If I have a range of data say all numeric and range form cells A1:A20. How would I find the minimum value except A4 where A4>0?
I know I can use the 'MIN' function and highlight all the data bar A4 (min(A1:A3,A5:A20) but i was hoping for an actual way so I could later fix the column such that first A1 is the first to be omitted A2 is the second and so on.
I am trying, without success, to create a formula that will refer to a column of data and do the following in one step:
1. Find the minimum value in the range, and then
2. From that minimum value, count back “up” the column the number of occurrences, including the minimum value, until a zero is reached. The zero should not be counted.
For example, if the values in A1:A6 are 1, 0, 2, -1, -2, 1, the minimum value is -2 and the count would return 3. (i.e. 2, -1 and -2)
I'm looking for a formula to find the minimum value in a non successive range of numbers (excluding zero values).
My sheet contains four fields of numbers (#1, #2, #3 and #4) and than start over again with number #1, #2, #3 and #4 etc. This goes on for approx. 25 4-column blocks. A simple MIN-formula or SMALL-formula doesn't seem to do the trick as it takes all values into account, not just the #1 or #2 or #3 or #4 values.
Example (cells A1..A24):
999-999-999-999-110-120-130-140-111-121-131-141-112-122-132-142-0-0-0-0-113-123-133-143
The minimum value of #1 (excluding the zero's) would be 110, the minimum value of #2 would be 120, #3 would be 130 and #4 would be 140.
Attached is a print screen. I'm struggling with using the min function in vba. I want it to find the minimum cumulative cost in week 0 out of the first three, and the copy the permutations of it (1,0 or 1, 1 , e.t.c.) to Week one column C & D of the model.
View 3 Replies View RelatedI have a range of cells (say A1:D8).
I wanna find the address (say $B$2) of the minimum value in that range.
This command does it but it only works on a column. it does not accept a range spanning more than one column.
=CELL("address",INDEX(B2:B7,MATCH(MIN(B2:B7),B2:B7,0)))
this will tell me the address of the minimum value.. but in a column... I need a range of many columns.
So I tried converting things to a Table.. but it never worked. basically the MATCH command is my problem. It only accepts single-column-ed ranges.
I want in A1 to find minimum SUM if no minimum number in row.
Here is example attached: ...
Trying to do the following. Look at a range of cells in a row, say A1- H1. Sum the last three cells that have a number in them versus being blank. So, let's say the last numbers in row 1 are in cells B1, F1 and H1, but in row 2 they may be in cells E2, F2 and G2.
View 3 Replies View RelatedI have a spread sheet that needs to compare numbers in a row & hightlight the lowest number in each row.
View 9 Replies View RelatedI have a set of worksheets all of which are identical and covered by first:last sheets
What I am trying to do is come to up with a minimum figure for cell G30
With the proviso that it is a minimum of 30 as some of the entries in G30 are less than that figure.
=MIN(first:last!G30) is not the answer as it gives an answer of zero.
I am having trouble with large data sets of rents by market: trying to find the peak rent in a time-series, and then look for the next trough rent in time. I tried using the Newsletter 3 techniques which feels like the right direction, but I am not getting the nesting right or some of the parameters in the functions.
So, within each time-series I need to find the MAX value (peak rent), wherever that is in the array. Then I need to look to the right of that exact MAX value and find the exact MIN value (trough rent), whereever that is in the array (again, to the right of the MAX value).
A small sample of what the data set looks like:
2008 Q22008 Q32008 Q42009 Q12009 Q22009 Q3
Atlanta771773768761749756
Austin770786784779776776
Baltimore947948949950950953
Boston1,6471,6601,6541,6481,6301,613
Chicago998998996985984986
I have been trying to solve this problem for the past couple of weeks and I have not been able to do so. I have come to do the operation manually, and it really takes a lot of my time, so if you guys could help me, I would really appreciate it.
Basically the problem is this:
In column "A" I have what I call point numbers for all the data entries.
In column "B" I have the station (or location) at which I vary slightly a parameter (represented by column "E") to give me a value shown in column "D" (the "Z" value, as shown in the sheet).
So basically you can see that my station 0 has 11 different "E" parameters (0, -1, -2.62, -5, etc) and each of them has a "Z" parameter (390.76, 390.775, etc).
What I am trying to do is to come up with a table that shows a summary of the following:
A column with each of the stations (0, 20, 40, etc -- notice that I have some weird numbered stations like 411.89).
Another column with the "E" parameter corresponding to the lowest (or minimum) "Z" parameter within the station range.
And a final column with the minimum "Z" parameter corresponding to its "E" parameter, which is included in the station range
You can see in yellow the way I have been doing this and you can see that it would take me so much time to accomplish the task.
I have following problem I have some table - 2 columns - in first is text in second is value.
example:
A 10
B 5
C 3
A 15
C 8
D 7
A 9
I need to use formula, which shows me minimal value for choosen text. I tried matrix formula like {=min(if(text table=choosen text; second column;0}, but it's not working
I want to find out the minimum $ amount in a row with multiple columns but some columns will also have numbers that cannot be converted to string.
What formula could I use to only find the lowest $ amount?
Look in Column A and find the cell that contains "Std A 1" and the cell that contains "Std A 2".
