Show Characters Left Of Delimiter (,)
Feb 25, 2009I need a formula, that will, Show the Characters Left of Delimiter (,).
for example:
CABLE, UD SECONDARY #4 DPLX AL
result:
CABLE
I need a formula, that will, Show the Characters Left of Delimiter (,).
for example:
CABLE, UD SECONDARY #4 DPLX AL
result:
CABLE
I have one field that contains a city, state and zip. I need to extract only the city. I need the proper function to ask Excel to go to the cell and return all the text beginning the first place on the left, continuing until it reaches a comma. The number of places in the city will always vary.
I have a series of alpha numerics items in Cells A1:A999 (i.e AB0001 to AB0999). I need to be able to perform a search the range (A1:A999), and extract items that do not conform to the standard AB prefix. Example, an item of BC0001 could be present in the range. I would need to have that item, either highlighted or displayed in a different column.
View 2 Replies View RelatedI am looking to write a formula in an excell cell to veiw some of the wording in another cell. I know how to say that i want to see the first or last "x" characters in a cell.. But how do i say that i want to see all the info/wording in a cell except the last "x" characters..
View 4 Replies View RelatedI need VBA coding that starts in a cell, moves 5 columns to the left, and then copies the left 8 characters of the string. The Macro should end there, but I'm hoping to be able to then paste those 8 characters elsewhere, say a different programme or web page.
I can move the cell no problem:
ActiveCell.Offset(0, -5).Select
But how to then copy those left 8 characters so it stays in the clipboard at the end of the macro?
The formula needs to be non-cell specific, i.e. I need to use the above selection and NOT a cell name such as A5 etc.
I am trying to write a function that finds and breaks a cell about the first space.
Worksheet is:
=LEFT(name,FIND(" ",name)-1)
Have tried...
Function Firstname(name)
Dim Space As Integer
Set Space = .Find(" ", name)
Firstname = Left(name, Space)
End Function
and also...
Function Firstname(name)
firstname = left(name,find(" ",name)-1))
End Function
I am attempting to utilize the Mid, Left, and Right functions to parse out data returned in a single cell. There are twelve months of data returned with the "title" listed after. I would like to be able to FIND the title and return a specific number of characters of data to the LEFT not the right (as Mid seems to do).
EX.
Cell A1{ 1 2 4 5 3 5 TITLE1 1 2 3 6 7 4 5 TITLE2 3 4 5 2 4 5 TITLE 4 }
Cell A2{ 1 2 4 5 3 5 TITLE2 1 2 3 6 7 4 5 TITLE3 3 4 5 2 4 5 TITLE 4 }
I would like to be able to search each cell for the "TitleX" then parse data out to the left of that title (and if not found, return "").
There are too many different Titles to use IF statements and I cannot change that the data comes to the left of the title.
I'm trying to figure out why i'm getting this error: "Object variable or With block variable not set" for this
Sub Macro3()
Dim cel As Range
Dim str1 As String
Dim SearchThing As Range
Set SearchThing = ActiveSheet.Range("I34")
str1 = Left(SearchThing.Value, Len(SearchThing) - 4)
cel.Value = str1
End Sub
The error is specifically with this line
cel.Value = str1....................
I want to take a lot of text fields with alphanumeric characters ie. " '49560-960-A908 "
(always beginning with the character " ' ") and display in another cell position 2 thur 6 ie. "49560"
I have a file that contains 3,500 cells with alphanumeric characters...always beginning with ' but I need the 1st 5 numbers after the ' in a second separate column
I am using (in Column "B") the formula: =IF(A2=A3."",1), copied down as required, to uniquely identify entries in Column "A". In this instance "10", "10A", "10B" and "10C" located in "A5" through "A11" are viewed as the same. Is it possible to have the formula recognize the enties in "A5:A11" as a unique entry and therfore have "1" entered into cell "B11"? The suffix, if used will always be A thorugh Z.
View 9 Replies View RelatedI've got a long list of account numbers of varying length and ultimately need to add a dash and a dot into these numbers. Here's an example
12345678 to> 1-2345.678
123456789 to> 12-3456.789
1234567890 to> 123-4567.890
The standard format is always 3 numbers after the . and 4 numbers between the - and .
I can get to this by doing a series of functions starting with this:
=LEFT(A1,LEN(A1)-3)&"."&RIGHT(A1,3) to get 12345.678 or 123456.789
copy/pasting that value into another field and then doing this
=LEFT(E1,LEN(E1)-8)&"-"&RIGHT(E1,8) to get the results above
I can't quite figure out the format to combine the multiple steps/functions into one so that I'm not copy/pasting values and re-doing the function.
I can do this in Excel, but I don't seem to have a single example to hand of how, using VBA, to extract all characters up to but not including, the first space character in a cell.
View 9 Replies View RelatedI have the following formula which doesn't work:
=COUNTIF(LEFT(proposedenter,7),LEFT(F127,7))
proposedenter is just a named range. I can see this is wrong but how do I base the count criteria on the left 7 characters of an item that is matched in the range?
I have numbers in a cell such as 1/25, 4/31, 12/35 etc I have the current formula to extract the left or right number but when there is only a single digit it also includes the / is there a way of eliminating this.
The numbers vary from 1 to 2 digits.
My current formula is =IF(C15<18,LEFT(E8,2))+IF(C15>18,RIGHT(E8,2))
I only want it to show the number not the forward slash
I have a very large workbook with multiple sheets and use macros to copy and paste all data as values, then delete some rows and columns depending on certain criteria. This starts at cell A1 and works right, then down.
This is then saved as a copy and distributed to a wide audience.
The problem is that when each page is opened up, the data shown is the bottom right of the whole sheet instead of the top left ( Panes are frozen for row and column headers).
