Search For Decimal And When Found Pass Row Number To Rest Of String?
Feb 12, 2014
I am trying to search through column "I" for numbers that are decimals, when the first decimal is found, use the row number that the first decimal appears in the string that populates the bookmarks stored in a word template I have created. The code I have so far checks for the decimal and then populates the bookmarks, however it requires me to input the ranges manually, meaning I can set them as the first row in my tabel. But if the decimal appears in the second row and not the first I'm bookmarking the wrong data. Here is the code I have so far;
[Code] ........
View 3 Replies
ADVERTISEMENT
Apr 11, 2013
I have a spreadsheet which has "Employee: [agent 1 name]" in column A and it may or may not have the word "Break" in the same column before it mentions "Employee: [agent 2 name]". The amount of data between agent 1 and agent 2 varies and am needing code which will insert a row above "Employee: [agent 2 name]" if "Break" is not found, and add the word "Break" in column A on the inserted row. I would need this to loop through the spreadsheet until all 100+ agents have been searched.
I'm also needing this done for the word "Meeting" and would insert a row 2 rows above the next agent.
View 6 Replies
View Related
Feb 8, 2012
I manage to do a proper search and the return value is correct, but the problem is when I don't get the correct value excel gives me an error, what I can add to make the result just to give me MsgBox "Not found"?
Code below:
Set Ran = Worksheets(2).Range("A:A").Find(CompName, lookat:=xlPart)
If Not Ran Is Nothing Then
MatchRow = Ran.Row
MatchCol = Ran.Column
End If
View 5 Replies
View Related
Jul 21, 2007
I am building a Workbook which takes data from SheetA and inserts it into SheetB.
Part of the data is only entered when a positive value exists.
I then do an export from SheetB.
The problem is that I need to get the column number and pass it to the cell reference based on the field name in row 1.
Dim sFindstring As String
Dim rFindcell As range
Dim iR As Integer
Dim iC As Integer
sFindString = " Find this string in the cell"
'Using cells find the findstring
Set rFindCell = Cells.Find(What:=sFindString, After:=[A1], LookIn:=xlValues, LookAt:=xlPart, SearchOrder:=xlByRows, SearchDirection:=xlPrevious)
'OK so look here
iR = 3
'I am trying to pick up the column number
iC = rFindCell.Column
rFindCell throws an object or with block variable not set error. Is there some property that I need to set.
View 3 Replies
View Related
Aug 13, 2007
I have the following code to search for serial numbers.
Private Sub CommandButton1_Click()
Dim Message, Title, Default, SearchString
Message = "Enter Serial Number" ' Set prompt.
Title = "Find Serial Number" ' Set title.
Default = "" ' Set default.
' Display message, title, and default value.
SearchString = InputBox(Message, Title, Default)
'SearchString = "Rob"
Set S = Sheets.Application
For Each S In Application.Sheets
With S.Range("A1:IV65536")
Set f = .Find(SearchString, MatchCase:=True, LookAt:=xlWhole, LookIn:=xlValues)
If Not f Is Nothing Then
f.Offset(, 3) = Date
Exit For
End If
End With
Next S
End Sub
I would like to amend this so that (a) if the serial number is not found I get a message box saying "Serial number not found" and (b) if the serial number is found, I would like it to highlight the relevant row (after inserting the date).
View 9 Replies
View Related
Feb 16, 2008
i have a workbook with several sheets in it. i would like to make a userform were i could put a number in a text box eg E045698.then use a command button to search all the worksheets for that number and display the sheet number where that number is in another textbox.
View 5 Replies
View Related
Jan 7, 2010
I have a column of numbers each have a 0. infront of them (example 0.2346
0.5698). I want to pull the number from the right until it hits the decimal sign. So for the two above the result would be 2346 and 5698
View 2 Replies
View Related
Aug 23, 2013
I am trying to count the number of specific words contained in a specific cell. If my data were static, and the list of keywords was short, there are many solutions such as using multiple instances of the length function as proposed by @shg here.
Suppose I have the following sheet: (column C is what I am trying to achieve)
A
B
C
1
[Code]....
That is, C2 will tell that B2 contained 3 of the keywords (1X beautiful, 2X happy) and so on.
View 9 Replies
View Related
Jun 3, 2008
Why when I want to use a varaible with a value like that 2.1, 0.9, 3.5 in a code to create a formula gives me an error? How to get it work?
Sub Code1()
Dim k As Double
k = 2.1
Range("h11").Formula = "=" & k
End Sub
Strange, but it works well if k is an integer with no Decimal Fraction, like 1, 2, 5, 11 ..
