How To Clear Label In Column Header
Mar 30, 2013
I created a Excel table with column headers in C15:H35 and the headers I want ONLY are in C15 (Item), F15 (Qty), G15 (Per Unit), and H15 (Total). In column D15 and E15 have Column 1 and Column 2 in them, I do not want them to be there how do I remove them without deleting the column?
ItemColumn1Column2QtyPer UnitTotal
View 8 Replies
ADVERTISEMENT
Jul 30, 2014
i have a vba that clears content from specific cells, hence somehow it also deletes the header as well
This is my code:
Dim LastRow As Long
Sheets("All").Select
LastRow = Range("J" & Rows.Count).End(xlUp).Row
Range("A2:J" & LastRow).ClearContents
Sheets("All").Select
LastRow = Range("AO" & Rows.Count).End(xlUp).Row
Range("AI2:AO" & LastRow).ClearContents
View 9 Replies
View Related
Nov 18, 2011
I've been trying find an appropriate formula to extract the column header from a table in a different sheet if the row header and value in that table is known.
in the lookup table the row titles (column A) are product codes, column titles (row 2, D through AX) are business names and the table values are quantity.
In a different table I have product codes in column A and in column B i have the max number/quantity of products for that code. In column C i want to put the company name associated with the product and the number/quantity.
View 4 Replies
View Related
Apr 25, 2014
For column "B" count all the 1's if column header is equal to name in column A.
For Column "C" needs to be checked if a value was filled in column "I" if yes then check if in column "L" has a value, count all these values.
View 5 Replies
View Related
Jun 13, 2013
I have two userforms with a label which displays CompetitorID. I want to transfer content (displayvalue) from UF1.label to UF2.Label. I know labels don't have a value property but want to simply know if it can be done as presently I'm getting run time error 380, can't set property value.
VB : HeadEntryForm.lbCompID = Me.lbCompID ' trf selected competitor ID to ID field on HeadEntryForm
View 3 Replies
View Related
Jan 14, 2009
I have a spreadsheet with a customers information and various parts we make for them. I need to be able to take this information and incorporate it into a label format. I need something quick and easy as there can be 150 parts per customer
Customer: ABCD
Customer PO: 12345
Part Number Quantity
AB 1
** 15
EF 22
GH 14
and I need it to output:
CUST: ABCD PART: AB
PO: 12345 QTY: 1
CUST: ABCD PART: **
PO: 12345 QTY: 15
CUST: ABCD PART: EF
PO: 12345 QTY: 22
CUST: ABCD PART: GH
PO: 12345 QTY: 14
View 4 Replies
View Related
Jul 25, 2014
I am trying to write a formula where the column header of the row in which a value other than 0 exists, will display for each instance (row) where a value exists in an array spanning 3 columns. So the result cell could be any of the three column headers, or a combination thereof.
I started the formula in P2 of the GL Detail-2012 tab. File attached.
Here is what I started: =INDEX($M$1:$O$1,SUMPRODUCT(COUNTIF($M$2:$O$67756,))). Not working.
View 7 Replies
View Related
Jul 22, 2014
I would like to display the column header of the row in which a value other than 0 exists in a cell for each instance that value exists in an array spanning 3 columns. So the result cell could be any of the three column headers.
I started the formula in P2 of the GL Detail-2012 tab. (FILE TOO BIG)
Excerpt:
Resin Sand Eliminated Segment
- (12,896.65)-
- (6,570.85) -
- (11,503.80) -
- (13,188.50) -
If there is any value other than 0 in Resin, Sand or Eliminated columns, return that column's header under Segment.
Here is what I started: =INDEX($M$1:$O$1,SUMPRODUCT(COUNTIF($M$2:$O$67756,)))
View 2 Replies
View Related
Feb 7, 2014
I have the following sample data set and I'm trying to return the appropriate column header based on criteria (i.e. DDD) and a number value which will be somewhere within the range of the table. In example below, the value returned should be Header 2 because the value is greater than those in Header 1 column (range H9 to L26).
