I basically want to find and replace certain characters in a formula, but the formula is quite intricate so I will give some background to the problem first:
I have a complex spread sheet which is used to check if a data array matches another data array (both data arrays are different sizes). One array has a set of parameters for a variable and the other array has the variables and the actual values for each variable. I have a section with the following formulas to check if the actual value (C121&D121) matches the parameters ($A$9:$A$108, $B$9:$B$108) & ($C$9:$C$108, $D$9:$D$108)
I have the following formula in cell AB121:
=(C121=INDEX($B$9:$B$108,ROW(101:101)-INT(ROW(100:100)/$D$1)*$D$1))
In cell AC121:
=(D121=INDEX($D$9:$D$108,ROW(101:101)-INT(ROW(100:100)/$D$1)*$D$1))
And have similar formulas from AD121 to AY121. I mention this to point out that excel regards this as an inconsistent formula, I haven't copied and pasted it over, I have had to re-enter it in each cell adjusting the parameter sections.
The problem I have is that currently this is set up to check through a data set and wrap around every 100 rows ('100' Entered in $D$1) but I want to adjust the formula when there is a different amount of rows to check. So basically the only way I can think to be able to do this is to have a formula or something in VBA (which I have very low level experience with) to be able to go into the formula and change certain characters within the formula. For example, if I wanted to check 95 rows instead of 100, it would need to have 95 in $D$1, which I enter in manually, but then how to go in and replace (101:101)-INT(ROW(100:100) with (96:96)-INT(ROW(95:95) in 2 sections in the 1 formula then do the same with the inconsistent formula from AC121:AY121?
I recently became owner of a spreadsheet with some issues, and I am trying to make it useful. Each row has a URL of a blog post, and I want to extract the date from it (which is present in each URL) while getting rid of the rest of the URL. I was able to get rid of everything up to the year (which comes first), but then the URL continues, for example, 2013/05/16/the-rest-of-the-url/ and I would like to just have 2013/05/16 remain.
I am trying to use find and replace with the find box reading 2013/??/??/*/ and replacing it with 2013/??/?? which effectively erases everything else in the url, but leaves ?? instead of the numbers. Is there any way to have it so that it keeps whatever was in the original box?
I have some records that include greek addresses. The greek alphabet contains letters that are common to the english one (A,B,E,Z,H,I,K,M,N,O,P,T,Y,X) and records with mixed characters will cause me problem. What can I do to find and replace any of those letters with the greek version of the letter.
example:
for a record:
T..5123 (this is the Greek abbreviation for P.O.BOX 5123)
I'm looking for a function to replace the first letter T (wether is Greek or English) with the Greek version of it
example 2:
KYMH 6 (kimis is the street, 6 the number)
I should replace English (first four ) letters with the Greek version...
example 3:
BAPITOY 14 (valaoritou is the street, 14 the number) ...........
I download several sets of data from an internet site. The only way I can do this is to copy and paste into Excel. The problem is, that all of the cells with numbers in them show up as text, and when I press F2, I find that there is a blank space at the end of each number.
Find and replace, searching for a blank space does not work - Excel "cannot find any data to replace". That function does work on cells in which I have created my own space at the end of a number, but not on these numbers. That leads me to believe that that "blank space" is actually some other invisible character that I need to be searching for. I've attached a bit of my data - maybe somebody else can identify my phantom character.
To get around this, I have been using the formula =(left(A1,len(A1)-1), and that works, it's just that it is a pain to create another table of 20-some columns with this formula, then copy those to values, then for each column convert text to columns to change the text to values, then search and replace for #value! where the original cells were blank.
I have two sheets in my workbook: One containing names with French and other European characters, the other containing a list of ISO entities for these characters, like these:
#224 #225 #226 #227 #228 #229 #230
I need to replace these characters in Sheet 1 with the equivalent ISO entity from Sheet2 and print the value into the same cell in Sheet1.
*****The last line of code is below***** =IF(COUNTBLANK($AE$6:$AE$7),"",MIN(U966,AD1248*$AE$37))
What I'm really trying to do is replace all the numbers (well, max of 3) after the U part to U6.
So,, for example ,, if in the code it shows MIN(U16,,,,,,,, I want it to show MIN(U6
So as an example
Code: =IF(COUNTBLANK($AE$6:$AE$7),"",MIN(U966,AD1248*$AE$37)) WILL NOW BE =IF(COUNTBLANK($AE$6:$AE$7),"",MIN(U6,AD1248*$AE$37)) So U6 is in all the formulas.
I've tried searching on google,, saw a video here on UTube; Excel Magic Trick 519: SUBSTITUTE & REPLACE Functions [URL] ........
Showed some great stuff,, but I just didn't quite get it for the above.
I have text in column 1 and need a formula that will replace it with text in column 2, as shown in (fig 2).
