String Parsing With Variable Length Strings
Mar 28, 2006
I am trying to split up a cell into numbers and charachters and place them in
separate columns, but the lenght of the number part varies as does the
content of the character part.
For example, one cell could be 5#, 10Tins, 4 lb, 100Pcs, etc.
I would like to be able to pull out the #, Tins, lb, and Pcs in to their
own column.
I have found this formula:
=LEFT(A1,FIND("-",A1,1)-1)
but it assumes some level of consistency, the "-" in the cell.
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Jun 10, 2014
Column M:
##/##/#### | Variable Length Text-####
Example:
01/06/2014 | Daniel Trimble-4048
I need to parse out the different parts of Column M.
In Column R -- "Close Date", I'm successfully using:
=LEFT(M2,FIND(" | ",M2)-1)
...to extract the close date of the donation.
In Column S, I want to list the donor name--which is all of the text after " | ", and before the "-".
I don't need anything after the hyphen, and fortunately in this data, no one's name has a hyphen in it.
The Close Date is working fine for the LEFT and FIND functions, but for the life of me, I can't seem to get MID to work for the variable-length text. The text will always start in the same position -- 14, as the date and delimiter are standardized. And the last 5 characters of the text are not variable in length, so they can be cut out completely.
How do I use MID to extract everything starting at position 14, and stopping 5 characters short of the end of the text?
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Apr 8, 2013
I have a set of data in Which in column A is the name of organisation.
If string in col A is longer than 50 I need to split in and put in col B.
That would be simple however I need to do it in a smart manner: i.e. cut it to the nearest full word.
Example:
THIS EXAMPLE NAME IS TOO LONG TO FIT INTO 50-TEXT CRITERIA SO I NEED TO DIVIDE IT INTO TWO STRINGS
Incorrect; length = 98
THIS EXAMPLE NAME IS TOO LONG TO FIT INTO 50-TEXT
Correct; trimmed down to 48.
My question is about formula that can detect spaces and depending on those trim the string down adequatly:
to 50 if 50th char is preceeded by space; if not then check where is the next space going towards left. Once you find it cut the string there.
What formula I can use to get desired effect?
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Dec 8, 2006
It's been a long time, but I use to parse a string in C.
How do you strip off the long directory path of a string to just the filename and extension?
String Example:
S:2006 jobs602f EID Bass Lake Recycle BPSConstructionSubmittal Review16940-Instrumentation602f-16940-01.rev.doc
Wanted result:
0602f-16940-01.rev.doc
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Jan 18, 2008
I have the following issue. I have a list of strings. Each string contains certain characters that are exactly the same for all strings, some characters are different making the string longer (in some cases). What I need to do is extract some combination of characters from each string. The strings look like this:
AB & CDE & FG & I mmmm yyyy.HIJK
AB & CDE & FG & II mmmm yyyy.HIJK
The part "AB & CDE & FG & " (incl. spaces) is the same for each string. The next part contains a roman count from I to VII, causing the length of each string to vary. The "mmmm" part contains the current month spelled in full e.g. December. This part differs as well, for each string. The "yyyy" part contains the year in four digits, e.g. 2007. The part after the dot is the same for each string again.
What I need to do:
- is to extract the month and assign it to a new string
- extract the year and assign it to a new string
- extract the roman number, translate it to a normal number (II -> 2) and assign to a string (or integer).
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Feb 9, 2014
i just wanna extract the date shown(last data until meet the first comma) in first column to another column.
column 1
abcde, 1234
abcd, 12345
abcdef, 123
column 2
1234
12345
123
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Jan 13, 2009
Hey I got a long String like this "[...] increase of x.xx% [...]".
I am trying to extract only the percentage number which can be of variable length, so maybe 900.99% or 9.99%.
I tried this formula:
=MID(G14,SEARCH("%",G14)-5,5)
but this one doesnt bring the right results as the percentage figure is often not exactly 5 characters long.
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Jan 25, 2007
Imagine that I have this list of thousands of customers, who are listed in column B in the format "customer no+space+customer name".
Now I want to extract ONLY the customer no from the text string in column B and insert it as number value in column A on the same row.
Would have been easy with "Left" command, but as the customer numbers have variable length, I have a problem.
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Apr 3, 2007
I am trying to parse employee names into seperate string variables in order to display surname, first name and middle name in seperate fields on a form.
The format of the full name is "Surname, First Name, Middle Name (If any)
I have managed to deal with surname and firstname but I am stumped on middle name. Not all employees will have a middle name but for those who do, I need to parse it.
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May 4, 2009
I have a spreadsheet that gathers information from multiple cells and strings the data into a long string - each piece of data broken by a comma in the string.
In another spreadsheet, I copy this data string into column A on sheet 1 - starting on row 2 and down.
On sheet 2 - and this is where I need help - I would like to have a macro that will take each data string on Sheet 1 column A and parse it out into multiple columns but the same row on Sheet 2.
