Calculate Large Binomial Coefficients

Dec 29, 2007

I'm trying to do a binomial distribution summation as part of a VBA function, and have been using the Application.WorksheetFunction.BinomDist function, which works fine until the numbers get large - the binomial coefficients used in the calculation end up being larger than can be held in a double floating-point number in VBA, so excel can't handle it. The final result of the calculation is a probability, so it's not a huge number! I was wondering if anyone knows an alternate way of calculating binomial probabilities which avoid any huge number intermediates.

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Calculate 2nd Degree Polynomial Trendline Coefficients In VBA Without Using Cells

Jul 17, 2014

i have a function in a cell (that works) to extract coefficients from a range of cells in a workbook:

VB: =INDEX(LINEST(CP25:CP27,CQ25:CQ27^{1,2}),1)}

i have variables for cp25:cp27 and cq25:cq27 already defined in my vba code. the values for these in the case i am working on are as follows (returns 110.5):

cp25 = 560
cp26 = 570
cp27 = 580
cq25 = .414
cq26 = .479
cq27 = .536

1) how to do this function in VBA only - this is part of a UDF and cannot have any helper cells
2) how to refer to 560,570,580 as a 'range'. is there a way to put these six variables into my ranges for later processing?

All of the google searches i have deal only with linear regression, taking from existing graphs, or say to just use the function i have above.

I have tried

VB:

Var = Application.WorksheetFunction.LinEst(Sheets("references").Range("CP25:CP27"), Sheets("references").Range("CQ25:CQ27^{1,2}"), 1)
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but return #value! errors. when i remove the ^{1,2} portion, i do return a value but it is incorrect (returns 160), what is the correct syntax for adding in the ^{1,2}? if you do that would be fantastic, but brings me back to issue #2 in that i need to refer to my variables in the vba code and not this range (as they will eventually be going away).

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Oct 6, 2011

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IS there syntax I could use that would calculate the average every 4-cells so I could get the hourly average without having to type =average(XX:XX) 6,554 times?

Example of set-up:

29-Sep-11
23:00:00
0.820412164= AVERAGE(B8735:B8738)
0.762574274 =average(D8735:D8738)
84.98389991 =average(F8735:F8738)
29-Sep-11 23:15:00 0.819168591
0.762781167

[Code]...

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Nov 25, 2013

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For instance, in my data set if I have something similar to below. How would I calculate variance in the different regions? Is it possible to automate this process? Also could the Analysis ToolPAk be used instead or in conjunction?

OrderDate
Region
Rep
Item

[Code]....

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Sep 10, 2008

I have been working on a problem that requires being able to calculate the chances of any winnng a series of coin tosses with a weighted coin.

The coin has for arguments sake a 65% / 35% chance of landing heads or tails and to win the game you need to hit your side 9 times.

Can you use excel to calculate things like: If heads takes the lead 1-0, what does that mean the its overall percentage chance of winning? If the score is 7-3 to tails, what are the chances of either side gaining victory? etc, etc.

I thought that there would be a way of setting up a spreadsheet that listed the goal (first to 9, 12, 15 or whatever) and below this the percentage chance of heads and the percentage chance of tails. Then somewhere would be a box to enter the current score (0-0, 3-5, 1-1 or whatever) and beside this the current chance of heads or tails gaining victory.

I've tried setting up something like this but am a bit of a dufus when it comes to knowing how, where and when to use the different functions of excel.

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Nov 27, 2006

There is trading system which generates a winning trade per ONE stock in ONE month’s time with a probability of 5/12 (0,4166%). If the system trades 10 independent stocks the probability of any number of winning trades occurring out of all of them in ONE month is shown below:

None 0,0046
One 0,0326
Two 0,1047
Three 0,1995
Four 0,2494
Five 0,2172
Six 0,1272
Seven 0,0519
Eight 0,0139
Nine 0,0022
Ten 0,0002

I took these values from a book…I tried to reproduce these values in the spreadsheet that I attached. My table looks as follows:

0 0,0046
1 0,0033
2 0,0023
3 0,0017
4 0,0012
5 0,0008
6 0,0006..........

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Mar 9, 2007

I have a VBA function that calculates polynomial coefficients for a series of data pairs. One selects the range of cells that the coefficients are to be stored in, and enters the polynomial formula:

{POLFIT(Xa, Ya, N)}

Where Xa is the array of ordinate values, Ya is the array of data values, and N is the polynomial order to be fit.

It is obvious that one needs to select at least N+1 cells when the array funtion is typed in. But, it is easy to select too few cells.

I am looking for a way to test whether enough cells were selected for the range formula: The function declaration is

Function POLFIT(Xa, Ya, N As Integer) As Variant

Various means I have tried to count POLFIT do not return the correct value.

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Apr 8, 2008

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Oct 14, 2008

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I turned the automatic calculation off.

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The majority of the array formulas are IF queries with multiple criteria.

Would it speed up the calculation if I didn’t use array formulas?

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to getting accurate regression coefficients from a dataset with *small* (standard) numbers, which contains centered predictors. More specifically, I have a dataset with 18 observed data points containing a criterion (y), a centered predictor variable (x), another centered predictor variable (z), and the interaction of the two centered predictor variables (xz). This multiple regression equation is structured to test for interactions between the two continuous predictor variables (x and z) as prescribed by Aiken and West (1991) in their classic book.

When I run the regression in Excel with the centered predictors, some of the regression coefficents in the output are estimated to be 0, although they are clealry *not* 0 as estimated by SPSS 14.0.2. I have spent many hours troubleshooting this problem (and searched many forums on the internet) and still do not know why this is happening.

Initially, I thought the problem might have to do with the cross-product of the centered predictors, but even just doing a regression with one of the centered predictors (for certain centered predictors) yields a regression coefficient of 0 (although it should be non-zero as per SPSS 14.0.2). When doing these multiple regressions with non-centered predictors, all regression coefficients are estimated accurately.

I was wondering if anyone had any insights on why I am experiencing these problems.... If anyone wants a sample of some test data I have used to troubleshoot these problems, you can download a file from: [url] and/or email me at (email deleted by Mod) for more datasets or questions.

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This is all I have.

O2:O11
=LARGE(Sheet1:Sheet5!$H$3:$H$102,1)
to
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I then have this which was the best I could find after about 30 different formulas.
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Most examples I see have the names they want right beside the values. So in my case H3 is 22 (and the largest value within H across all sheets) and if I followed their examples G3 would be Sheet1. So because it's side by side it'd be easily pulled. But the only name references I have are the worksheet name itself or A1 of Sheet1:Sheet5 so I'm not sure how to rework their formulas to suit mine.

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I've attached an example sheet that I hope gives a basic idea of what I'm trying to do. I'm looking for a method to fill in the data for cells A13:A15 and C13:C15 in the attached sheet.

I could modify my worksheet a bit and probably get the result I'm looking for, but I'm hoping to come up with a nicer solution, and hopefully learn Excel a bit better in the process.

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Option Explicit
Option Compare Text
Private Sub Worksheet_Change(ByVal Target As Range)
Dim cl As Range
Dim lng As Long
Application.EnableEvents = False

Select Case Target.Address
Case "$E$3"
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SelectNumber:
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.................................................(above statements repeat more than 300 times for different cells)..............................
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I attach short s/s to illustrate my need.

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A B C D E F G H
1 Region Product 235 236 237 238 239 240
2 RegionA ProductA 25 31 15 18 10 5
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4 RegionB ProductB 21 13 10 5 28 10
5 RegionC ProductB 21 13 10 5 28 10
6 RegionA ProductA 25 31 15 18 10 5
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