I have a unique 6 digit number in a column. I have 2500 rows. I need to cut the first three numbers only leaving the last 3 numbers in the column for each row.
Example:
112345
234325
I would need 112, and 234 deleted. Checked the forum and cannot get quite what I want.
I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.
=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)
I have a long list of 4 digit numbers:
e.g.
0234
2434
6566
4566
6785
But I only want the first 2 digits (I need the last two digits deleted). I don't want to just divide by 1000 as this will leve me with a decimal. The numbers are in text format as some of them begin with a 0. So it would be:
02
24
65
45
67
I have a excel file, I need to remove the first two digits if they are certain numbers, such as 12. For example, if the number is 12987654, then I need remove 12, and it will be "987654" , but if it is not 12 in the first two digits, then keep it no change, for example if it is 345678, then keep it.
I barely work with Excel formulas, now I need connect the excel file with my Database table. I need to make the file matches the DB.
Example numbers:
21130 & 21065
I want to check each number if EITHER of the two conditions is true:
1. if the third digit from the right (the hundreth place) is greater than zero;
or
2. if the second digit from the right (the tens place) is >=6.
If either is true I want to add a particular number to the original number.
My example numbers meet questions 1 & 2, respectively.
this may be simple but I need to convent say
A1 = 09
B1 = 23
into
C1 = 0
D1 = 9
E1 = 2
F1 = 3
..etc
I have a column with numbers in about 500 rows. The entries are 5 numbers long and others 8. So I thought i could use one of the following: A macro code to tell a cell to delete the first 3 numbers if the entry is 8 numbers long?
OR
A macro code to tell a cell to reduce itself to 5 digits long starting from the right? Attached is a small example
I need to list 4 digit numbers in each section followed by commas, but whatever I do it goes to 3digits (e.g. I need "1234,5678,9123" and as soon as I hit Enter it goes to "123,456,789,123"). It wont work to format as text because I have a whole bunch of 12 digit numbers to break up into 4.
View 9 Replies View RelatedI need a way to display all 8 digit numbers that have the digits 1-8 in them. (ie. 12345678 but NOT 12345679 OR 12345677) Also If I could somehow divide by 13 then check for whole numbers
View 14 Replies View RelatedI would like to extract numbers based on the first 2 digits (22....) of a column along with its next column (on the right) and put them on another sheet.
View 9 Replies View RelatedI am inserting data into my spreadsheet using VBA code to read a file and insert the data into the relevant cells. My problem arises when I have a string such as 80830410205724044. The actual code that inserts the data is as shown (temp is dimmed as string)....
View 9 Replies View RelatedI have a UPC list. Some are more than 12 digits, and some with less than 12 digits. I need to make sure there are 12 digits in each UPC. I know how to count using LEN, strip leading zeros of those UPCs that are >12 digits using RIGHT.
What I need now is any number with less than 12 digits, such as 000123, add a 4 to the beginning (4000123) and fill in '0's in between the 4 and the short UPC number to make 12 digits, 400000000123. They vary from 1 to 13 digits.
I have some numbers around 200 numbers which are not same digits i.e. if 1st number is 7 digits, 2nd number is of 10 digits.
Like this even if i have a number of 1 or 2 digits then all number should have equal digits i.e. in 200 numbers if one numbers is of 13 digits then all the numbers should be 13 digits.
To do this first i am doing this to the right align & comparison all numbers & taking the highest digit number & pre-fixing the other numbers with zeros so that all number are equal in number of digits. This is taking huge time.
I want to make a macro or any easy method so that all should have equal no of digits.
I want that if 200 numbers are pasted in the column E i.e. from E2 to E201 then all should be converted to equal digits number by prefixing zeros & should appear in column G from G2 to G201.
And after converting them it should be prefixed with D/ OR D/ABC:
This will be present in B2 cell i.e. this cell will be blank always. And once I have any thing in that cell that should be prefixed to the converted numbers in the column G & they should appear in Column I.
And again the numbers in column G should be prefixed with the content in B2 & should appear in column K in the Ascending order sorted.
Suppose if , I have 500 numbers then they should be converted automatically to equal digits & appear in Column G & prefixed with the contented in cell B2 should appear in Column I & sorted series in ascending order with prefixed with cell B2 in the column K.
And if I have 15 numbers only then it should do the same job easily. Here the numbers of numbers are not defined.
All this should be get done on click of the command button.