Here's data table:
CriteriaHeader 1Header 2Header 3Header 4
ZZZ5.0015.0050.00130.00
ZZ5.0015.0050.00130.00
Z5.0015.0050.00130.00
YYY5.0015.0050.00130.00
YY5.0015.0050.00130.00
Y5.0015.0050.00130.00
DDD5.0015.0050.00130.00
DD5.0015.0025.0075.00
D5.0015.0020.0065.00
RRR5.0015.0015.0045.00
RR2.5010.0010.0030.00
R1.503.0010.0025.00
UUU0.751.505.0020.00
UU0.751.505.0020.00
U0.751.505.0020.00
P0.751.505.0020.00
T0.100.105.0018.00
CriteriaNumberValue
DDD10.00Header 1>>>=INDEX($I$9:$L$9,MATCH(I29,INDEX($I$10:$L$26,MATCH(H29,$H$10:$H$26),)))
View 3 Replies
View Related
Mar 3, 2014
[Code] ......
This works, UNLESS "My Column Header" is the last column, or second to last column, then it jumps left two columns, instead of landing on the correct column.
The purpose of this script is to select a cell directly in that column that I was searching for.
View 2 Replies
View Related
Sep 18, 2012
I need a formula to return column header if there is data in the column, any data.But I also need to return the second, third, fourth header with data too
In column A row 2, I have =IF(M8"",$M$1,IF(N8"",$N$1,IF(O8"",$O$1,IF(P8"",$P$1,IF(Q8"",$Q$1,IF(R8"",$R$1,IF(S8"",$S$1,IF(T8"",$T$1,""))))))))
This returns the row 1 header for the first instance of data in row 2 columns M thru T But in B2, I need the second header with data in the column.
I need the results in yellow (1st, 2nd, 3rd, 4th) from the array to it's left
1St match2nd 3rd 4thColumn MColumn NColumn OColumn PColumn QColumn R
Column MColumn PColumn QData data2Data3
Column NColumn OColumn PColumn R Data Data2 data3 data4
Would use match/index but can't increment it to the second or 3rd match
View 2 Replies
View Related
Aug 17, 2012
I have a userform in Excel and I would like to have a label calculate from the sum of 3 different labels. I have tried a few ways of which none worked.
This is what I currently have. This returns $0.00 in the label value but does not calculate...
Code:
Public Sub TotalCACost()
If TextBox12.Value > "" Then
Label685.Caption = ""
[Code]....
The reason that I have it as a public sub is that I am calling it to Private Sub extBox12_Change() as well as a couple of other textboxes so that when ever TextBox12 or the other textBoxes gets changed, the value will recalculate. The "other textBoxes" change the values of label443, 444, 445, 385, 386, 387 etc..
View 4 Replies
View Related
Jan 2, 2014
[URL] to locate the first negative value. Several options are offered, of which these would work for me ....
VB:
=LEFT(ADDRESS(ROW(),CELL("col",INDEX(Range,MATCH(True,Range<0,0))),2),
FIND("$",ADDRESS(ROW(),CELL("col",INDEX(Range,MATCH(True,Range<0,0))),2),1)-1)
to return the Column Letter
And
VB:
=CELL("col",INDEX(Range,MATCH(True,Range<0,0)))
to return the Column Number.
However, I need to take it to the next step, in my application, B2:Z2 are year dates, 2014 et seq B3:Z3 contain $values , one of which might be negative So if D3 is the first negative, the solution will return the label "2016". In the same thread, the Editor offers a refinement needed for my solution, but is beyond my skill level to implement: Any solution to avoid #N/A errors for the ranges where there are no negative values? I would just use
IF(ISERROR(formula),"-",formula)....
View 5 Replies
View Related
Jan 15, 2013
I have a data set consisting of three columns. Column A is a name, B is an x-axis value, and C is an y-axis value.
I use the B and C column to plot the positions in an X/Y point diagram. This is working nicely. But is there a way for me to get the value in the A column as the label for the data? Or in some other way shown with mouse over or similar?
