My question is what formula if i'd have to enter to add three spaces between characters and five characters at every end of the word so it should look like this?:
a b s a h .
a b s e n .
a b s e n a n .
....
....
etc
Note i have entered a full stop at the end of the example above to make the five spaces visible in this demonstration (I dont need the period character inserted at all).
I am working on sales information which includes postcodes. What i need to do is seperate the first or first two text characters from the rest of the postcode. I have attached a small snipet of what i am working on. Currently i am using the =Left(A4,2) but this will give me in some case a numerical value aswell. For example E1 or G1 in the case of the sample attached. Is there a formula that exists where it will just return the text values in a cell and not numerical values.
I frequently need to extract email addresses from huge amounts of text, like 40+ pages long, etc... I was wondering if a macro could be developed somehow to leave me with a stack of email addresses. I suppose the macro would have to test each piece of text for an "@" and a ".com" and then stack only those terms in a column somewhere. Any ideas on how to do this? I am not macro savvy AT ALL...
How do I add special characters in-between text? I know how to include a registered sign by using =CHAR(174) but what I do not know is how to include text before and after the sign itself.
I am submitting a book CSV file to my website. However, the website will not accept any cell that contains more than 80 characters. The error states the following. "WARNING: Title should be less than or equal to 80 chars; your Title was truncated to 80 chars" repeated 13 times.
"Is there some VBA code which could delete all first, second or third characters of a text? Could it be done to the three last characters from this same text and these be displayed on reverse order?"
I have a textbox in a form and i need to check if the text posted there begins with zero or if it contains spaces. Ex:
05E 9050 01 if this is the text then it shoud warn me becouse there is a zero in the begining and it contain spaces 4P 565001 if this is the text then it shoud warn me becouse there is a space
if there is maximum number of characters in a cell, above which wrapping and the row height auto-fit functions will not work? I typed a paragraph into a cell and have the cell set to wrap and the row height to auto-fit but it does not display on print preview or on actual printing past a certain character in the cell. Even when I manually increase the row height, it still does not display.
I have a spreadsheet that uses sql to gather data from our servers. From this data, I use concatenate function to put the data into one cell ready to copy/paste into our sms program. The program will only take 160 characters at a time..
Result I need:
For the cell to split into two/three cells if over 160 characters (and to break after the last complete word), and if appropriate, it needs to say 1of2 at the beginning of the 1st message for example, and 2of2 at the beginning of the second.
I have a cell which holds text with a maximum number of characters of 6. Let´s say I want this cell to hold a word which is bigger, and trim it till it has 6 characters.
Example: word "Hippopotamus" (longer than 6 characters) should be trimmed so its displayed as "Hippop"(6 characters)
is there a way to specify how i want to trim, either right or left? Example "Hippop"(6 characters trim right) or "otamus" (6 characters trim left)
I pasted in 1369 characters (including spaces) to a cell, and NO MATTER what I try, all characters will not print.
If I have the cell up for formatting on the function line, all text can be seen, but for some reason it cuts off the last sentance or more and will not show it in print preview.
I've tried all kinds of cell text formatting, cell merging, etc. with no luck. The only work around I found is to just have the "missing text" on the following row.
This is very similar to my previous post, which was solved. Now that I've extract the numbers, I need to extract the text for the specific work activities, for example 13Z or 9GGG. I'm assuming some variation on this formula:
Is there a function that can remove all text and other characters from cell and only keep the numbers? The numbers can be randomly in the cell so not only in the end or beginning.
This should be simple, but I am struggling with finding a way to use the search or find function to identify text characters. This is my situation, I have for example a cell that contains FW023 or D1234. I need to be able to count the number of characters that are text.
i would think I would be able to do it with the search or find function, but can't figure out how to get it to just count the number of text characters with in it.
How I can change this formula to find the first 3 characters of a text string?
Instead of using numbers in column A, it will be Names, I need the user to enter only the first 3 characters of the name and then display the results, (Meaning that all others irrelaavnt rows will be hidden.
Sub myHidingRoutine() Dim foundCell As Range
With ThisWorkbook.Sheets("Sheet1") Set foundCell = .Range("a:a").Find(What:=.Range("a2").Value, After:=.Range("a2"), _ LookIn:=xlValues, LookAt:=xlWhole, SearchOrder:=xlByRows, _ SearchDirection:=xlNext, MatchCase:=False)
I'm trying to pull text out of a middle of a long string of data located within one cell. The string is not always the same size and the text I need to pull out is not always in the same spot
I want to pull out the text "Jimmy Bop (Broad) It will always be between "adgroup=" and ">>/" (although sometimes the character ">>/" will appear multiple times within the string.
I am attempting to utilize the Mid, Left, and Right functions to parse out data returned in a single cell. There are twelve months of data returned with the "title" listed after. I would like to be able to FIND the title and return a specific number of characters of data to the LEFT not the right (as Mid seems to do).
This may be a very simple question so forgive me for my ignorance. I have text in individual cells that look something like this (not actually addresses but same format):
Doe, John – 123, Anywhere St (Apt A), Anytown Anystate 12345
I have about 5,000 records. I would like to convert the records to look like this:
Doe John 123 Anywhere St Anytown Anystate 12345
Basically I want to take out all non alphanumeric characters and anything between curved or square brackets. In my minds eye my macro would read something like this:
Do until last character.
If character = alphanumericTrue – Move to next characterFalse – If character = spaceTrue – Move to next characterFalse – If character = curved or square bracketTrue – Delete all text in brackets including brackets then move to next characterFalse – Delete character then move to next character Loop. I would of course create an additional loop to run down the 5,000 records.
I am trying to write a formula that will recgonise either text or numicial value as the result is used with a match formula. In column C I have data as follows:
1400 SBY 1230 9985 ADO
I am using a =--RIGHT(C4,4) formula in column E to get the required data and then using my match formula to extract other data. How can I rewrite the above formula so that it can read either text or numbers that will allow my match formula to work.
I have a column of data; for each line of data I have something like ABCDEEast Anglia, ABCDFFarnborough. The text at the start is standard and all cases of East Anglia will have ABCDE prior to the East Anglia. Is there an easy way [aside from replacing] to loop through 1000 data points and replace the long method with a shorter concise version (i.e. East Anglia only). I have attached what I mean
I have some cells in a spreadsheet that contain unique numbers as the beginning of the cell (these numbers are always ten characters). In the rest of the cell there is text. the data would look something like this:-
SGGHNVT561 - 3yr Maintenance
I also have some cells which dont have the unique number at the begging, so the data would just look like:-
3yr Maintenance
In another table I have a list of the unique numbers and the name that they correspond to, for example (this is the 2 columns)
SGGHNVT561 - Dave HUKIDO8946 - Stuart HJUTIFHE78 - Graham
I have ben trying to construct a formula that only searches the beginning of the cells to see if it containts one of the unique numbers and if it does to put the name of the person beside the cell. If the unique number is not there to return a value like 'Check'.
i tried vlookup but then i ran out of ideas :/
this is what i came up with so far:- =IF(P7="","",VLOOKUP(P7,'[Master List.xls]Sheet1'!$B$2:$C$5,2))
The only problem i can see that this is looking for the full cell to be within the master list - but its really just the first 10 characters I want it to check
