To Check Whether A Cell Only Contains A-z Or 1-9 Characters
Jan 21, 2009Is there a formula to show (true or false) whether a cell contains any characters that aren't a letter or number without resorting to vba?
View 9 RepliesIs there a formula to show (true or false) whether a cell contains any characters that aren't a letter or number without resorting to vba?
View 9 RepliesI have a column which cells are populated with codes like
BGW
3UG
WWU
1BR
UUBRG
WUBRG
7UUGGRRR
and so on. As you could see, we'll always have a number from 1 to 20 (or no number at all) followed by those letters (which can be only W,U,B,R or G). I'd like to know if there is a function to count the # of times a particular character occurs in a colum. In the above example, the "U" character appears 8 times. This would be nice to automate part of the filling process.
Just a little difference: since numbers always come before the letters, I need to treat a number sequence as a single value: 12GWW should not be seen as 1 then 2, but "twelve", like it was a single character. So, if I have this column...
URR
12WBBB
6UBG
12R
12WG
...then "12" appears 3 times. Nevertheless, B appears four times (3 on line 2 and 1 on line 3.)
I need to come up with a formula to verify that the last 3 characters of a text string match the 3 characters in the adjacent cell. So I am comparing in the example below Column B to Column A.
Ex:
A1 010 B1 3.010
A2 010 B2 1A.010
My spreadsheet is very large and I need to get this done without manually having to look at each.
If character or letter "A", or "B", and so on (until "J") is found both in Column A and Column B in a given row, then it is TRUE.
If no character or letter (from A to J) matches in both columns, then FALSE.
**Numbers are irrelevant.
I have a textbox in a form and i need to check if the text posted there begins with zero or if it contains spaces. Ex:
05E 9050 01
if this is the text then it shoud warn me becouse there is a zero in the begining and it contain spaces
4P 565001
if this is the text then it shoud warn me becouse there is a space
In my column of text strings, I have a multiple format of strings make-up. Below is just one of them I have to check that the first 6 are digits from 0 to 9, and it is followed by a hypen. If condition is true, the first 6 digits is the output (ie. 345678).
345678-S
=IF(ISNUMBER(--(MID(A1, FIND("-",A1)-1,1))--(MID(A1,FIND("-",A1)-2,1))--(MID(A1,FIND("-",A1)-3,1))--(MID(A1,FIND("-",A1)-4,1))--(MID(A1,FIND("-",A1)-5,1))--(MID(A1,FIND("-",A1)-6,1))),LEFT(A1,FIND("-",A1)-1))
However, if I were to continue doing this for other strings, I would soon run out of characters limit that is allowed in a cell. I wonder whether a formulae such as below is valid? Any suggestion or help for a shorter formula is very much appreciated.
=IF(ISNUMBER(--(LEFT(A1,1+1+1+1+1+1))),LEFT(A1,6))
I want to write a macro that will check every selected cell. It should detect if there is a space after the fourth character. If there is a space, go to the next selected cell. If there is no space, add a space and go to the next selected cell.
View 5 Replies View RelatedI need a formula that will search the range D8-D100 to confirm that all cells within that range are either 11 characters in length or blank. I will use it inside of an error message that will look something like this:
=IF(****formula that checks to make sure all of the cells in that range are blank or 11 characters****=TRUE, "", "Please make sure that all cells are 11 digits or blank")
I have data in Row 53 that spans 7 columns, but stays in the same row. I want to design a loop to select every 7th cell in that row and check if it is empty. If not, add onto a "counter" then display the final number of occupied cells (the value of the counter) at the end. This is what I have so far, but I get all sorts of errors.
Code:
Sub Tester()
Dim WB As Workbook
Dim WS As Worksheets
Dim modCounter As Long
Dim Cell As Range
Set WB = Workbook("Transverse Series.xlsm")
Set WS = WB.Sheets(BM18)
[Code] ......
So we have people's names in a table. First name in one column and last name in another column. We have a 3rd column where we can use 8 characters to do a combination of First 5 of Last Name + first 3 of first name. However, if someone's last name is only 3 or 4 characters, we'd then want to take more from the first name to fill out the 8 characters.
So:
Charles Johnson -> Johnscha
John Smith -> Smithjoh
Willian Wu -> Wuwillia
What's the best way to do that without creating some crazy formula with tons of if/thens?
Is there an Excel formula to remove the spacebar + characters in red, as shown below? I need to be left with only the last name, first name and the semicolon.
Mouse, Mickey ;
Microsoft Outlook has changed the way that email addresses from the global addressbook copy and paste (from version 2003 to version 2010).
I'm trying to use conditional formatting to highlight cells in a column that have less than 8 characters.
I know the LAN function, but I don't know how to make it work for the conditional formatting.
Using Excel 2007. I have a limit of 80 characters and spaces in a particular cell and I need to force those characters/spaces over 80 to the next cell. Is that possible?
View 11 Replies View RelatedI have an index of 80,000 names from an index. Some names appear in multiple volumes and on multiple pages within a volume. While the name is the same, they are different people. The Roman numeral is the volume and the numeric is the page number.
