During work this thing stuck me that i have a column A1 an amount like 12345663..now what i want in column B1 the same amount but except first 3 digits..for example instead of 12345663 i want only 45663 in column b..
View 4 RepliesI'm struggling to find a good formula or code produce the below. I have a column that contains a text string followed by spaces then a number. I need to sparate these into two separate cells.
OldNew NewD-EUROBANK PROPERTIES REAL E 4D-EUROBANK PROPERTIES REAL E4D-ACTIVE INVESTMENT SA 12-SYNT 567D-ACTIVE INVESTMENT SA 12-SYNT567RSK HYDRO-NWKR 25(NORWAY REG 1RSK HYDRO-NWKR 25(NORWAY REG1ADRILL LTD 1ADRILL LTD 1OFFSHORE LIMITED 1OFFSHORE LIMITED 1TRATA PLC 2TRATA PLC 2
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05
DuToitskloof Pinotage/Merlot/Ruby Cabernet
1999 Tradition Juracon 375ml
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.
Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
2003 Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
Does anyone have an idea on how to help with this?
Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.
However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.
Attached file where i m not able to split data in seperate seperate coloumn
View 3 Replies View RelatedI have columns with titles at the top, and with numbers in the below cells.
What I would like is a formula for a column seperate to these that firstly, looks if there is a quantity in the relevant cell on that row, secondly takes the title (top cell) of that column, and thirdly puts the number in the cell on that row after the title:
A_____B_____ C_____ D_____ E______ F
1_____UK____ Ger___ M/E___ Rus_____ Nor
2_____80_____250___ 300___ 350_____200
3____ 60_____200____350____350____ 150
So in cell A1, I would like a formula that reads the subsequent cells and their titles, and gives a one-cell summary of the data seperated by commas. So in A1 it would say:
UK 80, Ger 250, M/E 300, Rus 350, Now 200
And in A2:
UK 60, Ger 200, M/E 350, Rus 350, Now 150
i need to format my numbers in the following format
10,00,000.00
the first three digits will be separated and then subsequently 2 digits
I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.
=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)
I have a formula that looks like this:
=IF(ISERROR((C101/G119)*G104)," ",((C101/G119)*G104))
There are about 15 cells with formulas similar to this. They are calculating a value for a row and at the end all of them should add up should equal C101.
The problem is the value that formula returns has to be two digits and I know it almost never is. But it ALWAYS equils C101. However because it only shows two digits somtimes if you manulally add up the value that you see it does not its off by +/-.01.
I need to fix it so that it does equal C101 AND if you were to add up the digits (with 2 decimal places) it will also equil C101.
I have this formula :
=SUM(LARGE((1-ISNUMBER(FIND({1,2,3,4,5,6,7,8,9,0},AQ10)))*{1,2,3,4,5,6,7,8,9,0},{1,2,3,4,5})*10^{1,2,3,4,5})/10^ISNUMBER(FIND(0,AQ10))
But sometime the number 1 is missing ? see example :
3890 the formula return : 24567 so I'm missing the digit 1 ?
same for this one :
2340 the formula return : 56789 so I'm missing the digit 1 again ?
and for this one it's good :
2389 the formula return : 145670
I have a list of project numbers in column "J" and i need to pull the first six digits of the project number to column "O"
View 4 Replies View RelatedWhen we give formulas say for eg
cell A5/Cel d4*30/365
we format for two digits so i get in my spread sheet cell as
60423.28
but it is actually
60423.28302
so over a period of time my figures posted in accounts dont match to excel spreadsheet.
How can i get the excel spreadsheet to not only show two digits but calculate to two digits as well So say if my calculation result is
60423.276 it should not only show 60423.28 but also be that way and not 60423.276
I would like a formula to track consecutive odd/even digits.
