Create PivotTable With Two Columns Of Data For The Same Column Header?

Dec 24, 2012

Can I create a PivotTable with two columns of data for the same Column header?

I have created a PivotTable in Excel 2003 with months for rows and cities for columns. I would like to have TWO columns of data for each city. The two data columns are: Average House Selling Price, and Number of Houses Sold. When I put both of these data fields into the PivotTable Wizard, they are listed below each other so that each Month occupies two rows, but each city occupies one column. I want the two data fields beside each other so that each month only occupies one row, but there are two data columns for each City.

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Macro To Copy Data From All Columns Containing Header To A Single Column In Workbook

Apr 11, 2014

I am a macro newbie and I think this is beyond me.

I've been trying all morning with no success to make a macro that will copy data from all columns of one workbook containing specified header text to a single column in a different workbook.

So for example, I've got a workbook called coupon barcodes that has multiple tabs for each person redeeming coupons on sheets 2-88 (sheet one can be skipped) and some of the columns are labeled "voucher 1" in cell A4 or B4 or C4 etc. with a list of all the coupon barcodes that customer redeemed below that. I want all of the data from all of the columns in this workbook that have the header "voucher 1" to be copied and pasted into one column (order doesn't matter) also labeled "voucher 1" in another workbook I have open called vouchering database.

There must be a way to do this that is easier than searching the internet all afternoon again

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I have a worksheet of data collected from on online list of names and addresses all in one column. I'd like to pivot the data so I can sort it, etc. Unfortunately, the entries are not the same length (meaning some have five rows some have six or seven, etc. I have created an only file so everyone can see the issue.

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As these are expanding tables feeding from the internet I don't think copy and paste into one column will work (I'm not sure about this but I would prefer a formula to avoid any issues).

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Mar 3, 2012

Is this possible? If

A B C
0 0 0
0 0 0
1 4 5
2 4 8
0 0 0
0 0 0
0 0 0
2 6 9
8 9 3
3 5 6
0 0 0

In the raw data, the 0s split up the data into different steps. I am trying to create a function that selects the data from the ABC column and puts it into new columns for each step. I.e:

New Columns with:
1 4 5
2 4 8

and
2 6 9
8 9 3
3 5 6

In the raw data files, there will be 10 steps, with a varying length of data.

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So I want to add some VBA Code that deletes specified columns and then insert Bolded Column headers to the remaining columns. The columns I want deleted are D,F,I,J,K. For simplicity purposes, the column headers would be A,B,C,D,E,F,G.

I tried using Columns("D,F,I,J,K").delete but I kept on getting 13 error.

[Code] ......

Attached File : Test VBA File.xlsx‎

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I just tried to switch to DAO and adapted my code accordingly but the new code fail at:

Code: ....

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I have VBA code to perform some actions on data in excel file and then convert all that data into semi-colon separated CSV/text file (code below).

Now, all I want is to add VBA code in the existing macro to find a column header (say, "Application date") and then convert all the dates into YYYY-MM-DD format. The original values in this column don't have a fixed date format.

Code:
Public Sub ExportToCsvFile(FName As String, _
Sep As String, SelectionOnly As Boolean, _
AppendDataOnExistingFile As Boolean)
Dim WholeLine As String Dim FNum As Integer
Dim RowNdx As Long Dim ColNdx As Integer

[code]....

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Apr 3, 2014

I want to rearrange(sort asscending) columns based on numerical value in column header string through VBA macro. Please check attachment.

i.e. (Present Data)
# A B C D
1 col.1 col.4 col.3 col.2

(Output Data )
# A B C D
1 col.1 col.2 col.3 col.4

test.bmp‎

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Sep 18, 2012

I need a formula to return column header if there is data in the column, any data.But I also need to return the second, third, fourth header with data too

In column A row 2, I have =IF(M8"",$M$1,IF(N8"",$N$1,IF(O8"",$O$1,IF(P8"",$P$1,IF(Q8"",$Q$1,IF(R8"",$R$1,IF(S8"",$S$1,IF(T8"",$T$1,""))))))))

This returns the row 1 header for the first instance of data in row 2 columns M thru T But in B2, I need the second header with data in the column.

I need the results in yellow (1st, 2nd, 3rd, 4th) from the array to it's left

1St match2nd 3rd 4thColumn MColumn NColumn OColumn PColumn QColumn R
Column MColumn PColumn QData data2Data3
Column NColumn OColumn PColumn R Data Data2 data3 data4

Would use match/index but can't increment it to the second or 3rd match

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Excel 2007 :: Match Data In Two Columns And Return Header

Apr 20, 2012

I have two columns with team abbreviations, one simply says whether they are AL or NL the other is the result of a search with multiple occurrences of the team name. I need to match the long list with the short and put the column header AL or NL in the adjacent cell.

