I have a row of 1's and blanks, where there might be 10 consecutive 1's, followed by four consecutive blanks. I want to calculate the average length of a string of 1's in the row -- how this might be accomplished?
View 7 RepliesI've set up a filing system which saves sheets/ workbooks based on the value of a cell - Range("B1") Everything works great apart from when ThisFile String length exceeds 31 characters which you may know is the max useable character length for a sheet name - I had no idea! 8-0
Is there a way i can check if string length exceeds 31 characters then, if it does, shorten it to 31 characters?
[Code] .....
I am trying to create a string of text that grabs info from other cells, which is easy so for example
=A1&A2&A3
would grab all the info from the 3 cells and merge them to create a string, but what I want to do is create a prefixed length.
Lets say A1, A2 and A3 would equal 10 characters in total but B1, B2 and B3 would equal 7 characters, these would be different lengths. so for a visual description I would like them to appear like this
At the moment
01MAIN-HELLO
01DESSERT-HELLO WORLD
Would like
01MAINXXX-HELLO
01DESSERT-HELLO WORLD
This would make both strings the same length and would make it easier for me to export to a custom file that needs a certain length prefix.
i just wanna extract the date shown(last data until meet the first comma) in first column to another column.
column 1
abcde, 1234
abcd, 12345
abcdef, 123
column 2
1234
12345
123
I get all my results from a CSV file. This isn’t a problem except for the first nine days of the month where excel cuts off the first 0 so 01012009 reads 1012009 and cannot be properly concatenated.
DateNameItem
1012009BobKeyboard
1012009SidMouse
1012009DaveMonitor
1012009EdMonitor
1012009AndrewKeyboard
1012009DanKeyboard
1012009BruceKeyboard
What I would like to do is have VB read the contents of the date cell and if it is less than eight characters, edit the cell by adding a zero at the beginning of the string. This needs to be a one off process for all cells. Can anyone come up with code that might make this happen?
I have an ODBC connection to a db2 database in MSQuery. I want to return the length of a string. I've tried Len(string) but it says its not in the library.
View 2 Replies View RelatedThe following afterupdate procedure for my txtStart1 text box sends the value to the FormatTimeValue function that is coded in a module.
Private Sub txtStart1_AfterUpdate()
MsgBox Len(Trim(Me.txtStart1.vaue)) '<= outputs 1
Me.txtStart1.Value = FormatTimeValue(Trim(Me.txtStart1.Value))
End Sub
As you can see from the bolded text, the length of the value is 1 when outputted from the forms code.
However, when I pass it to the following function in a module it outputs 2 as the length.
Function FormatTimeValue(vTarget As Integer) As String
Dim TimeStr As String
If IsNumeric(vTarget) Then
MsgBox Len(vTarget) '<= outputs 2
Select Case Len(vTarget)
Case 1 ' e.g., user entered 1 so time should be 01:00
TimeStr = "0" & vTarget & ":00"
I have looked into the maximum length of a variant/string in vba and it appears to be 250 characters. I am running a macro which first lists all excel files in a folder, returning them to a sheet, then using a loop statement opens each one in turn extracting the information to a second summary sheet before closing it. The file path to the folder is ridiculously long and the macro stumbles. I used the =LEN(A1) formula to check if the file names were too long for the string, but the maximum file name length was 226 characters. I've tried both String and Variant to collect the file names but both have the same effect.
View 2 Replies View RelatedI need to insert 00 if the string of text = 13 in a specific column.
eg. Column K can contain any amount of lines of data. The data will either be 15 or 13 characters in length. If its length is 15 its fine, if its 13 I need to get it to 15 characters.
The first 6 characters are letters so if the length is only 13 I need to add the 00 in after the last letter.
I am trying to split up a cell into numbers and charachters and place them in
separate columns, but the lenght of the number part varies as does the
content of the character part.
For example, one cell could be 5#, 10Tins, 4 lb, 100Pcs, etc.
I would like to be able to pull out the #, Tins, lb, and Pcs in to their
own column.
I have found this formula:
=LEFT(A1,FIND("-",A1,1)-1)
but it assumes some level of consistency, the "-" in the cell.
I have a set of data in Which in column A is the name of organisation.
If string in col A is longer than 50 I need to split in and put in col B.
That would be simple however I need to do it in a smart manner: i.e. cut it to the nearest full word.
Example:
THIS EXAMPLE NAME IS TOO LONG TO FIT INTO 50-TEXT CRITERIA SO I NEED TO DIVIDE IT INTO TWO STRINGS
Incorrect; length = 98
THIS EXAMPLE NAME IS TOO LONG TO FIT INTO 50-TEXT
Correct; trimmed down to 48.
