I have a row of cells that contain a single letter: W,C,O.
I need to provide a count of the number of occurancies of each letter. So I have a cell that shows me the total W's, a cell showing me total C's and another showing total O's.
Whats easiest way to do this?
I know its not ideal, but on this occassion ive no desire to add and hide another column.
Essentially what I'm trying to accomplish is import a file from Quickbooks and determine whether it was a Credit Card, Check or Invoice based on the account number.
For example:
45-12345 should return the value CC in an adjacent cell because it contains the "-" character.
I0123456 should return the value INV in an adjacent cell because it contains the "I" character.
01234567 should return the value ACH in an adjacent cell because it doesn't contain either character.
I tried using VLookup, but I can't figure out how to write a formula for when it just contains a character, only if it matches it or is text/number.
I am trying to put an IF statement together. If the 7th character from the left is 5 it must show M, and If 0(zero), it must show F
View 2 Replies View RelatedCells A1:A5 all have a vlookup formula that will pull one of the following into it:
1. The word "NONE"
2. #N/A error since it doesn't exist in the table
3. A text value that has the format 13.55.46.91
I want a formula that will look at these 5 cells and give me #3. That #3 value can only appear once in the 5 cells in any of those 5. The other 4 cells will contain either 1 or 2.
3 always has length equal to 11. It always has periods in those places. The digits do change.
How to find and show position number? I try merged two function, but doesn't work
1º=FIND("0";B2)
2º=FIND(CHAR(1);SUBSTITUTE(B2;"0";CHAR(1);2))
Number
Position
[Code].....
Can I get a formula for the below specification.
if a cell contains character A THEN multiply by cell B * 0.02,if a cell contains character B THEN multiply by cell B * 0.05,if a cell contains character C THEN multiply by cell B * 0.010
I have an excel spread sheet & I wish to highlight any cell that contains any of the following characters with in a string of text.
/ : * " < > ? |
E.g. a cell in the spread sheet containing the text "Is this a Question?" would be highlighted.
I have tried to use - 'Format only cells that contain' > Specific Text > Containing > for each of the characters and this does not work.
When I do this any cell containing any text is highlighted.
In addition there is formatting on any cell > 60 characters which turns the cell red and this works fine.
What would happen if (when I get the problem above resolved), a cell is > than 60 characters & contains a character listed above?
Does 1 formatting take precedent over another?
(Not critical to know the answer to the additional question, just curious - as long as it is highlighted one colour or another then no problem.)
I need to counting formula (I'm calculating weighted frequency of specific letters). My data is as follows:
A1 "lingual"
B2 "28"
The formula needs to look at the word in A1 and count the number of times a given letter (e.g., "l") appears in the cell (any position), and then multiply the result of the count by the value in B2. In the example above, the answer should be 56 (the letter "l" appears twice in "lingual", so it's 28X2).
I have a spreadsheet which has a column that contains route numbers (for collection of goods). Some addresses have 2 or 3 route numbers within the same cell i.e.
3
3 20
3 20 15
I would like to know the formula for counting the number of cells that contain each route number i.e. from above 3 = 3, 20 = 2, 15 = 1
1) In any cell, I would like to remove "Area#xxxxxxxxx" (where x are random numbers).
Example : "INFO Log - [sys] Area#541185471Character#46545"
2) I would like to remove x characters before a word.
Example : 2013-08-28.txt@INFO
I would need to remove 14 characters before the character "@".
I tried to play with the LEN and RIGHT/LEFT formula but so far, I can't get it to work... The idea is to parse some text and remove the part in red (I was thinking about using SUBSTITUTE).
I want a formula to find "#" character in a text.
Example
PO# 4343434, MINCDSD.LTD, 977766
Here i I want to find out the character "#" position
I used =FIND("#", A1,1) Answer is 3 it's ok fine.
But I have problem with this below example;
Revised PO#545455, INV# 434344 ABC LTD
In this example i want second "#" position..