Dataset could look like:
A
B
C
Jensen1
14
150
[Code] .......
View 6 Replies
View Related
Jan 16, 2007
Is ther a function that will return the column letter rather thatn the column number?
View 9 Replies
View Related
Jan 15, 2014
After pivot refresh, several individual cells of column labels are rotating again from vertical to horizontal.
How can I fix this format?
15-01-2014 8-47-31.png
View 6 Replies
View Related
Jun 16, 2014
I am new in Excel. Recently I have to copy a cell data from Pivot table (example value in B1 cell) to new sheet by this week. My problem is this value could move to C1 by next week & so on. I try to use the column label instead of hard coding like cell column name (B1).
View 1 Replies
View Related
Feb 9, 2009
I'm looking for a formula that will return the column header (a date) of the first instance of a number greater than 0. For example if columns A through S had dates as in row 1 (header row), and in row 2, every column contained a 0 up until column P, I would want the date (Row 1, Column P) returned? I think this might be a sort of index/match formula, but I am not very familiar with these.
View 3 Replies
View Related
Apr 29, 2009
I have a spreadsheet with several columns (all column names are in row 1).
I have 2 of column names. Note that their actual column# might change so the macro would have to look for the column name and NOT the column position ...
View 11 Replies
View Related
Apr 10, 2014
I need to clear the contents of a columns G and H starting 11th row based on what is there in F column. The macro should check for last non-empty cell in column F starting F11 (assume it finds F30 to be last non-empty cell), then it should clear the contents of G11 to G30, H11 to H30.
View 1 Replies
View Related
Aug 24, 2014
I have ~ 300 pivots (one on each tab) all linking to one data set in the same workbook. I realized that I neglected to select the year 2006 in my column label for every pivot table and hoping that there is some way to
simultaneously update all pivots to include 2006 data instead of manually checking the box off one by one.
View 2 Replies
View Related
Jan 12, 2006
I would like a flexible Formula to Return the Column Number of individual
Numeric Labels and their Numeric Value. I have a 2-Row by many Columns
chart/ grid layout. My 1st Column, Column Number "1" is Excel Column Letter
"F".
Numeric Label 17 is housed in Column Number "12" per my chart , its Numeric
Value 5 is housed on the next Row - directly below the Numeric Label.
Sample Data: ...
Scenario:
To Return the correct Column Number: locate the Numeric Label 17 and its
Numeric Value on the Row below, Numeric Value is 5. The Numeric Value is to
be increased by a Value of 1 (one) - NEW Numeric Value = 6. The Column
Number Returned should reflect Numeric Label of 17 remains the same but the
Numeric Value is increased by one.
To Return a Column Number representing the Numeric Label 17 and its original
Numeric Value +1 (plus one): the Numeric Label is still 17 but the Numeric
Value is NOW 6. From the oringal Column Number that housed Numeric Label 17,
that is Column Number "12", SEARCH in Ascending order: moving LEFT from
Column Number "12" and using the Numeric Value as the 1st (first) search
order and the Numeric Label as the 2nd (second) Ascending search order.
SEARCH the Numeric Value Row until the first Numeric Value either equal to 6
or more than 6 is found. Then Return the Column Number of the Column to the
Right of that Numeric Value.
Required Result:
Return the Column Number based on the Numeric Label 17 and the NEW Numeric
Value of 6, search in Ascending order - First search order based on Numeric
Value 6 - Second search order based on Numeric Label 17.
Returned Result should be Column Number 10.
View 14 Replies
View Related
Jun 13, 2013
I have the below data. I'm trying to create a lookup that would return the Month and Year in another cell. For example, I have in another cell the min of all the data, I want to get the month/year in the cell below it with lookups. I've tried INDEX/MATCH, but not getting the results I want.