I'm using Excel 2007

The last formula I tried was =INDEX($AY$1,MATCH(BB2,$AY$2:$AY$15,0),0)

The screen shot actually just part of the sheet copied since the screen shot look like a broken html page Ok I give up. I copy and paste a jpg it turns into code, I copy and paste the spreadsheet and formatting vanishes, I don't have a URL for the picture... I did look at FAQs and didn't find picture rules but I will look again. Meanwhile. . .

It's just six columns of data. The short list is in AY from AY2 : AY15
The long list is in BB from BB2:BB505
The column header "AL" is in AY1 and NL is in AZ1

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Jun 19, 2007

I have a data worksheet, which contains about 20,000 lines of journal entry info. There is a separate column for debit and credit, not one "amount" column. On another worksheet, I am aggregating the data to review the impact for this series of journal entries over a time period (12 months). Thus, my pivottable contains "Accounts" in the "ROW" and "Period" in the "COLUMN" sections of the PivotTable Layout. The "Debit" and "Credit" fields are then summed in the "DATA" portion of the PivotTable.

My issue revolves around getting the actual impact for each account for each time period. Essentially, I need an extra column inserted between each time period that sums the debits and credits for that period. Do I need a macro for this (not any experience with macros)? My file is way to big to share, so let me know if a pared-down sample would work.

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county Month Quarterly totals

UK June 200
july 200
August 200

Uk Total 200

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The code I'm using that results in the following error message: "Run-Time Error '1004':

The pivotTable field name is not valid. To create a pivottable report, you must use data that is organized as a list with labeled columns. If you are changing the name of a pivottable field, you must type a new name for the field." Here's the code, I've seperated it into each sub hoping that will make it easier to read:

Option Explicit

Sub main_prog()
Call td_metrics_import
Call pt_td_metrics("Pivot_Page1", "PivotTable1", "PivotTable2")
Call pt_td_metrics("Pivot_Page2", "PivotTable3", "PivotTable4")
Call create_graph
End Sub...............

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I have a list of S/N with Pass/Fail result next to it. A specific S/N can appear several times in the list:

SN...Result
-------------
111...FAIL
111...FAIL
111...FAIL
111...PASS
222...PASS
333...FAIL
333...FAIL

When creating a pivot table of SN vs. Result (count) I get:

****|FAIL...PASS
-------------------
111..|...3.....1
222..|..........1
333..|...2

I want to get the FAIL count of SN in which PASS > 0 (First two rows)

BUT I can not figure out how I can filter based on the values of the pivot table itself (rather than the values of the original list). When I try to use 'Result' field as report filter, I can not get it as a Column label (and vice-versa). In this case I get:

I get:
****|PASS
------------
111 | ...1
222 | ...1

Desired:

.......|..FAIL..PASS
-------------------
111 |...3...1
222 |........1

Desired (alternative):

......|..FAIL
-------------
111 |...3
222 |...0

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I've been trying find an appropriate formula to extract the column header from a table in a different sheet if the row header and value in that table is known.

in the lookup table the row titles (column A) are product codes, column titles (row 2, D through AX) are business names and the table values are quantity.

In a different table I have product codes in column A and in column B i have the max number/quantity of products for that code. In column C i want to put the company name associated with the product and the number/quantity.

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For example, move range B8 to B76 beneath range A8 to A76 and range C8 to C76 beneath that etc, page by page working through all 270 pages !

Also need to delete unnecessary 'page headers' throughout as in rows 2-6

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Company Name
Contact ID

Situation:
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Goal:
I would like to have a macro that will look at the Group Name column and create a new column for each distinct group. I then would like the macro to go down the Contact Name column (I believe that I will have to have it sorted)and look at the Group Name that is listed in that row and put "True" in the Group Column that was created in the above step. Then, go to the next row, if the Contact Name is the same, look that the Group Name column and put "True" in the corresponding Group Column in the FIRST ROW OF THAT CONTACT NAME. Then Delete that row.

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Example Below:

Column AColumn B Column C159261037114812

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The items of the second field ("type plate") are at each time visible (the macro make them visible to have the complete information concerning the "batch")

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Dim pt1 As PivotTable
Dim pf As PivotField
Dim pi As PivotItem
Dim pj As PivotItem
Dim i As Double
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Formula:

[Code] .....

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