I have searched this and other forums for a macro which will insert a "+" (international dialling prefix) character before a phone number in an Excel field with no success. I have tried the "record macro" function without success. Any ideas?
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I have a cell which will contain SER01+SER02+SER03
and what i need it to contain is [SER01]+[SER02]+[SER03]
and shocker is i've got this to work for the first instance but not the other two
code as below... be grateful for your help
Sub measure1()
Dim list As String, pos As Integer, refl As String, refr As String, newlist As String
list = Cells(1472, 16).Value
pos = InStr(list, "+")
refl = Left(list, pos - 1)
refr = Right(list, pos + 1)
newlist = "[" & refl & "]"
Cells(1472, 17) = newlist
End Sub
I am looking for a way to show the character location number of a text file, possibly in the first row or a macro that I can run at any given location that will give me the location # I am currently viewing.
Currently, when I open the file I can see the character # at the opening screen (see attached file) but they disappear when it actually converts. I would like to be able to keep the character location ruler once the file is opened in Excel so I don't have to manually count.
I need a macro to insert a new row with incremented serial number in column A, when done the first time - to insert the row at a specified cell starting with serieal no: 1 and later to insert the new row after the last row. Also I need the macro to insert certain pre-defined text values in specified cells in the new row..
View 11 Replies View RelatedMy first sheet shows the data - a list of audits and their current status.
AuditStageAlphaIn ProgressBetaReportingCharlieCompleteDeltaCompleteOmegaPlanning
I've then used a simple count formula to add up the number by each stage and it's these numbers that I want the macro to use when determining how many rows to input.
Complete2Reporting1In Progress1Planning1
A second worksheet hosts the desired output - a simple report template, split into stages for each status type (completed, planning etc.) with the correct number of rows for each.
Completed AuditsCharlieDeltaReportingBetaAudits in ProgressAlphaAudits in PlanningOmega
So, I want the macro to ensure that we have the right number of rows for each stage, as this month will be run on a monthly basis and the stage each audit is at will change, and the number of rows required in each section will also be different.
I received a request from a coworker regarding custom formatting some numbers in his spreadsheet. Those numbers are serial numbers of 20 characters long. Sometimes in my files I use this custom number formatting ###0 and its enough for the data I handle. But when I tried to use it in his spreadsheet, the following shows:
8456891070060510000
The cell must look like this: 08456891070060510302
The reason to have it like this is due to a Delivery Program requirement to deliver Set-top Units for repair. The Delivery Program do not recognize other format than the above. My coworker takes the data from a spreadsheet, and the spreadsheet needs a custom number format to display the correct number.
find a custom number format to be able to display as my coworker need it??
I have multiple columns with many rows of unique text in each. Here is an example of what the 1st few rows of column a and b might look like:
A___________B
hboc______dds
jk________optg
hbv_______pl
FIRST:
I would like to be able to sort the rows by the character length in a column. So, it would look like this (if sorted by 1st column):
A___________B
jk_________optg
hbv________pl
hboc_______dds
Second.........
I'm trying to determine if the last character of a cell is a number or not a number. So in a cell I may have a string like:
ZXC123
or
ZXC123A
If the last character is not a number I want the letter returned. So I thought I could use a formula like: =IF(NOT(ISNUMBER(RIGHT(D88,1))), RIGHT(D88,1),""). However for the string ZXC123 it still returns '3' so anyone have any ideas how I can do this?
I have a number of entries in column A.
The format is:
A1 B680192 Middle School
A2 Office Building Project
and so on;
I want to test if char.s 2 through 7 are numbers.
I can seperate one char at a time and use CODE function to check if the result is between 48 and 57.
I know how to split all six char.s at a time e.g. 680192, but I don't know how to test to see if it is a number?
ISNUMBER function doesn't work.
If I can do it with excel function, it would be better. If VBA has to be used, so be it.
I have a spreadsheet which I automatically generate using VBA. One of the columns lists account numbers. After the macro is complete, the account numbers are non-numeric and left justified. However if I select one of the account numbers by clicking on its cell, and then edit the account number in the formula window, it changes the cells property to numeric and right-justifies the cell.
