Is there a fomula that can add trailing spaces. For example....I need a certain feild to be 11 Characters in length. So lets say in Column A, I have a bunch of different words:
House
Bird
Up
Down
Yes
No
I would like to put a formula in column B that takes my original text and adds blank spaces to the end of it until it's 11 Characters. So "House" in Column A would be "House " in column B.
I have a column of data in which each cell contains a line of text. Each line of text has spaces after the letters end and there doesn't seem to be a consistent number of trailing spaces.
I can clean up the data using the TRIM function but is it possible to use the TEXT TO COLUMNS functionality?
I have an excel file with two sheets . One containing the updated prices with its code ( Sheet1) and the other containing the old prices with the same codes (sheet2). Now after several trials to copy the new prices from sheet 1 to sheet 2 with check if the code is same . ( I couldn't )
So how to get rid of the 20 spaces from Sheet1 column A.
I have written a function which works in the same way as the concatenate formula but where required it uses an underscore to make up the length (14 Characters) of the result. I seem however to have hit a minor snag when users input trailing spaces. I thought I could use trim to eliminate them but it doesnt seem to be working
Function HypCon(CorpAcct, Subdiv)
Dim n, i, iLen, iLen2 As Integer Dim sCorpAcct, sSubdiv As String Dim iLen3, iLen4 As Integer iLen = Len(Trim(CorpAcct)) iLen2 = 7 iLen3 = Len(Trim(Subdiv)) iLen4 = 5..............
The below code removes trailing spaces, but for some reason it does not remove space from this, i clicked F2 and the space is still there, why does it work on some but not others?
98956P102
Sub test() With ActiveSheet.UsedRange .Value = Evaluate("if(" & .address & """"",trim(" & .address & "),"""")") End With End Sub
I am doing a vlookup on fields such as 02-0223. In one table, there is a space at the end of 02-0223 and in the other table, there is no space. How can I delete the space so the numbers match in vlookup?
Any easy way to remove all spaces from a cell, both leading and trailing? I find it hard to believe that Excel doesn't have this functionality. I don't particulary want to write a VBA script since I have never done it but if that's the only way, I'd love to know how to write it. I have looked everywhere but obviously not in the right places.
I am using the following code to import an excel file into an existing sheet. The problem I am having is the way some of the cells are being imported. Some of the cells have spaces before and after the number.
I need to delete the leading and trailing spaces for each cell affected. Is there a code I can incorporate to do this? BTW…the columns effected are columns F & G.
how to remove multiple leading and trailing spaces while leave spaces in the middle of the string in place? I have tried text to columns but this does not remove the multiple spaces.
to trim leading and trailing spaces from values I'm getting from a For Next routine. I'm using c as my variable and Trim(c.value) as the operation.
There are other routines that search for the explicit string that's the result of the trimmed value and some can't be found because the trim as I'm using it isn't trimming.
I wrote a tool that people at work use. They initially need to paste in a bunch of customer locations with Address, City, State, Zip, etc. Sometimes the Users have "bad input" data that has non-breaking spaces, multiple space between words, or leading and trailing spaces and nonbreaking spaces. I have code to get rid of all of those problems. However, the Users often use their data for other important functions at work. So I want to give them a message to let them know that their Original Data is "bad".
So instead of just "Fix" . . . I want to "Report the problem", then "Fix". I need to identify exactly what problem was found - not just tell the User that their data is bad.
I wrote a simple Search routine with error handling that identifies 2 of the 4 cases and notifies the User: Case 1) ASCII 160 (non-breaking space, HTML   Case 2) multiple spaces (2 or more consecutive spaces) Case 3) Leading or Trailing Spaces (ASCII 032) Case 4 Leading or Trailing non-breaking spaces (ASCII 160, which is HTML  )
I cannot quite figure out how to find the 3rd and 4th Cases. If anyone can help me with Case 4 especially, then I can probably do the same thing for Case 3.
I think it will work to somehow use this idea - the code is not even real code but it is just conceptual: RIGHT(CellReference, 1) = Char(160) or Char(032) LEFT(CellReference, 1) = Char(160) or Char(032)
Anyway, here is what I have so far . . .
Sub NotifyBadInput ErrorFlag = False Cells.Select ' select entire worksheet
' BAD INPUT 1 - lLook for any occurence of ASCII 160 (non-breaking space, HTML  ) ' and Notify the User if any of his Input cells contain  's On Error Goto errormsg1 Selection.Find(What:=" ", After:=ActiveCell, LookIn:=xlFormulas, LookAt _ :=xlPart, SearchOrder:=xlByRows, SearchDirection:=xlNext, MatchCase:= _ False, SearchFormat:=False).Activate
While entering data space is given in the first and last of each cell content. For example
if there is a word Alex Patrix in a cell, space is given before A of alex and after x of Patrix. This is done fo many cells. I want to remove only initial and last space which is un-necessary. The space caused problem to compare cell so i've to remove space.
I have an Excel file with several worksheets and each of those worksheets has over 600 rows (a list of employees) and above or under 30 columns. Most of cells have trailing spaces in them and they vary in length. For example:
B5: "Jacobson " C5: "jacobson@jacobson.org " (Seems like it's not allowing me to post long gaps between the last letters and the "
I'm aware of the TRIM function and know that I could at least get a column or a few copied with the spaces removed. However, it would just take so much time. What would be the most efficient way of getting rid of all the trailing spaces in all the cells in all the columns in all the worksheets?
