I want to take a lot of text fields with alphanumeric characters ie. " '49560-960-A908 "
(always beginning with the character " ' ") and display in another cell position 2 thur 6 ie. "49560"
I have a file that contains 3,500 cells with alphanumeric characters...always beginning with ' but I need the 1st 5 numbers after the ' in a second separate column
I have found a very useful UDF for removing non-alpha characters from strings. (See below, Credit for posting to Stanley D Grom - Ozgrid post ´Removing Non-alpha Characters From Text´).
Option Explicit
Private Function RemoveCharacters(InString As String) As String
Dim intLoopCounter As Integer
Dim intStringLength As Integer
Dim intASCIIVal As Integer
intStringLength = Len(InString)
InString = LCase(InString)
For intLoopCounter = 1 To intStringLength
intASCIIVal = Asc(Mid(InString, intLoopCounter, 1))
If intASCIIVal >= 97 And intASCIIVal <= 122 Then
RemoveCharacters = RemoveCharacters + Mid(InString, intLoopCounter, 1)
End If
Next intLoopCounter
End Function
Two requests:
1. Could the UDF be modified such that any part of a string contained within brackets is also removed (e.g. "NLGA High Street (West-Enfield), EN6" becomes "nlgahighstreeten")?
2. Can an argument be added to the format of the UDF, such that numbers (0 to 9) are either included or excluded (e.g. RemoveCharacters(A1,1) where the argument ´1´ would include any numbers (0 to 9), so "NLGA2003 High Street (West-Enfield), EN6" becomes "nlga2003highstreeten6")? ´blank´or ´0´would exclude these numbers, i.e. would return "nlgahighstreeten"
I am blanking out. I want to pull the data out until a space (one formula from the left and one from the right). Ithink it's a mid function but not sure.
Example
John, Doe
I would like to get:
John,
and
Doe
I'm looking for a formula that pulls the text from a cell unti it hits a space. I'm using the formula below but keep getting #VALUE results. B1: =LEFT(A1,FIND(",",A1,1)). I know it's not that hard but can't figure it out.
View 4 Replies View RelatedIn a1 i have 100.888 and a2 122.222 and a3 122.555UK,(and so on) in column b i want just want the number and not the uk, i have tried =left(a1,7) which works until a3 then it give me characters 122.555 and not the number/value 122.55. I need it as a value to use the vlookup, how do i do it?
View 3 Replies View RelatedI have a series of alpha numerics items in Cells A1:A999 (i.e AB0001 to AB0999). I need to be able to perform a search the range (A1:A999), and extract items that do not conform to the standard AB prefix. Example, an item of BC0001 could be present in the range. I would need to have that item, either highlighted or displayed in a different column.
View 2 Replies View RelatedI am looking to write a formula in an excell cell to veiw some of the wording in another cell. I know how to say that i want to see the first or last "x" characters in a cell.. But how do i say that i want to see all the info/wording in a cell except the last "x" characters..
View 4 Replies View RelatedI need a formula, that will, Show the Characters Left of Delimiter (,).
for example:
CABLE, UD SECONDARY #4 DPLX AL
result:
CABLE
I need VBA coding that starts in a cell, moves 5 columns to the left, and then copies the left 8 characters of the string. The Macro should end there, but I'm hoping to be able to then paste those 8 characters elsewhere, say a different programme or web page.
I can move the cell no problem:
ActiveCell.Offset(0, -5).Select
But how to then copy those left 8 characters so it stays in the clipboard at the end of the macro?
The formula needs to be non-cell specific, i.e. I need to use the above selection and NOT a cell name such as A5 etc.
I am trying to write a function that finds and breaks a cell about the first space.
Worksheet is:
=LEFT(name,FIND(" ",name)-1)
Have tried...
Function Firstname(name)
Dim Space As Integer
Set Space = .Find(" ", name)
Firstname = Left(name, Space)
End Function
and also...
Function Firstname(name)
firstname = left(name,find(" ",name)-1))
End Function
I am attempting to utilize the Mid, Left, and Right functions to parse out data returned in a single cell. There are twelve months of data returned with the "title" listed after. I would like to be able to FIND the title and return a specific number of characters of data to the LEFT not the right (as Mid seems to do).
EX.
