There are about 15 cells with formulas similar to this. They are calculating a value for a row and at the end all of them should add up should equal C101.
The problem is the value that formula returns has to be two digits and I know it almost never is. But it ALWAYS equils C101. However because it only shows two digits somtimes if you manulally add up the value that you see it does not its off by +/-.01.
I need to fix it so that it does equal C101 AND if you were to add up the digits (with 2 decimal places) it will also equil C101.
I am using Excel 2003. I am trying to importing a 20 character from a barcode scanner to cell K2 in an Excel spreadsheet. When the part is scanned, the program handling the scanner data shows the data as being 12345678901234567890. I am running a macro that retrieves that data and places it in cell K2. The number that appears in cell K2 is 12345678901234500000. The macro module code reads:
Sub GetSWData() Dim WedgeData As Variant Dim MyPort As String Dim Chan As Long Dim StringVar As String Dim DataIn As Double MyPort = "COM1" Application.DisplayAlerts = False Chan = DDEInitiate("WinWedge", MyPort) WedgeData = DDERequest(Chan, "Field(1)") DataIn = WedgeData(1) Range("K2").Value = WedgeData(1) DDETerminate Chan End Sub
I am guessing that one of the Dim statements has the wrong word after As but nothing I have tried gets me past this point.
I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.
=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)
During work this thing stuck me that i have a column A1 an amount like 12345663..now what i want in column B1 the same amount but except first 3 digits..for example instead of 12345663 i want only 45663 in column b..
I'm struggling to find a good formula or code produce the below. I have a column that contains a text string followed by spaces then a number. I need to sparate these into two separate cells.
OldNew NewD-EUROBANK PROPERTIES REAL E 4D-EUROBANK PROPERTIES REAL E4D-ACTIVE INVESTMENT SA 12-SYNT 567D-ACTIVE INVESTMENT SA 12-SYNT567RSK HYDRO-NWKR 25(NORWAY REG 1RSK HYDRO-NWKR 25(NORWAY REG1ADRILL LTD 1ADRILL LTD 1OFFSHORE LIMITED 1OFFSHORE LIMITED 1TRATA PLC 2TRATA PLC 2
I need a lookup formula that matches first three digits of column, U (153 - LINE PIPE), and match Total 13153 - LINE PIPE, 7th, 8th, and 9th digit in column C. and bring value from either column T,
The formula that I am using is not obviously not correct, I am putting it here to show what I am trying to do.
I could really use some excel function. Within my office, we work with several hundred files. Each employee is assigned files based on the last two digits of the file number. What I need is a way to identify what file is assigned to which employee based on the term digits of the file.
So for example, I have the following list of files:
I'm able to do a formula to get the term digits (meaning the last two numbers), but i'd like to have another column that can put names based on the term digit column. For example, Tom might work 00-04, Sally works 05-09, Greg works 10-15, Lucy works 16-21.. etc
I came across the below IF formula that is exactly what i need, except it only works for two associates and not the multiple that i need.. but it looks to be a good starting point nonetheless.
------------------------------ =IF(C2<50,"Sheryl","Lisa"). You should enclose Sheryl and Lisa with quotation marks as these are string values.
You can also use (if A2 is where the Loan # is):
=IF(Right(A2,2)*1<50,"Sheryl","Lisa")
The formula will acquire the last 2 digits of the loan and check it if it's for Sheryl's or Lisa's. -----------------------------
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...). Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below: De Wetshof Finesse/Lesca Cahrdonnay ‘07 De Wetshof Sauvignon Blanc ‘07 Lord Neethling Cabernet Franc 2002 Lord Neethling Pinotage ‘01 Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07 Jacobsdal Pinotage 1994 Zondernaam Sauvignon Blanc 2007 Tokara Red 1976 St Emilion 03 Tokara rose Plasir de Merle Cabernet Sauvignon ‘05 DuToitskloof Pinotage/Merlot/Ruby Cabernet 1999 Tradition Juracon 375ml
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in: =IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.
Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below: De Wetshof Finesse/Lesca Cahrdonnay ‘07 De Wetshof Sauvignon Blanc ‘07 Lord Neethling Cabernet Franc 2002 Lord Neethling Pinotage ‘01 Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07 Jacobsdal Pinotage 1994 Zondernaam Sauvignon Blanc 2007 2003 Tokara Red 1976 St Emilion 03 Tokara rose Plasir de Merle Cabernet Sauvignon ‘05
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in: =IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2))) As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
Does anyone have an idea on how to help with this?
Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.
However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.
when i use a simple sum it only returns 0 but if I use the same cells and manually add them ie A1+A2+A3 and so on it give me the answer ? As there are over 500 cells it would be a pain to type them.
I have a workbook that is taking the avarage percentage of efficency over a possible of 7 days. If there were only 5 days of production it would average only 5 days. It pulls info from a tab that is call "Datalink" which is just that. As we have started our new fiscal year the person who uses this came to me with this problem
1) GrpIV on C15 is returning # DIV/0! and we need it to return 0. See the attachment.
I have always used unique ways to randomly make selections in my life, and was thrilled to learn that Excel could pick a name(not just a number) from a list. I've used the =INDEX($A:$A,RANDBETWEEN(1, COUNTA($A:$A)),1) function and entered items into Column A (or another if needed, and updated by trial and error accordingly). It worked very well for me for a long time and then stopped working. In multiple documents, with multiple lists (not connecting to each other), all of a sudden every random item started giving the #NAME error.
I entered exactly 113,876.92 in cell L16 I entered exactly 113,390.02 in cell L17 I entered =L16-L17 in cell L18 L18 incorrectly shows the result at 486.9000000000009000 (note the extra "9" after the 11 zeros). When I expand the viewable digits on L16 and L17, they have ALL zeros after the cents. (I went out at least 25 digits). I can't be the first one encountering this.
I need a formula that can return the value from a cell in the same row it searches. The row is unsorted and has blank cells. Seacchs row A12:X12 returns the text in C4 (data validation List) in A19 on a different sheet.
The results of the formula in cell K36 in the attached spreadsheet returns a value of null. It should be $1,200. Am I blind or have I done something wrong.
I placed this formula in cell A1 in workbook number 2which is suppose to grab what ever name is in cell A4 of workbook 1 However if the cell is blank it is returning a "0"I want it to be blank if there is no name in the cell?
For some reason it is returning #VALUE! in some cells. I think its something to do with the last part of the formula where it is bold.
The formula as you can see looks at data and matches relevant data to return specific depending on what has been matched. Now at the end it is matching the correct data and return that value however i want to divide the value by another (another value*4.33).
The formula below was written a couple of years ago and I just discovered an error. It returns an "S" for the value 0789 when it should be a "C", (Consecutive).
******** ******************** ************************************************************************>Microsoft Excel - FL MID PLAY 4 CONSECUTIVES.xlsm___Running: 12.0 : OS = Windows XP (F)ile (E)dit (V)iew (I)nsert (O)ptions (T)ools (D)ata (W)indow (H)elp (A)boutT215=OPQRST215078907893SSheet2 [HtmlMaker 2.42] To see the formula in the cells just click on the cells hyperlink or click the Name boxPLEASE DO NOT QUOTE THIS TABLE IMAGE ON SAME PAGE! OTHEWISE, ERROR OF JavaScript OCCUR.
I need a formula to drag down the attached that will place zeros infront of any numbers that don't have 9 digits. so if a part number consists of 6 digits then i need 3 zeros in front of it, if a part number consists of 9 digits then i dont need any zeros proceeding it.
I have a two different formulas the return a numbered result(PO Number) in the same column. I then vlookup both of them with the same formula into a pivot table, one returns the result one doesn't. format appears to be the same.