ColumnA Row2 Sheet1 -> changing to many columns on Sheet2 but still on the same row.
The data string always represents the same number of data components - its just a matter of breaking it out and placing each data piece into its own column.
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Jun 27, 2008
in vba. is left and right the only way to extract substring?
e.g.
AAA (BBB 14:45:8)
i only need AAA and the numbers in 2 columns
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Mar 27, 2014
I've set up a filing system which saves sheets/ workbooks based on the value of a cell - Range("B1") Everything works great apart from when ThisFile String length exceeds 31 characters which you may know is the max useable character length for a sheet name - I had no idea! 8-0
Is there a way i can check if string length exceeds 31 characters then, if it does, shorten it to 31 characters?
[Code] .....
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Jan 9, 2010
My worksheet contains data with the reaction times on a psychological test. Each respondent in the test has 280 rows in my excel sheet.
The 'perfect' length of the row, is from A to M. When an error is made in the test, the length of the row will increase. So the error length can be A to AA.
For me it is important to analyse the error. So I would like to give a perfect row length, the value 1, and an error row length a value 2.
So, in conclusion:
If:
Cell length = A1 - M1? --> Copy A1 B1 C1 (A B Cof that row) to Sheet3, and give D1 in sheet 3 the value 1
Cell length >= A1 - M1? --> Copy A1 B1 C1 (A B C of that row) to Sheet3, and give D1 in sheet 3 the value 2
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May 9, 2008
Am trying to devise a formula that will allow me to extract a date (not stored in date format or recognizable by excel as such: "DEC1/09") and then manipulate it so that excel can recognize it and change it to a "1-Jan-01" form. Problem for me is that functions such as LEFT MID and RIGHT are very specific and sensitive obviously to any additional characters. some of my dates are preceded by "CAN BND 4.25/09"; "CANB BND 4.25/09"; "BC BND 4.25/09" and so on, you get the idea im sure that they are of differing lengths. The dates are equally strewn around as some (these are bond maturities) are 1st of the month while others may hold dates in the middle-end...15th, 30th, 31st etc.
is there a formula that will recognize the dates in the text strings regardless of string length and then a subsequent formula to manipulate the date to proper format?
i.e. "CAN BND 4.25/09 DEC1/09" and "CANB BND 4.25/07 JUN15/07"
Converted into: "01-Dec-09" and "15-Jun-07"
Not that the other parts of the string don't matter, already have macro that can recognize and rip bond coupons.
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Nov 16, 2008
I am trying to figure out how to parse some strings. Example of strings
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Jun 21, 2007
if i have to search for some special character in a string and i use Instr function then which of the following is the correct way. Lets say i have to search for "****" in the string
(1)
instr(myString,"****")
(2)
instr(myString,"****")
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Apr 10, 2008
I have a series of codes, such as:
xxx-xxx-xx/xy-xxx
yy-yy-yy/yz
zzz-zz/za-zz/za-zzz
The /'s represent variations on the same code, so the first one is shorthand for:
xxx-xxx-xx-xxx
xxx-xxx-xy-xxx
I would like to be able to split the code into a new line (or lines) wherever a / occurs.
There are any number of dashes and slashes within the code, however, there are none at the beginning or end of the code.
The slashes will be always surronded by dashes eg xxx-xx/xy-xxx.
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Jul 23, 2009
I have some code that will parse the FIRST IP address it finds in a string. Could someone help with the code for continuing through the remaining part of the string and parsing out any additional IP addresses it finds and concatenating them with a comma and space (", ")?
There are specific rules for validating a "proper" IP, but for the purposes of my work, I don't need to validate. I found the following code on a google group (thanks Jeff M). All it does is parse the numeric text surrounding the 3 periods that all valid IPv4 addresses contain. For my purposes, it works ....
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Dec 10, 2009
I have code that retrieves the body of an email. I need to parse out certain parts of the text. For example, the text will look like the following;
LastName: John Doe
Email: johndoe@aol.com
Cell#: 555-555-5555
FileRequested: xxxxx.xlsx
I have the code to find where the specific item, ie LastName, starts in the whole text. I need to retrieve everything to the right of the : before the CRLF. That's what Im having trouble with.
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Feb 14, 2010
I am reading lines from a textfile. Each line in the textfile has the identical format: textstring1:textstring2. The two strings are always separated by the : character. I have the code to get textstring1, but because I'm a rookie, I can't figure out how to get textstring2. See the code in bold, this is the line I need to get textstring2.
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Feb 1, 2013
I have an Excel sheet with lots of shortcuts in the first column. It's the entire shortcut, including the .lnk extension.
What I need to do is to be able to parse out the string to make the shortcut human readable when I create the hyperlink. I'm saving the output as HTML for a user to open these shortcuts. It's on an internal LAN & secure. Using various versions of Excel (2010, 2007 & 2003, predominately the first). Trying to make an ugly, 140+ character shortcut into a more readable form for web navigation purposes.