Cell A1{ 1 2 4 5 3 5 TITLE1 1 2 3 6 7 4 5 TITLE2 3 4 5 2 4 5 TITLE 4 }
Cell A2{ 1 2 4 5 3 5 TITLE2 1 2 3 6 7 4 5 TITLE3 3 4 5 2 4 5 TITLE 4 }
I would like to be able to search each cell for the "TitleX" then parse data out to the left of that title (and if not found, return "").
There are too many different Titles to use IF statements and I cannot change that the data comes to the left of the title.
I'm trying to figure out why i'm getting this error: "Object variable or With block variable not set" for this
Sub Macro3()
Dim cel As Range
Dim str1 As String
Dim SearchThing As Range
Set SearchThing = ActiveSheet.Range("I34")
str1 = Left(SearchThing.Value, Len(SearchThing) - 4)
cel.Value = str1
End Sub
The error is specifically with this line
cel.Value = str1....................
I am using (in Column "B") the formula: =IF(A2=A3."",1), copied down as required, to uniquely identify entries in Column "A". In this instance "10", "10A", "10B" and "10C" located in "A5" through "A11" are viewed as the same. Is it possible to have the formula recognize the enties in "A5:A11" as a unique entry and therfore have "1" entered into cell "B11"? The suffix, if used will always be A thorugh Z.
View 9 Replies View RelatedI'm trying to pull text out of a middle of a long string of data located within one cell. The string is not always the same size and the text I need to pull out is not always in the same spot
For example - in this string
source=google&adgroup=Jimmy Bop (Broad) >>/yes/klingon/GetStarted.aspx >>/finace/success.aspx?
I want to pull out the text "Jimmy Bop (Broad)
It will always be between "adgroup=" and ">>/" (although sometimes the character ">>/" will appear multiple times within the string.
I am trying to create a data sheet to simplify the filling of corporate documents on our company computer systems. I have a working system, flawed, but working. What I want is to simplify it and correct some mistakes I made when I first made it. At the moment the priority is the field for our serial numbers. They vary from 1 to 10 digits in length with a alpha-numeric system. Some serial numbers even include hyphens, but the hyphens need to be removed for the forms. My system uses a modified form to allow for hyphens, but my boss wants them removed. ^^'
Anyways, the serial number of an item is entered into the data sheet field and my macro breaks down the serial number piece by piece. On the form the there are ten blocks for each digit of the serial number and I have coded the macro to put one digit per box. The trick is that the serial number must be right aligned and any empty fields must stay empty. This is where my request comes into play. I have already programmed the macro to do everything required except remove hyphens. The problem is that it is a REALLY long macro using If Then End statements to to compensate for the varying lengths of a serial number. Is there anyway to simplify this task?
Public Sub SerialNo()
Sheets("Data").Select
Dim SerialNo As String
Dim SerialNo1 As String
Dim SerialNo2 As String
Dim SerialNo3 As String
Dim SerialNo4 As String
Dim SerialNo5 As String
Dim SerialNo6 As String
Dim SerialNo7 As String
Dim SerialNo8 As String
Dim SerialNo9 As String
Dim SerialNo10 As String
I've got a long list of account numbers of varying length and ultimately need to add a dash and a dot into these numbers. Here's an example
12345678 to> 1-2345.678
123456789 to> 12-3456.789
1234567890 to> 123-4567.890
The standard format is always 3 numbers after the . and 4 numbers between the - and .
I can get to this by doing a series of functions starting with this:
=LEFT(A1,LEN(A1)-3)&"."&RIGHT(A1,3) to get 12345.678 or 123456.789
copy/pasting that value into another field and then doing this
=LEFT(E1,LEN(E1)-8)&"-"&RIGHT(E1,8) to get the results above
I can't quite figure out the format to combine the multiple steps/functions into one so that I'm not copy/pasting values and re-doing the function.
I can do this in Excel, but I don't seem to have a single example to hand of how, using VBA, to extract all characters up to but not including, the first space character in a cell.
View 9 Replies View RelatedI have the following formula which doesn't work:
=COUNTIF(LEFT(proposedenter,7),LEFT(F127,7))
proposedenter is just a named range. I can see this is wrong but how do I base the count criteria on the left 7 characters of an item that is matched in the range?
I would like to count the number of cells that contain a word. My table looks as follows:
BDL1,500BDL3,135BDL2,1004.31,400254,6001.41144
In Column 1 (left column) I have 3 cells that contain the alphanumeric value "BDL". This would yield a non-numeric count of "3". Column 2 would yield a count of "0". I hope I'm being clear. Anyone hav an idea?
