Excel 2003 :: Restriction On Number Of Characters In A Cell
Jan 18, 2012Does 2003 restrict how may characters that you can put in a wrapped cell? Is there anyway to expand?
View 3 RepliesDoes 2003 restrict how may characters that you can put in a wrapped cell? Is there anyway to expand?
View 3 RepliesTrying to isolate the second number in cell.
If I have 48X144X68 in J10, I need 144.
I tried:
=MID(J10,FIND("X",J10,2)+1,3) which works, but when a cell has 65X50X68, then I get 50X where I only want 50.
The numbers can vary in size (i.e., 1 to 5 digits) but always separated by an X or some letter.
Excel 2003
I have a column of text where I need to remove all the characters to the right of the last occurance of a special character.
I think a process like reading from right to left, look for the first occurance of the special character, and return the characters to the left of this position.
If I can determine the position of the last occurance of the special character, I could use the LEFT function.
The SEARCH function is close. It finds the position of the first occurance of text inside text but it reads from left to right. I need to read from right to left.
Another approach is to examine each character one by one from right to left. If the character is not the special character, delete it. When the character is the special character, delete it and stop the process.
There is no consistency in the text. The total lengths vary. The number of times the special character occurs in the text vary. The number of characters to the right or left of the last special character vary.
I much prefer not to have the solution be some VBA because I need to share it with others who are even less capable than I am. We are using Excel 2003.
I have a worksheet with five columns (A, B, C, D and E)
The cells in Column B contain letters and/or numbers (without spaces) in no particular order.
The cells in Column C contain letters and/or numbers (without spaces) in no particular order.
I want to compare all characters in 1st Cell of Column B with all characters in 1st Cell of Column C, and display the matching characters in 1st Cell of Column D, and the character count of 1st Cell in Column D must be displayed in 1st Cell of Column E. note that multiple instances of the same character must not be treated as duplicates. When execution on 1st Row is finished then repeat procedure for Row 2, etc... Stop execution when first empty cell in Column B is located.
Example:
B1 = LJLM12
C1 = KY2MLK
B2 = ZCG4GM
C2 = X4GGGC
B3 = KTCBNG
C3 = GNBTBB
The script/code/formula must output the following:
D1 = LM2
E1 = 3
D2 = CG4G
E2 = 4
D3 = TBNG
E3 = 4
I am using Excel 2003. Y
I have a requirement where I want my list should auto increment with number only.
For example: I want to fill below text in cell and when I drag the cell( Along the column A) and fill the rows downward it should automaticallly incremented.
Data in one cell say (A1) is like 001_TCO_CM, now I want to drag data present in cell A1 and wants data in cell A2, A3, A4 etc... it should get increment like
A2 = 002_TCO_CM
A3 = 003_TCO_CM
A4 = 004_TCO_CM
and so on...any method or way present in Excel 2003 so that my series should get auto filled.
I have a sheet where I want to not enable someone to enter data in a cell unless there is data entered in a range of other cells.
Range A1:A5 compulsory data to be entered
Range A6:A20 No data can be entered can be entered unless A1:A5 is filled in
Does someone have some code that can enable me to do this?
I'd like a cell to contain only the characters "1E4" without automatically changing to 10,000.
How do I turn this automatic feature off?
I'm using excel 2003.
I have several sources of information for client files. the number format includes a reference number and a month, eg 123/11, 456/02. In some cases, the numbers may be presented including the company initials, eg ABC/00123/11. I want to make sure all numbers on all sources are the same as I am using Vlookup and this reference no to copy information from one source to another. Sometimes when I change the format Excel sees this as a date, eg 11/11 is 11-Nov, and in some cases Excel sees a fraction, eg 123/11 is 123 11ths or 123 divided by 11.
I can easily take out the reference no with a find and replace FIND ABC/ replace with . But this often results in a number with leading zeroes, eg ABC/0123/06 will leave 0123/06.
I am using Excel 2003.
I am using excel 2003. My sheet contains Times in column A and numbers in column B. I want to be able to count how many of those rows fall into time periods. Such as how many are from 8:00-9:00 AM. I do have the time column formatted as Time.
Ex:
A1: 3:40 PM
A2: 8:20 AM
A3: 8:55 AM
A4: 10:23 AM
etc.
B1: 23
B2: 34
B3: 12
B4: 35
etc.
So I want to be able to pull that between 8 and 9 AM there are 2 records.
