I have this formula :
=SUM(LARGE((1-ISNUMBER(FIND({1,2,3,4,5,6,7,8,9,0},AQ10)))*{1,2,3,4,5,6,7,8,9,0},{1,2,3,4,5})*10^{1,2,3,4,5})/10^ISNUMBER(FIND(0,AQ10))
But sometime the number 1 is missing ? see example :
3890 the formula return : 24567 so I'm missing the digit 1 ?
same for this one :
2340 the formula return : 56789 so I'm missing the digit 1 again ?
and for this one it's good :
2389 the formula return : 145670
i need to format my numbers in the following format
10,00,000.00
the first three digits will be separated and then subsequently 2 digits
I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.
=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)
I have a formula that looks like this:
=IF(ISERROR((C101/G119)*G104)," ",((C101/G119)*G104))
There are about 15 cells with formulas similar to this. They are calculating a value for a row and at the end all of them should add up should equal C101.
The problem is the value that formula returns has to be two digits and I know it almost never is. But it ALWAYS equils C101. However because it only shows two digits somtimes if you manulally add up the value that you see it does not its off by +/-.01.
I need to fix it so that it does equal C101 AND if you were to add up the digits (with 2 decimal places) it will also equil C101.
I have a list of project numbers in column "J" and i need to pull the first six digits of the project number to column "O"
View 4 Replies View RelatedDuring work this thing stuck me that i have a column A1 an amount like 12345663..now what i want in column B1 the same amount but except first 3 digits..for example instead of 12345663 i want only 45663 in column b..
View 4 Replies View RelatedWhen we give formulas say for eg
cell A5/Cel d4*30/365
we format for two digits so i get in my spread sheet cell as
60423.28
but it is actually
60423.28302
so over a period of time my figures posted in accounts dont match to excel spreadsheet.
How can i get the excel spreadsheet to not only show two digits but calculate to two digits as well So say if my calculation result is
60423.276 it should not only show 60423.28 but also be that way and not 60423.276
I'm struggling to find a good formula or code produce the below. I have a column that contains a text string followed by spaces then a number. I need to sparate these into two separate cells.
OldNew NewD-EUROBANK PROPERTIES REAL E 4D-EUROBANK PROPERTIES REAL E4D-ACTIVE INVESTMENT SA 12-SYNT 567D-ACTIVE INVESTMENT SA 12-SYNT567RSK HYDRO-NWKR 25(NORWAY REG 1RSK HYDRO-NWKR 25(NORWAY REG1ADRILL LTD 1ADRILL LTD 1OFFSHORE LIMITED 1OFFSHORE LIMITED 1TRATA PLC 2TRATA PLC 2
I would like a formula to track consecutive odd/even digits.
Odd= 1,3,5,7,9 consecutive 135,357,579,791 any order of those values.
example 135,153,315,351,513,531
Even= 0,2,4,6,8 consecutive 024,246,468,680 any order of those values.
example 024,042,204,240,420,402
If no CE or CO, return N
Sheet1BCDEF1103/29/14208CE1203/29/14913CO1303/28/14462CE1403/28/14795COExcel 2007
I need a lookup formula that matches first three digits of column, U (153 - LINE PIPE), and match Total 13153 - LINE PIPE, 7th, 8th, and 9th digit in column C. and bring value from either column T,
The formula that I am using is not obviously not correct, I am putting it here to show what I am trying to do.
{=INDEX($T$2:$T$16,MATCH(LEFT(S2,3),MID(C2:C273,FIND(" ",C2),3)),FALSE)}
I have two columns which i want to compare, they contain text data such as A123.
what I'd like is if its in column A and not in Column B then add to bottom of column A.
Once its in column A i can do the vlookup's to draw the other data, costs etc, over but don't know how to identify, and add, the missing codes to the list.
I could really use some excel function. Within my office, we work with several hundred files. Each employee is assigned files based on the last two digits of the file number. What I need is a way to identify what file is assigned to which employee based on the term digits of the file.
