Sum Up The Digits Within A Range Of Cells
Nov 28, 2008I am looking for a formula to sum up all the digit(s) within a range of cells, e.g.
View 7 RepliesI am looking for a formula to sum up all the digit(s) within a range of cells, e.g.
View 7 RepliesI am trying to sum the digits in a range of cells, as per the attached example.
I modified a formula I found on this site for summing digits in a single cell, to deal with a range, giving this, entered as an array formula.
{=SUM((LEN(A5:A9)-LEN(SUBSTITUTE(A5:A9,{1,2,3,4,5,6,7,8,9},"")))*{1,2,3,4,5,6,7,8,9})}
This works for cells in a cloumn, but not for a row or a block.
How could it be modified to deal with a row or block?
i need to format my numbers in the following format
10,00,000.00
the first three digits will be separated and then subsequently 2 digits
I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.
=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)
I have a long string that has a list of digits in the middle that I want to extract. The string is variable length and the number of digits I want to extract is 5-7. I also have slashes in between the numbers I want to extract. I need a UDF that allows me to extract the 5-7 digit number from the string and restrict around the slashes (i.e. if two sets of digits in the string match the condition for extraction, extract the one around the slashes.) For example my original data is like
1. aaa/12345/aaa/123
2. aaaaa/123456/aaaaaa/3423
3. 323/aa/1234567/aa
and I want for results
1. 12345
2. 123456
3. 1234567
Is there a UDF that allows me to do this?
I would like a formula to count the number of unique digits from a range of cells.
For example...
Range A1:F1...
11 23 36 47 48 49 = 8
Range A2:F2...
1 11 12 21 30 31 = 4 etc
I am trying to create a formula that sums all the cells that have numbers that begin with 12. For example, here are the numbers in cells A1 through A6 (my actual spreadsheet is much larger):
12
1200
13
1
120
112
I want to pull the 12, 1200, and 120 for a total of 1332.
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05
DuToitskloof Pinotage/Merlot/Ruby Cabernet
1999 Tradition Juracon 375ml
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.
Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay ‘07
De Wetshof Sauvignon Blanc ‘07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage ‘01
Bouchard Finlayson Tete de Cuvee Pinot Noir ‘07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
2003 Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon ‘05
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
Does anyone have an idea on how to help with this?
Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.
However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.
I basically I have a column with numbers. All the numbers are positive integers. What I like to do is have a VBA function that extracts the integers with the largest number of digits. So for example if we have the following column:
12
123
234
12346
2345
[code].....
So basically we search for largest number of digits, and extract the numbers that fit this category, which could be just one number or multiple numbers.
I have four different cell.
Cell a1 contains 6 digits
Cell a2 contains 1 digit
Cell a3 contains 6 digits
Cell a4 contains 4 digits.
Cells a3 and a4 may contain a number less than number of digits specified above but are custom formatted 000000 and 0000 respectively to ensure they have the correct number of digits. My problem is when I try to combine the four cells they lose their formatting. I have tried =A1&A2&A3&A4 and = concatenate(A1,A2,A3,A4). But both formulas loose the formatting from the individual cells.
I have a row data corresponding to the measuring of load cell per min and I need to average the values per hour. So I have a column B for the date (from 1-01-2013 to 31-01-2013, column C for the time (0:00:00 to 23:59:00), and D de values per min I want to average. I have to do the same for the rest of the month of 2013 (February, ...., December).
I would like to know if there is a way to create a formula to calculate the average of the first 60 values (to get the average of the first hour of 1-01-2013), and then copy it to get the average of the following 60 (average of the second hour in 1-01-2013) and so on.
If there is no way to do it, I would like to know if I can do it using functions like average, match, index, offset, what would be the best match of those functions.
I also tried it by doing the analysis in another tab and using the function "averageifs" with two criterias: one for the date (example 01-01-2013) and another one for the hour (example 0:00:00), but it didnt work, it show error: #value. I inserted an extra column in the data tab with just the hour (example 0:00:00) in front of the corresponding column with (example 0:01:00, 00:02:00, etc)
Equation I used for this:
=AVERAGEIFS('Data (min)'!D$6:D$43206,'Data (min)'!$A$6:$A$44646,A6,'Data (min)'!$B$6:$B$44646,B6)
=AVERAGEIFS(TAB AND COLUMN WHERE THE RAW DATA IS,RANGE OF CRITERIA 1,CRITERIA 1,RANGE CRITERIA 2,CRITERIA 2)
Is there a way I can stop a range of cells from recalculating once the cells in that range have a certain value?
I'm a complete newbie when it comes to any kind of programming and so...I'd need a little bit of handholding with this.
I got a range of data on sheet2, size changes everyday (dynamic) And in sheet1. I got a range of data and the size changes everyday as well. I need to copy the range in sheet2 to sheet1. The position would be at the cell after the last data in sheet1. e.g.
sheet1 got 105 data
I need to paste data of sheet2 start of row106 in sheet1
I can't seem to find a way to find the max of only the last four digits of a cell, matching the first 8. As an example:
I have thousands of cells in a column like this, (and I can't add any columns to the sheet), and I have a cell with the first three digits and the second three digits. So, out of all these numbers, I want the MAX of ONLY the numbers with the first 8 digits of "800-123-". Also, the decimal on the end is how many times the number was called, and any the decimal and any number after it is to be ignored. The answer would be "800-123-0024", or "0024", I just need a faster way to find it without searching for it.