The second part would be (in another cell) to pull the SUM of the numbers that correspond to the previous question. In the previous example it would be the SUM of all corresponding cells (Column B) that fall within the 8 and 9 AM range. Which would be 46 in this example.
I'm trying to get the number of items against a specific department which are contained in a sheet called "data", the sheet is contained in the same workbook.
There are named ranges for
Department (text)
Date_From & Date_To (in the format dd/mm/yyyy)
Band (Numeric 1 to 3)
Items (Numeric)
Using the following formula I get an #NUM error (using Excel2003)
=SUMPRODUCT(--(Department=A7),--(Date_From>=$B$2),--(Date_To
From an Excel 2003 workbook I generate some product labels. Each label has a 5 digit job number and a quantity that are passed to variables. If the quantity is 1, then I have no problems in printing my label. My problem is where the quantity is greater than 1. If a job has more than 1 item (can be up to 40 or 50) I need to add a series of letter (or letters) to the end of the job number.
For example:
Job number 12345
qty 1
number on label 12345
Job number 12346
qty 4
numbers on labels 12346A, 12346B, 12346C, 1234D
so that each printed label has a unique job number
I want to use a formula, in another cell, to convert "Friday, 30 May 2014, 3:47:16 PM" to a value. I am using Excel 2003.
View 2 Replies View RelatedI would like to perform a sum of randomly generated numbers between 0 and 6, but I want the number of independent random numbers to be dependent on another cell. I have =SUM(RANDBETWEEN(0,6) and then I get stuck. Is there a way to perform the RANDBETWEEN(0,6) a number of times stated in another cell? In this case that value is 67 but it will vary from around 5 to 150. I think there is a way to do this with macros, but I am not versed in visual basic. I am using Excel 2003.
View 2 Replies View Related I have created a workbook to input, store and part edit defects on plants and machinery by userforms. I have everything working except either picking up a number I have pre-loaded into a column or auto generating a number onto the inputting userform. I need a number in the userform to be either generated in the next empty row in column I or taken from the numbers in the next empty row I have loaded into column I. Password is snatch.
Input 2003 test1.xls
I am trying to do the following.
Monday=0
Tuesday=5
Wednesday=10
Thursday=0
Friday=5
Saturday=0
Sunday=0
Averages
Monday=0
Tuesday=5
Wednesday=7.5
Thursday=0 (I have got a value return of 7.5)
Friday=5
Saturday=0 (I have got a value return of 5)
Sunday=0 (I have got a value return of 5)
I need to work out averages for cells higher than zeros, in other words, I need to ignore those.
Also say I have got an average of 5 by Tuesday and no number yet for the rest of the week, I still get an average of 5 for all days left which I do not want.
I am using excel 2003 and formula =SUM(RANGE)/COUNTIF(RANGE,">=0").
I would also like to hide the annoying #DIV/0! error.
I need a formula that returns the Nth number from a single column that contains a small number of values within a span of 1000 cells. E.g., within 1000 cells there are 36 with numbers and the remaining cells are blank. I need to obtain the first occurrence of a number in the column, then the second, third... to the thirty-sixth. The end result would be a column with 36 numbers with no blanks in between without loosing the correct order of the numbers.
I have excel 2003 and have been tooling around with the index and lookup functions with no success.
I am having difficulty calculating the number of total overlapping days between several date ranges (6 of them to be precise)
I am using Excel 2003 and my data looks like this:
Sent Out (A) - Received (B)
01/06/2010 13:00 - 30/06/2010 13:00
02/06/2010 13:00 - 16/06/2010 13:00
09/06/2010 13:00 - 10/06/2010 13:00
21/06/2010 13:00 - 25/06/2010 9:44
23/06/2010 13:00 - 25/06/2010 10:56
23/06/2010 13:00 - 29/06/2010 13:00
I really can't wrap my head around the idea of calculating overlap (in network days) between six date ranges and was wondering if any of you would have a solution to this problem.
I am having difficulty calculating the number of total overlapping days between several date ranges for each item in another sheet which has unique items
I am using Excel 2003 and my data looks like this:
Sheet-1 Sheet-2
Item - Sent Out (A) - Received (B) Unique Item Number of days excluding overlap days
1234 01/06/2010 - 30/06/2010 1234 -
4321 02/06/2010 - 16/06/2010 4321 -
1234 09/06/2010 - 10/06/2010
4321 21/06/2010 - 25/06/2010
1234 23/06/2010 - 25/06/2010
4321 23/06/2010 - 29/06/2010
I have used the below formula found from the earlier post but need to add a condition calculating the days for each item.
