Formula- Return Number Of Aged Breaks Under Each Criteria

Jun 30, 2009

I need a formula that will return number of aged breaks under each criteria in sheet 1 row 1 and each team based on the unique case number, so for example in sheet 2 I have my raw data starting in A1, i should get the below results in sheet1 ...

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Formula Return The Number Of Asset Breaks For Each Head Of Department In Sheet3

Jun 30, 2009

I have the following formula which returns the number of asset breaks for each head of dept in sheet3 based on their teams in Sheet1 and then does a countif in >30_DAYS_ASSET in sheet2. In sheet 1 is a mapping table with range names "Teams2", "Teams" & "Managers". I now need the formula to also do a count on the unique numbers in sheet2 Column B, if there are duplicate numbers then that will be 1 asset break, so for example for for Joe plummer we can see there are duplicate case numbers so the formula in total should return 2.

=SUMPRODUCT(--ISNUMBER(MATCH(Teams2,INDEX(Teams,MATCH(C11,Managers,0),0),0)),
COUNTIF('>30_DAYS_ASSET'!$B:$B,Teams2))
Sheet1

AB2ManagersTeams3JOE BLOGGSAMP14JOE PLUMMEREQADMIN567Teams28SECADMIN9AMP1

Excel tables to the web >> http://www.excel-jeanie-html.de/index.php?f=1" target="_blank"> Excel Jeanie HTML 4

Sheet3

AB4Head of DeptASSETS5JOE BLOGGS286JOE PLUMMER3

Excel tables to the web >> http://www.excel-jeanie-html.de/index.php?f=1" target="_blank"> Excel Jeanie HTML 4

Sheet2

AB6SourceCase No.7SECADMIN4498618SECADMIN4498619SECADMIN44991310AMP144986211AMP144918012AMP1550935

Excel tables to the web >> http://www.excel-jeanie-html.de/index.php?f=1" target="_blank"> Excel Jeanie HTML 4

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I am trying to add a number to a cell for work breaks. Below is what I am trying to do:

If F3 is < 4 then 0
If F3 is > 4 but < 6 then .25
If F3 is < 6 then .50

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eg, 104, will return D

MinMaxReturn030A3160B6190C91150D151240E241360F

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Feb 15, 2010

I have a produced an Excel workbook which uses a VBA sign in/out userform.
Once you sign in on the Userform the sheets update. A list is completed of the times people enter and leave.

To make the code easier I currently have the name being returned to the excel sheet and performing a “match” function to return the row number. This row number is then used to carry out what I need to happen in this row. However, as you can see from attached doc (and the brief example below), based on IDnumber "2", the match function returns row 5 not row 8.
I need to have the row number returned for the IDnumber where the Out cell is blank.
This should be the last occurrance of the IDnumber

Example
Row
1 ID# In Out
2 1 9:00 13:00
3 4 9:00 13:00
4 3 9:00 13:00
5 2 9:00 13:00
6 5 9:00 13:00
7 6 9:00 13:00
8 2 14:00

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I can do a match for one criteria, but where I'm having problems is getting it so the two matches are on the same row.

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In the case of descending numbers, if I would like to pick out the first cell that goes below 10.2, would the formula be the same?

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Jan 10, 2010

I want to achieve is a procedure that inserts horizontal page breaks at certain parts of the sheet where there is a cell equal to 2. Here is the code I have so far.

Sub insert_pagebreak()
Dim printbreak_cell As Range
Dim j As Long
Dim i As Long
ActiveSheet.ResetAllPageBreaks
Set printbreak_cell = Range("AD1")
j = 1
For i = 1 To 100
If printbreak_cell.Value = 2 Then
Set ActiveSheet.HPageBreaks(j).Location = printbreak_cell
j = j + 1
End If
Set printbreak_cell = printbreak_cell.Offset(1, 0)
Next i
End Sub

Everything works until the cell value reaches a 2, and then once it goes into the If statement I get a 'Application-defined or object-defined error' at the below line.

Set ActiveSheet.HPageBreaks(j).Location = printbreak_cell.............

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Jul 8, 2014

I'm struggling to come up with a formula that ill give me the following:

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Dec 19, 2013

I can manage an array formula that returns a value based on a criteria. Simple. But I want to add in an additional couple of criteria. Now I'm stuck....