My question is about formula that can detect spaces and depending on those trim the string down adequatly:
to 50 if 50th char is preceeded by space; if not then check where is the next space going towards left. Once you find it cut the string there.
What formula I can use to get desired effect?
Hey I got a long String like this "[...] increase of x.xx% [...]".
I am trying to extract only the percentage number which can be of variable length, so maybe 900.99% or 9.99%.
I tried this formula:
=MID(G14,SEARCH("%",G14)-5,5)
but this one doesnt bring the right results as the percentage figure is often not exactly 5 characters long.
I have a spreadsheet with 2 sheets. The first just links to another file and pulls in the contents of a particular sheet, cell for cell. The second sheet is a formatted report that I'm creating to put that data into a different format for presenting to others. I'm using the Index and Match function along with range names. All is fine except where the string that should be returned is very long. When that happens, I get "######" all the way across the cell. It doesn't matter how wide I make the column or how tall I make the row, the "#s" do not go away. Is there a limit on the number of characters the Index function can return?
View 5 Replies View RelatedImagine that I have this list of thousands of customers, who are listed in column B in the format "customer no+space+customer name".
Now I want to extract ONLY the customer no from the text string in column B and insert it as number value in column A on the same row.
Would have been easy with "Left" command, but as the customer numbers have variable length, I have a problem.
I have a google earth KML file that I have converted to text, and through a bunch of manipulation have been able to pull a series of GPS coordinate strings into a single cell string. Unfortunately, the string data is beyond what excel 2007 can handle for a single cell. so my thought is to have excel pull each coordinate string into a separate cell with which i can then run a macro to develop a new KML dynamically. (changing multiple attributes based on a query to a database)
Each string of coords actually maps out a single region (path) on the KML, truth be told it is telecom rate center data, and each rate center will have numerous other variables applied to it depending on my company's voice network capability for a given rate center. Currently my only desire is to depict differently any rate centers that I'm able to deliver VOIP services to by showing them in a different color...but these change very often so it will support to be able to auto generate the map from time to time.
the raw data from the KML looks like this:
Code:
CLINTONVL
RATE_CNTRCLINTONVL
STATEPA]]>
ff000000
1
0
1
[Code] ..........
After doing my data import, i extracted via various manipulations, the rate center name (a common lookup value that stays constant across multiple databases), and the string of coordinates. this is where i run into trouble. i need to pull each coord into a separate cell assuming i won't run out of cells in the x coordinates to gather this data OR find a way to grab the data via another lookup to another document...not desireable.
I want my output to look like:
Code:
RC_NAMECOORDSLATAVoip?
ALIQUIPPA
80.334114,40.520974,0-80.327493,40.520023,0-80.323915,40.51957,0-80.31997800000001,
40.519933,0-80.316958,40.521221,0-80.314431,40.521445,0-80.314262,40.521332,0-80.31398,
40.521194,0-80.31315600000001,40.520832,0-80.313057,40.520794,0-80.312805,40.520641,
[Code] ........
First off, my import was jacked up by missing some comma's...this i can fix easily with the string importation and manipulation HOWEVER...i still run into the issue of string length OFTEN.
Is there a way to stop getting the error of a string of poind signd (which look like ################) whenever I'm trying to copy and paste information from another worksheet, or trying to link one sheet to another?
I've already tried resizing the rows and columns to their respective maximums but it doesn't seem to work.
How to create a code formula to calculate the arc length from a given chord length?
If you know the radius of the major circle.
Say the chord is 50mm and major circle dia is 72mm (radius 36mm)
arc from chord.jpg
My worksheet contains data with the reaction times on a psychological test. Each respondent in the test has 280 rows in my excel sheet.
The 'perfect' length of the row, is from A to M. When an error is made in the test, the length of the row will increase. So the error length can be A to AA.
For me it is important to analyse the error. So I would like to give a perfect row length, the value 1, and an error row length a value 2.
So, in conclusion:
If:
Cell length = A1 - M1? --> Copy A1 B1 C1 (A B Cof that row) to Sheet3, and give D1 in sheet 3 the value 1
Cell length >= A1 - M1? --> Copy A1 B1 C1 (A B C of that row) to Sheet3, and give D1 in sheet 3 the value 2
(I need to do this using VBA so that it can work as an excel macro and/or a vba function in access.)
How can I extract the first occurance of any substring over a certain character length from within a string ?
eg. My string may take any of the forms given below (or something similar), how can I extract the first set of characters that is at least (say) 4 characters long ? i.e. always get the 'Phillips' out of the below...
Phillips Homes Ltd
Mr T A Phillips
TA Phillips Homes Ltd
T A Phillips Homes Ltd
T. A. Phillips Homes Ltd
The names used are only an example (Phillips could be any name whatsoever).I am familiar with Search, Len, Left, Right, Mid, Instr etc. but just can't figure this one out.