View 6 Replies View RelatedIn column N I would like a formula to add 3 columns,e.g. C and D and F. The problem is I want the symbol ~ replaced by 1.0 for calculation purposes.I need a solution in 1 column,if possible. I have made a few efforts,but just not getting there. See attached section of sheet.
View 2 Replies View Related Cell B23:687968307=ISTEXT(MID(RIGHT(B23,3),1,1))TRUE
Cell B24:C8796B07=ISTEXT(MID(RIGHT(B24,3),1,1))TRUE
I'm trying to test whether the third last character (3 and B) is a text or not.
As you can see, the reslts are both TRUE, but I'm expecting to see that the first one should be FALSE, as '3' is a number right?
Likewise, if I replace the formula with ISNUMBER instead of ISTEXT, the results are both FALSE, but shouldn't the first one be TRUE, again, because the '3' is a number?
Have I missed something in the formula, or is there a better way of expressing this formula?
I have a number and i wanted to convert it to a number or character.
Ex.
if i have value of 7, should be converted to a character of "*", the output will be 7 times of "*" (*******)
if value is 10, so it will be 10 times "*". (**********)
I need composing a formula that will add a space after every 4th Number in a 16 digit Character Set.
ex. 0101 0101 0101 0101
I have a cell range that is passed as a String to a function, and within that function I need to extract only the Column letter. If it was just 1 letter it would be simple, but it may be 2, so does anybody know of a way of testing to see if the second character is a letter or a number?
View 5 Replies View RelatedThey have a list of data numbers which are yy/#####/@@@@@ (2digit year/casenumber/alphanumeric code). Where some people have typed in the code wrong (6 or more digits in case number) we want to know is there a way of doing this.
Ideally I want something that says "If 9th character is a slash then yes, if not no" or "if 9th character is a number then yes, if not, no".
Example of data is (where we want third option highlighted as erroneous (6 not 5 numbers in middle)
09/56487/KFJT
09/42105/PLOUR3
09/002145/PLIFD
09/02145/ASDF
Is there a way of getting the first three character of every word or number in a cell ( seperated by spaces) ?
for example in cell E2 I have
BASE 150 WALL COLOUR GREEN
and would like it to read
BAS150WALCOLGRE
I have a approx a 1000 rows that I would like to do this with.
I need to limit the number of Characters that can be inputted to the popup InputBox to just 31. How do I set MaxLength? Code I am using is listed below.
Code:
Sub NewRecipeSheet()
Dim ws1 As Worksheet
Set ws1 = ThisWorkbook.Worksheets("1. Recipe Master Sheet")
ws1.Copy ThisWorkbook.Sheets(Sheets.Count)
Application.Goto Reference:=Sheets("1. Recipe Master Sheet").Range("A1")
Range("A1").Value = InputBox("Menu Item Name?")
End Sub
I have part numbers in a column that look like the numbers listed below. All numbers begin with A, so the default sort begins with the first number. I would like to sort the list using the middle three numbers denoted by the red x's in the first example. Is this possible?
A 385 XXX 0055 A 385 466 0060 A 385 466 0160 A 385 584 7024 A 387 284 0185 A 388 017 0160 A 389 260 1485 A 389 262 0293 A 389 262 4935 A 389 262 9134 A 389 267 2819 A 389 267 3319 A 393 328 0065 A 398 267 3319 A 403 990 0210 A 403 997 0620 A 404 260 0074
I have an Excel file that quiries Google for driving distance (someone helped me with this.) It returns the correct miles but has some 'extra' characters. Example:
31.1&nb or 886&nbs
So the answer always has &nbs after the mileage. I tried the following function which works when there is a decimal but fails when there is not. =REPLACE(MID(E2,1,SEARCH("&",E2,1)-1),SEARCH(".",E2,1),1,","). Can this be done with a function or must it be VB script? Which is fine if it is.
Pretty sure this has been asked but have searched the forum to no avail, but I need to extract the numbers from a value which has a letter on the end.
eg. 1000x I need to get out the 1000
or 2p I need the 2
I have sooooo many values ranging in numbers of digits, so just basic left(A1,2) won't work, I'm sure I've seen a search or find function but don't know how to use them!