Compare the corresponding values in Column B, and multiply the lowest value by .2
I've tried using various methods (find, if cell.value.instr) but I keep getting errors. Can anyone point me in the right direction?
I need a formula that will return the minimum value from a column range that flexs without having to manually go in an change row references. There is a blank row between each section of data in order to separate info. As an example:....
Need to formula to flex to include rows 5 thru 7 in the first section but expand to include rows 9 thru 13 in the second section. =MIN(A5.A7) works but how do I get next section to flex to =MIN(A9.A13) without manually changing the cell references? There is always a blank row in between the sections to separate.
I have inherited some legacy templates (Standard, Leave and Exception) which cannot be changed. I need to summarise them (Total) selecting the earliest start and the latest finish. (Sample attached). The templates are 90 columns wide and about fifty lines deep so named ranges isn't practicle (I think). I'm running 2003.
View 4 Replies View RelatedHow do I find the minimum and maximum numbers in a table if I do not know the size of the table but can assume the user will choose the first cell (upper left cell) of the table and run the macro?
View 5 Replies View RelatedSo i need a way to find the minimum number in a given set of numbers without there being multiple minimums. For example if you had 1,2,3,4,5,6,7 the minimum would be 1. If however you had 1, 1, 2, 3, 4, 5....i want excel to recognize there are multiple minimums (two 1's) and produce a warning (i realize this probably needs to be coupled with an if statement).
View 3 Replies View RelatedI have a range of values, (1,10,20,0,2,5)
I need to find the minimum values, but I want to avoid 0(zero)
I have a table that contains various aspects of information about customer cases, and I want to replicate a user 'picking up' the case by a simple press of a button.
Users have access to only one Country, so I want to be able to search a particular column for the lowest value, but check that the Country for that row matches the user's access. If it doesn't, I then want to find the next lowest value in the column, and this is what's perplexing me??? As mentioned, I want to click a button to trigger this, and therefore want to use VBA code.
Is it possible to find the minimum distance between two points using two separate lists of different lengths without creating separate columns of equal row sizes
? I am trying to find the shortest distance form one point to another which is a fixed value. I am using the standard distance formula: =SQRT(((X2-X1)^2)+((Y2-Y1)^2)+((Z2-Z1)^2)).
My X1,Y1, Z1, has 2,000 rows in three columns that need to be compared to find the minimum distance from my one row/column of X2,Y2,Z2.
Is there a command that could go through and use each row of the X1, Y1, Z1, while looking for the MIN of the above formula without having to create an equal amount of rows for the X2, Y2, Z2?
I know I could do it by running this out the long way and then finding the min after I do all the math but I am wondering if there is an automated way for Excel to go through and do the forumla and then only return the MIN value?
Daily At the end of day We receive sales files from our different teams, these files are received at different times due to difference in working shifts. I have collated last one month data and from this data I want to know the earliest and maximum time and date on which we received the files in last month, so that i can fix the receiving time for all regions.
View 5 Replies View RelatedReferring to the post Find Min Value In Multiple Columns And Match The Header. I would like to go little bit further and see is there a way to find and match not just in multiple columns but in multiple tables (see the example)
View 4 Replies View RelatedI'm trying to use solver to find the minimum value of a cell by changing 5 separate cells. These cells are subject to a set of constraints that are formulae. On top of that I have a large number of these solve's to run (The spreadsheet is creating randomly distributed data to form a Monte Carlo simulation). Therefore I am referencing the formulas using the ActiveCell, Offset() function. For some reason when running this code none of the values are changed. Also I changed the UserFinish to false so I could see what solver was doing at each solve, It stops at the correct cell (one after the final cell) but without me having to confirm it each time.
Here is the ....
I am looking to create a formula to determine the minimum value within the top 80% of a range, but relative to certain values in other columns.
e.g.
Column A Country
Column B New Customer
Column C Revenue
I need to determine what the minimum value is for the top 80% of revenue in column C, but only including Country=UK in column A and New Customer=Yes in column B. This will tell me that the top 80% generate at least £x in revenue
I searched and found a couple things dealing with zeroes or other errors, but not the #N/A errors.
I have a range of numbers in A1:a100. To make this range linegraph-friendly, I have all blank or zero entries defaulted to appear as #N/A. Now the problem is that I would like to find the minimum number in the range, but the #N/A entries are messing things up.
I want to find the minimum time value within a range of cells, excluding 0:00. Currently,
VB:
=MIN(BL5:CP5)
returns 0:00 if it exists in any of the cells.
I need to highlight the minimum value amount in a range. For example I need to highlight the minimum value for the values in column A, C, and E. I want to do this for lot of rows. Is it possible to use the conditional format for all the rows at once or do I have to do it one by one.
View 1 Replies View RelatedI want to find the minimum time value within a range of cells, excluding 0:00. Currently, =MIN(BL5:CP5). returns 0:00 if it exists in any of the cells.
View 2 Replies View RelatedI have used max and min function to display minimum and maximum time value; however, it is not displaying the correct time value from the list. I think there is a better formula to achieve this. From the sample data displayed below, minimum time value should be 11:30PM and maximum time value should be 6:30AM
See sample data below:
4/1/2013 11:45 PM
4/1/2013 11:30 PM
4/2/2013 6:30 AM
4/2/2013 6:15 AM
4/2/2013 6:00 AM
4/2/2013 5:45 AM
[Code]....