Returning A Number Of Characters From A Variable String

Jun 4, 2014

If for example, I have a set of IDs like:

Bellen-234-B25R
Carlota-345-C20RDF
Quad-765-Q20LP

How would I return just the first 4 characters after the second dash? The closest I can get is ALL the characters after the second dash.

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Removing Characters From A String Variable

Jun 12, 2006

Let us assume x and y are strings. Now let us make x equal to a small sentence (ie. full of words and spaces). I now need to somehow make y equal to x, but with the last word removed. I need to do this in VBA.

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Returning Number From Text String

Jul 24, 2007

I have been trying a few formulas to return numbers from a string of text. The problem I am having is that there are more than one set of numbers that I need returned.

Here is an example of the text entered in F2

"K2PT bus structure [2 locations] & strain structure South West of L9L12-12 [1 location] / Use #4/0, std, cu conductor, connector Cat ID#10842 at structure leg & connector Cat ID#9655 at #4/0, std, cu gnd loop to connect #4/0, std, cu gnd loop to str leg."

What I need returned in a cell H2 is the numbers beside the Cat ID#

10842, 9655

I tried a Return Right Value formula, but I think because there are more than one possible value it isn't working properly.

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Extract The First 5 Characters In A String, And Convert Them To A Number

Nov 7, 2008

Say I have a string "09800EBHR052708"

How would I take the first 5 characters and get a number out of them?

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Count Number Of Characters In String/Text

Aug 24, 2006

If 'a' is a string that contains x number of characters, how do I find out what x is (in VBA)?

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Remove A Variable Number Of Characters In A Cell

Jul 7, 2008

way to remove a varible number of characters in a cell? My example is in cell range A1:Z1 and each cell could have a different number of characters.

Smith, Sally 5348
Jones, Johnathan 7893
Doe, Mike 2223


What I would like to do is remove the second space and the numbers that follow to get a result of

Smith, Sally
Jones, Johnathan
Doe, Mike

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Extracting Number Of Seconds From Variable Text String?

Oct 2, 2011

I have a column of cells, each with a with text string that has three possible formats where I want to extract the total number of seconds.

The three formats are:

nnn hrs nn min nn sec (example: 1 hrs 42 min 58 sec)
or
nn min nn sec (example: 55 min 1 sec)
or
nn sec (example: 10 sec)

The result I want is a numeric value of the total number of seconds in the text string.

For example a text string of: 1 hrs 42 min 58 sec

Should give the result: (1 x 3600) + (42 x 60) + 58 = 6,178

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Extract Number Of Variable Length From Text String

Jan 25, 2007

Imagine that I have this list of thousands of customers, who are listed in column B in the format "customer no+space+customer name".

Now I want to extract ONLY the customer no from the text string in column B and insert it as number value in column A on the same row.

Would have been easy with "Left" command, but as the customer numbers have variable length, I have a problem.

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Find Variable Size Number Within Text String

Sep 20, 2007

I have a spreadsheet with a couple of hundred rows on each tab that looks like this: A1: #1 PENROSE TIJUANA MAMA PCH 2620039190 665794 12.00 CT 1 Front 1 1 1. The only constant is the 10 digit number followed by the 6 digit number in the middle and I want to use it to parse the text string. I want the output to be everything prior to the 10 digit number in A1, the 10 digit number in B1, the 6 digit number in c1 and everything else in D1 and so on through the rows.

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How To Change Variable Data Type To String If User Input Is Not A Number

Jun 3, 2014

I have declared a 'long' variable. however; how do I change the variable data type to string if user input is not a number? how do I recognize the user input's datatype?

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Extract String Between Characters After Specific String

Dec 22, 2013

I have the following type of info in A1,A2,A3...

