I would like to take a string such as R0-H6-D2 and return a number (1-4) based on one of four values for R, H and D in a separate column for each. The attachment should make what I am trying to do clearer.
Substitute.png
I have a text field (description) and in the description i have a product code S followed by 7 digits and then in the process of pasting into excel i have lost the space after this code and before the next text. E.g. "Ballpoint pen S1234567With Free Delivery" should be "Ballpoint pen S1234567 With Free Delivery".
I dont know how to say =if("S" followed by 7 numbers,subsitute ..... etc)
I understand how to use IF and substitute. its the 7 numbers part i am stuck on.
I could do it in access with the wildcards but excel is different.
I have a text variable MtgDate containing "25/03/2014"
I need to produce another text variable (to build into a file name) MtgDate1 with the text "2014-03-25"
I was going to use the Substitute function to replace the "/" with a "-" then Mid to juggle the dd-mm-yyyy to yyyy-mm-dd but at the moment I can't even find the right syntax for the Substitute.
Got as far as:
[Code] .....
but this just sets MtgDate1 as "=Substitute(MtgDate, " / ", " - ") ie reduces the double quotes to single ones.
I'd like to use VBA to create a super substitute function. For my needs, nesting is insufficient because my substitution list is at 20 and growing. To make matters worse, the function needs to be used in several places.
What I'd like to do is have a named table with two columns for the function to use as a look-up for potential substitutions. The first column would contain the original text and the second would contain the replacement text. This way, whenever new items come up, all I have to do is add them to the list. The syntax of the function would be along the lines of SUPERSUB(TextString, table), where TextString contains the text that could be modified.
I've in cell A1 an entry like this: 123*456*7890
=SUBSTITUTE(A1) in cell 'A2' gives me: 1234567890
=ISTEXT(A2) in cell 'A3' gives me: TRUE
BUT, =A3+1 gives me: 1234567891
Hows that happening? Substitute function gives me the output which is a TEXT, and how is it that when I add 1 to it, I get an answer? Shouldn't I get a #VALUE! error instead?
In cell A1, I have three possible text strings: (1) "change/s: changed the color green to red", (2) "change/s: changed the color from green to red, changed the size from big to small", or (3) "changed the color from red to green".
I need a formula that will look at a text string, and if there is a comma in the string, it finds the word "change/s" and substitutes it with "changes", if it finds no comma, it substitutes the word "change/s" to "change", and if the word "change/s" is not in the text string at all, it leaves that text string unchanged.
Find a short text string in a column of longer text strings and when that short text string is found return the longer text string that matches.
View 3 Replies View RelatedI have a set of task descriptions that I am attempting to trend on. Some of these (Column B) have the customer's name added to the description; others do not. I need to be able to make a list of task names (ColumnA), removing the name from the text string.
The formula I am using is [=LEFT(B3,FIND("for",B3)-2)].
The problem I am having is when the description does not contain the "for" built into the formula, I get "VALUE" error. What adjustment can I make to the formula to pull over the Description if the "for" does not appear in the text string?
I need to create a macro to do the following:
Search the activecell for a text string (a), and then either paste in text string (b) at the end of the cell if (a) is found, or text string (c) if (a) is not found.
For example, if the activecell has "AA/" in it, I want the cell to become "AA/01" (pasting in "01" at the end), and if the cell has just "AA" in it, I want it to still become "AA/01" (pasting "/01" at the end). The macro will be linked to a commandbutton.
refer to the attached workbook for reference. I am looking for a function in Sheet1, Column E that will search for the value of Sheet1, Column A within Sheet2, Column A. When a match is found, the function should look across Sheet2, Columns B - V for values of 1. When such values are found, the function should return the associated value from Sheet2, Row 2. There may be multiple values of 1, and as such, the function should separate values with a comma.
View 3 Replies View RelatedHow do I use an Excel formula to find which (if any) multiple sets, each of up to 50 words, exist in a series of rows of a spreadsheet - if set A has one or more words found in a searched cell.
A positive result will return a specific value in the designated result cell. If none of the words in Set A is found in the searched cell, the formulae will repeat the test for the words in Set B, and so on.
After all 50 sets of words have been tested, the formula will move to the next cell in the searched column.
New words will be added to the sets of words continually as required.
Multiple words within sets are included in double quotes. Within each set of words there will be some n-tuples of words (i.e. 24 adjacent words) that contain one or more of the words in the set, but for which the formula will be required to return a negative result. Example: Set A = word 1, word2, word 3, "word1 word2 word3". (The words within a set could also be each entered in separate columns, as opposed to all included in a single cell.) The single column of text to be searched is about 10,000 rows.
I am wanting to use the above in a spreadsheet that contains data downloaded from a series of bank accounts to automatically allocate items of expenditure to one of 20 or so different categories of expenditure.
The formula will search the description field to find words that are used in the in the downloaded files from the various accounts to describe each transaction.