View 4 Replies
View Related
Aug 13, 2009
I have a vba macro that takes data from one workbook and pastes it into another workbook. In doing this I have declared a few variables of type single (I only need two decimal precision). However, when I copy the values from the cells on the source workbook and paste them into the target workbook, the numbers end up having 12 decimal places. Ultimately, this extra precision causes my totals to be off by .01 or more after a while. I have tried rounding the number as I pull it off the source workbook into the variable, but that didn't matter. How do I solve this problem? Code for pulling data from source workbook:...
View 2 Replies
View Related
Jun 10, 2007
I need a formula to multiply only the decimal number in a cell and not the integer. For example: the number in the cell is 57.3615. I want to multiply .3615 only.
View 2 Replies
View Related
Jan 31, 2008
Find a short text string in a column of longer text strings and when that short text string is found return the longer text string that matches.
View 3 Replies
View Related
Jan 11, 2009
I have the following which is in a column.
View 9 Replies
View Related
Jul 3, 2014
I am trying to pass a string to a function requiring a ParamArray. See below
Code:
Declare Function LibFunc1 Lib "FuncAddin" (ByVal vtSheetName, ParamArray Mylist() As Variant) As Long
Sub testsub()
Year = 2013
Period = December
MyStr = "Year#" & MyYear & """", "Period#" & MyPeriod & """"
LibFunc1("Sheet1", MyStr) 'how to declare string so it can be passed as ParaArray?
End Sub
View 1 Replies
View Related
Oct 23, 2013
how to specify a file extension type for a browseforfolder part of what i've been doing.
It's not calling correctly as i'm not sure how to feed the inputData string back into the main.
Obviously there's probably better ways of doing this, but can my way be corrected easily?
I've been looking into ByVal and ByRef, but have only seen examples goin from main to the sub and not the other way.
Code:
Sub Main()
Dim strFolderName As String
Dim strFolderTest As String
Dim FRCntrHiLim As Variant
MsgBox "before calling inputbox"
Call InputBoxTest(inputData) '
View 4 Replies
View Related
Aug 3, 2006
Have a file lets say is named
sample.xls
Does anyone know how to retrieve the name of the file in VB?
just the name and put it in a string?
View 3 Replies
View Related
May 29, 2013
I want to display a string to users. Normally I would do that using message boxes. But that would not give me enough control over the font size, and I want to display using font size 48.
I could have used global variables, but that is not a good coding way. The other way of doing that is using property procedures. I could pass a string variable to a Label control on the form and then could format it.
View 9 Replies
View Related
Mar 31, 2014
I am trying to do a sort of index match thing using VBA. What I am attempting to do is to use the prefix of a long number and try to find that exact prefix in a string array, and output that string array value. So this is what I have so far as a test:
[Code].....
So I can match the text exactly so if I put PREFIXB in cell A1 in this example, i will get the msg box saying "YES", but if I make it PREFIXB1231k4j3jj1kj32cj, it will display "NO". I want to get it so that PREFIXB will be displayed in the cell that I put the formula in. So if A1 = "PREFIX1AAA100CF" and cell B1 = "=ABC(A1)", cell B1 will display "PREFIX1AAA".
Now the thing is that these prefixes can have different lengths, but will never encompass the exact prefix of another. So if I had a prefix of: PRE1AB, I won't have a prefix of PRE1A.
View 2 Replies
View Related
Apr 28, 2014
I am currently using this macro for deleting a row if a string is found:
[Code] .....
But I would like to be able to not delete that row, but also to delete the 13 row above that row, including that row too.
ROW 1
ROW 2
ROW 3
ROW 4
ROW 5
ROW 6
ROW 7
ROW 8
ROW 9
ROW 10
ROW 11
ROW 12
ROW 13
ROW 14 - NO MONEY
All this from No Money up to Row 1 will be delete, and loop.
View 3 Replies
View Related
Feb 29, 2008
I am looping in Excel to find "NUMBER OF EMPLOYEES". IF found I want to go up one row and replace the first 4 digits with " 9ZZ". The Line 1 data will alway be different so I just want to replace the first 4 digits. I don't want it to effect the rest of the line.
Example:
Line 1 - 100 6300 BRCH TOTALS
Line 2 - NUMBER OF EMPLOYEES
RESULTS NEEDED:
Line 1 - 9ZZ 6300 BRCH TOTALS
Line 2 - NUMBE OF EMPLOYEES
View 9 Replies
View Related
Aug 30, 2007
I have a workbook with a sheet for every month. I have a searchbox searching for a client and jumping to that location. The problem I am having is that it takes me to the last occurence in the workbook if there is more that one client with the search criteria. Do you have any suggestions for a searchbox that whould take me to the first occurence and give me an option to go to the next occurence in the workbook. Please see the code below that I am using currently using.