I have a macro that copies long decimals (11 places) from an Excel file to a CSV file. However, the long decimals often get truncated from 11 places down to 3 or 4. I've tried a number of different coding methods to combat this, the most recent and most successful of which is shown below
Application.Workbooks.Open Filename:="C:...2008_alldata.csv"
Cells.Select
Selection.ClearContents
ActiveWindow.ActivateNext
Application.Goto Reference:="AllDataTable"
Selection.Copy
ActiveWindow.ActivateNext
Application.Goto Reference:="R1C1"
Selection.PasteSpecial Paste:=xlPasteValues
Range("R2:BI5000").Select
Selection.NumberFormat = "#,##0.00000000000"
ActiveWorkbook.Save
ActiveWindow.Close savechanges:=False
However, sometimes this method also fails. Is there a better way anyone knows of to ensure that the entire decimal is copied?
I am trying to filter my excel sheet based on certain digits in a column of part numbers. The part number has 10 characters. I would like to filter it so that all part numbers where the 4th character is the number 5 or 7 is listed and where the 5th character is a zero. (i.e. R4X5831310 is a part number where 5 is the 4th character; I would like the filter to show this part number)
View 2 Replies View Relatedvb code that will break out each 6 digit media used in their own rows such as in the illustration below.
Sample data before macro
Master Backup
GTI - Hostname
[Code]....
I have a column that has section numbers like 001.002.006.003.010.011.002.
I would like to divide that single column into seven columns with only the single or double digit in it, ie
1 in a cell
2 in a cell
6 in a cell
3 in a cell
10 in a cell
11 in a cell
2 in a cell
Have been using MID and FIND togther, but when I get to the double digits like 10 an 11 I run into problems.
I need a formula to drag down the attached that will place zeros infront of any numbers that don't have 9 digits. so if a part number consists of 6 digits then i need 3 zeros in front of it, if a part number consists of 9 digits then i dont need any zeros proceeding it.
View 2 Replies View Relatedi need to format my numbers in the following format
10,00,000.00
the first three digits will be separated and then subsequently 2 digits
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay 07
De Wetshof Sauvignon Blanc 07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage 01
Bouchard Finlayson Tete de Cuvee Pinot Noir 07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon 05
DuToitskloof Pinotage/Merlot/Ruby Cabernet
1999 Tradition Juracon 375ml
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.
Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay 07
De Wetshof Sauvignon Blanc 07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage 01
Bouchard Finlayson Tete de Cuvee Pinot Noir 07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
2003 Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon 05
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
Does anyone have an idea on how to help with this?
Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.
However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.
Is it possible to delete a column of numbers then replace those numbers from adjacent columns and the adjacent columns are then filled with the numbers adjacent to them
View 9 Replies View RelatedI want to ask that I have got a workbook with different number series i want user form where i can enter its start number and end number and then it finds and delete shift cells up said series number i have entered in user form please see mentioned below example.
Series
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
and i want to delete 1 to 5 numbers delete to shift cells up.
I have got a list of numeric abbreviations, for instance 10739011/21/31/41. What it should really display are the numbers 10739011, 10739021, 10739031 and 10739041 (the first six figures stay the same). All the numbers in my list are 8 figures long. I want to change the list from the list seperated by the backward slash to the complete numbers. I have uploaded an example of the list with backward slash between the numbers. Is there a way that Excel can automatically change these numbers to the full numbers?
Because all the numbers are 8 figures long, I thought the first 6 figures of the 1st number can be copied and those 6 figures pasted before the other two figures after the backslash. Auto Merged Post Until 24 Hrs Passes;sorry, pressed OK too quickly. The problem is that there are sometimes 4 numbers in the cell, sometimes 6 and once three. I would like Excel to complete all the numbers in the cell and then move on to the cell underneath it and so on. Also, I would like each number to have it's own cell.
How is it possible to delete the phone numbers which include 39 like (323940, 393312, 124039, and so) suppose all the phone numbers are in cell B
View 9 Replies View RelatedIs there a way to delete only numbers ending in a decimal from a column of numbers? I have a column of numbers but only the non decimals are relevant to the next equation.
View 3 Replies View RelatedI have attached a pdf of part of my data. I wish to delete those cells in column 2 containing values between 9044795 and 9372402; then have the column below move up (into the cell deleted). Its a large data set so doing it manually is not an option.
After doing this the data across the rows should line up. I have tried using the replace and filter functions but I can't make it work. I've tried some VBA but my knowledge is wanting.
is there anyway i can delete all numbers from a column, leaving only alpha characters?
View 8 Replies View RelatedI have 50,000 to 150,000 rows of data. Row M has data from 0001 to 9999. I need to delete all rows except the rows with values 2500 to 4999. I had this working with a similar and smaller spreadsheet awhile back using an advanced filter. In this case I need to delete the unneeded rows. I would imagine I could also achieve it with a VLOOKUP array and a lot of finagling but with this many records to repetitively
View 8 Replies View RelatedI'm looking for a way, inside a Macro, to delete any value in a range of cells that is not a whole number.
Say I have a range from "A4:C50" I am pasting items from another sheet through a Macro Button but I want code at the end of the Macro to then delete anything in this range that is not a whole number.