I am a beginner to VBA and Macros, and I have a fairly complicated macro that I am pressed to make.
I am working with alphanumeric data that is unorganized. Here is an example of what it looks like: ...
I have a spreadsheet,section attached.
In column a is the distance in miles and furlongs and yards..sometimes there is only miles..sometimes only miles and furlongs,,sometimes only miles and yards..
I need a formula i can fill down in column b to convert to furlongs in decimal format
e.g. 2miles 3 furlongs and 20 yards converts to 19.09 furlongs..
there are 8 furlongs in a mile and 220 yards in a furlong...
I have many strings of arbitrarily length. Each string always
has one number (0-9) component and one alpha-character (A-Z) component.
The order of the components in the string is entirely random.
Sometimes numbers come first and sometimes letters/characters.
Also, the length of each separate component is also varies and
there is no fixed rule to how long it will be each time.
Examples are:
String: RGH45 Alpha: RGH Num: 45
String: 4589THF Alpha:THF Num: 4589
String: FGGFFF56464645464 Alpha:FGGFFF Num: 56464645464
String: sdgdfgdfg874645 Alpha:sdgdfgdfg Num: 874645
String: 54sfsdfdsf Alpha:sfsdfdsf Num: 54
String: s54654646 Alpha:s Num: 54654646
etc..
I want to have two strings. One called Alpha and One called Num
I want to have the alpha-character component to be extracted from the string
and set to Alpha and the numerical component to be extracted & set to Num.
How/what is the Excel Macro VB code to accomplish this from within the macro?
I am try to convert a letternumber (both single) to a number, ie 3b to 5, 7a to 17 etc. I am using a vlookup formula at the moment, =VLOOKUP(J3,'Test levels'!$R$4:$S$54,2) but if J3 is 4b it finds 3b and puts in that reference.
View 3 Replies View RelatedI'm trying to find a way to have excel 2003 format the data I put in a cell to auto insert dashes every five characters. I'm entering product keys for the software we have on hand, and it would be a little quicker if I could simply have excel auto format the data entered in to include dashes every five characters.
Example:
- I would enter: D5ATT3D28F6F44536489413E2 (This is a fake, non-working product key, I just typed in random numbers a letters.)
-Excel would format it like: D5ATT-3D28F-6F445-36489-413E2
I was recently issued an alphanumeric range that I would like excel to manage for me. The alphanumeric numbers contain 5 characters. The basic pattern starts zero to nine, then A-Z, then 10. For example, A0500 through A0509, A050A-A050Z, A0510-9, A051A-A051Z, A0520-A0529, etc.
View 4 Replies View RelatedIs there a vba function that can determine that "1B" is > then "1A"? Max only works with numbers apparently, but I know that MS Access' version of Max does this.
View 2 Replies View RelatedI have a 2010 excel sheet containing 14 columns and 45082 rows in total. I am quite illiterate when it comes to writing macros but I know that what I need can be achieved with a set of codes.
To be more clear, I inserted two tables below. The first one represents the current data structure, and the second one is the way I want my data to look like.
Current data structure looks like
Variable 1
Variable 2
Variable 3
[Code].....
I am having trouble filling a formulae series to the left on one spreadsheet, the fomulae being references to another sheet.
For example, I have two sheets 'Mtce Options' and 'Base Case'. In 'Mtce Options' I have the following formulae
A B C
1='Base Case'!A15='Base Case'!D15='Base Case'!G15
I want to fill to the left, incrementing the column references by a factor of 2 each time, eg. next two should be ='Base Case'!J15 and ='Base Case'!M15.
However, if I autofill to the left by highlighting A1, B1 and C1 or just B1 and C1 all I get is an inappropriate reference such as ='Base Case'!D15 or ='Base Case'!F15, respectively, in D15.
I have a column of numbers each have a 0. infront of them (example 0.2346
0.5698). I want to pull the number from the right until it hits the decimal sign. So for the two above the result would be 2346 and 5698
I want to grab everything left of the last occurrence of "." in a string, and in the next cell everything right of the last occurrence of "."
so say the string is 111.111.1.222
column 1
111.111.1
column 2
222
my current code (which works, but its messy) for the first cell is