Need formula to count the number of times a particular character is found in a string I have been experimenting with the likes of
View 5 Replies View RelatedI need to make a list of Part Numbers in quotation marks. If a number of digits of a P/N is less than 13 a number of space characters has to be added to make the string 13 characters long.
We have example P/N:
1234567890123
12345678
123456
should become:
"1234567890123(no extra space characters should be filled-13chars)"
"12345678(5 extra space characters here)"
"123456(7 extra space characters)"
Is there a function that inputs a cerain number of a specific character ("space" in this example)?
I have a requirement where I have to count number of "-" character in particular row
I am using a excel database for promotion records of my team....The data base works as follows. I am using countif function to calculate number of associates in specific grade for specific month. One associate is getting promoted to next level, I will add one more row with the same employee name with change in designation and diff start and end date. I want to generate report for monthly promotions, The report should depict number of promotions in each month. ie in Jul there is one promotion from trainee to Engg for EMP1. There are hundreds of employees, eligible for promotion in each month.
A B C D E F G H I J K L
Emp Name Desig From Date To Date Apr-13 May-13 Jun-13 Jul-13 Aug-13 Spt 13 Oct-13 Nov-13
EMP 1 trainee 4-1-13 6-30-13 trainee trainee trainee - - - - -
EMP 1 Engg 7-1-13 11-30-13 - - - Engg Engg Engg Engg Engg
How can I extract mid section of the string which is always 5 characters long and is always followed by a period "." ?
My account strings are in 3 sections (but the third section isn't always used)
For example,
1.10210
1.22556.001
900101.56201
955261.54444.001
5566625.58886.957756
I need a formula which can pick out the names from string of text, each name follows "-->", the number of names in each cell differs and is undefined. The result needs to be posted into each column following these cells.
An example of a cell is below:
"W/L FIGHTER Str TD Sub Pass EVENT METHOD ROUND TIME
Loss -->--> Tom Aaron -- -- -- -- Strikeforce - Hen... U. DEC 3 5:00
-->--> Matt Ricehouse -- -- -- -- Dec. 4, 2010
Win -->--> Tom Aaron -- -- -- -- Strikeforce - Hea... SUB 1 0:56
-->--> Eric Steenberg -- -- -- -- May. 15, 2010 Guillotine Choke"
I have tried using text to columns but everything after the first line is not recognised (when I click finish anything after "TIME" is simply not there).
Example attached : UFCv1.xlsx
I want to find the total number of times the number 1 appears in cells B2 to B33.
In each cell I have codes such as 4919409382a, 5021193035v and so on.
I have tried =COUNTIF(B2:B33,"1") but just get 0 returned.
I've tried and tried and I con not get it right. In A1 I have a validation, it onlu allows to enter a 6-digit number between 100000-899999 or the same numbers with the letter I in front, that is I100000-I899999. Now I need a macro to check that cell F2 is not empty if the value in Cell A1 is above 299999. And this should also apply if there is an I in front. The function for the validation is:
=IF(AND(LEFT(A17)="I";--MID(A17;2;6)>100000;--MID(A17;2;6)<900000);OCH(A17>100000;A17<900000))
The code I have is:
If Range("A" & i).Value > "299999" Then
If Range("F" & i).Value = "" Then
MsgBox "Indicator missing on row " & i
Application.Goto .Range("F" & i)
Exit Sub
End If
End If
It works wor the nubers without the I but it demands a vlaue in F on all I numbers and I only want it for >I299999.
What formula or function truncates a text field that is in the following consistent format:
number. name
ie. 3. Super Bella
and 150. Taoist
I wish to truncate the field so I have just the integer without the dot, space or word(s).
Tried Len, Left & Replace but they require a specific number of characters. Since the number can be 1 to 3 digits long, this doesn't work.
I want to force my user to input a date in a userform. I have a normal Textbox and assumed i'd be able to set the properties to mean that imput had to be an integer and the format had to be "00/00/00" but I can't see how to do this.
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