I'm struggling to find a good formula or code produce the below. I have a column that contains a text string followed by spaces then a number. I need to sparate these into two separate cells.
OldNew NewD-EUROBANK PROPERTIES REAL E 4D-EUROBANK PROPERTIES REAL E4D-ACTIVE INVESTMENT SA 12-SYNT 567D-ACTIVE INVESTMENT SA 12-SYNT567RSK HYDRO-NWKR 25(NORWAY REG 1RSK HYDRO-NWKR 25(NORWAY REG1ADRILL LTD 1ADRILL LTD 1OFFSHORE LIMITED 1OFFSHORE LIMITED 1TRATA PLC 2TRATA PLC 2
Can a vba macro be provided for splitting a number into digits? The number will be in Sheet 1 but splitted number will be on sheet 2. Splitting of numbers means a number entered into a cell will be splitted into different column/cells with one digit per cell.
During work this thing stuck me that i have a column A1 an amount like 12345663..now what i want in column B1 the same amount but except first 3 digits..for example instead of 12345663 i want only 45663 in column b..
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...). Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below: De Wetshof Finesse/Lesca Cahrdonnay ‘07 De Wetshof Sauvignon Blanc ‘07 Lord Neethling Cabernet Franc 2002 Lord Neethling Pinotage ‘01 Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07 Jacobsdal Pinotage 1994 Zondernaam Sauvignon Blanc 2007 Tokara Red 1976 St Emilion 03 Tokara rose Plasir de Merle Cabernet Sauvignon ‘05 DuToitskloof Pinotage/Merlot/Ruby Cabernet 1999 Tradition Juracon 375ml
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in: =IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.
Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below: De Wetshof Finesse/Lesca Cahrdonnay ‘07 De Wetshof Sauvignon Blanc ‘07 Lord Neethling Cabernet Franc 2002 Lord Neethling Pinotage ‘01 Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07 Jacobsdal Pinotage 1994 Zondernaam Sauvignon Blanc 2007 2003 Tokara Red 1976 St Emilion 03 Tokara rose Plasir de Merle Cabernet Sauvignon ‘05
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in: =IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2))) As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
Does anyone have an idea on how to help with this?
Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.
However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.
In an adjacent column, I am seeking to display the letters, numbers or symbols that appear before '/'. I would normally solve this little problem with something like =left(A5,2) or some combination of left and len. This method fails when the formula finds a len of 8 when the previous highest len was 7.
Formula to split a cell at the first break/space and to keep the rest of the cell contents together? For example to separate addresses from the street and street name.
Eg.
A1 1111 AAAA BBB
into
B1 C1 111 AAAA BBB
I have tried to use text to columns but as the cell contains three or four words I don't want to have to rejoin cells afterwards.
I am suffering with split a long descriptions into 3 cells with criteria 1st cell not more than 30 characters, 2nd cell not more than characters and 3rd cell will locate the remaining characters there. I think this is quite easy if I use LEN/MID/RIGHT/LEFT formula. However, I wish the formula will smart enough to split word by word. refer to example below:-
"My lecturer replied, that i really did very bad in final, nothing's gonna change my plan."
If I use left(A1,30) formula, the result is "My lecturer replied, that i re"however, the word "really" is cut half way. I am finding the formula that split description to not more than 30 characters and won't cut my string and become incomplete word. Expected result should be 1st cell "My lecturer replied, that i", then "really did very bad in final," at 2nd cell.
I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.
=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)
There are about 15 cells with formulas similar to this. They are calculating a value for a row and at the end all of them should add up should equal C101.
The problem is the value that formula returns has to be two digits and I know it almost never is. But it ALWAYS equils C101. However because it only shows two digits somtimes if you manulally add up the value that you see it does not its off by +/-.01.
I need to fix it so that it does equal C101 AND if you were to add up the digits (with 2 decimal places) it will also equil C101.
I need a lookup formula that matches first three digits of column, U (153 - LINE PIPE), and match Total 13153 - LINE PIPE, 7th, 8th, and 9th digit in column C. and bring value from either column T,
The formula that I am using is not obviously not correct, I am putting it here to show what I am trying to do.
I could really use some excel function. Within my office, we work with several hundred files. Each employee is assigned files based on the last two digits of the file number. What I need is a way to identify what file is assigned to which employee based on the term digits of the file.
So for example, I have the following list of files:
I'm able to do a formula to get the term digits (meaning the last two numbers), but i'd like to have another column that can put names based on the term digit column. For example, Tom might work 00-04, Sally works 05-09, Greg works 10-15, Lucy works 16-21.. etc
I came across the below IF formula that is exactly what i need, except it only works for two associates and not the multiple that i need.. but it looks to be a good starting point nonetheless.
------------------------------ =IF(C2<50,"Sheryl","Lisa"). You should enclose Sheryl and Lisa with quotation marks as these are string values.
You can also use (if A2 is where the Loan # is):
=IF(Right(A2,2)*1<50,"Sheryl","Lisa")
The formula will acquire the last 2 digits of the loan and check it if it's for Sheryl's or Lisa's. -----------------------------
I entered exactly 113,876.92 in cell L16 I entered exactly 113,390.02 in cell L17 I entered =L16-L17 in cell L18 L18 incorrectly shows the result at 486.9000000000009000 (note the extra "9" after the 11 zeros). When I expand the viewable digits on L16 and L17, they have ALL zeros after the cents. (I went out at least 25 digits). I can't be the first one encountering this.
I need a formula to drag down the attached that will place zeros infront of any numbers that don't have 9 digits. so if a part number consists of 6 digits then i need 3 zeros in front of it, if a part number consists of 9 digits then i dont need any zeros proceeding it.
I was wondering how do you format a cell so that when i enter the number 7 it automatically sets it at 007 and for like 10 it would be 010 so a must have of 3 digits
Here's my problem. I have a cell where there are many data strings seperated by ",". Each data string has a seperate value of its own like for e.g: A2: aa,ab,ac
String Value aa 1 ab 1 ac 3
What I want it accomplish is that, split the A2 cell into the different data string entities seperated by ",", then get the corresponding value of each of the data string entity, and to take the average of all the values of the different data string entities.
I found a formula that would copy only the last 2 digits of a previous cell and put it in a new cell. For example below, I want the cells to the right of the below to be:
I have pasted over 1300 numbers in a list, all of which need to have 5 digits. However, when I pasted the 5 digit number (ie 00003) into the cell, it omits the leading 0's.
Is there any way to get these numbers back to having 5 digits....and if it omitted the 0's, can I put them back all in one fell swoop?
I have a sheet with column A. This column A contains numbers from 1 number to 6 numbers.
So, one cell can have a '1' or a '999999' or any combination between them. Now this is the problem.
I want a formula that will fill those cells that don't contain a number up to 6 digits. So if a cell contains '254' I will like this formula to fill the cell like this: 000254.
This should happen with any number that don't have a number with six digits.
78 should be 000078, 78652 should be 078652 and so on.
