I have a textbox in a form and i need to check if the text posted there begins with zero or if it contains spaces. Ex:
05E 9050 01
if this is the text then it shoud warn me becouse there is a zero in the begining and it contain spaces
4P 565001
if this is the text then it shoud warn me becouse there is a space
I have a column which cells are populated with codes like
BGW
3UG
WWU
1BR
UUBRG
WUBRG
7UUGGRRR
and so on. As you could see, we'll always have a number from 1 to 20 (or no number at all) followed by those letters (which can be only W,U,B,R or G). I'd like to know if there is a function to count the # of times a particular character occurs in a colum. In the above example, the "U" character appears 8 times. This would be nice to automate part of the filling process.
Just a little difference: since numbers always come before the letters, I need to treat a number sequence as a single value: 12GWW should not be seen as 1 then 2, but "twelve", like it was a single character. So, if I have this column...
URR
12WBBB
6UBG
12R
12WG
...then "12" appears 3 times. Nevertheless, B appears four times (3 on line 2 and 1 on line 3.)
I need to come up with a formula to verify that the last 3 characters of a text string match the 3 characters in the adjacent cell. So I am comparing in the example below Column B to Column A.
Ex:
A1 010 B1 3.010
A2 010 B2 1A.010
My spreadsheet is very large and I need to get this done without manually having to look at each.
If character or letter "A", or "B", and so on (until "J") is found both in Column A and Column B in a given row, then it is TRUE.
If no character or letter (from A to J) matches in both columns, then FALSE.
**Numbers are irrelevant.
Is there a formula to show (true or false) whether a cell contains any characters that aren't a letter or number without resorting to vba?
View 9 Replies View RelatedIn my column of text strings, I have a multiple format of strings make-up. Below is just one of them I have to check that the first 6 are digits from 0 to 9, and it is followed by a hypen. If condition is true, the first 6 digits is the output (ie. 345678).
345678-S
=IF(ISNUMBER(--(MID(A1, FIND("-",A1)-1,1))--(MID(A1,FIND("-",A1)-2,1))--(MID(A1,FIND("-",A1)-3,1))--(MID(A1,FIND("-",A1)-4,1))--(MID(A1,FIND("-",A1)-5,1))--(MID(A1,FIND("-",A1)-6,1))),LEFT(A1,FIND("-",A1)-1))
However, if I were to continue doing this for other strings, I would soon run out of characters limit that is allowed in a cell. I wonder whether a formulae such as below is valid? Any suggestion or help for a shorter formula is very much appreciated.
=IF(ISNUMBER(--(LEFT(A1,1+1+1+1+1+1))),LEFT(A1,6))
I want to write a macro that will check every selected cell. It should detect if there is a space after the fourth character. If there is a space, go to the next selected cell. If there is no space, add a space and go to the next selected cell.
View 5 Replies View RelatedI need a formula that will search the range D8-D100 to confirm that all cells within that range are either 11 characters in length or blank. I will use it inside of an error message that will look something like this:
=IF(****formula that checks to make sure all of the cells in that range are blank or 11 characters****=TRUE, "", "Please make sure that all cells are 11 digits or blank")
I am working on sales information which includes postcodes. What i need to do is seperate the first or first two text characters from the rest of the postcode. I have attached a small snipet of what i am working on. Currently i am using the =Left(A4,2) but this will give me in some case a numerical value aswell. For example E1 or G1 in the case of the sample attached. Is there a formula that exists where it will just return the text values in a cell and not numerical values.
View 6 Replies View RelatedI have a cell (B2) I would like to apply multiple data validations to.
I know I need to use the custom formula option but don't know how to write the formula.
I don't even know if it is possible, but here is what I'm after
I need to make sure the cell is 4 digits long
I need to make sure the cell starts with a zero (Because the cell starts with a zero I have it as a text cell)
I need to make sure the 2nd number is not 0 if A2 begins with 5 (A2 is also a text cell).
I have a sheet in which some of the cells have two strings separated by a linefeed. I have come up with a cumbersome formula which will let me check if either of the two strings is a member of a list stored on another sheet. However, it fails if there is only one string in the cell, presumably as there is no linefeed for the formula to find. How can I modify the formula to cope with this situation?
There are also on occasions, three strings in the cell, but I can't seem to access the middle string with the formula. Simplified spreadsheet attached to show the problem. This must be formula-based, as we have a no VBA policy. If you think there is better way of doing this, please let me know.
I frequently need to extract email addresses from huge amounts of text, like 40+ pages long, etc... I was wondering if a macro could be developed somehow to leave me with a stack of email addresses. I suppose the macro would have to test each piece of text for an "@" and a ".com" and then stack only those terms in a column somewhere. Any ideas on how to do this? I am not macro savvy AT ALL...
View 9 Replies View RelatedI've searched Excel's Help but still unsure how to do this. I hope excel experts here can lend me a hand...
I have literally thousands of words in a single columns column which looks like this:
absah
absen
absenan
absensi
abses
absis
absolusi
absolut
absolutisme
...
...
...
etc
My question is what formula if i'd have to enter to add three spaces between characters and five characters at every end of the word so it should look like this?:
a b s a h .
a b s e n .
a b s e n a n .
....