Example of original data: Joe Shmoe V-225, 310 VIII-22, 86, 110
I have separated the data into separate columns. Now I have:
Col 1 Col 2 Col 3 Col 4 Col 5 Col 6
Joe Shmoe V-225 310 VIII-22 86 110
At this point, I want to combine the Roman numeral in Col 2 with Col 3 and 4 and combine the Roman numeral in Col 4 with Col 5 and 6.
There are way too many records for me to manually enter the Roman numeral where missing.
When I try to enter 18 numeric characters in a single cell, the last three characters are converted to zeros. I can find no format that would allow me to see all 18 entered characters. Is there a way of doing this?
View 2 Replies View RelatedI have a spreadsheet which I use to enter notes related to particular invoice numbers. A v-lookup pulls the notes into another tab. What I'm running into is that the notes can be quite lengthy - in excess of 1,000 characters. When the notes get too long, they don't all appear in a single cell (unless it's extremely wide).
I'm wondering if there may be a way to maintain my notes in a word doc instead? Maybe in a table that pulls in using a v-lookup? But I'm not able to figure out how to direct a v-lookup to a word doc.
how many characters a cell can contain?
View 3 Replies View RelatedAs you can see, in D5, I have the charactor chain SRG-DC01-RA-xxxxxxx, and in D6 I have the charactor chain SRG-DC43-RA-xxxxx.
With the formula that I have entered, I would have thought that E5 would have generated "Lawnton". I don't want the formula to pick up the SRG, the RA, or the number, just the DCXX component.
This is what I have now:
=IF(OR(ISNUMBER(SEARCH({"DC43","DC01"},D5))),"Erskine Park","Lawnton")
which has not changed a thing from:
=IF(OR(ISNUMBER(SEARCH({"DC43"},D5))),"Erskine Park")
Surely I am not far off the mark??
Cell E1 having 150 characters (letters), I want to trim first 45 characters in cell E1 and place it in cell B2 and remaining characters in cell E1 (ie. from 46th character till end) and place it in cell A3.
View 1 Replies View RelatedI have SKU numbers in a cell and need to change the location of the sizing digits. Here is the example:
AOP6000SSUMD
AOPSS6000UMD
Is it possible to count the number of characters in a cell?
View 1 Replies View RelatedIn one of my columns I need to count the characters (alpha/numeric AND blank spaces) in each cell. (Any that are over 300, I will need to manually reduce to under 300.) How can I do this? Basically I would simply like to know which cells exceed 300 characters.
View 9 Replies View Relatedi have a long text in A1 field and i just need to capture some characters in between. Below is the example.
Raw Data:
Cell A1 (r1,c1) = Target: ABC, CustomerOrder, Results: BDE, LastUpdate: 12Dec08
I want to get the Result as below:
Cell A2 = Target: ABC Cell B2 = Results: BDE
Can this be done in Excel Cell format? Or do i need to do it in MS Access?
I am not sure whether this can be done with a function/formula or with VBA, hence posting this query in general. A neat formula however would be the best solution, coz the number of entries varies, in the workbook attached I have 14 different cases though. I need to know when a cell does not repeat any of the possible 7 letters, in each given cell. If there is repetition then leave the cell blank , if all four of the letters are different then place "NR" in the cell.
See attached wrkbk: Book1.xlsx‎
See the attached file. I regularly receive input files which I have to reformat and upload to a website as a .csv. The website does not like the / between the characters on the Input Data tab. Is there a way to automatically search and remove them and leave the rest of the characters intact? The columns do not always appear in the same order and there could be more or less columns. On the Import Template tab, columns A-I will always be there, so ideally the code should make the changes from the Input Data tab and copy the present columns (J thru whatever) header and data over to the Import Template tab starting in 'J1'. I think that VBA would be the best way to go due to the variable nature of the columns.
View 4 Replies View RelatedI have cells that look like the following
PN„¢HWA„¢PN
HWA„¢PN
PN
HCC
PN„¢HWA
HCC„¢HWA
PN„¢HWA
PN
Not the most exciting data, but I need to identify which cells contain the sub string "HWA". Ideally the next column would have that string extracted into it or some kind of indentifier
We are in the middle of a system conversion and I need to make sure our data is not over the length of the maximum character count for certain fields in the new system. Is there any function in Excel that counts the # of characters in a cell or will highlight the cells that contain larger than a certain # of characters?
View 2 Replies View RelatedI am looking for a function that will count characters[text or numbers] in a cell
View 9 Replies View RelatedI have the following in cell A1:
0113 CDW 3 yr Coterm - Ironport devices
I need to remove 0113 from this cell to read only:
CDW 3 yr Coterm - Ironport devices
Any formula to do this?
I need a VBA code to find the number of characters in each cell and display the result in next column.
For Ex:
ColA:
HI
who
There
output should be
ColA,ColB
HI,2
who,3
there,5
I have shown example for 3 rows only but there are chances like it contains more than 3 rows(Dynamic rows).I tried by creating Range variable but I couldn't succeeded.