I've spent way too much time trying to figure out this simple thing. Doh! I have a text string that may have one or more CR and/or LF characters on the right. Unfortunately, RTrim doesn't remove CR/LF characters.
Is there an easy way to do something similar to the following that will remove the CR/LF characters?
I have come up with this to Trim all of the data from rows 2:30 removing any trailing spaces after the last word in each cell. The macro takes a couple of minutes to run have I got something wrong that is making it run slowly or does the Trim process just take longer?
Sub TRIM_RANGE() Dim myRange As Range Dim myRow As Range Sheets("CAMPAIGNS_2007").Select Set myRange = Range("2:30") If myRange Is Nothing Then Exit Sub Application. ScreenUpdating = False myRange.Replace What:=Chr(160), Replacement:=Chr(32), _ LookAt:=xlPart, SearchOrder:=xlByRows, MatchCase:=False For Each myRow In myRange.Columns If Application. CountA(myRow) > 0 Then myRow.TextToColumns Destination:=myRow(1), _ DataType:=xlFixedWidth, FieldInfo:=Array(0, 1) End If Next myRow Application.ScreenUpdating = True End Sub
We are moving to a new accounting system and we need to import the creditors' master data but there are field length limitations in the new system. I have the full details off our current system and I would like to highlight cells that fall outside of the character length.
I am sure this isn't just a setting that can be enable in excel. I was wondering if there is a code that will allow the display of the number of characters in a cell when typing in it.
I know there is a len() function but I don't know how to use it so it displays my char length on the go.
I'm trying to set my code to force the user to enter in 8 characters for an employee ID within a text box. Currently when I attempt to enter in an employee ID, my message box alert appears after the first digit. So instead of validating the user has entered in 8 characters for the employee ID, the msgbox alert appears as soon as the user enters in the first number. I cannot figure out what I am missing within my code.
Code: Private Sub txtPERNR_Change() If Len(Me.txtPERNR.Text) 8 Then Me.txtPERNR.SetFocus MsgBox ("PERNR number must be 8 characters in length") Cancel = True End If End Sub
I honestly thought this validation would be easy, but I've tried it a couple of different ways and nothing is working.
In Userform1 I have several textbox and one commandbutton1. If I mouseclick on a textbox and click commandbutton1 the letters YES is entered in the texbox. To prevent double click entry into the same textbox I set the maximum length property at 3. However, setting the maximum length to 3 does not work. Subsequent commandbutton1 clicks will result in an infinite YES entries.
Is the maximum length property disabled when commandbutton entries are applied?
Is there a way to stop getting the error of a string of poind signd (which look like ################) whenever I'm trying to copy and paste information from another worksheet, or trying to link one sheet to another?
I've already tried resizing the rows and columns to their respective maximums but it doesn't seem to work.
I'm attempting to create a spreadsheet to calculate various things at my work, however I'm running into a problem that I can't solve. In one cell, I have a formula that returns an value to two significant figures. The number of decimal points that this value has is then used at various points throughout the sheet to truncate/round/etc. However, if the first value has a trailing zero as the second significant figure (ex. 0.20), that trailing zero is dropped. This creates problems since downstream calculations are then truncating to an incorrect number of decimal points. How to retain this trailing zero IF the formula results in one?
I have seen a few posts that are close to this but not quite right. I have a situation where I need to do "=LEN..." formula that counts trailing zeros at the end of numbers (meaning zeros that are displayed at the end of a number but do not appear in the actual cell value).
example: Cell E19 contains the actual value 4773.52, but it is displayed in currency format with FOUR digits so it displays as $4,773.5200.
The formula I am using is =LEN(MID(E19,FIND(".",E19)+1,4)). The result is 2, which means it does not include the last two trailing zeros in the LEN count.
Is there anyway to get it to include the trailing zeros so the result equals 4? Either w/formula, macro, or UDF?
Is weird I know, but I need to know how many decimal places (displayed, not actual) for many numbers on many sheets that I do not create myself.
I've set up a filing system which saves sheets/ workbooks based on the value of a cell - Range("B1") Everything works great apart from when ThisFile String length exceeds 31 characters which you may know is the max useable character length for a sheet name - I had no idea! 8-0
Is there a way i can check if string length exceeds 31 characters then, if it does, shorten it to 31 characters?
My worksheet contains data with the reaction times on a psychological test. Each respondent in the test has 280 rows in my excel sheet.
The 'perfect' length of the row, is from A to M. When an error is made in the test, the length of the row will increase. So the error length can be A to AA.
For me it is important to analyse the error. So I would like to give a perfect row length, the value 1, and an error row length a value 2.
So, in conclusion:
If: Cell length = A1 - M1? --> Copy A1 B1 C1 (A B Cof that row) to Sheet3, and give D1 in sheet 3 the value 1
Cell length >= A1 - M1? --> Copy A1 B1 C1 (A B C of that row) to Sheet3, and give D1 in sheet 3 the value 2
I am having difficulty with creating an IF formula that will only show 9 digit numbers. If the cell the formula is looking at has less or more than a 9 digit number in it, or the cell ha no value, the result will be blank.