....
etc
Note i have entered a full stop at the end of the example above to make the five spaces visible in this demonstration (I dont need the period character inserted at all).
In my worksheet, column C contains a list of part numbers of various lengths.
How do I copy the part number without the last 3 characters & paste in col D?
I don't mind if this is achieved using VBA code or excel function.
How do I add special characters in-between text? I know how to include a registered sign by using =CHAR(174) but what I do not know is how to include text before and after the sign itself.
ie timeware *registered sign* community
I want to trim text into 10 characters.I am new to excel.
Attached is the sample sheet.
TRIM.xls‎
I am submitting a book CSV file to my website. However, the website will not accept any cell that contains more than 80 characters. The error states the following. "WARNING: Title should be less than or equal to 80 chars; your Title was truncated to 80 chars" repeated 13 times.
View 2 Replies View Related"Is there some VBA code which could delete all first, second or third
characters of a text? Could it be done to the three last characters
from this same text and these be displayed on reverse order?"
Example:
AAAASAHDASK
AAASAHDASK
AASAHDASK
ASAHDASK
SADHASAAAA
ADHASAAAA
DHASAAAA
From the names listed in column A, in the table listed below, I wish to delete everything
to the right of the first two characters.
So the new column A would look this.
A
1
E HAZARD
2
F LAMPARD
3
F MALOUDA
[code].....
if there is maximum number of characters in a cell, above which wrapping and the row height auto-fit functions will not work? I typed a paragraph into a cell and have the cell set to wrap and the row height to auto-fit but it does not display on print preview or on actual printing past a certain character in the cell. Even when I manually increase the row height, it still does not display.
View 4 Replies View RelatedI have a spreadsheet that uses sql to gather data from our servers. From this data, I use concatenate function to put the data into one cell ready to copy/paste into our sms program. The program will only take 160 characters at a time..
Result I need:
For the cell to split into two/three cells if over 160 characters (and to break after the last complete word), and if appropriate, it needs to say 1of2 at the beginning of the 1st message for example, and 2of2 at the beginning of the second.
I have a cell which holds text with a maximum number of characters of 6. Let´s say I want this cell to hold a word which is bigger, and trim it till it has 6 characters.
Example: word "Hippopotamus" (longer than 6 characters) should be trimmed so its displayed as "Hippop"(6 characters)
is there a way to specify how i want to trim, either right or left?
Example "Hippop"(6 characters trim right) or "otamus" (6 characters trim left)
In order to compare strings I have to remove a special character from imported text.
It is character F008 from Unicode(hex).
This charcter is not on my keyboard.
I find it under Insert - Symbol but I can't copy and paste it to the find/replace window.
how can I key in this character so that I can use it for find and replace?
I pasted in 1369 characters (including spaces) to a cell, and NO MATTER what I try, all characters will not print.
If I have the cell up for formatting on the function line, all text can be seen, but for some reason it cuts off the last sentance or more and will not show it in print preview.
I've tried all kinds of cell text formatting, cell merging, etc. with no luck. The only work around I found is to just have the "missing text" on the following row.
This is very similar to my previous post, which was solved. Now that I've extract the numbers, I need to extract the text for the specific work activities, for example 13Z or 9GGG. I'm assuming some variation on this formula:
=LOOKUP(9.99E+307,--MID(C4,MIN(FIND({1,2,3,4,5,6,7,8,9,0},C4&1234567890)),ROW(INDIRECT("1:"&LEN(C4)))))
is the solution, but I'm struggling with making the correct alterations.
I am trying to extract text from stings that appear in the following format XXX-XXX-XXX and XXX-XXX-XXX-XXX.
I have figured out how to extract the first and second sets of data, what I am stuck on is getting the third and (if present) fourth sections.
Is there a function that can remove all text and other characters from cell and only keep the numbers? The numbers can be randomly in the cell so not only in the end or beginning.
See attached file.
This should be simple, but I am struggling with finding a way to use the search or find function to identify text characters. This is my situation, I have for example a cell that contains FW023 or D1234. I need to be able to count the number of characters that are text.
i would think I would be able to do it with the search or find function, but can't figure out how to get it to just count the number of text characters with in it.
I need a Excel 2007 formula that will extract a string of text that is seperated by characters.
Example:
in Cell (A1) I have the following
ALA 11 : [ MOBILE ] 36619 1/2 ... HOME ... JUNE 2009 / TODAY: $ 50000
End Result wanted:
Cell (A2) 11
Cell (A3) MOBILE
Cell (A4) 36619 1/2
Cell (A5) HOME
Cell (A6) JUNE 2009
Cell (A7) 50000
How I can change this formula to find the first 3 characters of a text string?
Instead of using numbers in column A, it will be Names, I need the user to enter only the first 3 characters of the name and then display the results, (Meaning that all others irrelaavnt rows will be hidden.
Sub myHidingRoutine()
Dim foundCell As Range
With ThisWorkbook.Sheets("Sheet1")
Set foundCell = .Range("a:a").Find(What:=.Range("a2").Value, After:=.Range("a2"), _
LookIn:=xlValues, LookAt:=xlWhole, SearchOrder:=xlByRows, _
SearchDirection:=xlNext, MatchCase:=False)