Excel 2007ABCDEFGHIJKLMN3JanFebMarAprMayJunJulAugSepOctNovDecYTD420134.47 (0.35)0.86 4.98 520121.27 (2.29)(0.27)1.55 4.61 (2.33)2.07 1.38 0.62 (0.60)2.50 0.12 8.63 620111.41 3.69 3.97 2.49 2.06 3.14 (2.97)5.83 (1.26)(1.30)0.34 (0.36)17.04 720103.34 2.24 1.59 (0.33)7.70 0.63 (0.26)2.00 2.78 2.81 3.01 7.96 33.47 820098.51 3.12 (1.95)(7.30)7.91 8.94 2.90 0.41 0.66 0.67 1.39 3.10 28.36 920084.09 1.60 6.83 8.65 4.42 6.79 11.01 8.16 1.03 18.41 17.74 7.01 95.74 1020072.08 (0.62)6.02 (0.30)4.74 (2.28)4.04 (1.12)1.29 0.89 11.58 1.79 28.11 1120064.87 (1.83)4.56 5.04 2.19 0.53 3.55 6.00 (0.68)2.76 2.82 4.74 34.55 1220052.43 3.17 1.71 4.44 5.78 5.84 (2.61)5.21 0.04 6.34 1.87 5.76 39.98 132004(0.22)4.98 2.86 (0.52)4.80 3.22 3.45 1.97 2.77 2.61 25.92 Portfolio Summary
View 9 Replies
View Related
Jan 31, 2013
I would like to add the column header to each of the row item and price, we maintain masters in the matrix format, butthe application supports only the row item mapping with the customer and pricing. Attached excel file
View 2 Replies
View Related
May 13, 2014
I created a userform where if a value from cell x is true then the label caption changes to value in cell z. While everything works fine, the label caption does not seem to appear in my userform until i click on the label. Is there anyway that it can appear automatically once the userform opens?
Also example of my code is:
Private Sub EventDateResult_Click ()
If Range("A5") = "1" Then
Me.EventDateResult.Caption = Range("N4")
End If
End Sub
View 3 Replies
View Related
Feb 9, 2010
I need a formula to lookup and retrieve data from a table of values. Given an EMP-ID in column A of the row that contains the formula and given a column name in row 1 of the column that contains the formula, I need to do a lookup. So, in effect, I am doing a lookup based on two values .. the column header and the row header.
I have attached a small model to illustrate what I need. Cell C-3 in the first worksheet will contain the formula to lookup and retrieve the value in cell C-7 in the second worksheet, based on the values in cell C-1 (column header = “Database Col 2”) and in cell A-3 (row header = “257”) in the first worksheet.
View 2 Replies
View Related
Sep 14, 2007
Is there a way to reference a column depending on its header? Is there a way of doing this without the need of surveying one-by-one all the column headers with a for loop? I need this cuz if I have a very dinamic program which moves columns arround and depending on the state of the program the position of a column can change.
View 2 Replies
View Related
Jan 15, 2008
Have a set of dates as column headers across a worksheet. Rows are product names. When a product is delivered, the cell is marked "delivered" for the date (in the column header) it was delivered. Need a formula that will look across each row (product), and return the date of the first cell with the value "delivered". I have: =INDEX(F19:AS19,1,MATCH("delivered",F19:AS19,0)) <for row 19. right now, but its just giving me "delivered" as the value and I cant figure out why.
View 2 Replies
View Related
Jan 24, 2013
I have software (SAS Add-In for Microsoft Office) that loads external data into Excel. The data has a title, header, and rows/columns. It automatically creates a named range such as Table1. The named range does NOT include the headers.
Here is an example:
Code:
SASApp:SASHELP.CLASS
Name
Sex
[Code]....
As above, can I dynamically derive the column number based on the header row of the named range, where such named range refers to a table?
On a related topic, can I derive the column name given the column number? For example, in pseudocode:
Code:
For currCol = firstCol To (firstCol + lastCol - 1)
' Assume a function called ColumnName
Debug.Print ColumnName(currCol)
Next
View 1 Replies
View Related
Jun 23, 2008
Is there a way to link a header or a portion of a header to a specific cell?
View 14 Replies
View Related