In a cell(s) I have for example {text}dd%2BMore_Text}
what i want to do is search and replace the final }
so it should be {text}dd%2BMore_Text
the regular search and replace in excel removes all } which is not what i need.
Switched to Excel after using OpenOffice and I'm stuck on knowing what an old a 'find and replace' formula would be in Excel. It would remove a specific character (or word) ONLY if it was the last characters in a cell.
The old find and replace for open office:
Find: (.*)/$
Replace: $1
It's not that important now to delete a word, mainly the last slash '/' ONLY if it's the last character e.g. this data has 2 rows with a '/' as the last character
website.com/page
website.com/page/
website.com/page/page/
Running my old find and replace formula would remove the last slashes, but leave the others
website.com/page
website.com/page
website.com/page/page
Need simple replacement to the find and replace but a formula is also right.
How to get Excel to select all cells within a specific column that contain a specific character. In this instance, I need to select all the cells which contain a comma...
And even better would be if I could get Excel to not just select all the cells in a specific column containing a comma, but each of the rows in which those cells reside.
I need to make a list of Part Numbers in quotation marks. If a number of digits of a P/N is less than 13 a number of space characters has to be added to make the string 13 characters long.
We have example P/N:
1234567890123
12345678
123456
should become:
"1234567890123(no extra space characters should be filled-13chars)"
"12345678(5 extra space characters here)"
"123456(7 extra space characters)"
Is there a function that inputs a cerain number of a specific character ("space" in this example)?
I have an excel file in which the cell has more than 3000 entries, like following. I would like to copy the contents before ";" to next row & continue.
Question:
CN=123,CN=12,CN=ABC,CN=AB,;CN=345,CN=34,CN=CDF,CN=DC,;CN=510,CN=51,CN=PQR,CN=PQ;
Answer should be in excel:
CN=123,CN=12,CN=ABC,CN=AB
CN=345,CN=34,CN=CDF,CN=DC
CN=510,CN=51,CN=PQR,CN=PQ
I do not know how can I achieve this through "Macro". I would like to detect ; in the cell & copy the contents before/after it in the next rows & continue till the last figure.
How can I extract mid section of the string which is always 5 characters long and is always followed by a period "." ?
My account strings are in 3 sections (but the third section isn't always used)
For example,
1.10210
1.22556.001
900101.56201
955261.54444.001
5566625.58886.957756
I have one column with many numbers. Some have one dash and some have two.
Example:
123-123456-65
012-789546-1
98B12354-889
Is there a way that I can remove all characters after the last – (dash) in the number?
Example:
If number is 123-123456-65
Then 123-123456
If number is 98B12354-889
Then 98B12354
If someone could just lead me in a direction, I might be able to figure it out. However, my code is elementary and most of the time, I record macros and the play with the code until it does what I want.
I want to count the number of rows in a specific column up to an empty cell and assign this value to a cell. I don't want to count the total number of rows but instead I want the number of the first group of rows.
For example, column A may have cells ranging from row 2 to 10 and then from row 12 to 20, so I only want to count the first group.
The below code counts the total which is not what i need.
Code:
Sub test()
Dim Mycount As Single
Mycount = Application.Count(Range("A:A"))
Cells(1, 4) = Mycount
End Sub
if a cell contains "usable characters". By usable characters i mean i want something to check if a cell contains a number or letter.
cell = AAAAA formula returns true
cell = A123 formula = true
cell = 123 formula = true
cell = ----- formula = false
I need a formula that counts the number of cells in a range that only contains one character. Example, column A contains:
Hello
Goodbye
A
B
Hello
Goodbye
In the above, I want the result to be 2. I've tried =countif(a1:a6,len=1) but that doesn't work.