So for example, I have the following list of files:
1002856101
22781721
1044863815
1008799064
1044779765
1006511115
1007641804
0729939256
5303486020
8364709
0014094759
0019921519
8172717
I'm able to do a formula to get the term digits (meaning the last two numbers), but i'd like to have another column that can put names based on the term digit column. For example, Tom might work 00-04, Sally works 05-09, Greg works 10-15, Lucy works 16-21.. etc
I came across the below IF formula that is exactly what i need, except it only works for two associates and not the multiple that i need.. but it looks to be a good starting point nonetheless.
------------------------------
=IF(C2<50,"Sheryl","Lisa"). You should enclose Sheryl and Lisa with quotation marks as these are string values.
You can also use (if A2 is where the Loan # is):
=IF(Right(A2,2)*1<50,"Sheryl","Lisa")
The formula will acquire the last 2 digits of the loan and check it if it's for Sheryl's or Lisa's.
-----------------------------
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05
DuToitskloof Pinotage/Merlot/Ruby Cabernet
1999 Tradition Juracon 375ml
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.
Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
2003 Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
Does anyone have an idea on how to help with this?
Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.
However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.
I need creating a tool for numerology.
Every alphabet from a to z has a number associated with it.
A = 1, b 2 , c = 3 etc
Numeric Values for Each Numeral
A1N5
B2O7
C3P8
D4Q1
E5R2
F8S3
G3T4
H5U6
I1V6
J1W6
K2X5
L3Y1
M4Z7
I can either use excel or access or write this.
Example 1 , r = 2 , I = 1, L = 3. .
If I write RIL in column 1 , column 2 should say 213 and column 3 should add 2+1+3 and display 7.
Example 2:
Col 1 = Infosys Ltd
Col 2 should say 1587313 344
Col 3 = 1 + 5 + 8+ 7+ 3+1+3 3+4+4 = 39 , 3+ 9 = 12 , add 1+2 = 3
"your formula is missing --) or (. Check the formula and then add the parenthesis in the appropriate place. The following is one long string. I broke it up to make it easier to read.
=IF(OR(ISNUMBER(FIND("J",M117)),K114,
OR(ISNUMBER(FIND("S",M117,)),K112,
OR(ISNUMBER(FIND("HOH",M117,)),K117,
OR(ISNUMBER(FIND("MF",M117)),K113,
OR(ISNUMBER(FIND("QW",M117)),K116,
OR(ISNUMBER(FIND("B",M117)),K115,0
The formula works well 50% of the time, but randomly skips over some values. I have attached a sample of what I'm working on.
Extracting example.xlsx
There will be thousands of questions similar, but think there will be a limit of 4 numbers to be taken out.
using IF formula [ =IF(SUM(C3),LOOKUP(DATEDIF($C3,NOW(),"y"),(0,3,),(0,3,)),"")] holiday sheet after 5 years service employee get 3 days extra holiday trying to in E3 to add 3 days to holiday entitlement to take from 16 days to 19 days
View 2 Replies View RelatedI have a workbook that on sheet one I mark qualifications with an X. On sheet 2 I use a formula that places an X in cells if all requirements are met example:
=IF(((Sheet1!C5="X")*(Sheet1!D5="X")*(Sheet1!E5="X")*(Sheet1!F5="X")*(Sheet1!H5="X")*(Sheet1!I5="X")*(Sheet1!AO5="X")*((Sheet1!AL5="X")+(Sheet1!AM5="X"))),"X","")
Is there a formula I can use that if one of the requirements are not met it will tell me what is missing instead of me going back and have to look through all the data to find out D5 was missing as an example?
I entered exactly 113,876.92 in cell L16 I entered exactly 113,390.02 in cell L17 I entered =L16-L17 in cell L18 L18 incorrectly shows the result at 486.9000000000009000 (note the extra "9" after the 11 zeros). When I expand the viewable digits on L16 and L17, they have ALL zeros after the cents. (I went out at least 25 digits). I can't be the first one encountering this.