If a word describing travel expenditure (e.g. hotel, "holiday inn" but not "holiday travel") is found in the description of an expenditure item - the item cost will be allocated to the TRAVEL EXPENDITURE column, which is one of 20 or so different categories of expenditure.
Happy to consider a different solution if the task can be done better a different way.
Tried using a combination of INDEX/SEARCH/IF in Excel, but was not able to get a correct result. PS I am using Excel 2011 for Mac - which does not allow macros, so the solution needs to be entirely formula based.
I'm pulling phone numbers out of text strings. There is text string ("Office:") indicating that the number following is an office number (the number that I need). MID and FIND take care of this. There are sometimes two instances of office numbers in single text string, so adding a second column using the third argument of FIND lets me start another search past the first instance of an office number. We have a bunch of office numbers with the qualifier "(Text)" after the original "Office" but before the phone number. How do I catch these ones?
View 8 Replies View RelatedI have the cell data as below
How would I split into a new column the first part which is a date into a new column, then the country and the remainder into separate columns?
I still want the original data as I need to check that the splits worked well?
16.5.90 CH 1671/90-4
18.10.1991 CH 3056/91-1
24.07.92 ch 2341/92-2
30.7.92 ch 2395/92-3
18.11.92 Us 3533/92-5
26.5.93PCT 1577/93-0
9.8.93 CH 2363/93-8
17.8.93 CH 2445/93-0
25.1.94ch209/94-6;8.12.94ch3714/94-1
25.1.94 ch 209/94-6 ; 8.12.94 ch 3714/94-1
8.4.94 ch 1047/94-0
22.4.94 ch 1255/94-7
18.11.1992 CH 3533/92-5
18.11.1992CH 3533/92-5
I have a dataset of shifts and want to compare each shift that needs to be filled to a list of requests for time off (vacation, etc).
For one cell the code is: =IF(ISERROR(SEARCH(B1, A1), 0,1)
Where A1 is the column of requests in comma delimited forme (ie: "AB,CD,EF").
Where B1 is the column containing the person assigned to shift 1 (ie: "AB")
In this case, would return a "1" as no error was returned, as AB was found in the list. Here "1" would represent a schedule conflict.
Without creating many cells for each shift- there are 20 shifts- can I create an array or string together this type of "SEARCH" function?
An original text string entry appearing in an Excel cell would be:
"N7C Neuroprotective J5Z Antiviral, other M2Z Antiarthritic, other J5A Antiviral, anti-HIV"
I need to extract N7C, J5Z, M2Z and J5A from this string and list these alphanumeric values in separate cells adjacent to the original text string. The challenge is that these alphanumeric references may appear in different positions within the original string with no fixed value e.g. a "," separating them. The alphanumeric references may also be 3 or 4 characters in length and there may be different numbers of alphanumeric references in the original string.
Another example would be (very different from the first):
"T2Z Recombinant, other K5B Radio-chemoprotective J3Z Antibacterial, other D3A Vulnerary A10C Symptomatic antidiabetic K6Z Anticancer, other R8A Antiasthma B6A Septic shock treatment I1Z Immunostimulant, other S1Z Ophthalmological R8B Antiallergic, non-asthma M1A1 Anti-inflammatory"
You can see that in this further example "A10C" & "M1A1" are 4 character alphanumeric strings wheras the others feature 3 characters.
I have a column of data with letters in each cell, no numerical, only alpha. Now, some of those cells contain the letters "adj sub" as part of the text string in each cell. "Adj sub" is always at the beginning of the text string. As an example, a cell will look like this - "adj sub mhm". I want to delete rows whose cell description does not contain "adj sub" as part of the text in the cell.
View 5 Replies View RelatedI am working on modifying this code (below) that I found here: VB Macro to search webpage for text string
Code:
Option Explicit
Public stResultstr As String
Sub SearchForString()
Dim rngURL As Range
Dim cll As Range
Dim stCheck As String
Dim xmlHttp As Object
[Code]...
So right now I have the script prompt you for a URL range, then it asks you for what you want to search for, and I have it set to return the next 10 characters from that found point.
You can see here:
Code:
If InStr(1, stResult, stCheck, vbBinaryCompare) > intt Then
intt = InStr(1, stResult, stCheck, vbBinaryCompare) + Len(stCheck)
I began to create something to identify the last position of the found item because next I want to loop it to find the next occurance of the same thing and return the next 10 characters after it in the next cell to the right in that same row:
Code:
cll.Offset(, 1).Value = stResultstr
Again, what I want to do here is find and parse out every occurence of a string (inputbox) found on a web page url in column A. The parse occurrences will go to the right in cells C though ? for row N.