888-555-0099.2
800-123-0022.3
555-333-0474
[Code]....
I have a long list of 4 digit numbers:
e.g.
0234
2434
6566
4566
6785
But I only want the first 2 digits (I need the last two digits deleted). I don't want to just divide by 1000 as this will leve me with a decimal. The numbers are in text format as some of them begin with a 0. So it would be:
02
24
65
45
67
I would like to take the first three digits of column A and do a lookup of column B that would return the corresponding number from column C. For example, if I entered the formula for 103PH, the lookup would find the 103 in column B and return "2775.00" from column C...........
View 4 Replies View RelatedI was wondering how do you format a cell so that when i enter the number 7 it automatically sets it at 007 and for like 10 it would be 010 so a must have of 3 digits
View 5 Replies View Relatedadding the sum of digits in a cell using VBA. For eg: in A1 if I have 12345 I need the sum of 12345 (15) in cell B1.
View 3 Replies View RelatedI have a number 53.30242 in a cell a1. How can I just make it 53.302? I don't want to round it to 3 decimal place, just keep the first 3 digits.
View 6 Replies View RelatedI have a column with social security numbers, i.e. 555-33-2222 and I need to change to show only the last four digits, i.e. xxx-xx-2222. Can this be done in excel?
View 4 Replies View RelatedI have 2 columns, A and B. The data looks like this:
0040005A2002868000PMTo 164.40
003000005000037000PMTo 104.40
001000002002090000PMTn 188.35
002000002000015000PMTn 104.35
001000002000298000PMTn 92.80
001000004001042000PMTo 78.00
001000004001050000PMTo 78.00
003000001002100000PMTo 97.10
001000004002115000PMTn 92.75
I want to have column J with values from column A grouped by the first 9 digits and column J with the totals for these groups. It would look something like this:
002000002 250
002000004 300
003000027 100
003000050 70
004000002 90
etc
I have a column of numbers, all with varying numbers of digits. I want to make them all have only 4 DIGITS in total (regardless of where the decimal is located... so there could be 4,3, 2, 1,or, 0 decimal places). I just want to make everything the same number of digits.
View 9 Replies View RelatedIn this worksheet , in Columns B4:F2615, there are rows of digits that range from 1-36, I have a need to find the 10 digits that were drawn togather the most. I have no idea how to do this in Excel or can it be done? ....
View 9 Replies View RelatedI have a pair of digits in col B, that I would like to match with the digits in in col D, and display those matches in col E. If possible I would delete the duplicates in col E, and show results in col F.
View 9 Replies View RelatedI have a formula now that is =right(C2,5)+0 that is working well. However the data has grown and sometimes there is also 6 digits now instead of 5. So I need it to pick up either one 5 or 6. When I change the formula to 6 it works but picks up a / which happens to be before the 5 digit # sequence when there is only 5 digits. It works great for the 6. Is there another way around this so I only get the numbre digits if there are 5 or 6 and not the /. Maybe an if statement. I've tried several ways but none work right. The only other thing I can think of is to get it as above with the =right(C2,6)+0 and then afterwards to a find and replace and remove the / from the data. I was just tryign not to add an extra step to the process. Any ideas please?
Example of the data in coloumn C2 is:
15/2000/4567/NA/NA/97305or with 6 digits at the end15/2000/4567/NA/NA/973052there is always just 5 or 6 digits at the end that I need.
1. Remove the first 4 digits from each "Appeal ID"
2. Insert a new column (first column) called "Chapter"
3. Run a v-lookup down the new column against a file that is stored on my desktop. The v-lookup will cross check the Appeal ID against the file to identify the Chapter
4. Sort the data alphabetically by Chapter
5. Create seperate Excel files for each Chapter ...
I tried every filter function I know of, to no avail, and am yielding my stupidity to the forum. I have this series of numbers as an example:
456912
789547
785171
658712
968712
369874
258741
127812
All I want to filter is all values ending with 12.
how can i do this in excel 2002?
for example.....
mod(95000000922019182020281000,97)=24
but in excel im getting the value as 0
also when i type the 24 digits its show like ..... # NUM!
if i put the function like =A1-FLOOR(A1,B1) its working for 13 digits but not for 24 digits.
I've recorded a macro to replace the Australian telephone number area codes (at the beginning of each phone number) with international dialling codes. I also need to replace the first two digits ONLY of mobile ( cell) phone numbers which, in Australia, all begin with "04" (see last part of macro code below - column L:L).
With the code the way I've recorded it, if it finds "04" in another part of the number (e.g. 0411 104 111), the second occurrence of the "04" will automatically be replaced with "614" as well which I don't want. So I need some code to add so that the macro only searches and replaces those first two digits in that column. I hope I'm making sense?!
Sub ConvPhNo()
'
' ConvPhNo Macro
' Macro recorded 12/12/2007 by xxxxxxxxx
'
'
Columns("C:C").Select
Selection.Replace What:="(", Replacement:="", LookAt:=xlPart, _ ...........