In column A, I have the following lines:
2014-05-15 02:08:43 @Centre INFO - CHANGE WORLD (Original World to Destination World)
2014-05-15 02:31:37 @Centre INFO - CHANGE WORLD (Original World to Destination World)
2014-05-15 02:37:19 @Centre INFO - CHANGE WORLD (Original World to Destination World)
2014-05-15 02:37:20 @Centre INFO - CHANGE WORLD (Original World to Destination World)
2014-05-15 03:07:19 @Centre INFO - CHANGE WORLD (Original World to Destination World)
2014-05-15 15:01:37 @Centre INFO - CHANGE WORLD (Original World to Destination World)
2014-05-15 15:04:46 @Centre INFO - CHANGE WORLD (Original World to Destination World)
I would like to use conditional formatting to highlight cells which have the same first 16 characters (yyyy-mm-dd hh:mm) before the "@" AND that contains the words "CHANGE WORLD". Therefore, I'm looking for a formula I could include in the conditional formatting so I can easily find the "CHANGE WORLD" that occurred at the same time (minus the seconds, they may vary slightly).
How can i split a string of "name*sirname" by the * character. At the end i want to msgbox the both 2 results as "name" and "sirname"
Code:
Private Sub CommandButton1_Click()
Dim myArray() As String 'DEFINE THE ARRAY
i = 0
[Code].....
What formula or function truncates a text field that is in the following consistent format:
number. name
ie. 3. Super Bella
and 150. Taoist
I wish to truncate the field so I have just the integer without the dot, space or word(s).
Tried Len, Left & Replace but they require a specific number of characters. Since the number can be 1 to 3 digits long, this doesn't work.
I have a cell which will contain SER01+SER02+SER03
and what i need it to contain is [SER01]+[SER02]+[SER03]
and shocker is i've got this to work for the first instance but not the other two
code as below... be grateful for your help
Sub measure1()
Dim list As String, pos As Integer, refl As String, refr As String, newlist As String
list = Cells(1472, 16).Value
pos = InStr(list, "+")
refl = Left(list, pos - 1)
refr = Right(list, pos + 1)
newlist = "[" & refl & "]"
Cells(1472, 17) = newlist
End Sub
excel.jpg
how to make my network days stop counting when I insert a value in the completed column (in this case H3). I have a Date Received column (A3), a due day column (G3) and the last column with the date (N3). My remaining days column keeps counting after I filled the completed cell (H3) and won't stop counting after. I need a formula to stop after the completed cell is fill up.
I've got the following sumproduct formula (which seems to work):
=SUMPRODUCT(--(ISNUMBER(SEARCH($B17,Product_Keywords))),--(YEAR(Invoice_Date)=H$3),--(ROUNDUP(MONTH(Invoice_Date)/3,0)=H$4),--(Invoiced_Amount))
B17 is a keyword to be found in the Product_Keywords range
I'd like to modify it so that:
ifthe cell in the range Product_Keywords also includes "," thendivide the sumproduct by the number of commas+1
Presumably I could add --(ISNUMBER(SEARCH(",",Product_Keywords) as one of the conditions,
but how would I keep track of the number of commas in the cell?
One has numbers the other has "YES" or is blank. I want a formula to look at the second column and where there is a "Yes" then count the number in the same row in the first column.
View 4 Replies View RelatedI need to count how many times I've got, for instance, "a" in several cells where I typed some text...
I would need a formula where I can indicate the letter I want and the range of cells where to look at, and having as result how many occurances there are...
If you are very good instead of a single letter, maybe a sequence of letters... but this is an extra!
I'm trying to use logic to identify trends...in each of the strings below, I want to count the occurrences of the left most character appearing consecutively. The answer is to the left
I'm trying to do this via a formula vs. vba if possible
BBBBBBBBBBBBBBBBBBB - 19
BBBDUDUUUUDDBBBBBBB - 3
UUDUDDUUUDUDBBBBBBB - 2
UDUDDUDUUUDDBBBBBBB - 1
[Code] .....