My sheet looks at a manually entered postcode, finds out what region this is in, and returns a list of postcode I have defined as being in that region. (So the postcode WF1 3JY would return a region of Yorkshire, and list postcodes of WF, BD, L, etc)

I also have a list of engineers, with a column for their home postcode.I want to be able to list all the engineers from my list whose home postcode matches any of the values on the already created list from the postcode and region entered. So far I have this, which finds me all the engineers for just one postcode area.

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Aug 25, 2006

I would like to be able to use the Vlookup function to return more then one value as a result of the criteria. I have a cloumn of dates that populates the X axis of a gantt chart with data whilst the Y axis will be populated by a site reference resulting in a program of work, the Y axis data is the result of a vlookup function. My difficulty arises however with multiple sites, for instance where two or three sites will be visited on the same day. The vlookup function will only return the first value it finds in a range to the formulated cell. The result being a missing site(s) from the gantt chart / work program. is it possible to return all values to a cell i.e. site1, site2, site3. using a vlookup or do i need to use another method of doing this?

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I know you can count them with

=IF(LEN(TRIM(A2))=0,0,LEN(TRIM(A2))-LEN(SUBSTITUTE(A2,” β€œ,””))+1)

but the the cells have line breaks so this formula won't work

I've understood that since there is a space before the new line, the formula will not recognise the space and therefore not recognise a new word.

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Nov 2, 2009

See the attached spreadsheet and the comment boxes inserted containing my questions.

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Jan 9, 2013

I have a rolling 12 month (each day in column) tab in Excel 2010 that references variances by ID number in column A, and the column headers are each day for 366 days (2011). I would like to create a tab that shows the past 10 day's variances by ID number. I haven't been able to write a formula that will look at the date headers and the row ID number to return the figure for that day. Here is a sample of the 12 month rolling and the 10 days at a glance that I want to populate.

Rolling 12 Months
IDName12/25/201212/26/201212/27/201212/28/201212/29/2012and so on
1234Employee Name - - - - (11.07)
1235Employee Name - - - 0.20 -
1236Employee Name - - - - -
1237Employee Name - - - - (1.00)

[Code] .........

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Feb 12, 2009

My objective is to take two different random counts of numbers written in column b, ranging from B9:B66. However I want to highlight the specific fields listed in the example below, and pull random numbers from those selected fields only. Then I want to pull another set of random numbers in the same column B9:B66, however using a different specific set of fields within column B; as shown in the second random formula string. Use the Press 9 feature to randomly select the two different numbers. What this attempt is trying accommplish is selecting one boy, one girl who have assigned numbers adjacent to their names(name field populated in column c).
What am I doing in correctly?

HTML Formula written to B70
=INDEX(B9:B66,RANDBETWEEN(1,COUNTA(B9,B13,B15,B16,B17,B20,B21,B23,B25,B31,B33,B34,B35,B37,B38,B39,B41,B42,B44,B45,B47,B50,B51,B52)),1)

Formula written to B72
=INDEX(B9:B66,RANDBETWEEN(1,COUNTA(B10,B11,B12,B14,B18,B19,B22,B24,B26,B27,B28,B29,B30,B32,B36,B40,B43,B46,B48,B49,B53,B54,B55,B56)),1)

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Ref
Selection
Stock
Order
Matched
Type

[code].....

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Jan 4, 2013

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The periods are :
25/12/11 - 31/03/12
01/04/12 - 30/06/12
01/07/12 - 29/09/12
30/09/12 - 29/12/12

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Example

11:45
12:00
12:30X
12:45
13:00
13:15
13:30
14:00X

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Here's data table:

CriteriaHeader 1Header 2Header 3Header 4
ZZZ5.0015.0050.00130.00
ZZ5.0015.0050.00130.00
Z5.0015.0050.00130.00
YYY5.0015.0050.00130.00
YY5.0015.0050.00130.00
Y5.0015.0050.00130.00
DDD5.0015.0050.00130.00
DD5.0015.0025.0075.00
D5.0015.0020.0065.00
RRR5.0015.0015.0045.00
RR2.5010.0010.0030.00
R1.503.0010.0025.00
UUU0.751.505.0020.00
UU0.751.505.0020.00
U0.751.505.0020.00
P0.751.505.0020.00
T0.100.105.0018.00

CriteriaNumberValue
DDD10.00Header 1>>>=INDEX($I$9:$L$9,MATCH(I29,INDEX($I$10:$L$26,MATCH(H29,$H$10:$H$26),)))

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A1 =

Multiple «
App1
App2
App3
App4
App5

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13Diana
19Diana
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[Code] .....

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