Odd= 1,3,5,7,9 consecutive 135,357,579,791 any order of those values.
example 135,153,315,351,513,531
Even= 0,2,4,6,8 consecutive 024,246,468,680 any order of those values.
example 024,042,204,240,420,402
If no CE or CO, return N
Sheet1BCDEF1103/29/14208CE1203/29/14913CO1303/28/14462CE1403/28/14795COExcel 2007
I need a lookup formula that matches first three digits of column, U (153 - LINE PIPE), and match Total 13153 - LINE PIPE, 7th, 8th, and 9th digit in column C. and bring value from either column T,
The formula that I am using is not obviously not correct, I am putting it here to show what I am trying to do.
{=INDEX($T$2:$T$16,MATCH(LEFT(S2,3),MID(C2:C273,FIND(" ",C2),3)),FALSE)}
I could really use some excel function. Within my office, we work with several hundred files. Each employee is assigned files based on the last two digits of the file number. What I need is a way to identify what file is assigned to which employee based on the term digits of the file.
So for example, I have the following list of files:
1002856101
22781721
1044863815
1008799064
1044779765
1006511115
1007641804
0729939256
5303486020
8364709
0014094759
0019921519
8172717
I'm able to do a formula to get the term digits (meaning the last two numbers), but i'd like to have another column that can put names based on the term digit column. For example, Tom might work 00-04, Sally works 05-09, Greg works 10-15, Lucy works 16-21.. etc
I came across the below IF formula that is exactly what i need, except it only works for two associates and not the multiple that i need.. but it looks to be a good starting point nonetheless.
------------------------------
=IF(C2<50,"Sheryl","Lisa"). You should enclose Sheryl and Lisa with quotation marks as these are string values.
You can also use (if A2 is where the Loan # is):
=IF(Right(A2,2)*1<50,"Sheryl","Lisa")
The formula will acquire the last 2 digits of the loan and check it if it's for Sheryl's or Lisa's.
-----------------------------
I want to be able to look up values based on what I put in a seperate cell. For instance, I want to be able to type in 11 in cell B1 and have A1 return the value for E11. Then if I change the value to 10 in B1, the value for E10 would be returned.
View 3 Replies View RelatedI need creating a tool for numerology.
Every alphabet from a to z has a number associated with it.
A = 1, b 2 , c = 3 etc
Numeric Values for Each Numeral
A1N5
B2O7
C3P8
D4Q1
E5R2
F8S3
G3T4
H5U6
I1V6
J1W6
K2X5
L3Y1
M4Z7
I can either use excel or access or write this.
Example 1 , r = 2 , I = 1, L = 3. .
If I write RIL in column 1 , column 2 should say 213 and column 3 should add 2+1+3 and display 7.
Example 2:
Col 1 = Infosys Ltd
Col 2 should say 1587313 344
Col 3 = 1 + 5 + 8+ 7+ 3+1+3 3+4+4 = 39 , 3+ 9 = 12 , add 1+2 = 3
I have a spreadsheet with two sheets, 'Sheet0' & 'Sheet1'. In 'Sheet0' I have a column named 'A_Sheet0' containing a list of numbers from Rows 2 - 50. In 'Sheet1' I have 3 columns, the first containing numbers 1 to 50, the second, 'B_Sheet1' containing a list of ascending numbers and the third is the column of interest. This column entitled 'Nearest Value' must read the corresponding value of Column 'B_Sheet1' then find the closest number to that from the numbers in 'Sheet0', column 'S_Sheet0'.
I have included a sample file with this thread, and in the 'Nearest Value' column I have manually input some of the nearest values for your information.
I had getting a hyperlink from a Shape to a Cell on seperate worksheets and the macro works fine:
View 4 Replies View RelatedI am somewhat new to excel and have a task I have a catalogue that I need to separate multiple printer models that all have the same part # into individual line items. This will save me weeks of work.
I have this:
Model
part
DCP-7020/HL-2030,2040,2070N/MFC-7220,7420,7820N
TN350
And want to end up with this:
Model
Part
DCP-7020
TN350
HL-2030
TN350
HL-2040
TN350
[Code]...
Or even this:
Series
Model
Part
DCP
7020
TN350
HL
2030
TN350
[Code]...