Code:
nameGaryage40cityPittsburgheight190
age30height150
ameLindacityMichigan
citySan Jose
ameHarryheight180age50

My goal is to get as close as possible to this,so it will be easier to sort and manage

Code:
nameGaryage40cityPittsburgheight190
nameLindaage30cityMichiganheight150
nameHarryage50citySan Joseheight180

I can't use the "" sign as delimiter to separate them into different columns because the age,city,name and height fields are in random positions on different cells.The good thing is person's name will always come after "name" string, age is alwals followed by "age" string, so it cannot be like nameheight40Michigan180

I think the following would be the easiest method(not for me tho).If on B1 I had a formula that said "find the string "name" and write anything after it until you reach the next "" character".On C1 field I could have a formula "find the string "age" and write anything after it until you reach the next "" character.On D1 I would have the same for "height" string,then on E1 for city string.

My question is somewhat similar to this one
Extract A String Between Two Characters

Formula which outputs the data between 3rd and 4th instances of the "_" character.Can we substitute "3rd and 4th" with a specific strings like "age" or "height" ?

Code:
=TRIM(LEFT(SUBSTITUTE(MID(A1,FIND("|",SUBSTITUTE(A1,"_","|",3))+1,LEN(A1)),"_",REPT(" ",LEN(A1))),LEN(A1)))

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Returning Characters After A Series Of Numbers

Dec 10, 2013

I have a list of data in Column A of a spreadsheet that is all at different lengths.

I would like to return the numbers from this (see below) seperately and also everything after the last number so returning "green"

Example:

EAST MIDS, YORKSHIRE0112012green
EAST MIDS, YORKSHIRE0112012red
EAST MIDS, YORKSHIRE0112013black
EAST MIDS, YORKSHIRE0112013brown

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Returning Numerical Characters In A Cell

Feb 2, 2014

i am trying to return the numerical characters from a cell so in A1 i have 6-4 3-6 7-5

A2 i would like to return 6

A3 4
A4 3
A5 6
A6 7
A7 5

there are also possibilties that A6 & A7 could b 2 digit numbers such as 10-12 or could be 9-11 or 11-9 etc

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If Statements: Non-numerical Characters Returning False When True

Jun 24, 2009

I have a formula in column A of the following sheet. The problem is that when the entry in cell H contains a letter as well as a number then the formula in column a returns 0.

Also if the value for false in the forumula is changed from 0 i.e to 1 or 2, then a value is returned in column A (this is shown in the red highlighted cells).

AssetRegexample.xls

Does anyone have any idea why this is?

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Inputbox Value Can Be Compared To A String Variable Or A Numeric Variable At The Same Time

Dec 7, 2008

I am trying to develope a "goto" page macro where the page value maybe 1,34,7A, 256C etc. I am not clear on how an inputbox value can be compared to a string variable or a numeric variable at the same time. This is what I have done, but when the texboxvalue is "7A" it doesn't work.

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String Variable To Call Defined Range Variable

Nov 10, 2006

Say you define a public range variable called Inputworksheet and you set it to refer to the worksheet called Inputworksheet. You have a separate string variable with the value Inputworksheet. How do you get this string variable value to call/control the range variable Inputworksheet?

I am getting an excel worksheet value from a lookup function that corresponds to the name of a VBA range variable. Once I have this worksheet value, I would like to use the range variable that has the same name as the worksheet value.

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Feb 18, 2014

I'm using a userform to create a new sheet. The form already creates the sheet and names it what was typed into the userform. Now I want it to place that variable in a cell along with a string. the following code will place the variable from the form (tbname) into cell b5.

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Variable Returning Empty Value?

Mar 8, 2013

I have been trying to register a macro and modify it. That was supposed to autofilter a table by date between values contained in 2 cells (start date & end date).

I declared variables for that, but for some reason, value returned are Emty (date 00:00:00).

Do you see something wrong in this small code?

