able to give the user some advice when they enter too many characters.
I have found that, as long as I have manually named the shape "Diamond1", I can get the count in my immediate window with the following:
?ActiveSheet.Shapes("Diamond1").TextFrame.Characters.Count
but I want the count to relate to the active shape. So I tried:
?selection.shapeRange.TextFrame.Characters.Count
and I get a "runtime error 438 Object doesn't support this property or method".
How should I count the characters in the selected shape, and then if it is over say 12, require the user to shorten it or at least present yield a message Box?
I want to automatically prevent users from entering more than two digits into a textbox.
i dont want to show a message box or anything like that. I want it to be physically imposible for them to enter more than two digits i.e. when they enter two digits, pressing any other keys on the keyboard should have no effect on the contents of the textbox.
If for example, I have a set of IDs like:
Bellen-234-B25R
Carlota-345-C20RDF
Quad-765-Q20LP
How would I return just the first 4 characters after the second dash? The closest I can get is ALL the characters after the second dash.
Say I have a string "09800EBHR052708"
How would I take the first 5 characters and get a number out of them?
If 'a' is a string that contains x number of characters, how do I find out what x is (in VBA)?
View 2 Replies View RelatedHow can I extract mid section of the string which is always 5 characters long and is always followed by a period "." ?
My account strings are in 3 sections (but the third section isn't always used)
For example,
1.10210
1.22556.001
900101.56201
955261.54444.001
5566625.58886.957756
I'm working with a large list of items of varying length. A sample worksheet is attached. I need to do the following:
1) If the characters after the final forward slash from the right are of the pattern "tttxxx" (where "t" is text and "x" is a number/digit), then return all characters to the right of the final slash, including the slash itself:
Y:/Series/hun/hun109 ----> /hun109
2) if the characters after the final slash from the right are not of the pattern "tttxxx", then return all characters after the second slash from the right, including the slash:
Z:/Series/crd/crd409/editorial ----> /crd409/editorial
3) if there are less than 3 backslashes in the item, return a blank.