Private Sub CommandButton1_Click()
Dim ws As Worksheet
Dim cl As Range, rng As Range
For Each ws In ActiveWorkbook.Worksheets
Set rng = ws.UsedRange
With rng
Set cl = .Find(Me.TextBox1.Value, LookIn:=xlValues)
If Not cl Is Nothing Then
Application.Goto cl
Else
View 7 Replies
View Related
Sep 5, 2007
I need a VBA code that will search column H for any value that DOES NOT start with "9" (this is a character field). If it finds a cell that doesn't start with "9", I would like it to delete the entire row. It will need to repeat this process for every cell in Column H that has a value and then stop.
View 7 Replies
View Related
Aug 16, 2012
I'm writing a macro that will automatically change the display in a column of cells.
The input in the cell would be a decimal value, (e.g. 1, 1.25, 1.5, 1.75, 2). As of now, I think the only input options are whole numbers and 1/4, 1/2, 3/4 fractions.
After inputting the decimal value, the cell should update to display the value as the following string format :
Input: 1.25
Displays: 1-1/4"
The purpose being to enable fast data entry while displaying in the desired format.
Here is where I know to begin for the automatic update:
Code:
Sub Worksheet_Change(ByVal Target As Range)
Application.EnableEvents = False
'
'
'Code
'
'
Application.EnableEvents = True
End Sub
View 6 Replies
View Related
Jun 4, 2014
I am using this code to remove a row if string is found, however, I would like to know how can I set it to do the same for all the worksheet in the same excel?
[Code] ....
View 5 Replies
View Related
Jan 22, 2014
I have data in cells B2:E2 and this can go down 100+ rows.
In column B i have invoice numbers but some cells contain the word "Deposit".
I have sorted this data so that the invoice numbers appear first and then all the Deposits.
I need a code to find the first instance of the word "Deposit" and to insert a row so that all the invoices and Deposits are seperated by a single row.
View 4 Replies
View Related
Aug 28, 2007
I need a VBA script that can display a search box on multiple sheets within the same workbook similar to using ctrl + F and search values in column B only. If there is text or the row happens to be empty then it should skip that and only search numbers. Also the numbers in column B range from 50000 to 89000 and if there is a wrong number entered then I want to have a pop up box saying Error: invalid value or something like that.
Sub search_box()
Range("B49000").Select
Cells.Find(What:="some#", After:=ActiveCell, LookIn:=xlValues, LookAt:= _
xlWhole, SearchOrder:=xlByColumns, SearchDirection:=xlNext, MatchCase:= _
False, SearchFormat:=False).Activate
Cells.FindNext(After:=ActiveCell).Activate
End Sub
View 8 Replies
View Related
Sep 8, 2007
In a large spreadsheet that receives external data, I have codes (U, N or V) allocated at various times to different rows as shown in sample worksheet attached. Elsewhere in the spreadsheet, I need to display (for later export) these codes along with their respective number in a sorted list. Please review the attached:
In the spreadsheet you'll see a column of codes, the next column is the data reference number, then to the right is three columns, one for each code. As displayed in the sample book attached, each Code column is to display the data reference number (from column 2)that matches that column's code.
What formula can I use to list these numbers in the appropriate columns?
View 5 Replies
View Related
Oct 18, 2007
I was looking at this VBA code the other day and i was wandering what i meant. I thought if somone could expliane line by line,
Sub CommandButton1_Click()
Dim ThisAddress$, Found, FirstAddress
Dim Lost$, N&, NextSheet&
Dim CurrentArea As Range, SelectedRegion As Range
Dim Reply As VbMsgBoxResult
Dim FirstSheet As Worksheet
Dim Ws As Worksheet
Dim Wks As Worksheet
Dim Sht As Worksheet
View 6 Replies
View Related
Oct 23, 2011
I have a problem that when I try to convert text to number and format the number without 2 decimal places as seen on the link I have given below, Instead of 1607.947, I get 1607947. I have Excel 2010 loaded. The details are in below picture.
[URL]
View 4 Replies
View Related
Feb 9, 2013
How can I drop the whole number part of a number and leaving only the decimal part of the number. Then multiply the decimal part of the number with a number. Then repeat this in a sequence. The object is to convert Lat and Long decimals to Hr. Min. Sec.
eg. 53.535663 .535663*60=32.13978 .13978*60=8 53 32 8
eg. 113.352640 .352640*60=21.1584 .1584*60=9 113 21 9
eg. 113.306579 .306579*60=18.39474 .39474*60=23 113 18 23
View 1 Replies
View Related