Check If Celll Contains Certain Characters

Mar 20, 2007

If character or letter "A", or "B", and so on (until "J") is found both in Column A and Column B in a given row, then it is TRUE.

If no character or letter (from A to J) matches in both columns, then FALSE.

**Numbers are irrelevant.

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Want To Combine Celll Values

Oct 6, 2008

I have a sheet in which there ara $ and Cents but in the bottom i want to sum them together. How can i do that?

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Feb 6, 2010

I have a column which cells are populated with codes like

BGW
3UG
WWU
1BR
UUBRG
WUBRG
7UUGGRRR

and so on. As you could see, we'll always have a number from 1 to 20 (or no number at all) followed by those letters (which can be only W,U,B,R or G). I'd like to know if there is a function to count the # of times a particular character occurs in a colum. In the above example, the "U" character appears 8 times. This would be nice to automate part of the filling process.

Just a little difference: since numbers always come before the letters, I need to treat a number sequence as a single value: 12GWW should not be seen as 1 then 2, but "twelve", like it was a single character. So, if I have this column...

URR
12WBBB
6UBG
12R
12WG

...then "12" appears 3 times. Nevertheless, B appears four times (3 on line 2 and 1 on line 3.)

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A1 010 B1 3.010
A2 010 B2 1A.010

My spreadsheet is very large and I need to get this done without manually having to look at each.

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I have a textbox in a form and i need to check if the text posted there begins with zero or if it contains spaces. Ex:

05E 9050 01
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4P 565001
if this is the text then it shoud warn me becouse there is a space

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Aug 10, 2007

In my column of text strings, I have a multiple format of strings make-up. Below is just one of them I have to check that the first 6 are digits from 0 to 9, and it is followed by a hypen. If condition is true, the first 6 digits is the output (ie. 345678).

345678-S

=IF(ISNUMBER(--(MID(A1, FIND("-",A1)-1,1))--(MID(A1,FIND("-",A1)-2,1))--(MID(A1,FIND("-",A1)-3,1))--(MID(A1,FIND("-",A1)-4,1))--(MID(A1,FIND("-",A1)-5,1))--(MID(A1,FIND("-",A1)-6,1))),LEFT(A1,FIND("-",A1)-1))

However, if I were to continue doing this for other strings, I would soon run out of characters limit that is allowed in a cell. I wonder whether a formulae such as below is valid? Any suggestion or help for a shorter formula is very much appreciated.

=IF(ISNUMBER(--(LEFT(A1,1+1+1+1+1+1))),LEFT(A1,6))

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Dec 3, 2008

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example
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I have a list of stores across the ABC columns and a list of items down the number rows.

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I need a formula that will search the range D8-D100 to confirm that all cells within that range are either 11 characters in length or blank. I will use it inside of an error message that will look something like this:

=IF(****formula that checks to make sure all of the cells in that range are blank or 11 characters****=TRUE, "", "Please make sure that all cells are 11 digits or blank")

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Mouse, Mickey ;

Microsoft Outlook has changed the way that email addresses from the global addressbook copy and paste (from version 2003 to version 2010).

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My company uses 4 types of barcodes 8, 12, 13, & 14 number barcodes for our products my problem is that I can't figure out how to force the barcode to format properly no matter how somebody enters it if they don't use spaces or put them in the wrong spots, I can't use custom formats because there is 4 different layouts

8 digit should be "#### ####"
12 digit should be "###### ######"
13 digit should be "# ###### ######"
14 digit should be "# ## ##### ######"

these barcodes are in columns L, M, & N also right now 'm using a formula in another cell to verify the barcodes by calculating the check digit and comparing it to the check digit typed the formula i'm using is

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I have data in Row 53 that spans 7 columns, but stays in the same row. I want to design a loop to select every 7th cell in that row and check if it is empty. If not, add onto a "counter" then display the final number of occupied cells (the value of the counter) at the end. This is what I have so far, but I get all sorts of errors.

Code:
Sub Tester()

Dim WB As Workbook
Dim WS As Worksheets
Dim modCounter As Long
Dim Cell As Range

Set WB = Workbook("Transverse Series.xlsm")
Set WS = WB.Sheets(BM18)

[Code] ......

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I am using this code

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So we have people's names in a table. First name in one column and last name in another column. We have a 3rd column where we can use 8 characters to do a combination of First 5 of Last Name + first 3 of first name. However, if someone's last name is only 3 or 4 characters, we'd then want to take more from the first name to fill out the 8 characters.

So:
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What's the best way to do that without creating some crazy formula with tons of if/thens?

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I have attempted to attach an example worksheet.

Test check control.xlsx

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The way I want the display to work is that if the 10th checkbox is ticked all other checkboxes are cleared. Also if the 10th checkbox is ticked and any of the other check boxes is selected then the 10th checkbox should be selected.

I have tried coding this up but the checkboxes don't seem to operate as desired. I placed some code on the click event for the last option button to set the vlaue for all other buttons to false. This works but the 10th check box doesn't get ticked itself. When I try to code up the other bit I get similar issues.

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Sep 14, 2009

I have a string of names that run together without spaces or commas between each name.

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Is there a way to add a comma and space when an upper case letter is immediately followed by a lower case letter?

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By moving my charts to the same sheet and getting rid of the INDIRECT formulas, I shortened my formula to 291 characters which is too long as the limit is 255.

=IF($G$9="Sodium",$N$34,IF($G$9="Manganese",$N$35,IF($G$9="Iron",$N$36,IF($G$9="Nitrate Nitrite",$N$37,IF($G$9="Nitrite",$N$38,IF($G$9="Nitrate",$N$39,IF($G$9="PH",$N$40,
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Is there any way to make my formula shorter? Or to reference a cell where I place the formula?

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Jun 9, 2009

I've searched Excel's Help but still unsure how to do this. I hope excel experts here can lend me a hand...

I have literally thousands of words in a single columns column which looks like this:

absah
absen
absenan
absensi
abses
absis
absolusi
absolut
absolutisme
...
...
...
etc

My question is what formula if i'd have to enter to add three spaces between characters and five characters at every end of the word so it should look like this?:

a b s a h .
a b s e n .
a b s e n a n .
....
....
etc

Note i have entered a full stop at the end of the example above to make the five spaces visible in this demonstration (I dont need the period character inserted at all).

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How to limit this to only column G as opposed to the entire sheet?

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