I have three search boxes in XL , two are search from and to dates and the other is search be ref.
I can currently search by dates and ref but would like to show all records in the specified dates if the ref field is left blank.
I am using the query writer and referencing back to cells in XL. I don't use the wizard or SQL. I have tried many options and think I should be using a OR statement with a wildcard but can't seem to get the result, does the wildcard just show the blank cells in the actual data?
How to show progress bar for both percentage completion and time left.
The code below is already created with percentage completion. Just to add time left.
[Code] ........
Is there a way to show the Vertical axis on both right and left side of the graph or at least on the Right hand side?
View 5 Replies View RelatedIn column B I only want to show the results from Column A if the character count equals 3. In Column C I only want to show the results from Column A if the character count is greater than 3
Example:
Column A
ast
john
julie
tyw
nhy
frank
I've two columns of numbers in Col J and Col P how can I make cell P2 characters that are not in J2 show the difference by making them bold
J2 = 00342 P2 = 0034211
J3 = 00344 P3 = 003443
J4 = 233 P4 = 23377
Till last row with data in the sheet.
Is is possible to get a dropdown list to show the actual characters as they appear in windings or marlett as shown in the source? When I try I am just getting a load of u's with accents and dots above.
I am trying to do this without using a macro.
I have a 2010 excel sheet containing 14 columns and 45082 rows in total. I am quite illiterate when it comes to writing macros but I know that what I need can be achieved with a set of codes.
To be more clear, I inserted two tables below. The first one represents the current data structure, and the second one is the way I want my data to look like.
Current data structure looks like
Variable 1
Variable 2
Variable 3
[Code].....
I am having trouble filling a formulae series to the left on one spreadsheet, the fomulae being references to another sheet.
For example, I have two sheets 'Mtce Options' and 'Base Case'. In 'Mtce Options' I have the following formulae
A B C
1='Base Case'!A15='Base Case'!D15='Base Case'!G15
I want to fill to the left, incrementing the column references by a factor of 2 each time, eg. next two should be ='Base Case'!J15 and ='Base Case'!M15.
However, if I autofill to the left by highlighting A1, B1 and C1 or just B1 and C1 all I get is an inappropriate reference such as ='Base Case'!D15 or ='Base Case'!F15, respectively, in D15.
I want to grab everything left of the last occurrence of "." in a string, and in the next cell everything right of the last occurrence of "."
so say the string is 111.111.1.222
column 1
111.111.1
column 2
222
my current code (which works, but its messy) for the first cell is
to concatenate across columns, say J through Q, (some of which are blank) and have the results delimited by a comma without returning anything for columns that might be blank. So R660 would read "0263B001A,FX9,FX-9,FX10,FX-10" and R669 would ...
View 9 Replies View RelatedI'm looking for a worksheet function that will allow me to separate into another cell the characters between the second and third slash in the source cell. The number of characters varies, but the value I want is always between the second and third slash.
View 3 Replies View RelatedI have a column with cells that look like: XYZ - JobABC - Area 1-A. I'd like to split the column into to and have it look like: XYZ <next column> Job ABC - Area 1-A
Normally I'd use the text to columns function and "-" as delimiter, however, there are other instances of "-" which I do not want separated. Note that the XYZ can vary in length and therefore fixed width will not work either. I have attached a small sample with the different variations that I could encounter.
I'm trying to check that part of a delimited field has been entered with a date format of DD-MON-YYYY and I cannot work out how to do this.
The following is what I have so far:
Public Sub date_val()
Dim rCell As Range
Dim RowCounter As Integer
Dim ColumnsChecked As Integer
Dim InvoiceDate As Date
For Each rCell In Range("B14:B5000")
RowCounter = rCell.Row
ColumnsChecked = 41
If UBound( Split(Cells(RowCounter, ColumnsChecked).value, "|")) <> 11 Then
MsgBox "Incorrect number of delimiters. Please correct", vbCritical, " Validation"
Cells(RowCounter, ColumnsChecked).Select
End
Else
End If
I receive multiple worksheets containing transaction data with multiple numbers of row and columns. The data columns contain varying types of information like: price, quantity, location1, location2, loading dock, transaction date, buy/sell, purchaser, seller, currency unit, etc.
I have a need to concatenate into a single cell in a blank column, data from a number of cells in each row -- sometimes two cells, sometimes more. In some instances, I'd like to concatenate data for location1 and location2 with a delimiter like a semicolon-and-a-space to create a cell with: "location1; location2" Or in another instance, I'd like to concatenate multiple cells in a row, like: "location1; price; quantity; transaction date", etc.
I'm looking to create a macro that, with the cursor in a blank cell in a blank row, would open an input box, ask a user to select with the cursor the cells in the row to concatenate and then concatenate them into the blank cell in the row.
Ideally, the macro would populate the entire blank column with the concatenated data for the group of selected cells (from the same columns as in the row where the cells to be concatenated were selected) for each row where there is data. It is also possible that some cells in some rows of the selected columns would contain no data. In that case, I'd be looking to return just the delimiter, like: "location1; ; quantity; transaction date"
Right now, with no macro, I do it by hand like this:
To concatenate into cell I6, the contents of cells A6, B6, G6 and H6, I do a "=CONCATENATE(A6,"; ",B6,"; ",G6,"; ",H6)" in blank cell I6, but I'm looking for a way to do it fast in a macro that would fill in all of Column I.
Is there an Excel formula to remove the spacebar + characters in red, as shown below? I need to be left with only the last name, first name and the semicolon.
Mouse, Mickey ;
Microsoft Outlook has changed the way that email addresses from the global addressbook copy and paste (from version 2003 to version 2010).