Sub Filter()
Dim fDate As Date
Dim lDate As Date
fDate = Range("B1")
lDate = Range("B2")
Range("B3:I3").Select
Selection.AutoFilter
ActiveSheet.Range("$B$3:$I$99").AutoFilter Field:=1, Criteria1:= _
">=" & Val(fDate), Operator:=xlAnd, Criteria2:="

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Mar 25, 2013

Seems like this one should be pretty easy but I'm stuck... I just want to return a boolean based on whether the currently active cell contains the character "#". I've been trying to use the find method but I can't figure out how to convert a match or lack of a match to a boolean.

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Feb 17, 2014

i have 8 digit invoice numbers. Each 8 digit number starts with one of three 4 digit ID codes. Depending on the first 4 digits, I want a different "company" to show up.

First seems to work fine.

=IF(E6>"1NCC","North Carolina",IF(E6>"2ALA","Alabama",IF(E6>"3SCC","South Carolina")))

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Selecting 5th And 6th Characters From Right End Of String?

Feb 24, 2014

I have variable length strings, as shown in the sample cells below

TopographyTAB_FormatSP9200
TopographyTAB_FormatSP9400
OS_DataLandline
ITNTileTabTQ2286

I want to select any record where 5th and 6th character from the right hand end of the string which = either "SP" or "TQ". Where this is the case I'm then looking to truncate the string to remove the last 7 chacters.

None of what I have so far found using mid or right string appears to be particularly applicable.

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Remove Characters From Right Of String

Dec 26, 2009

I'm trying to remove everything after a specific character in a string.

I.e. change a website address to the hostname

http://www.excelforum.com/newthread.php
http://usa.excelforum.com/forum/new

to

excelforum.com
usa.excelforum.com

I'm using this formula, which strips the http:// and the www., but does not replace the characters after the first remaining "/" as the wildcard is not recognized.

=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(A2,"www.",""), A2,"http://",""), A2, "/*", "")

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Feb 11, 2009

Replace characters in a string. I have this macro:

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Feb 21, 2010

I'm importing data from the internet. The cell I'm trying to get is B8 on "Temp_Data" onto cell E3 on "Other Data". When it imports the cell into Temp_Data for some reason the cell expands, and I can't have that. I would manually copy and "Paste Special", text, into the proper cell, and that works. I can also copy the fist 7 letters in the string from B8 and paste them into E3. My code currently looks like this:

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Aug 21, 2012

I'm having difficulty figuring out how i can Trim the last 3 characters from this string

Code:
FeatureCode1 = Split(errorChecker.lstErrorMessage.List(0), " [")(0))

I tried

Code:
FeatureCode1 = Left(Split(errorChecker.lstErrorMessage.List(0), " [")(0)), 3)

But that only SHOWS the last 3 characters... how i can just cut off the last 3 characters?

I'm guessing something to do with TRIM, but not sure how to implement it?

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Dec 30, 2008

I am trying to count the characters in a string in one cell. For example, I want to count the number of "-"'s in the cell. The version number of part numbers is always the last two characters if the value contains at least one "-". However the parts have a non standard number of characters.

444444 = 0
444-44 = 1
44-44-44 = 2

There can be 0,1 or 2 "-" in the string. I can use the substitute formula to get the root part number, but I was wondering if there is an easier way. The raw data is from our ERP system, so I multiply the value by 1 to get a number if there are no "-" for the vlookup in another formula to work....

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Is it possible to format a character in a string using vba?

For example if i had a string of GGGFF, and i wanted to make the G's appear as Green font and the F's as Red font.

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I have a string like: AAJDGYE030000460. How can I remove the first character in a macro? I need to look at the second,third, and forth character

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I have a set of data in column a that consists of email addresses. These email addresses all have underscores after them, ie "abc@hotmail.com_______". It will be a different amount of underscores everytime and I don't want underscores to be removed that are actually part of the address. I had been using the find replace function through vba, ie

Range("A:A").Select
Selection.Replace What:="_", Replacement:="", LookAt:=xlPart, _
SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _
ReplaceFormat:=False

however this ofcourse removes from actual parts of the email address. Is there a way to do this?

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