Date: 17/09/2013 KO: 19:45 Ref: B Malone Att: 7,574 extraction of text from the above text string which is say in A1. What l need is for Date to go in A2, KO in B2, Ref in C2, & Att in D2. I'm using Excel 2003
View 7 Replies View RelatedCell H1 has a variable string of references for eg
"FI570783AQ3516346EQ3516346FXVB123456"
I want to return the reference beginiing with "FXVA" so it would ignore the rest and only return FXVB123456 - this should always be 10 characters.
Just to add another complication to the mix, there may be 2 "FXVA" references in the string and i want to get both (these can be in the same string so FXVB123456FXEL123456 - but this might not happen regularly.
I have a sheet in which some of the cells have two strings separated by a linefeed. I have come up with a cumbersome formula which will let me check if either of the two strings is a member of a list stored on another sheet. However, it fails if there is only one string in the cell, presumably as there is no linefeed for the formula to find. How can I modify the formula to cope with this situation?
There are also on occasions, three strings in the cell, but I can't seem to access the middle string with the formula. Simplified spreadsheet attached to show the problem. This must be formula-based, as we have a no VBA policy. If you think there is better way of doing this, please let me know.
I have a report that in column BX has a large string of text (html information). Within this text there is a phrase called "| Hear = Education Website |" The phrase Education Website can be a variety of things though (Up to 9 choices). What is a formula I could use to just pull out the text after "Hear =" but before |""?
View 8 Replies View RelatedI have one column full of Item #s and Descriptions. I have another column that I want JUST the Item# in it.
For example:
Column 1:
Gyroscope REF#1234 Bike Thing
Column 2 Should Be:
1234
Column 1:
BallWall Bikes Ret# 12456 Helmet Thing
Column 2S hould Be:
12456
I don't know how to do this (I do know how to do VBA mildly, and I am pretty good with formulas). I also have a database of every Item# that could be in that cell.
I have a bunch of these following below which I need extract text from the first "." from the right hand side.
The amount of text and "." can vary as does the number of characters.
XXXXXXXX.XXXXXX.XXXX.XXX.XXXXX.XXXXXXXXXXXXX.XXXXXXXXXX.Vibrating Screen SC409
XXXXXXXX.XXXXXX.XXXXX.XXXXX.XXXXXXXX.XXXXXXXXXX.Scalping Circuit 4
XXXXXXXX.XXXXXX.XXXXXXX.XXX.XXXX.XXXXX.Fines Stacker ST601
Ultimately i want it to display the following:
Vibrating Screen SC409
Scalping Circuit 4
Fines Stacker ST601
I have used LEFT, RIGHT, SEARCH, LEN functions in various combinations but cant get it to reference the last "." from the right.
I am trying to remove a middle initial from a text string however not all of the cells have middle initials. In column B I would like to return the first and last name. If needed I can have the first name in column B and the last in column C then combine them.
Example
John A Smith John Smith
John Smith John Smith
I am trying to extract numbers after a specific text in a text string, for eg :abc SN 12345 xyzedf SN No. 456 mnoAs per above, i want to extract any numbers afters "SN". the numbers can be vary in digits i.e. it can be 3 digit numbers or 4 or 6. Also, at times there is some other text in between (like SN No.) numbers and search word (i.e. SN)Any formula to get result as "12345" and "456".
View 5 Replies View RelatedI have data coes that need to be converted, basically need to remove 1st and 12th digits, 12th digit only, or 11th digit. I have built spreadsheet with a mid sub formula to do all 3 separately, but cannot figure out how to combine the formula to do all three.
I am attaching the spreadsheet,
Following code doesn't work
Dim Value1 as String
Value1 = Substitute(Cells(4, "A"), "A", "", 1)
correct syntax to assign the result of substitute function in the Variable?
I have a formula who examines if they are the same. The last number at first quote is not a problem (the 45). The problem occurs only and allways when the horse's name have an apostrophe " ' ". In first example apostrophe is different from the usual. If i manually delay it and replace it - type keyboards apostrophe everything works fine. Obviusly its a symbol. I want a small macro for replacing all these symbols at, lets say column B ,where these names are located. How can i use substitute at this case?
I understand that Microsoft left Filesearch out of VBA for Office 2007 because it was buggy. Sadly, however, I still need it. It would help if they placed a comment in VBA help that stated that it was discontinued. As it is, they make it look as if Filesearch is still available for use. OK, I'll stop ranting now.
After reading several earlier posts, apparently I have to use the Dir function. I learn visually and cannot figure out how to use the function from the VBA help file since there are no examples. Does anyone have an example of code using the Dir function to insert filenames in an array? Once I see the code, I'm sure I can adapt it to suit my needs.
I have a whole bunch of dates in a column that look like this:
5/01/1998 when it is supposed to be 5/01/2098 is there a character you can use when you are using the find & replace mode i.e.
*/**/20** I know it is not the asterisk but I believe there is some other character that can be used and it won't change any other of the numbers except the 19. I tried reformating and it does'nt work because of the way they sent it to me.