Using IF Statement With Length Formula

Jan 2, 2014

I'm trying to use an if statement with a LEN function, i want to say if column O2 is 5 characters long then populate with Y if not populate with N.

I have tried.

=IF(LEN(O2,5),"Y","N"

but it doesn't work?

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How to create a code formula to calculate the arc length from a given chord length?

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Say the chord is 50mm and major circle dia is 72mm (radius 36mm)

arc from chord.jpg

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I'm having a bit of trouble with a macro designed to read the length text in a cell and if it = a certain length then perform an action (in this case Text to column)

Here is a small sample of the data I'm working with:

Tue 02/11/2014
LastBootUpTime
20140211082244.222441+000 <<

Tue 02/11/2014
LastBootUpTime
20140211082244.222441+000 <<

Tue 02/11/2014
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20140211082244.222441+000 <<

Tue 02/11/2014
LastBootUpTime
20140211082244.222441+000 <<

Tue 02/11/2014
LastBootUpTime

Tue 02/11/2014
LastBootUpTime
20140211082244.222441+000 <<
*End Sample*

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I have the text to column code already done with relative references however the long text string I want the statement activated on is not always present which means that the pattern (0,3) is not always consistent.

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[Code] .....

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For me it is important to analyse the error. So I would like to give a perfect row length, the value 1, and an error row length a value 2.

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If:
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sample file : [url]

file that might help out: [url]

checks would be:
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You can check this on the file, go the "records" sheet, add the time in the "shift start" and "shift end" fields, then the difference value goes to "hours" in the sheet.

[URL] .....

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[Code] ........

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---------------------------------------------------------------------------------
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