Up to a point, the shortcuts are similar:
a123meworkfolder1folder2folder3shortcut1.lnk
a123meworkfolder1folder4folder5shortcut1.lnk
a123meworkfolder1folder6folder7shortcut1.lnk
a123meworkfolder1folder8folder9shortcut1.lnk
but, later on, they vary from that point out.
a123meworkfolder1folder10folder10Afolder11shortcut1.lnk
a123meworkfolder1folder_12folder12Afolder12Bshortcut1.lnk
The strings are the same up to the 7th occurrence of the "" character, but after that, the foldernames start to change & the shortcut may be down a level (an extra folder) or more. Also, the lengths of the strings change as well, so I can only do positional parsing up to a point.
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Dec 1, 2009
I am trying to create a string of text that grabs info from other cells, which is easy so for example
=A1&A2&A3
would grab all the info from the 3 cells and merge them to create a string, but what I want to do is create a prefixed length.
Lets say A1, A2 and A3 would equal 10 characters in total but B1, B2 and B3 would equal 7 characters, these would be different lengths. so for a visual description I would like them to appear like this
At the moment
01MAIN-HELLO
01DESSERT-HELLO WORLD
Would like
01MAINXXX-HELLO
01DESSERT-HELLO WORLD
This would make both strings the same length and would make it easier for me to export to a custom file that needs a certain length prefix.
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Apr 8, 2013
I have a row of 1's and blanks, where there might be 10 consecutive 1's, followed by four consecutive blanks. I want to calculate the average length of a string of 1's in the row -- how this might be accomplished?
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Jun 20, 2014
So I have got an identifier and a corresponding column of values. I need to calculate sum of those corresponding values for each identifier, so if identifier is 1993, I need to have a sum of all the corresponding values. These identifiers repeat, and I do not want to calculate sum for all of them, just the immediate identifiers (i.e. you have 1993, after that you may have 1994 etc etc and then at one point you will have 1993 again, but that "new" 1993 will have a different sum of course). Also, identifiers do not go in sequence sometimes (however, most of the case they do), for example 1993 may jump suddenly to 2004. The trick with all of this is variable "row width" of these identifiers...
222.xlsm
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Sep 1, 2009
I get all my results from a CSV file. This isnt a problem except for the first nine days of the month where excel cuts off the first 0 so 01012009 reads 1012009 and cannot be properly concatenated.
DateNameItem
1012009BobKeyboard
1012009SidMouse
1012009DaveMonitor
1012009EdMonitor
1012009AndrewKeyboard
1012009DanKeyboard
1012009BruceKeyboard
What I would like to do is have VB read the contents of the date cell and if it is less than eight characters, edit the cell by adding a zero at the beginning of the string. This needs to be a one off process for all cells. Can anyone come up with code that might make this happen?
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May 21, 2012
I have an ODBC connection to a db2 database in MSQuery. I want to return the length of a string. I've tried Len(string) but it says its not in the library.
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Sep 28, 2006
The following afterupdate procedure for my txtStart1 text box sends the value to the FormatTimeValue function that is coded in a module.
Private Sub txtStart1_AfterUpdate()
MsgBox Len(Trim(Me.txtStart1.vaue)) '<= outputs 1
Me.txtStart1.Value = FormatTimeValue(Trim(Me.txtStart1.Value))
End Sub
As you can see from the bolded text, the length of the value is 1 when outputted from the forms code.
However, when I pass it to the following function in a module it outputs 2 as the length.
Function FormatTimeValue(vTarget As Integer) As String
Dim TimeStr As String
If IsNumeric(vTarget) Then
MsgBox Len(vTarget) '<= outputs 2
Select Case Len(vTarget)
Case 1 ' e.g., user entered 1 so time should be 01:00
TimeStr = "0" & vTarget & ":00"
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Aug 10, 2007
I have looked into the maximum length of a variant/string in vba and it appears to be 250 characters. I am running a macro which first lists all excel files in a folder, returning them to a sheet, then using a loop statement opens each one in turn extracting the information to a second summary sheet before closing it. The file path to the folder is ridiculously long and the macro stumbles. I used the =LEN(A1) formula to check if the file names were too long for the string, but the maximum file name length was 226 characters. I've tried both String and Variant to collect the file names but both have the same effect.
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Jun 6, 2008
I need to insert 00 if the string of text = 13 in a specific column.
eg. Column K can contain any amount of lines of data. The data will either be 15 or 13 characters in length. If its length is 15 its fine, if its 13 I need to get it to 15 characters.
The first 6 characters are letters so if the length is only 13 I need to add the 00 in after the last letter.
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Jul 26, 2013
how can I make this simple macro sum columns that will be of variable length? I would like the sum to appear as the last entry in that column and highlighted.
VB:
Range("H36").Select
Selection.FormulaR1C1 = "=SUM(R[-34]C:R[-1]C)"
Range("J36").Select [code]....
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