E11 through E24 contains numbers and a few errors (#N/A) that need to persist (the errors need to show).
E10 needs to show the average of the numbers that are in E11 through E24, and just ignore the errors.
I have many columns like that - where the errors need to show and I need to show an average of the number/values that do appear, ignoring the errors.
i have two columns...a and b (a w/ names, and b w/grades). then i have the table lookup with names and grades all mixed up for many rows. i want to be able to average the grades with appropriate names.
=average(vlookup(name, table, column, false))?? i don't get it to work and how can i specify the grade to average?
TotHCInv.Value = WorksheetFunction. Sum(KRInv, PBLInv, CRInv, PVInv)
If i >= 34 Then CPSCtphRMA.Value = WorksheetFunction.Average("G" & (i - 30) & ":G" & i)
The first line runs properly, but the second line bugs out with the error message "Unable to get the Average property of the WorksheetFunction class". I can simply do the math, but I thought that using the worksheet function would be easier than summing and dividing. I'm curious, though, as to why I can't seem to use the Average function.
Can I get a minimum average and a maximum average, I have a worksheet with days of supply for 100 stores with about 100-200 products each, the dos resides in column D.
I was going to create a summary page and reference column d.
The following just gives me the min, I want the min average if possible:
I am attempting to calculate Grade point averages for my students for all classes. There are 5 columns of grades to be considered. I frist assign values of 0-5 to the grades then average the points. My problem is that I want the AVERAGE to ignore the zero but it calculates it as well. (I enter a 0 if I have no grade for that class.) I have tried the{ } to make it an array formula but this also did not work. Here is what I have, can anyone help?
=SUM(AVERAGE(IF(AND(L2>89,L2<100),5,IF(AND(L2<90,L2>79),4,IF(AND(L2>69,L2<80),3,IF(AND(L2<70,L2>59), 2,IF(AND(L2>0,L2<60),1,0))))),IF(AND(T2>89,T2<100),5,IF(AND(T2<90,T2>79),4,IF(AND(T2>69,T2<80),3,IF( AND(T2<70,T2>59),2,IF(AND(T2>0,T2<60),1,0))))),IF(AND(AB2>89,AB2<100),5,IF(AND(AB2<90,AB2>79),4,IF(A ND(AB2>69,AB2<80),3,IF(AND(AB2<70,AB2>59),2,IF(AND(AB2>0,AB2<60),1,0))))),IF(AND(AJ2>89,AJ2<100),5,I F(AND(AJ2<90,AJ2>79),4,IF(AND(AJ2>69,AJ2<80),3,IF(AND(AJ2<70,AJ2>59),2,IF(AND(AJ2>0,AJ2<60),1,0))))) ,IF(AND(AR2>89,AR2<100),5,IF(AND(AR2<90,AR2>79),4,IF(AND(AR2>69,AR2<80),3,IF(AND(AR2<70,AR2>59),2,IF (AND(AR2>0,AR2<60),1,0)))))),-1)
I know it is huge. The syntax is correct. It calculates the average, but always for all 5 columns. It will not ignore a 0 in a column.
I'm using the formula =AVERAGE(B16:L16) to give me the average.
However I have a couple of problems with this. Firstly I would like to exclude the value zero from the average. Secondly to also ignore the lowest and highest values.
Example, if the values in the cells are 0,1,2,3,4,5,6,7,8,9,10 then the current result shows 5, by ignoring the 0 and lowest value 1 and highest value 10 the average should be 4.5.
Ok, I for some reason just cant wrap my head around this. I need to to get the average time per call of two rows, but they are based on how many calls taken.
so in one column i have 50168 calls taken at 4:21 seconds per call. and in the next row i have 597 calls taken at 5:20 per call. I need to see what the new average will be with them combined, and I need it to display in m:ss form.
Is there any length limit for the cell names? is there any lenght after wich it makes VBA or the spreadsheet unstable or clumpsy? I´m using Excel 2003
View 6 Replies View RelatedI would like to create a formula that would calculate the length of a person's employment, i.e. hired 8/14/94 till today, for example.
View 10 Replies View RelatedI am struggling with a macro that is supposed to hide a row if length of cell A =9 and the value of cell C =0. The error I get is "object required".
Code:
Sub hide()
Dim cntA As Long
Dim rng As Range
[Code].....
I am rebuiliding my deck on my house and I am laying the boards on a 45 degree angle. Boards come in 12', 16', 20' lengths and are 5.5" wide.
The overall measurement of the deck is 12'x17'6".
What I need to know is how many boards I will need of each length. I would be grateful to see how this is solved w/ formulas, etc...