FIG 112X Jan 2009 7.5000 put X Jan 2010 5.0000 callAA Jan 2010 17.5000 call AA Jan 2009 9.0000 putIBM Jan 2010 130.0000 call IBM Jan 2009 17.5000 put PLCE Jan 2009 30.0000 call PLCE Feb 2010 7.5000 put
FIG 212X Jan 2009 7.5000 put X Jan 09 7.50 putX Jan 2010 5.0000 callX Jan 10 5 callAA Jan 2010 17.5000 call AA Jan 10 17.50 call AA Jan 2009 9.0000 putAA Jan 09 9 putIBM Jan 2010 130.0000 call IBM Jan 10 130 call IBM Jan 2009 17.5000 put IBM Jan 09 17.50 putPLCE Jan 2009 30.0000 call PLCE Jan 09 30 call PLCE Feb 2010 7.5000 putPLCE Feb 10 7.50 put
I have text string and would like two formulas to find, 1) the characters after the last space and 2)to find the number of characters after the last space.
I need a macro that will change the part of the formula that is "CI10001G" to the value of cell A2 which would basically be something along the lines of "CI10004D" so the formula would change to the following:
='H:Folder[CI10004D.xlsm]Sheet'!$C$5
And then this formula will then successfully look in the newly directly file path.
I'm receiving this message when I attempt to use the Find, Replace function. Formula is too long". I have a column of cells containing text only. ( about 2-3 paragraphs worth) I'm trying to replace a name with another name, which works fine where the cell contains a single or few sentences, but fails to replace when the cell contains too much information.
This problem has come up fairly frequently lately, and I'm not sure how to fix it, or if this is by design...but in Excel 2003 I can't seem to do a "Find and Replace" based on the value of a cell. I can do a find, based on cell value, but the moment I change to the replace tab, the "values" and "comments" are missing from the "look in" dropdown.
I've only noticed this when I'm trying to replace on a filtered list, so I'm not sure if that is part of the issue.
Perhaps an alternative way of arriving at the same goal. Basically I have a worksheet with a number of filtered columns. They are filtered just right, using custom filtering, and so I do not want to undo the filters. In some columns I have formulas that are returning #VALUE! errors. I'd like to replace all of these cells with NA.
Trying to repeat a 550 or so character statement with a find/replace however I am getting type mismatch errors. When I use a smaller message in the "replace" it works.
I need it to post a message exactly as long as what I have in there. How do I get it to work?
Need assistance with the code for catching errors when using the find / replace function in excel? In particular, I am trying to write code to break to an error message when the value or string searched for isn't found in the find / replace. At the minute I have just copied the standard code using a macro and all this does is return a message box saying X entries replaced.
A range of cells contain characters that i want to replace with spaces. The problem is that the length of the string differs and also the characters differ.
For example, below a list of cell values:
GR GRKR GRKRKR GRKRK1 GRON GRONBL
As a result for the first value i want 2 spaces, for the second one 4 spaces etc.
Is it possible to do this with a formula? I don't want to use VBA for this if possible...
I'm trying to do a quick find and replace across a range of cells to remove Chr(10) and Chr(13) characters. For some strange reason, some of the cells are being good and duly allow the removal of said characters and some are not - they stubbornly refuse to remove with no error message. The ones that are not allow removal if I copy the individual cell to a new sheet.
Sub removeCharNew() 'Dim x As Integer Cells(1, 1).Select Range(Selection, Selection.End(xlToRight)).Select Range(Selection, Selection.End(xlDown)).Select Cells.Replace Chr(10), "" Cells.Replace Chr(13), "" End Sub
Is it possible to display a dialog box or msgbox that doesnt have an OK button ?
i.e I want a message that comes up on the screen that says "Links Updating...Please Wait" which then automatically changes to "Links Sucessfully Updated" on completion...I dont want the macro to be interrupted by the msgbox/dialog...
I am trying to create a macro where it finds a a certain word in a column for example C. What i want it to do is find anything that says FWD_EUR and then replace that cell (e.g C2) with CASH_EUR_FWD and after it has done that it replaces the adjacent cell (e.g. D2) with EUR_FWD. I then want this to do the same with FWD_USD to CASH_USD_FWD and adjacent cell to USD_FWD.
I have a worksheet that I produced from optical character recognition, and there are a lot of funky characters that I need to get rid of. One is a line break or carraige return (I assume it's the same character that I could insert by entering ALT+ENTER). How do I search for this special character to replace it? How do I identify what that invisible character is?
I have very large text data which contains accented characters (E.g., "ÑÒÓÔÕÖÙÚÛÜÝàáâãäåçèéêëìíîïðñòóôõöùúûüýÿˆµ" etc.) within words.
Since I have several data sheets, some of which having 500000+ rows, Find and Replace and similar options are not viable.
I wish to replace each of these characters with regular English characters in all sheets. If that is difficult, these must at least be removed from the whole text. note that I need to preserve regular characters that are commonly used, particularly the hyphen (-) and underscore (_).
I am looking a macro which should perform below activities
I have a lists of suppliers which needs to cleansed....
1.replace all the special characters with a space
2.replace Corporation with Corp Incorporation with Inc Limited with Ltd Limited partnership/ltd partnership with LP Company with Co ASSC/ASSOC with ASSOCIATION/ASSOCIATES (SEARCH SUPPLIER IN GOOGLE FOR THE CORRECT ONE) MGNT with MANAGEMENT SVCS with SERVICES DEPT with DEPARTMENT Unltd with UNLIMITED Ctr with CENTER UNIV with UNIVERSITY
3. Remove any text, Special characters and numbers after INC,CO, LTD, CORP,LLP, LLC
The macro should when I select any particular column... not restricted to column A