View 4 Replies View RelatedIs there anyway to find missing numbers from column by excel formula?
Here is an example:
A
B
C
01 06 44
01 31 45
01 39 48
04 21 27
07 21 44
27 30 44
[Code] .....
Missing Numbers
32, 41, 49
02, 06, 11, 14, 17, 25,33, 34, 46, 47, 50, 51
04, 05, 13, 20, 29, 33, 40, 41, 49
I need a formula to drag down the attached that will place zeros infront of any numbers that don't have 9 digits. so if a part number consists of 6 digits then i need 3 zeros in front of it, if a part number consists of 9 digits then i dont need any zeros proceeding it.
View 2 Replies View RelatedI have a decent working knowledge of excel, but I'm stuck... I teach and I have created an excel spread sheet to help me keep track of grades, attendance, etc.
I'm trying to figure out how to get excel to figure out the assignments a student has missing (cells with no data input), then take the assignment name (column title with missing data) and students name (first column of data) and put that information in another worksheet. Basically I would like excel to tell me what students are missing work and what assignments they are missing so I don't have to scroll through hundreds of lines of data whenever I have midterms or a student wants a list of "missing assignments". BTW---I can get it to list the number of assignments a student has missing, but not list the specific assignment titles.
I know theoretically this is possible, but I'm having trouble figuring out how to do it. Any help would be appreciated as it will save a lot of time and help out my students! If you can give me a "fake" formula, I should be able to update it for my purposes...
I am looking for a formula that I can use in the lower table to fill in the missing County cells, based on the values in the Town/Zip columns on the top table (I apoligize for the crudeness):
CountyTownZipAbleTownA00000AbleTownB00001AbleTownC00002BravoTownD00003BravoTownE00004CountyTownZipMemberTownD00003BlackTownC00002FrankTownA00000GreeneTownB00001JonesTownA00000SmithTownC00006ThomasTownE00004White
This would consist of hundreds of Zips and Towns and this is just an abbreviated mock up.
Is it possible to have a formula that generate a Unique list (List 1 and List 2) of Missing values in List 2 by comparing two lists? Something like this
List 1 List 2 Missing in List 2
1 1 3
3 4 6
5 5
6 6
I have a tracking template with a column listing dates, all i want to do is find all the missing dates from that column of dates.
Example:
Column A
1-May
2-May
4-May
5-May
7-May
8-May
10-May
11-May
12-May
14-May
15-May
I want to list the missing dates from this list.
I can't seem to find a way to find the max of only the last four digits of a cell, matching the first 8. As an example:
I have thousands of cells in a column like this, (and I can't add any columns to the sheet), and I have a cell with the first three digits and the second three digits. So, out of all these numbers, I want the MAX of ONLY the numbers with the first 8 digits of "800-123-". Also, the decimal on the end is how many times the number was called, and any the decimal and any number after it is to be ignored. The answer would be "800-123-0024", or "0024", I just need a faster way to find it without searching for it.
888-555-0099.2
800-123-0022.3
555-333-0474
[Code]....
I have a long list of 4 digit numbers:
e.g.
0234
2434
6566
4566
6785
But I only want the first 2 digits (I need the last two digits deleted). I don't want to just divide by 1000 as this will leve me with a decimal. The numbers are in text format as some of them begin with a 0. So it would be:
02
24
65
45
67
I would like to take the first three digits of column A and do a lookup of column B that would return the corresponding number from column C. For example, if I entered the formula for 103PH, the lookup would find the 103 in column B and return "2775.00" from column C...........
View 4 Replies View RelatedI was wondering how do you format a cell so that when i enter the number 7 it automatically sets it at 007 and for like 10 it would be 010 so a must have of 3 digits
View 5 Replies View Related
