Column Header Of Specific Value In 2nd Row

Jan 15, 2008

Have a set of dates as column headers across a worksheet. Rows are product names. When a product is delivered, the cell is marked "delivered" for the date (in the column header) it was delivered. Need a formula that will look across each row (product), and return the date of the first cell with the value "delivered". I have: =INDEX(F19:AS19,1,MATCH("delivered",F19:AS19,0)) <for row 19. right now, but its just giving me "delivered" as the value and I cant figure out why.

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Multiple commodities and multiple engineers should be separated by definite structure.

find worksheet with input and output (manual) as expected.

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in the lookup table the row titles (column A) are product codes, column titles (row 2, D through AX) are business names and the table values are quantity.

In a different table I have product codes in column A and in column B i have the max number/quantity of products for that code. In column C i want to put the company name associated with the product and the number/quantity.

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The column header row for a string; if the header contains one of two possible strings then copy the entire column. I've tried the following code but it's not working.


Select Case oColHeader
Case InStr(oColHeader, "how much", 1) > 0
Selection.EntireColumn.Copy
Case InStr(oColHeader, "level of sat", 1) > 0
Selection.EntireColumn.Copy
End Select

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I am trying to write a formula where the column header of the row in which a value other than 0 exists, will display for each instance (row) where a value exists in an array spanning 3 columns. So the result cell could be any of the three column headers, or a combination thereof.

I started the formula in P2 of the GL Detail-2012 tab. File attached.

Here is what I started: =INDEX($M$1:$O$1,SUMPRODUCT(COUNTIF($M$2:$O$67756,))). Not working.

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Jul 22, 2014

I would like to display the column header of the row in which a value other than 0 exists in a cell for each instance that value exists in an array spanning 3 columns. So the result cell could be any of the three column headers.

I started the formula in P2 of the GL Detail-2012 tab. (FILE TOO BIG)

Excerpt:

Resin Sand Eliminated Segment
- (12,896.65)-
- (6,570.85) -
- (11,503.80) -
- (13,188.50) -

If there is any value other than 0 in Resin, Sand or Eliminated columns, return that column's header under Segment.

Here is what I started: =INDEX($M$1:$O$1,SUMPRODUCT(COUNTIF($M$2:$O$67756,)))

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Feb 7, 2014

I have the following sample data set and I'm trying to return the appropriate column header based on criteria (i.e. DDD) and a number value which will be somewhere within the range of the table. In example below, the value returned should be Header 2 because the value is greater than those in Header 1 column (range H9 to L26).

Here's data table:

CriteriaHeader 1Header 2Header 3Header 4
ZZZ5.0015.0050.00130.00
ZZ5.0015.0050.00130.00
Z5.0015.0050.00130.00
YYY5.0015.0050.00130.00
YY5.0015.0050.00130.00
Y5.0015.0050.00130.00
DDD5.0015.0050.00130.00
DD5.0015.0025.0075.00
D5.0015.0020.0065.00
RRR5.0015.0015.0045.00
RR2.5010.0010.0030.00
R1.503.0010.0025.00
UUU0.751.505.0020.00
UU0.751.505.0020.00
U0.751.505.0020.00
P0.751.505.0020.00
T0.100.105.0018.00

CriteriaNumberValue
DDD10.00Header 1>>>=INDEX($I$9:$L$9,MATCH(I29,INDEX($I$10:$L$26,MATCH(H29,$H$10:$H$26),)))

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Mar 3, 2014

[Code] ......

This works, UNLESS "My Column Header" is the last column, or second to last column, then it jumps left two columns, instead of landing on the correct column.

The purpose of this script is to select a cell directly in that column that I was searching for.

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I'm trying to find a way to use a macro to extract data from a specific column from Sheet1 based on the columns header/title and copied into Sheet2 into the respective column with matching header/title.

For instance, in Sheet1:

Chicken
Cow
Donkey
Pig

[Code]....

So the above table would be the result i'm aiming for.

NOTE, its not different workbooks. I'm looking for sheet to sheet macro.

I've attached a file as well if someone wants to have a go at it. There are no codes in it.

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Sep 18, 2012

I need a formula to return column header if there is data in the column, any data.But I also need to return the second, third, fourth header with data too

In column A row 2, I have =IF(M8"",$M$1,IF(N8"",$N$1,IF(O8"",$O$1,IF(P8"",$P$1,IF(Q8"",$Q$1,IF(R8"",$R$1,IF(S8"",$S$1,IF(T8"",$T$1,""))))))))

This returns the row 1 header for the first instance of data in row 2 columns M thru T But in B2, I need the second header with data in the column.

I need the results in yellow (1st, 2nd, 3rd, 4th) from the array to it's left

1St match2nd 3rd 4thColumn MColumn NColumn OColumn PColumn QColumn R
Column MColumn PColumn QData data2Data3
Column NColumn OColumn PColumn R Data Data2 data3 data4

Would use match/index but can't increment it to the second or 3rd match

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Feb 9, 2009

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I have attached a small model to illustrate what I need. Cell C-3 in the first worksheet will contain the formula to lookup and retrieve the value in cell C-7 in the second worksheet, based on the values in cell C-1 (column header = “Database Col 2”) and in cell A-3 (row header = “257”) in the first worksheet.

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Jan 24, 2013

I have software (SAS Add-In for Microsoft Office) that loads external data into Excel. The data has a title, header, and rows/columns. It automatically creates a named range such as Table1. The named range does NOT include the headers.

Here is an example:

Code:
SASApp:SASHELP.CLASS
Name
Sex

[Code]....

As above, can I dynamically derive the column number based on the header row of the named range, where such named range refers to a table?

On a related topic, can I derive the column name given the column number? For example, in pseudocode:

Code:
For currCol = firstCol To (firstCol + lastCol - 1)
' Assume a function called ColumnName
Debug.Print ColumnName(currCol)
Next

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Deal Jan Feb Mar....... Dec
A 0 11 0
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and so on

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Jan 29, 2013

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SKuIDItemNameCustomerRate

11682Item 1Cust 1312.56
11682Item 1Cust 2411.27
11682Item 1Cust 3411.27

[code]....

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ItemColumn1Column2QtyPer UnitTotal

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BOY
GIRL
John Doe
TRUE
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Jul 16, 2013

Cells A3:A500 contain product numbers, e.g. 1001, 1002, 1003 etc.. etc...
Cells G2:N2 are column headers, e.g. North2011, South2011, North2012, South2012 etc... etc...
Cell F2 is a lookup that will return a year, e.g. 2011, 2012, 2013 etc... etc...

Against each product is a "yes" if it was sold in the north or south region for each year. This could be both north and south, one or the other or none at all.

What I would like is a formula in cells E3:E500 that looks at the year in cell F2 and if there is a "yes" in either the North or South for that year to return "yes" otherwise blank.

I am unable to upload a sample document due to firewalls.

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