I have a list of sales enquiries 1600 rows long. Each has a brand recorded in cell J (from j4 above is headers)
I have 4 brands
A, B, C & D
I would like to copy the data from the master sheet into 4 tabs lables A, B, C & D depending on the brand recorded in J
I have a bunch of cells (could be varying amounts from 2 to about a 100). I need a macro which can find out how many rows in column A contain values and then i need to pick values from each cell in column A and put them in Cell B2 seperated by a comma.
eg.
Column A Column B
22 22,35,67,34,56
35
67
34
56
Column A could contain as many as 100 values.
I entered exactly 113,876.92 in cell L16 I entered exactly 113,390.02 in cell L17 I entered =L16-L17 in cell L18 L18 incorrectly shows the result at 486.9000000000009000 (note the extra "9" after the 11 zeros). When I expand the viewable digits on L16 and L17, they have ALL zeros after the cents. (I went out at least 25 digits). I can't be the first one encountering this.
View 4 Replies View RelatedIs it posible to do 3 seperate calculations in a single cell and desplay those results? For example in a single cell: A1+A2 | A3+A4 | A5+A6|
Where:
A1 = 1
A2 = 2
A3 = 3
A4 = 4
A5 = 5
A6 = 6
Results Display: 3,7,11.
I have cells in a column that record time in date. Unformatted it would appear as 19789.51407 but formatted to show time and date it would as appear as 3/6/54 12:20 PM. I am making graphs with the data and I want the title of my x axis to read "GMT Time (mm/dd/yyyy - mm/dd/yyyy)" or "GMT Time (mm/dd/yyyy)" depending on if the event spans more then one day. Using the following code, it almost accomplishes this.
Dim strDate As String
Range("CO3").Value = Range("A3").Value
Range("CP3").Value = Range("A" & Drag).Value
Range("CO3:CP3").NumberFormat = "m/d/yyyy"
If Range("CO3").Value = Range("CP3").Value Then
strDate = "GMT Time (" & Range("CO3") & ")"
Else
If Range("CO3").Value < Range("CP3").Value Then
strDate = "GMT Time (" & Range("CO3") & " - " & Range("CP3") & ")"
End If
End If
Where "Drag" is a variable that signifies the total number of cells in the column; ie the first and last dates. It compares the values and saves the results as a string. The problem is that when the string is saved it saves the date in mm/dd/yyyy hh/mm/ss. How can i separate the date from the time so I can have the title of my x axis appear as i need them?
I need a formula to drag down the attached that will place zeros infront of any numbers that don't have 9 digits. so if a part number consists of 6 digits then i need 3 zeros in front of it, if a part number consists of 9 digits then i dont need any zeros proceeding it.
View 2 Replies View RelatedI have two sheets in my workbook, and I am trying to reference one chart's value into the other. (attached)
I have referenced successfully by manually typing in the reference on row 2 for all values on Sheet 1:
Sheet 1 - C2 needs to reference Sheet 2 - B2. (Sheet2!B2) - no problem all the way across to F2. All those values are correct b/c I manually typed in the reference.
The problem comes when I just want to drag over that same formula to increment for the other cells. It's not incrementing the formula like I need it to.
So, Sheet 1, Row 2 shows how the correct values I need to pull over but was done in a manual way. Sheet 1, Row 5 shows how it increments incorrectly when I try to just drag/copy the formula over. What I need is for Sheet 1 - D5 to reference Sheet 2 - C3, but instead if I try and drag to copy the formula instead of manually typing it in, it increments when I drag reference D2 instead of C3.
I was wondering how do you format a cell so that when i enter the number 7 it automatically sets it at 007 and for like 10 it would be 010 so a must have of 3 digits
View 5 Replies View Relatedadding the sum of digits in a cell using VBA. For eg: in A1 if I have 12345 I need the sum of 12345 (15) in cell B1.
View 3 Replies View RelatedI found a formula that would copy only the last 2 digits of a previous cell and put it in a new cell. For example below, I want the cells to the right of the below to be:
12345 45
26548 48
21854 54
211ae ae
I thought it was a =right or something.