=SUM(IF(MMULT((NETWORKDAYS(ROW(INDIRECT(MIN(INT(A2:A7))&":"&MAX(INT(B2:B7)))),2)<6)
*(ROW(INDIRECT(MIN( INT(A2:A7))&":"&MAX(INT(B2:B7))))>=TRANSPOSE(INT(A2:A7)))
*(ROW(INDIRECT(MIN(INT(A2:A7))&":"&MAX(INT(B2:B7))))<=TRANSPOSE(B2:B7))+0,ROW(A2:A7)^0),1))
I need a VBA code to find the number of characters in each cell and display the result in next column.
For Ex:
ColA:
HI
who
There
output should be
ColA,ColB
HI,2
who,3
there,5
I have shown example for 3 rows only but there are chances like it contains more than 3 rows(Dynamic rows).I tried by creating Range variable but I couldn't succeeded.
in ROW 1 I have columns A thru AD populated with a number in each cell. what I need to do is take that number and fill the below cell with the number times a set character. for instance, A1 has "4" in it, so I want A2 to look like "----"
View 3 Replies View RelatedI am looking too limit a cell too only contain 5 or 7 characters.
I can limit too one length, i.e. just 7, using the data validation function.
I'm creating a spreadsheet (Excel 2003) in which a user enters data in several cells, each of which will permit different numbers of characters (to include spaces). For example, in the first cell, the user will be limited to 50 characters, in the second cell, the limit is 30 characters, and so on.
I found the data validation error alert feature, but want to give the user a cue that the entry is too long so they know to stop typing before moving to the next cell. If they only are alerted when they finish making the entry, they might not take the time to properly reconstruct the entry to meet the size limitation. I'm trying to make this more user-friendly.
Is there a way to set up the worksheet so the user knows that the entry is approaching the character limit? For example, each character filling an individual cell or having a display appear with a count-down for the number of characters remaining in the limit, or something similar.
I have a column that is made up of postcodes, lat, long, eastern, northern data eg: SK10 5BA, 53.291013, -2.096675, 393652, 377121
And I want to end up with a column containing the lat (53.291013) and another containing the long (-2.096675).
I have worked out to use formula's to remove a certain number of characters from the left and right of the cell, but the challenge here is the postcode at the begining of the data, can be varying in length.
know of a formula that will let me copy a certain number of characters within the cell, but counted from the right, as the eastern and northern numbers are always the same length.
I have a cell (A1) with a number in it. The number has 30 digits. I need a formula for (B1) that will enter the same number as A1 but restrict the number to 28 digits. Basically I need it to cut off the last 2 digits.
View 3 Replies View RelatedI need to do a macro to do this:
Count the numbers of the characters in a cell.
The number of characters must be appear in another cell.
This number must be refresh when you type the key, not when you push enter.
I have a description for a couple trucks in my inventory, rather than retyping all the mileage, I would like to select the miles out of the description.
Example:
14.0 Detroit 515 HP, 10 Spd OD, Engine Brake, Air Ride Suspension, 3.42 Ratio, 234" WB, 70" Double Deck Condo, 22.5LP Tires, Aluminum/Steel Wheels, Tandem Axle, 12,000# FA, 40,000# RA, 259,000 Miles
I have tried the find, left and mid formulas but haven't put something together to work just right. I would like to select the 7 characters to the left of "Miles".
Does anyone have any ideas?
i have a problem counting the number of characters in each cell in column "A" in a sheet and checking if number of characters in a cell exceeds 5 characters.
View 10 Replies View Relatedi have a problem counting the number of characters in each cell in column "A" in a sheet and checking if number of characters in a cell exceeds 5 characters.
View 8 Replies View Relatedtrying to limit the number of characters entered in a cell.
I clicked on Custom then =LEN(A10)=6 which works when i enter more or less than 6 characters, however it lets you paste in something which has more than 6 charters.
way to remove a varible number of characters in a cell? My example is in cell range A1:Z1 and each cell could have a different number of characters.
Smith, Sally 5348
Jones, Johnathan 7893
Doe, Mike 2223
What I would like to do is remove the second space and the numbers that follow to get a result of
Smith, Sally
Jones, Johnathan
Doe, Mike